Develop Reference

Python 3: Making a new line in a variable

I'm currently trying to make an ASCII map via python using segments of walls. I got it to work in print() but I'm a bit new and don't know how to store it to a variable.
If I invoke the variable, it prints the list with no line breaks. If I assign a variable to a print, it works, but prints it all first before I want it to.
Any solutions? Can I format the initial a1_map list to create the new lines?
Here's what I have:
north_exit = ' ___| |___'
north_no_exit = ' ___________'
south_exit = ' ```| |``` '
mid_no_exit = '| |'
top_WandE_exit = '\u2143 L'
top_W_exit = '\u2143 |'
top_E_exit = '| L'
mid_WandE_exit = ' (\u00B0.\u00B0) '
mid_W_exit =' (\u00B0.\u00B0) |'
mid_E_exit ='| (\u00B0.\u00B0) '
lower_W_exit = '\u02E5 |'
lower_WandE_exit = 'T T'
lower_E_exit = '| T'
current_room = 'the crew quarters'
a1_map = print(north_no_exit,'\n' + top_E_exit,'\n' + mid_E_exit,'\n' + lower_E_exit, '\n' +south_exit, '\n'+ 'You are in',current_room+'.')
I could just type:
print(north_no_exit,'\n' + top_E_exit,'\n' + mid_E_exit,'\n' + lower_E_exit, '\n' +south_exit, '\n'+ 'You are in',current_room+'.')
each time. However I want to format it so I can just type:
print(a1_map)
As an example, the list output without print() looks like:
(' ___________', '\n| L', '\n| (°.°) ', '\n| T', '\n | | ', '\nYou are in', 'the crew quarters.')
I would like it to look like (as an example):
___________
| L
| (°.°)
| T
```| |```
(EDIT: Sorry, trying to make it look like a box but I cant even do it on here!)

So, I feel dumb.
Formatting it and then using a loop seemed to work
a1_map = [north_no_exit, top_E_exit, mid_E_exit, lower_E_exit, south_exit]
for segment in a1_map:
print(segment)

You can simply use + to join strings or string join() method to join them with a separator string.
You can also make a dictionary or a list to help you manage them and iterate them

I think you can use Python's f-string.
north_exit = ' ___| |___'
north_no_exit = ' ___________'
south_exit = ' ```| |``` '
mid_no_exit = '| |'
top_WandE_exit = '\u2143 L'
top_W_exit = '\u2143 |'
top_E_exit = '| L'
mid_WandE_exit = ' (\u00B0.\u00B0) '
mid_W_exit =' (\u00B0.\u00B0) |'
mid_E_exit ='| (\u00B0.\u00B0) '
lower_W_exit = '\u02E5 |'
lower_WandE_exit = 'T T'
lower_E_exit = '| T'
current_room = 'the crew quarters'
a1_map = f"{north_no_exit}\n{top_E_exit}\n{mid_E_exit}\n{lower_E_exit}\n{south_exit}\n"
message = "You are in',current_room."
print(a1_map+message)

how to pass variable instead of number in sendcommand in autocad python

how to pass variable instead of number in sendcommand
acad.doc.SendCommand('QLEADER ' '0,500' '\n' '200,1000 ''\n' '500 ' 'ABC \n' '\n' )
this works but
a=0
b=500
acad.doc.SendCommand('QLEADER ' 'a,b ' '\n' '200,1000 ''\n' '500 ' 'ABC \n' '\n' )
but this doesn't work

Try using f-String:
a=0
b=500
acad.doc.SendCommand('QLEADER ' f'{a},{b} ' '\n' '200,1000 ''\n' '500 ' 'ABC \n' '\n' )
Hope it helps.

Need help joining dictionary items and remove newlines and multiple spaces and special characters

Dictionary with 2 urls and their text: Need to get rid of all multiple spaces, special characters and new lines
{'https://firsturl.com': ['\n\n',
'\n ',
'\n \n \n ',
'\n \n ',
'\n \n ',
'\n\n ',
'\n',
'\n',
'\n ',
'\n ',
'Home | Sam ModelInc',
'\n \n\n\n',
'\n\n\n\n',
'\n\n',
'\n \n\n\n\n\n\n\n\n\n \n \n',
'\n',
'\n',
'\n',
'\n',
'\n ',
'\n ',
'Skip to main content'],'https://secondurl.com#main-content': ['\n\n',
'\n ',
'\n \n \n ',
'\n \n ',
'\n \n ',
'\n\n ',
'\n',
'\n',
'\n ',
'\n ',
'Home | Going to start inc',
'\n \n\n\n',
'\n\n\n\n',
'\n\n',
'\n \n\n\n\n\n\n\n\n\n \n \n',
'\n',
'\n',
'\n',
'\n',
'\n ',
'\n ',
'Skip to main content',
'\n ',
'\n \n',
'\n\n ',
'\n\n ',
'\n \n \n \n \n ',
'\n\n ',
'\n ',
'\n\n \n ',
'\n ',
'\n\n \n ',
'\n ',
'Brands',
'\n',
'About Us',
'\n',
'Syndication',
'\n',
'Direct Response']}
Expected Output:
{'https://firsturl.com': ['home sam modelInc skip to main content'], https://secondurl.com#main-content': ['home going to start inc skip to main content brands about us syndication direct response]}
Help would be much appreciated

So let's try to walk through this instead of just throwing some code at you.
