python subprocess "mount" does not prompt for password - python

I just learned subprocess.check_call() function today. I intend to use it to replace my os.system command.
Originally, I have my command as such:
os.system("mount -t cifs //source/share /mnt/share -o username=user")
The command above will prompt for password and it will mount the drive if the password is correct.
However, if I tried:
cmd_string="mount -t cifs //source/share /mnt/share -o username=user"
subprocess.check_call(cmd_string.split(" "), shell=True, stdin=sys.stdin)
It would not ask for password. Instead, it just print the partitions. It's like invoke "mount" command without parameters.
Any idea how I can use check_call and still receive interactive input from user?

You are invoking mount without parameters. If you specify shell=True, subprocess expects the entire command including arguments is passed to the shell as one big string. If you specify shell=False (the default if not specified), the command and its arguments are passed as a list of strings, as you have done by using split. By mixing the two forms, you are effectively only passing the string mount as the command to be executed. Either remove shell=True or remove the .split(" "). The first choice is usually better unless there is some reason you need shell parsing to be involved, normally something to be avoided.

Related

Using ssh and sed within a python script with os.system properly

I am trying to run an ssh command within a python script using os.system to add a 0 at the end of a fully matched string in a remote server using ssh and sed.
I have a file called nodelist in a remote server that's a list that looks like this.
test-node-1
test-node-2
...
test-node-11
test-node-12
test-node-13
...
test-node-21
I want to use sed to make the following modification, I want to search test-node-1, and when a full match is found I want to add a 0 at the end, the file must end up looking like this.
test-node-1 0
test-node-2
...
test-node-11
test-node-12
test-node-13
...
test-node-21
However, when I run the first command,
hostname = 'test-node-1'
function = 'nodelist'
os.system(f"ssh -i ~/.ssh/my-ssh-key username#serverlocation \"sed -i '/{hostname}/s/$/ 0/' ~/{function}.txt\"")
The result becomes like this,
test-node-1 0
test-node-2
...
test-node-11 0
test-node-12 0
test-node-13 0
...
test-node-21
I tried adding a \b to the command like this,
os.system(f"ssh -i ~/.ssh/my-ssh-key username#serverlocation \"sed -i '/\b{hostname}\b/s/$/ 0/' ~/{function}.txt\"")
The command doesn't work at all.
I have to manually type in the node name instead of using a variable like so,
os.system(f"ssh -i ~/.ssh/my-ssh-key username#serverlocation \"sed -i '/\btest-node-1\b/s/$/ 0/' ~/{function}.txt\"")
to make my command work.
What's wrong with my command, why can't I do what I want it to do?
This code has serious security problems; fixing them requires reengineering it from scratch. Let's do that here:
#!/usr/bin/env python3
import os.path
import shlex # note, quote is only here in Python 3.x; in 2.x it was in the pipes module
import subprocess
import sys
# can set these from a loop if you choose, of course
username = "whoever"
serverlocation = "whereever"
hostname = 'test-node-1'
function = 'somename'
desired_cmd = ['sed', '-i',
f'/\\b{hostname}\\b/s/$/ 0/',
f'{function}.txt']
desired_cmd_str = ' '.join(shlex.quote(word) for word in desired_cmd)
print(f"Remote command: {desired_cmd_str}", file=sys.stderr)
# could just pass the below direct to subprocess.run, but let's log what we're doing:
ssh_cmd = ['ssh', '-i', os.path.expanduser('~/.ssh/my-ssh-key'),
f"{username}#{serverlocation}", desired_cmd_str]
ssh_cmd_str = ' '.join(shlex.quote(word) for word in ssh_cmd)
print(f"Local command: {ssh_cmd_str}", file=sys.stderr) # log equivalent shell command
subprocess.run(ssh_cmd) # but locally, run without a shell
If you run this (except for the subprocess.run at the end, which would require a real SSH key, hostname, etc), output looks like:
Remote command: sed -i '/\btest-node-1\b/s/$/ 0/' somename.txt
Local command: ssh -i /home/yourname/.ssh/my-ssh-key whoever#whereever 'sed -i '"'"'/\btest-node-1\b/s/$/ 0/'"'"' somename.txt'
That's correct/desired output; the funny '"'"' idiom is how one safely injects a literal single quote inside a single-quoted string in a POSIX-compliant shell.
What's different? Lots:
We're generating the commands we want to run as arrays, and letting Python do the work of converting those arrays to strings where necessary. This avoids shell injection attacks, a very common class of security vulnerability.
Because we're generating lists ourselves, we can change how we quote each one: We can use f-strings when it's appropriate to do so, raw strings when it's appropriate, etc.
We aren't passing ~ to the remote server: It's redundant and unnecessary because ~ is the default place for a SSH session to start; and the security precautions we're using (to prevent values from being parsed as code by a shell) prevent it from having any effect (as the replacement of ~ with the active value of HOME is not done by sed itself, but by the shell that invokes it; because we aren't invoking any local shell at all, we also needed to use os.path.expanduser to cause the ~ in ~/.ssh/my-ssh-key to be honored).
Because we aren't using a raw string, we need to double the backslashes in \b to ensure that they're treated as literal rather than syntactic by Python.
Critically, we're never passing data in a context where it could be parsed as code by any shell, either local or remote.

