How to catch IndentationError [duplicate] - python

This question already has answers here:
SyntaxError inconsistency in Python?
(2 answers)
Closed 5 years ago.
First of all - I don't have a problem with bad-indentated code and I have an idea of how does this exception works like.
I ask, if there is any way to catch IndentationError in code with a try/except block? For example, let's say I'm writing a test for a function written by someone else. I want to run it in try/except block and handle all warning he/she could make. I know, that it's not a best example, but the first one coming to my mind. Please, don't focus on an example, but rather on problem.
Let's look at the code:
try:
f()
except IndentationError:
print "Error"
print "Finished"
The function:
def f():
print "External function"
And the result is:
External function
Finished
And that's something, I'm ready to understand, becouse indentation in external function was consistant.
But when the function look like that:
def f():
print "External function"
print "with bad indentation"
The exception is unhandled:
print "with bad indentation"
^
IndentationError: unexpected indent
Is there any way to achieve it? I guess that's the matter of compiling, and as far I don't see any possibility to catch. Does the except IndentationError make any sense?

Yes, this can be done. However, the function under test would have to live in a different module:
# test1.py
try:
import test2
except IndentationError as ex:
print ex
# test2.py
def f():
pass
pass # error
When run, this correctly catches the exception. It is worth nothing that the checking is done on the entire module at once; I am not sure if there's a way to make it more fine-grained.

IndentationError is raised when the module is compiled. You can catch it when importing a module, since the module will be compiled on first import. You can't catch it in the same module that contains the try/except, because with the IndentationError, Python won't be able to finish compiling the module, and no code in the module will be run.

You could use a tool such as pylint, which will analyse your module and report bad indentation, as well as many other errors.

Related

Is there a simple way to comment out or diable a python try statement without re-indenting

Problem:
Sometimes it is nice to be able to remove or apply a try statement temporarily. Is there a convenient way to disable the try statement without re-indenting?
For example, if there was a python block statement equivalent called "goForIt:" one could edit the word "try:" to "goForIt:" and it would just execute the block as though it were not wrapped in a "try" and ignore the "except" line too.
The problem I'm trying to solve is that while I want the try statement in production I want to be able to remove it temporarily while debugging to see the error traceback rather than have it trap and process the exception.
Currently I work around this by commenting out the "try" then re-indent the code in the block. Then comment out the entire "except" block. This seems clumsy.
Instead of removing the try, you could make the except re-raise the exception:
try:
raise ValueError('whoops')
except ValueError as e:
raise # <-- just put this here
print('caught')
This will raise the error, just as if it were not caught:
ValueError Traceback (most recent call last)
<ipython-input-146-a6be6779c161> in <module>
1 try:
----> 2 raise ValueError('whoops')
3 except ValueError as e:
4 raise
5 print('caught')
ValueError: whoops
I do not believe there is a way to fix this.
Is it adequate to catch the exception, print it out and, if wanted, end the program?
try:
# code
except Exception as e:
print(e)
# end program if wanted
If you want a none code solution you need to use an IDE or a good text editor.
I am using Visual Studio code where I can indent with a keyboard shortcut (Ctrl + ` in my case)
(This is not my answer, but the answer from Alani's comment. If credits, find the original comment under the question.)
The solution is good because it allows global replacement:
try: --> if 1: # try:
except --> if 0: # except
The 2nd one is a little unsure. Exact and full word match should be used, or replace twice (for except<space> and except:). Or you can fix error fast by hand if there is any.
The replacement back is sure.
I need now such solution to debug error in strawberry which is only printed. So I think I need deactivate all try/except structures in 3 libraries (strawberry + 2 libs for django).

Ignore/handle 'unexpected indent' error. Get indent stack level

I want to use indentations for code control, and have two questions.
1) Is it possible to force python ignore 'unexpected indent' errors?
Code like this raises 'unexpected indent' exception.
def test():
print ('hello')
print ('again!')
Is here any flag or another trick to execute above code as normal?
2) How I can get indention level in my program? Is something like that possible:
import introspectionmagic
def a():
l = introspectionmagic.get_indent_level_of_function_call ()
print ('level =', l)
def test():
a()
a()
Output:
level = 1
level = 2
Thanks!
IndentationErrors are syntax errors; they happen at compile time, not run time. So you can't do anything in code to ignore them; you'd need to change the parser somehow.
You might consider using Python's context managers. These enable running specific code when entering a block; this might fit your use case, even if the actual enter code is pretty trivial. See the contextlib module for some examples.

Why isn't my code excepting the errors?

I have this little piece of code I wrote that isn't excepting the errors that could be thrown at it. Here's the code:
def println(stringint):
try:
print stringint
except (SyntaxError, NameError):
print "Invalid format."
I run the code from the python interpreter like this, and only like this:
>>> import pcl
>>> pcl.println("Hello")
Why aren't the errors being excepted? How can I catch the errors?
Those errors that has to do with syntax are parse level errors, which means, that are errors that take place before that particular code being interpreted.
The following arenĀ“t the same type of errors:
print("Hello) # Note the missing '"'
that
print(4/0) # Syntactically correct, but obviously an error.
Hence, syntax error can't be handled by the try -- except block.
See this answer for more detail: SyntaxError inconsistency in Python?
Your code works fine, "Hello" should raise neither an EOLError nor a NameError, because the quotes are closed, and it is a string.

