What is the difference between __init__ and __call__? - python

I want to know the difference between __init__ and __call__ methods.
For example:
class test:
def __init__(self):
self.a = 10
def __call__(self):
b = 20

The first is used to initialise newly created object, and receives arguments used to do that:
class Foo:
def __init__(self, a, b, c):
# ...
x = Foo(1, 2, 3) # __init__
The second implements function call operator.
class Foo:
def __call__(self, a, b, c):
# ...
x = Foo()
x(1, 2, 3) # __call__

Defining a custom __call__() method allows the class's instance to be called as a function, not always modifying the instance itself.
In [1]: class A:
...: def __init__(self):
...: print "init"
...:
...: def __call__(self):
...: print "call"
...:
...:
In [2]: a = A()
init
In [3]: a()
call

In Python, functions are first-class objects, this means: function references can be passed in inputs to other functions and/or methods, and executed from inside them.
Instances of Classes (aka Objects), can be treated as if they were functions: pass them to other methods/functions and call them. In order to achieve this, the __call__ class function has to be specialized.
def __call__(self, [args ...])
It takes as an input a variable number of arguments. Assuming x being an instance of the Class X, x.__call__(1, 2) is analogous to calling x(1,2) or the instance itself as a function.
In Python, __init__() is properly defined as Class Constructor (as well as __del__() is the Class Destructor). Therefore, there is a net distinction between __init__() and __call__(): the first builds an instance of Class up, the second makes such instance callable as a function would be without impacting the lifecycle of the object itself (i.e. __call__ does not impact the construction/destruction lifecycle) but it can modify its internal state (as shown below).
Example.
class Stuff(object):
def __init__(self, x, y, range):
super(Stuff, self).__init__()
self.x = x
self.y = y
self.range = range
def __call__(self, x, y):
self.x = x
self.y = y
print '__call__ with (%d,%d)' % (self.x, self.y)
def __del__(self):
del self.x
del self.y
del self.range
>>> s = Stuff(1, 2, 3)
>>> s.x
1
>>> s(7, 8)
__call__ with (7,8)
>>> s.x
7

>>> class A:
... def __init__(self):
... print "From init ... "
...
>>> a = A()
From init ...
>>> a()
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
AttributeError: A instance has no __call__ method
>>>
>>> class B:
... def __init__(self):
... print "From init ... "
... def __call__(self):
... print "From call ... "
...
>>> b = B()
From init ...
>>> b()
From call ...
>>>

__call__ makes the instance of a class callable.
Why would it be required?
Technically __init__ is called once by __new__ when object is created, so that it can be initialized.
But there are many scenarios where you might want to redefine your object, say you are done with your object, and may find a need for a new object. With __call__ you can redefine the same object as if it were new.
This is just one case, there can be many more.

__init__ would be treated as Constructor where as __call__ methods can be called with objects any number of times. Both __init__ and __call__ functions do take default arguments.

I will try to explain this using an example, suppose you wanted to print a fixed number of terms from fibonacci series. Remember that the first 2 terms of fibonacci series are 1s. Eg: 1, 1, 2, 3, 5, 8, 13....
You want the list containing the fibonacci numbers to be initialized only once and after that it should update. Now we can use the __call__ functionality. Read #mudit verma's answer. It's like you want the object to be callable as a function but not re-initialized every time you call it.
Eg:
class Recorder:
def __init__(self):
self._weights = []
for i in range(0, 2):
self._weights.append(1)
print self._weights[-1]
print self._weights[-2]
print "no. above is from __init__"
def __call__(self, t):
self._weights = [self._weights[-1], self._weights[-1] + self._weights[-2]]
print self._weights[-1]
print "no. above is from __call__"
weight_recorder = Recorder()
for i in range(0, 10):
weight_recorder(i)
The output is:
1
1
no. above is from __init__
2
no. above is from __call__
3
no. above is from __call__
5
no. above is from __call__
8
no. above is from __call__
13
no. above is from __call__
21
no. above is from __call__
34
no. above is from __call__
55
no. above is from __call__
89
no. above is from __call__
144
no. above is from __call__
If you observe the output __init__ was called only one time that's when the class was instantiated for the first time, later on the object was being called without re-initializing.