Bash script will not run with subprocess in Python

For some reason, no matter how many variations I've tried, I can't seem to execute a bash script I've written. The command words 100% fine in Terminal, but when I try calling it with a subprocess, it returns nothing.
from os import listdir
import subprocess
computer_name = 'homedirectoryname'
moviefolder = '/Users/{}/Documents/Programming/Voicer/Movies'.format(computer_name)
string = 'The lion king'
for i in listdir(moviefolder):
title = i.split('.')
formatted_title = title[0].replace(' ', '\ ')
if string.lower() == title[0].lower():
command = 'vlc {}/{}.{}'.format(moviefolder, formatted_title, title[1])
subprocess.call(["/usr/local/bin",'-i','-c', command], stdout=subprocess.PIPE,
stderr=subprocess.PIPE, shell=True)
else:
continue
The bash executable file looks like this:
#/bin/bash
func() {
open -a /Applications/VLC.app/Contents/MacOS/VLC $1
}
Where have I gone wrong?
You should call open directly:
import os
import subprocess
computer_name = 'homedirectoryname'
moviefolder = '/Users/{}/Documents/Programming/Voicer/Movies'.format(computer_name)
string = 'The lion king'
for filename in os.listdir(moviefolder):
title = filename.split('.')
if string.lower() == title[0].lower():
subprocess.call(['open', '-a', '/Applications/VLC.app/Contents/MacOS/VLC', os.path.join(moviefolder, filename)])
Since you are using shell=True, the command must be a string:
On Unix with shell=True, the shell defaults to /bin/sh. If args is a
string, the string specifies the command to execute through the shell.
This means that the string must be formatted exactly as it would be
when typed at the shell prompt. This includes, for example, quoting or
backslash escaping filenames with spaces in them. If args is a
sequence, the first item specifies the command string, and any
additional items will be treated as additional arguments to the shell
itself. (docs)
Like you even mentioned in a comment, you get /usr/local/bin: is a directory when you properly capture the error from the shell (and take out the erroneous shell=True; or correspondingly refactor the command line to be suitable for this usage, i.e. pass a string instead of a list).
Just to spell this out, you are attempting to run the command /usr/local/bin with some options; but of course, it's not a valid command; so this fails.
The actual script you seem to want to run will declare a function and then exit, which results in the function's definition being lost again, because the subprocess which ran the shell in which this function declaration was executed has now terminated and released all its resources back to the system.
Perhaps you should take more than just a few steps back and explain what you actually want to accomplish; but really, that should be a new, separate question.
Assuming you are actually trying to run vlc, and guessing some other things, too, perhaps you actually want
subprocess.call(['vlc','{}/{}.{}'.format(moviefolder, formatted_title, title[1]),
stdout=subprocess.PIPE, stderr=subprocess.PIPE)
If your PATH is correct, you should not need to specify /usr/local/bin/ explicitly (and if your PATH is wrong, correct it in the code before, instead of hardcoding a directory for the executable you want to call).
/usr/local/bin is a directory. You can't run a directory as if it were a command.
Anyhow, there's no point to having /usr/local/bin anywhere in your command at all. Leave out the shell=True, and explicitly call vlc:
subprocess.call([
'vlc',
'{}/{}.{}'.format(moviefolder, formatted_title, title[1])
])
When shell=True is used in subprocess.call, if the command arguments is a sequence, then the first element of the sequence needs to be the command, and the rest are treated as argument(s) to the shell itself.
So, this should do:
subprocess.call(["/usr/local/bin/{}".format(command), '-i','-c'], shell=True, ...)
Otherwise, you can make the command a string.
Example:
In [20]: subprocess.call(["cat spamegg", "-i", "-c"], shell=True)
foobar