Can Syntax Errors be handled?

Consider the following code:
try:
if True a = 1 #It's missing a colon So it's a SyntaxError!!!!!!!
except SyntaxError:
print 'hey'
You'd expect it to print hey However It raises a SyntaxError, The same error I'm trying to avoid. So Can all Exceptions be handled using a try-except block? Well If SyntaxError's were an exception why is it included in the built-in exceptions? and finally how can I fix the above piece of code so that it handles the exception properly?
Note: I know what I'm trying to do Is utterly pointless and serves no real purpose
SyntaxError is a perfectly ordinary built-in exception. It is not special in any way. Only the circumstances of when it's (usually) thrown are a bit unusual.
A syntax error means that the code featuring said error cannot be parsed. It doesn't even begin to be a valid program, hence it cannot be executed. Therefore SyntaxError exceptions are raised before the program is run, and hence can't be caught from within the program.
More specifically, this exception is raised by the parser. Because the parser runs fully before the code is executed, rather then interleaved with it, a program can't catch its own syntax errors.
The parser itself is just another program though: Code invoking the parser can catch SyntaxErrors like every other exception (because it is like every other exception). Examples of "invoking the parser" include:
compile, exec, eval
import statements
Several functions in modules like ast, tokenizer, parser, etc.
Of course you need SyntaxError as a built-in exception - what else should be raised if the compiler/parser encounters a syntax error?
You're right that this error usually happens at compile time, which is before you're able to catch it (runtime). (And how would you recover from it?)
I can think of one exception, though:
>>> try:
... eval("hello =")
... except SyntaxError:
... print("Hey! Who's using eval() anyway??")
...
Hey! Who's using eval() anyway??

Ignore exceptions thrown and caught inside a library

The Python standard library and other libraries I use (e.g. PyQt) sometimes use exceptions for non-error conditions. Look at the following except of the function os.get_exec_path(). It uses multiple try statements to catch exceptions that are thrown while trying to find some environment data.
try:
path_list = env.get('PATH')
except TypeError:
path_list = None
if supports_bytes_environ:
try:
path_listb = env[b'PATH']
except (KeyError, TypeError):
pass
else:
if path_list is not None:
raise ValueError(
"env cannot contain 'PATH' and b'PATH' keys")
path_list = path_listb
if path_list is not None and isinstance(path_list, bytes):
path_list = fsdecode(path_list)
These exceptions do not signify an error and are thrown under normal conditions. When using exception breakpoints for one of these exceptions, the debugger will also break in these library functions.
Is there a way in PyCharm or in Python in general to have the debugger not break on exceptions that are thrown and caught inside a library without any involvement of my code?
in PyCharm, go to Run-->View Breakpoints, and check "On raise" and "Ignore library files".
The first option makes the debugger stop whenever an exception is raised, instead of just when the program terminates, and the second option gives PyCharm the policy to ignore library files, thus searching mainly in your code.
The solution was found thanks to CrazyCoder's link to the feature request, which has since been added.
For a while I had a complicated scheme which involved something like the following:
try( Closeable ignore = Debugger.newBreakSuppression() )
{
... library call which may throw ...
} <-- exception looks like it is thrown here
This allowed me to never be bothered by exceptions that were thrown and swallowed within library calls. If an exception was thrown by a library call and was not caught, then it would appear as if it occurred at the closing curly bracket.
The way it worked was as follows:
Closeable is an interface which extends AutoCloseable without declaring any checked exceptions.
ignore is just a name that tells IntelliJ IDEA to not complain about the unused variable, and it is necessary because silly java does not support try( Debugger.newBreakSuppression() ).
Debugger is my own class with debugging-related helper methods.
newBreakSuppression() was a method which would create a thread-local instance of some BreakSuppression class which would take note of the fact that we want break-on-exception to be temporarily suspended.
Then I had an exception breakpoint with a break condition that would invoke my Debugger class to ask whether it is okay to break, and the Debugger class would respond with a "no" if any BreakSuppression objects were instantiated.
That was extremely complicated, because the VM throws exceptions before my code has loaded, so the filter could not be evaluated during program startup, and the debugger would pop up a dialog complaining about that instead of ignoring it. (I am not complaining about that, I hate silent errors.) So, I had to have a terrible, horrible, do-not-try-this-at-home hack where the break condition would look like this: java.lang.System.err.equals( this ) Normally, this would never return
true, because System.err is not equal to a thrown exception, therefore the debugger would never break. However, when my Debugger class would get initialized, it would replace System.err with a class of its own,
which provided an implementation for equals(Object) and returned true if the debugger should break. So, essentially, I was using System.err as an eternal global variable.
Eventually I ditched this whole scheme because it is overly complicated and it performs very bad, because exceptions apparently get thrown very often in the java software ecosystem, so evaluating an expression every time an exception is thrown tremendously slows down everything.
This feature is not implemented yet, you can vote for it:
add ability to break (add breakpoint) on exceptions only for my files
There is another SO answer with a solution:
Debugging with pycharm, how to step into project, without entering django libraries
It is working for me, except I still go into the "_pydev_execfile.py" file, but I haven't stepped into other files after adding them to the exclusion in the linked answer.

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