__call__ allows to return arbitrary values, while __init__ being an constructor returns the instance of class implicitly. As other answers properly pointed out, __init__ is called just once, while it's possible to call __call__ multiple times, in case the initialized instance is assigned to intermediate variable.
>>> class Test:
... def __init__(self):
... return 'Hello'
...
>>> Test()
Traceback (most recent call last):
File "<console>", line 1, in <module>
TypeError: __init__() should return None, not 'str'
>>> class Test2:
... def __call__(self):
... return 'Hello'
...
>>> Test2()()
'Hello'
>>>
>>> Test2()()
'Hello'
>>>

So, __init__ is called when you are creating an instance of any class and initializing the instance variable also.
Example:
class User:
def __init__(self,first_n,last_n,age):
self.first_n = first_n
self.last_n = last_n
self.age = age
user1 = User("Jhone","Wrick","40")
And __call__ is called when you call the object like any other function.
Example:
class USER:
def __call__(self,arg):
"todo here"
print(f"I am in __call__ with arg : {arg} ")
user1=USER()
user1("One") #calling the object user1 and that's gonna call __call__ dunder functions

You can also use __call__ method in favor of implementing decorators.
This example taken from Python 3 Patterns, Recipes and Idioms
class decorator_without_arguments(object):
def __init__(self, f):
"""
If there are no decorator arguments, the function
to be decorated is passed to the constructor.
"""
print("Inside __init__()")
self.f = f
def __call__(self, *args):
"""
The __call__ method is not called until the
decorated function is called.
"""
print("Inside __call__()")
self.f(*args)
print("After self.f( * args)")
#decorator_without_arguments
def sayHello(a1, a2, a3, a4):
print('sayHello arguments:', a1, a2, a3, a4)
print("After decoration")
print("Preparing to call sayHello()")
sayHello("say", "hello", "argument", "list")
print("After first sayHello() call")
sayHello("a", "different", "set of", "arguments")
print("After second sayHello() call")
Output:

Case 1:
class Example:
def __init__(self, a, b, c):
self.a=a
self.b=b
self.c=c
print("init", self.a, self.b, self.c)
Run:
Example(1,2,3)(7,8,9)
Result:
- init 1 2 3
- TypeError: 'Example' object is not callable
Case 2:
class Example:
def __init__(self, a, b, c):
self.a=a
self.b=b
self.c=c
print("init", self.a, self.b, self.c)
def __call__(self, x, y, z):
self.x=x
self.y=y
self.z=z
print("call", self.x, self.y, self.z)
Run:
Example(1,2,3)(7,8,9)
Result:
- init 1 2 3
- call 7 8 9

Short and sweet answers are already provided above. I wanna provide some practical implementation as compared with Java.
class test(object):
def __init__(self, a, b, c):
self.a = a
self.b = b
self.c = c
def __call__(self, a, b, c):
self.a = a
self.b = b
self.c = c
instance1 = test(1, 2, 3)
print(instance1.a) #prints 1
#scenario 1
#creating new instance instance1
#instance1 = test(13, 3, 4)
#print(instance1.a) #prints 13
#scenario 2
#modifying the already created instance **instance1**
instance1(13,3,4)
print(instance1.a)#prints 13
Note: scenario 1 and scenario 2 seems same in terms of result output.
But in scenario1, we again create another new instance instance1. In scenario2,
we simply modify already created instance1. __call__ is beneficial here as the system doesn't need to create new instance.
Equivalent in Java
public class Test {
public static void main(String[] args) {
Test.TestInnerClass testInnerClass = new Test(). new TestInnerClass(1, 2, 3);
System.out.println(testInnerClass.a);
//creating new instance **testInnerClass**
testInnerClass = new Test().new TestInnerClass(13, 3, 4);
System.out.println(testInnerClass.a);
//modifying already created instance **testInnerClass**
testInnerClass.a = 5;
testInnerClass.b = 14;
testInnerClass.c = 23;
//in python, above three lines is done by testInnerClass(5, 14, 23). For this, we must define __call__ method
}
class TestInnerClass /* non-static inner class */{
private int a, b,c;
TestInnerClass(int a, int b, int c) {
this.a = a;
this.b = b;
this.c = c;
}
}
}