SSH: A javac command that works in terminal doesn't work when executed over SSH

I'm using Python code to run a Hadoop program on a Linux (Cloudera) machine using SSH.
I'm having some trouble with compiling java files to class files. When I'm executing the command:
javac -cp /usr/lib/hadoop/*:/usr/lib/hadoop/client-0.20/* remote_hadoop/javasrc/* from the Linux terminal all the files get compiled successfully.
When I'm executing the same command through my Python SSH client I'm receiving an 'invalid flag' error:
spur.results.RunProcessError: return code: 2
output: b''
stderr output: b'javac: invalid flag: remote_hadoop/javasrc\nUsage: javac \nuse -help for a list of possible options\n'
The python code:
list_of_commands = ["javac", "-cp", r"/usr/lib/hadoop/*:/usr/lib/hadoop/client-0.20/*", input_folder + r"/*"]
print ' '.join(list_of_commands)
self.shell.run(list_of_commands)
The command is getting rendered correctly, since what is getting printed is javac -cp /usr/lib/hadoop/*:/usr/lib/hadoop/client-0.20/* remote_hadoop/javasrc/*.
UPDATE: It's pretty weird. I can compile one file at a time over ssh, but not all of them. Seems like something happens to the "*" over ssh.
You're passing a list of arguments, not a list of commands. It's not even an accurate list of arguments.
If your underlying tool expects a list of arguments, then pass:
['sh', '-c', 'javac -cp /usr/lib/hadoop/*:/usr/lib/hadoop/client-0.20/* remote_hadoop/javasrc/*']
If it expects a list of commands:
['javac -cp /usr/lib/hadoop/*:/usr/lib/hadoop/client-0.20/* remote_hadoop/javasrc/*']
If it expects something else -- read the documentation and determine what that something is!
Note that SSH doesn't provide a way to pass a literal argv array when running an arbitrary command; rather, it expects -- at the protocol level -- a string ready for parsing by the remote shell. If your self.shell.run code is doing shell quoting before joining the argument list given, then it would be passing the last argument as the literal string remote_hadoop/javasrc/* -- not expanding it into a list of filenames as a shell would.
Using the sh -c form forces the remote shell to perform expansion on its end, assuming that contents are being given to it in a form which doesn't have remote expansion performed already.
The problem is the way that spur builds the command list into a command string. It takes every command token and encloses it in single quotes (["ls", "*.txt"]) becomes 'ls' '*.txt'). There is no shell expansion of * inside quotes, so the command doesn't work.
You can see the problem in spur's ssh.py on line 323:
def escape_sh(value):
return "'" + value.replace("'", "'\\''") + "'"
I don't use spur, but it looks like it just doesn't allow you to do such things. The problem with "simplifiers" like spur is that if they simplify in a way you don't want, you can't use them.

Python Subprocess Error in using "cp"

I was trying to use subprocess calls to perform a copy operation (code below):
import subprocess
pr1 = subprocess.call(['cp','-r','./testdir1/*','./testdir2/'], shell = True)
and I got an error saying:
cp: missing file operand
Try `cp --help' for more information.
When I try with shell=False , I get
cp: cannot stat `./testdir1/*': No such file or directory
How do I get around this problem?
I'm using RedHat Linux GNOME Deskop version 2.16.0 and bash shell and Python 2.6
P.S. I read the question posted in Problems with issuing cp command with Popen in Python, and it suggested using shell = True option, which is not working for me as I mentioned :(
When using shell=True, pass a string, not a list to subprocess.call:
subprocess.call('cp -r ./testdir1/* ./testdir2/', shell=True)
The docs say:
On Unix with shell=True, the shell defaults to /bin/sh. If args is a
string, the string specifies the command to execute through the shell.
This means that the string must be formatted exactly as it would be
when typed at the shell prompt. This includes, for example, quoting or
backslash escaping filenames with spaces in them. If args is a
sequence, the first item specifies the command string, and any
additional items will be treated as additional arguments to the shell
itself.
So (on Unix), when a list is passed to subprocess.Popen (or subprocess.call), the first element of the list is interpreted as the command, all the other elements in the list are interpreted as arguments for the shell. Since in your case you do not need to pass arguments to the shell, you can just pass a string as the first argument.
This is an old thread now, but I was just having the same problem.
The problem you were having with this call:
subprocess.call(['cp','-r','./testdir1/*','./testdir2/'], shell = False)
was that each of the parameters after the first one are quoted. So to the shell sees the command like this:
cp '-r' './testdir1/*' './testdir2/'
The problem with that is the wildcard character (*). The filesystem looks for a file with the literal name '*' in the testdir1 directory, which of course, is not there.
The solution is to make the call like the selected answer using the shell = True option and none of the parameters quoted.
I know that the option of shell=True may be tempting but it's always inadvisable due to security issues. Instead, you can use a combination of the subprocess and glob modules.
For Python 3.5 or higher:
import subprocess
import glob
subprocess.run(['cp', '-r'] + glob.glob('./testdir1/*') + ['./testdir2/'])
For Python 3.4 or lower:
import subprocess
import glob
subprocess.call(['cp', '-r'] + glob.glob('./testdir1/*') + ['./testdir2/'])

Why does subprocess.Popen() with shell=True work differently on Linux vs Windows?

