Ubuntu 18.04:
I created a script to check if a python script is running and to start it if not. I'm using echo statements for debugging that output to verify.txt.
The debug statements inside the IF statement are not executing. I believe it's the syntax comparing a variable to an int. Does this look correct?
# Script to check if python script is running
echo "(verify.sh): checking to see if scripts are running..." > verify.txt
output="$(pgrep -f -c myprogram.py)"
echo "(verify.sh): assigned the output correctly as $output" > verify.txt
if [[$output -eq 0]];
then
echo "(verify.sh): entered the if loop" > verify.txt
python /home/User/myprogram.py &
echo "(verify.sh): started myprogram.py" > verify.txt
fi
Note: The file name is verify.sh, so I added it to the echo just to keep track of who was writing to the debug file.
You need to add some spaces, it should look like if [[ $output -eq 0 ]].
Try it out.
I am using a batch file to access my portable VLC executable to convert an mp4 to an mp3:
set arg1=%1 REM -> arg1={my_mp4_full_path}
set arg2=%2 REM -> arg2={my_mp3_full_path}
echo %arg1%
echo %arg2%
REM batch file is in the same directory as "VLCPlayer" folder
"%~dp0\VLCPlayer\VLCPortable.exe" -I dummy %arg1% --sout=#transcode{acodec=mp3,ab=128,vcodec=dummy}:std{access="file",mux="raw",dst=%arg2%} vlc://quit
When I run this script the first time, vlc crashes and I get an unplayable mp3 file, however when I run the script again the script works and I get a playable mp3. Is there a way to remedy this, or make it consistent? I don't see why running it twice would yield different outcomes.
No I don't have ffmpeg on my computer it is unrecognizable internal or external command.
Note that I face the same problem when using powershell to perform the same task, when I import my function from a .psm1 script:
function ConvertToMp3(
[switch] $inputObject,
[string] $vlc = '{PAth_TO_PORTABLE_VLC}\VLCPortable.exe')
{
PROCESS {
$codec = 'mp3';
$oldFile = $_;
$newFile = $oldFile.FullName.Replace($oldFile.Extension, ".$codec").Replace("'","");
&"$vlc" -I dummy "$oldFile" ":sout=#transcode{acodec=$codec,
vcodec=dummy}:standard{access=file,mux=raw,dst=`'$newFile`'}" vlc://quit | out-null;
# delete the original file
Remove-Item $oldFile;
}
}
I get the same random output that sometimes works, sometimes crashes.
Update:
I feel like I should add more info of how I use the batch file:
I have a python script Convert.py and I call my batch file inside using os.system():
mp4_to_convert = arguments.file
full_path_mp4 = os.path.join(outdir,mp4_to_convert)
mp3_to_convert_to = mp4_to_convert.replace(".mp4",".mp3")
full_path_mp3 = os.path.join(outdir,mp3_to_convert_to)
command_string = """Convert_Script.bat \"{}\" \"{}\"""".format(full_path_mp4, full_path_mp3)
os.system(command_string)
This is the documentation of os.system():
os.system(command)
Execute the command (a string) in a subshell. This
is implemented by calling the Standard C function system(), and has
the same limitations. Changes to sys.stdin, etc. are not reflected in
the environment of the executed command. If command generates any
output, it will be sent to the interpreter standard output stream.
On Unix, the return value is the exit status of the process encoded in
the format specified for wait(). Note that POSIX does not specify the
meaning of the return value of the C system() function, so the return
value of the Python function is system-dependent.
On Windows, the return value is that returned by the system shell
after running command. The shell is given by the Windows environment
variable COMSPEC: it is usually cmd.exe, which returns the exit status
of the command run; on systems using a non-native shell, consult your
shell documentation.
Any pointers or suggestions would be helpful, thank you in advance for your help.
I have a batch script which is generating a configuration file after its execution, the configuration file generated has some data inside it. When i execute it from command prompt as follows i get the desired output :
C:/> start.bat
but if i try to execute from python script as follows or even if i double click and execute it i do get the configuration file but it does not contain any required data it just have '0' inside it:
import subprocess as sp
p= sp.Popen("C:/pathtobatch/start.bat",stdin=sp.PIPE, stdout = sp.PIPE, stderr=sp.PIPE)
Inside the batch script(start.bat) i am actually executing a python script and retrieving its data to a configuration file as follows:
python C:\inetpub\ftproot\sample.py > log.txt
set myvar =< log.txt
del log.txt
echo %errorlevel% %myvar% >C:\inetpub\ftproot\config.txt
I need to execute the batch(start.bat) from the python script and generate the config.txt file having the required data. So, how shall i do that.
Why the start.bat is not working fine if i double click it and why is it working fine if i am executing it from command prompt.
Is it possible that you get '0' as it is the value of %errorlevel%?
I found two issues in your case:
1) batch file - can you please update your batch file to something like:
for /f %%i in ('python C:\inetpub\ftproot\sample.py') do set myvar=%%i
echo %errorlevel% %myvar% >C:\inetpub\ftproot\config.txt
Credit for the idea of setting variable: https://stackoverflow.com/a/2340018/5088142
2) python script - can you please update your python script to be:
import os
os.system("C:/pathtobatch/start.bat")
I have a python script that takes two arguments, and when I run it the script outputs 3 new files as it is supposed too:
>>> python importpymol2.py 65_*.pdb BTB_old.pdb
but when I put is through a shell loop that also changes directories(the script is in each directory):
>>>> for i in *;do current_dir=$PWD; cd $PWD/*;python importpymol2.py 65_*.pdb BTB_old.pdb;cd $current_dir; done
but, it runs perfectly normal with the exception that it doesn't output the files.... how can I get it to output the files?