__init__ is a special method in Python classes, it is the constructor method for a class. It is called whenever an object of the class is constructed or we can say it initialises a new object.
Example:
In [4]: class A:
...: def __init__(self, a):
...: print(a)
...:
...: a = A(10) # An argument is necessary
10
If we use A(), it will give an error
TypeError: __init__() missing 1 required positional argument: 'a' as it requires 1 argument a because of __init__ .
........
__call__ when implemented in the Class helps us invoke the Class instance as a function call.
Example:
In [6]: class B:
...: def __call__(self,b):
...: print(b)
...:
...: b = B() # Note we didn't pass any arguments here
...: b(20) # Argument passed when the object is called
...:
20
Here if we use B(), it runs just fine because it doesn't have an __init__ function here.

We can use call method to use other class methods as static methods.
class _Callable:
def __init__(self, anycallable):
self.__call__ = anycallable
class Model:
def get_instance(conn, table_name):
""" do something"""
get_instance = _Callable(get_instance)
provs_fac = Model.get_instance(connection, "users")

I want to bring to the table some short cuts and syntax sugar, as well as few techniques that can be used, but I haven't see them in the current answers.
Instantiate the class and call it immediately
In many cases, for example when need to make a APi request, and the logic is encapsulated inside a class and what we really need is just give the data to that class and run it immediatelly as a separate entity, the instantiate class may not been needed. That is the
instance = MyClass() # instanciation
instance() # run the instance.__call__()
# now instance is not needed
Instead we can do something like that.
class HTTPApi:
def __init__(self, val1, val2):
self.val1 = val1
self.val2 = val2
def __call__(self, *args, **kwargs):
return self.run(args, kwargs)
def run(self, *args, **kwargs):
print("hello", self.val1, self.val2, args, kwargs)
if __name__ == '__main__':
# Create a class, and call it
(HTTPApi("Value1", "Value2"))("world", 12, 213, 324, k1="one", k2="two")
Give to call another existing method
We can declare a method to the __call__ as well, without creating an actual __call__ method.
class MyClass:
def __init__(self, val1, val2):
self.val1 = val1
self.val2 = val2
def run(self, *args, **kwargs):
print("hello", self.val1, self.val2, args, kwargs)
__call__ = run
if __name__ == '__main__':
(MyClass("Value1", "Value"))("world", 12, 213, 324, k1="one", k2="two")
This allows to declare another global function instead of a method, for whatever reason (there may be some reasons, for example you can't modify that method but you need it to be called by the class).
def run(self, *args, **kwargs):
print("hello",self.val1, self.val2, args, kwargs)
class MyClass:
def __init__(self, val1, val2):
self.val1 = val1
self.val2 = val2
__call__ = run
if __name__ == '__main__':
(MyClass("Value1", "Value2"))("world", 12, 213, 324, k1="one", k2="two")

call method is used to make objects act like functions.
>>> class A:
... def __init__(self):
... print "From init ... "
...
>>> a = A()
From init ...
>>> a()
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
AttributeError: A instance has no __call__ method
<*There is no __call__ method so it doesn't act like function and throws error.*>
>>>
>>> class B:
... def __init__(self):
... print "From init ... "
... def __call__(self):
... print "From call it is a function ... "
...
>>> b = B()
From init ...
>>> b()
From call it is a function...
>>>
<* __call__ method made object "b" to act like function *>
We can also pass it to a class variable.
class B:
a = A()
def __init__(self):
print "From init ... "