When using subprocess.Popen(args, shell=True) to run "gcc --version" (just as an example), on Windows we get this:
>>> from subprocess import Popen
>>> Popen(['gcc', '--version'], shell=True)
gcc (GCC) 3.4.5 (mingw-vista special r3) ...
So it's nicely printing out the version as I expect. But on Linux we get this:
>>> from subprocess import Popen
>>> Popen(['gcc', '--version'], shell=True)
gcc: no input files
Because gcc hasn't received the --version option.
The docs don't specify exactly what should happen to the args under Windows, but it does say, on Unix, "If args is a sequence, the first item specifies the command string, and any additional items will be treated as additional shell arguments." IMHO the Windows way is better, because it allows you to treat Popen(arglist) calls the same as Popen(arglist, shell=True) ones.
Why the difference between Windows and Linux here?
Actually on Windows, it does use cmd.exe when shell=True - it prepends cmd.exe /c (it actually looks up the COMSPEC environment variable but defaults to cmd.exe if not present) to the shell arguments. (On Windows 95/98 it uses the intermediate w9xpopen program to actually launch the command).
So the strange implementation is actually the UNIX one, which does the following (where each space separates a different argument):
/bin/sh -c gcc --version
It looks like the correct implementation (at least on Linux) would be:
/bin/sh -c "gcc --version" gcc --version
Since this would set the command string from the quoted parameters, and pass the other parameters successfully.
From the sh man page section for -c:
Read commands from the command_string operand instead of from the standard input. Special parameter 0 will be set from the command_name operand and the positional parameters ($1, $2, etc.) set from the remaining argument operands.
This patch seems to fairly simply do the trick:
--- subprocess.py.orig 2009-04-19 04:43:42.000000000 +0200
+++ subprocess.py 2009-08-10 13:08:48.000000000 +0200
## -990,7 +990,7 ##
args = list(args)
if shell:
- args = ["/bin/sh", "-c"] + args
+ args = ["/bin/sh", "-c"] + [" ".join(args)] + args
if executable is None:
executable = args[0]
From the subprocess.py source:
On UNIX, with shell=True: If args is a string, it specifies the
command string to execute through the shell. If args is a sequence,
the first item specifies the command string, and any additional items
will be treated as additional shell arguments.
On Windows: the Popen class uses CreateProcess() to execute the child
program, which operates on strings. If args is a sequence, it will be
converted to a string using the list2cmdline method. Please note that
not all MS Windows applications interpret the command line the same
way: The list2cmdline is designed for applications using the same
rules as the MS C runtime.
That doesn't answer why, just clarifies that you are seeing the expected behavior.
The "why" is probably that on UNIX-like systems, command arguments are actually passed through to applications (using the exec* family of calls) as an array of strings. In other words, the calling process decides what goes into EACH command line argument. Whereas when you tell it to use a shell, the calling process actually only gets the chance to pass a single command line argument to the shell to execute: The entire command line that you want executed, executable name and arguments, as a single string.
But on Windows, the entire command line (according to the above documentation) is passed as a single string to the child process. If you look at the CreateProcess API documentation, you will notice that it expects all of the command line arguments to be concatenated together into a big string (hence the call to list2cmdline).
Plus there is the fact that on UNIX-like systems there actually is a shell that can do useful things, so I suspect that the other reason for the difference is that on Windows, shell=True does nothing, which is why it is working the way you are seeing. The only way to make the two systems act identically would be for it to simply drop all of the command line arguments when shell=True on Windows.
The reason for the UNIX behaviour of shell=True is to do with quoting. When we write a shell command, it will be split at spaces, so we have to quote some arguments:
cp "My File" "New Location"
This leads to problems when our arguments contain quotes, which requires escaping:
grep -r "\"hello\"" .
Sometimes we can get awful situations where \ must be escaped too!
Of course, the real problem is that we're trying to use one string to specify multiple strings. When calling system commands, most programming languages avoid this by allowing us to send multiple strings in the first place, hence:
Popen(['cp', 'My File', 'New Location'])
Popen(['grep', '-r', '"hello"'])
Sometimes it can be nice to run "raw" shell commands; for example, if we're copy-pasting something from a shell script or a Web site, and we don't want to convert all of the horrible escaping manually. That's why the shell=True option exists:
Popen(['cp "My File" "New Location"'], shell=True)
Popen(['grep -r "\"hello\"" .'], shell=True)
I'm not familiar with Windows so I don't know how or why it behaves differently.

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