Don't try to cd back. Instead, just run in a subshell:
for i in *; do ( cd $i; python ...; ); done
There may be a typo in your shell command, try to change it to:
for i in *;do current_dir=$PWD; cd $PWD/$i;python ../importpymol2.py 65_*.pdb BTB_old.pdb;cd $current_dir; done
(I assume importpymol2.py is located in your $PWD.)
How can I create a simple BAT file that will run my python script located at C:\somescript.py?
c:\python27\python.exe c:\somescript.py %*
Open a command line (⊞ Win+R, cmd, ↵ Enter)
and type python -V, ↵ Enter.
You should get a response back, something like Python 2.7.1.
If you do not, you may not have Python installed. Fix this first.
Once you have Python, your batch file should look like
#echo off
python c:\somescript.py %*
pause
This will keep the command window open after the script finishes, so you can see any errors or messages. Once you are happy with it you can remove the 'pause' line and the command window will close automatically when finished.
Here's how you can put both batch code and the python one in single file:
0<0# : ^
'''
#echo off
echo batch code
python "%~f0" %*
exit /b 0
'''
print("python code")
the ''' respectively starts and ends python multi line comments.
0<0# : ^ is more interesting - due to redirection priority in batch it will be interpreted like :0<0# ^ by the batch script which is a label which execution will be not displayed on the screen. The caret at the end will escape the new line and second line will be attached to the first line.For python it will be 0<0 statement and a start of inline comment.
The credit goes to siberia-man
Just simply open a batch file that contains this two lines in the same folder of your python script:
somescript.py
pause
If you've added Python to your PATH then you can also simply run it like this.
python somescript.py
You can use python code directly in batch file,
https://gist.github.com/jadient/9849314.
#echo off & python -x "%~f0" %* & goto :eof
import sys
print("Hello World!")
See explanation, Python command line -x option.
--- xxx.bat ---
#echo off
set NAME1="Marc"
set NAME2="Travis"
py -u "CheckFile.py" %NAME1% %NAME2%
echo %ERRORLEVEL%
pause
--- yyy.py ---
import sys
import os
def names(f1,f2):
print (f1)
print (f2)
res= True
if f1 == "Travis":
res= False
return res
if __name__ == "__main__":
a = sys.argv[1]
b = sys.argv[2]
c = names(a, b)
if c:
sys.exit(1)
else:
sys.exit(0)
Similar to npocmaka's solution, if you are having more than one line of batch code in your batch file besides the python code, check this out: http://lallouslab.net/2017/06/12/batchography-embedding-python-scripts-in-your-batch-file-script/
#echo off
rem = """
echo some batch commands
echo another batch command
python -x "%~f0" %*
echo some more batch commands
goto :eof
"""
# Anything here is interpreted by Python
import platform
import sys
print("Hello world from Python %s!\n" % platform.python_version())
print("The passed arguments are: %s" % sys.argv[1:])
What this code does is it runs itself as a python file by putting all the batch code into a multiline string. The beginning of this string is in a variable called rem, to make the batch code read it as a comment. The first line containing #echo off is ignored in the python code because of the -x parameter.
it is important to mention that if you want to use \ in your batch code, for example in a file path, you'll have to use r"""...""" to surround it to use it as a raw string without escape sequences.
#echo off
rem = r"""
...
"""
This is the syntax:
"python.exe path""python script path"pause
"C:\Users\hp\AppData\Local\Programs\Python\Python37\python.exe" "D:\TS_V1\TS_V2.py"
pause
Basically what will be happening the screen will appear for seconds and then go off take care of these 2 things:
While saving the file you give extension as bat file but save it as a txt file and not all files and Encoding ANSI
If the program still doesn't run save the batch file and the python script in same folder and specify the path of this folder in Environment Variables.
If this is a BAT file in a different directory than the current directory, you may see an error like "python: can't open file 'somescript.py': [Errno 2] No such file or directory". This can be fixed by specifying an absolute path to the BAT file using %~dp0 (the drive letter and path of that batch file).
#echo off
python %~dp0\somescript.py %*
(This way you can ignore the c:\ or whatever, because perhaps you may want to move this script)
ECHO OFF
set SCRIPT_DRIVE = %1
set SCRIPT_DIRECTORY = %2
%SCRIPT_DRIVE%
cd %SCRIPT_DRIVE%%SCRIPT_DIRECTORY%
python yourscript.py`
i did this and works:
i have my project in D: and my batch file is in the desktop, if u have it in the same drive just ignore the first line and change de D directory in the second line
in the second line change the folder of the file, put your folder
in the third line change the name of the file
D:
cd D:\python_proyects\example_folder\
python example_file.py
Use any text editor and save the following code as runit.bat
#echo off
title Execute Python [NarendraDwivedi.Org]
:main
echo.
set/p filename=File Name :
echo.
%filename%
goto main
Now place this file in the folder where python script is present. Run this file and enter python script's file name to run python program using batch file (cmd)
Reference : Narendra Dwivedi - How To Run Python Using Batch File
Create an empty file and name it "run.bat"
In my case i use "py" because it's more convenient, try:
C:
cd C:\Users\user\Downloads\python_script_path
py your_script.py
#echo off
call C:\Users\[user]\Anaconda3\condabin\conda activate base
"C:\Users\[user]\Anaconda3\python.exe" "C:\folder\[script].py"
start xxx.py
You can use this for some other file types.