__init__() can:
initialize the instance of class.
be called many time.
only return None.
__call__() can be freely used like an instance method.
For example, Person class has __init__() and __call__() as shown below:
class Person:
def __init__(self, f_name, l_name):
self.f_name = f_name
self.l_name = l_name
print('"__init__()" is called.')
def __call__(self, arg):
return arg + self.f_name + " " + self.l_name
Now, we create and initialize the instance of Person class as shown below:
# Here
obj = Person("John", "Smith")
Then, __init__() is called as shown below:
"__init__()" is called.
Next, we call __call__() in 2 ways as shown below:
obj = Person("John", "Smith")
print(obj("Hello, ")) # Here
print(obj.__call__("Hello, ")) # Here
Then, __call__() is called as shown below:
"__init__()" is called.
Hello, John Smith # Here
Hello, John Smith # Here
And, __init__() can be called many times as shown below:
obj = Person("John", "Smith")
print(obj.__init__("Tom", "Brown")) # Here
print(obj("Hello, "))
print(obj.__call__("Hello, "))
Then, __init__() is called and the instance of Person class is reinitialized and None is returned from __init__() as shown below:
"__init__()" is called.
"__init__()" is called. # Here
None # Here
Hello, Tom Brown
Hello, Tom Brown
And, if __init__() doesn't return None and we call __init__() as shown below:
class Person:
def __init__(self, f_name, l_name):
self.f_name = f_name
self.l_name = l_name
print('"__init__()" is called.')
return "Hello" # Here
# ...
obj = Person("John", "Smith") # Here
The error below occurs:
TypeError: __init__() should return None, not 'str'
And, if __call__ is not defined in Person class:
class Person:
def __init__(self, f_name, l_name):
self.f_name = f_name
self.l_name = l_name
print('"__init__()" is called.')
# def __call__(self, arg):
# return arg + self.f_name + " " + self.l_name
Then, we call obj("Hello, ") as shown below:
obj = Person("John", "Smith")
obj("Hello, ") # Here
The error below occurs:
TypeError: 'Person' object is not callable
Then again, we call obj.__call__("Hello, ") as shown below:
obj = Person("John", "Smith")
obj.__call__("Hello, ") # Here
The error below occurs:
AttributeError: 'Person' object has no attribute '__call__'

Related

Aliase a class function to be assigned from init method

Given I have a class such as:
class Model(object):
def __init__(self, foo = 'bar'):
if foo == 'bar':
self.f = self._sse
else:
self.f = None
def _sse():
pass
Is there a way I can create an alias so I do not have to check what's the value of the non-positional argument foo? Something like
class Model(object):
alias = {'bar': _sse}
def __init__(self, foo = 'bar'):
self.f = foo
def _sse():
pass
Technical answer: you can do it by defining the target function before the initializer, referencing this function as the default argument (Python functions are objects too), and manually invoking the descriptor protocol on the target function:
>>> class Model(object):
... def _sse(self):
... print("in self._sse")
... def __init__(self, foo=_sse):
... self.f = foo.__get__(self, type(self))
...
>>> m = Model()
>>> m.f()
in self._sse
Just note that with this solution, if you want to pass another function, this function has to take self as first argument :
>>> # doesn't work
... def bar(): print("bar")
...
>>> m2 = Model(bar)
>>> m2.f()
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: bar() takes no arguments (1 given)
>>> # works:
... def baaz(self): print("baaz({})".format(self))
...
>>> m3 = Model(baaz)
>>> m3.f()
baaz(<__main__.Model object at 0x7fc3e2337090>)
Now from a readability POV this is barely an improvement IMHO...
EDIT: as Aran-Fey mentions, this doesn't exactly answer the question so for a more "literal" version (and that doesn't require special definitions ordering etc):
class Model(object):
def _sse(self):
print("in self._sse")
alias = {"bar": "_sse"}
def __init__(self, foo="bar"):
self.f = getattr(self, self.alias.get(foo, "___"), None)
But this is still not improving readability...
Using #KlausD. suggestion and including alias in the __init__ method does the trick for me.
class Model(object):
def __init__(self, foo = 'bar'):
alias = {'bar': self._sse,
'bar2': self._sse2}
self.f = alias.get(foo)
def _sse(self):
print('in sse')
def _sse2(self):
print('in sse2')
m = Model(foo='bar')
m.f() # in sse
m = Model(foo='bar2')
m.f() # in sse2

Python: how to monkey patch class method to other class method

I have got the following code:
class A:
def __init__(self):
self.a = "This is mine, "
def testfunc(self, arg1):
print self.a + arg1
class B:
def __init__(self):
self.b = "I didn't think so"
self.oldtestfunc = A.testfunc
A.testfunc = self.testfuncPatch
def testfuncPatch(self, arg):
newarg = arg + self.b # B instance 'self'
self.oldtestfunc(self, newarg) # A instance 'self'
instA = A()
instB = B()
instA.testfunc("keep away! ")
I want to do the following:
Some class A consists of a function with arguments.
I want to monkey patch this function to a function in class B do some manipulate the arguments and accessing class B's variables, my problem being the patched function actually needs two different 'self' objects, namely the instance of class A as well as the instance of class B.
Is this possible?
the issue is that when you override a class function with an already bound method, trying to bind to other instances just ignore the second instance:
print(instA.testfunc)
#<bound method B.testfuncPatch of <__main__.B object at 0x1056ab6d8>>
so the method basically is treated as a staticmethod meaning you would have to call it with the instance as the first argument:
instA.testfunc(instA,"keep away! ")
I first ran into this issue when trying to import random.shuffle directly into a class to make it a method:
class List(list):
from random import shuffle #I was quite surprised when this didn't work at all
a = List([1,2,3])
print(a.shuffle)
#<bound method Random.shuffle of <random.Random object at 0x1020c8c18>>
a.shuffle()
Traceback (most recent call last):
File "/Users/Tadhg/Documents/codes/test.py", line 5, in <module>
a.shuffle()
TypeError: shuffle() missing 1 required positional argument: 'x'
To fix this issue I created a function that can be rebound to a second instance on top of the first:
from types import MethodType
def rebinder(f):
if not isinstance(f,MethodType):
raise TypeError("rebinder was intended for rebinding methods")
def wrapper(*args,**kw):
return f(*args,**kw)
return wrapper
class List(list):
from random import shuffle
shuffle = rebinder(shuffle) #now it does work :D
a = List(range(10))
print(a.shuffle)
a.shuffle()
print(a)
#output:
<bound method rebinder.<locals>.wrapper of [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]>
[5, 6, 8, 2, 4, 1, 9, 3, 7, 0]
So you can apply this to your situation just as easily:
from types import MethodType
def rebinder(f):
if not isinstance(f,MethodType):
raise TypeError("rebinder was intended for rebinding methods")
def wrapper(*args,**kw):
return f(*args,**kw)
return wrapper
...
class B:
def __init__(self):
self.b = "I didn't think so"
self.oldtestfunc = A.testfunc
A.testfunc = rebinder(self.testfuncPatch) #!! Edit here
def testfuncPatch(selfB, selfA, arg): #take the instance of B first then the instance of A
newarg = arg + selfB.b
self.oldtestfunc(selfA, newarg)
If B could be a subclass of A, the problem would be solved.
class B(A):
def __init__(self):
A.__init__(self)
# Otherwise the same

Methods called within __new__

I would like to create a class which returns an int when initiated, like so:
r = Foo(10)
print r # 1000
I know you can do this by overriding the __new__ method. However I need it to also execute other class functions within the __new__ method, how do I do this?
So far I have:
class Foo(object):
def __new__(cls, i):
cls.i = i
return cls.foo_fun()
def foo_fun(self):
return self.i * 100
print Foo(5)
and the error I get:
Traceback (most recent call last):
return cls.foo_fun()
TypeError: unbound method foo_fun() must be called with Foo instance as first argument (got nothing instead)
You don't have an instance in your __new__ factory method (which is static, really). You don't have a self to call things on. Use another static or class method:
class Foo(object):
def __new__(cls, i):
return cls.foo_fun(i)
#staticmethod
def foo_fun(i):
return i * 100
print Foo(5)
Setting cls.i is not thread-safe as that state is shared between all __new__ calls; you are much better off passing along the value as a parameter to another method.
However, you are abusing classes here; you never create an instance of this class, there is no way to use the class in isinstance() type checks, etc. Just use a factory function:
def foo(i):
return i * 100
If you really meant for this to be a subclass of int, you'll still need to create an actual instance of your class to return:
class Foo(int):
def __new__(cls, i):
i = int(i) # ensure you have an actual integer first
value = cls.foo_fun(i)
return super(Foo, cls).__new__(cls, value)
#staticmethod
def foo_fun(i):
return i * 100
The above inherits from int, handles the case where the argument is not an integer (like"42"`, a string convertible to an integer) and returns an instance of your class.
Demo:
>>> class Foo(int):
... def __new__(cls, i):
... i = int(i) # ensure you have an actual integer first
... value = cls.foo_fun(i)
... return super(Foo, cls).__new__(cls, value)
... #staticmethod
... def foo_fun(i):
... return i * 100
...
>>> f = Foo(42)
>>> f
4200
>>> isinstance(f, Foo)
True
>>> Foo("42") # non-integer input works too
4200

Decide baseclass at runtime

I want to do something like this:
class A:
def methodA(self):
return 5
class B:
def methodB(self):
return 10
class X(...):
def __init__(self, baseclass):
if baseclass =='A' : derive X from A
elif baseclass == 'B' : derive X from B
else: raise Exception("Not supported baseclass %s!" % (baseclass))
def methodX(self):
return 42
X('A').methodA() # returns 5
X('A').methodX() # returns 42
X('A').methodB() # methodB not defined
X('B').methodB() # returns 10
X('B').methodX() # returns 42
X('A').methodA() # methodA not defined
How can I implement this?
If you want to add methodX to the existing classes, you could consider multiple inheritance:
class A:
def methodA(self):
return 5
class B:
def methodB(self):
return 10
class X():
#classmethod
def new(cls, baseclass):
if baseclass == A:
return AX()
elif baseclass == B:
return BX()
else: raise Exception("Not supported baseclass %s!" % str(baseclass))
def methodX(self):
return 42
class AX(A, X):
pass
class BX(B, X):
pass
You can add args and kwargs to X.new and pass them on to the specific constructors. Here are the outputs of your tests (I corrected the last on in your question):
>>> ax = X.new(A)
>>> ax.methodA() # returns 5
5
>>> ax.methodX() # returns 42
42
>>> ax.methodB() # methodB not defined
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
AttributeError: AX instance has no attribute 'methodB'
>>> bx = X.new(B)
>>> bx.methodB() # returns 10
10
>>> bx.new(B).methodX() # returns 42
42
>>> bx.new(B).methodA() # methodA not defined
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
AttributeError: BX instance has no attribute 'methodA'
You should define two classes, X and Y, and a factory-method to instantiate either X or Y, depending on a parameter.
In general, the behavior you try to implement is somewhat confusing. When you create an instance (that is what X(...) does) you should get an instance of X, and instances of a class should have same attributes. That is one of the main reasons why classes exist.
Example:
class A:
def methodA(self):
return 5
class B:
def methodB(self):
return 10
def x(class_name):
name2class = {"A":A, "B":B}
return name2class[class_name]()
for name in ["A","B","C"]:
instance = x(name)
print name, instance
will print
A <__main__.A instance at 0x022C8D50>
B <__main__.B instance at 0x022C8DF0>
Traceback (most recent call last):
File ".../14834949.py", line 21, in <module>
instance = x(name)
File ".../14834949.py", line 18, in x
return name2class[class_name]()
KeyError: 'C'

Python, a function in a method

I have a method (__init__) in a class, and I want to use a function from the class in this method.
But when I want to run my program. I get: NameError: global name 'myfunction' is not defined
Someone, who knows what I have to do? :)
Thank you. But I have still a problem, because def myFunc(self, a): is a method and I wanted a function.
class Myclass(object):
def __init__(self, a):
self.a = self.myFunc(a)
def myFunc(self, a):
return a+1
Then you don't have a function call in the method, but you have a method call in it.
When creating a class you must specify the object when calling its methods:
>>> class A(object):
... def __init__(self, val):
... self.val = self._process(val)
... def _process(self, val):
... return val % 7
... process = _process #if you are outside methods then you don't
... #have to add "self.".
...
>>> a = A(5)
>>> a.process(3)
3
>>> a._process(6) #"a" is passed as the "self" parameter
6
As you can see in a class definition, but outside the methods you must specify the method name only, and not the "self.". Also you can't refer to a method not already defined:
>>> class B(object):
... def __init__(self):pass
... def method1(self):pass
... __call__ = method2 #method2 not defined!
...
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "<stdin>", line 4, in B
NameError: name 'method2' is not defined

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