The first element we want to get rid of is the newline. So we could start with something like:
ex_dict = {"a": ["\n\n", "\n"]}
for x in ex_dict:
new_list = [e for e in ex_dict[x] if "\n" not in e]
ex_dict[x] = new_list
If you run that, you'll see that we now filter out all new lines.
Now we have the following cases:
Home | Sam ModelInc
Skip to main content
Home | Going to start inc
Brands
About Us
Syndication
Direct Response
According to your expected output, you want to lowercase all words and remove non-alphabet characters.
Did a little research for how to do that.
In code, that looks like:
import re
regex = re.compile('[^a-zA-Z ]') # had to tweak the linked solution to include spaces
ex_dict = {"a": ["\n\n", "\n"]}
for x in ex_dict:
new_list = [e for e in ex_dict[x] if "\n" not in e]
"""
>>> regex.sub("", "Home | Sam ModelInc")
'Home Sam ModelInc'
"""
new_list = [regex.sub("", e) for e in new_list]
ex_dict[x] = new_list
so now our final new_list looks something like: ['Home Sam ModelInc', 'Skip to main content']
Next we want to lowercase everything.
import re
regex = re.compile('[^a-zA-Z ]') # had to tweak the linked solution to include spaces
ex_dict = {"a": ["\n\n", "\n"]}
for x in ex_dict:
new_list = [e for e in ex_dict[x] if "\n" not in e]
"""
>>> regex.sub("", "Home | Sam ModelInc")
'Home Sam ModelInc'
"""
new_list = [regex.sub("", e) for e in new_list]
new_list = [e.lower() for e in new_list]
ex_dict[x] = new_list
and lastly we want to combine everything with only one space between each word.
import re
regex = re.compile('[^a-zA-Z ]') # had to tweak the linked solution to include spaces
ex_dict = {"a": ["\n\n", "\n"]}
for x in ex_dict:
new_list = [e for e in ex_dict[x] if "\n" not in e]
"""
>>> regex.sub("", "Home | Sam ModelInc")
'Home Sam ModelInc'
"""
new_list = [regex.sub("", e) for e in new_list]
new_list = [e.lower() for e in new_list]
new_list = [" ".join((" ".join(new_list)).split())]
ex_dict[x] = new_list

How do I make a dictionary that stores data as a list? [More complicated]

I have a problem with dictionaries that I need help with.
Here is an excerpt from weather.txt:
Hail : 1 : xxx
Hail : 2 : xxx
Hail : 3 : xxx
Rain : 1 : xxx
Rain : 2 : xxx
Rain : 3 : xxx
The first value is the weather, the second value is the intensity and the third is just a short description.
Here is an excerpt from my game:
weather = open("weather.txt")
weather_list = {}
for line in weather:
line = line.rstrip().split(":")
weather_list[line[0][int(line[1]) -1]] = (line[0], line[1], line[2])
for key, value in weather_list.items():
print key, ":", value
That prints this:
a : ('Rain ', ' 2 ', ' xxx')
i : ('Rain ', ' 3 ', ' xxx')
H : ('Hail ', ' 1 ', ' xxx')
R : ('Rain ', ' 1 ', ' xxx')
But I want it to print this:
'Rain': [('Rain ', ' 1 ', ' xxx'), ('Rain ', ' 2 ', ' xxx'), i : ('Rain ', ' 3 ', ' xxx')]
'Hail': etc...
I know my issue is with the syntax "weather_list[line[0][int(line[1]) -1]]". What I want it to do is have 1 key for each weather, and each value to be a tuple or list containing all the values for that weather, sorted by intensity, (intensity 1, intensity 2, intensity 3).
Any and all help is appreciated. Hope I explained it better this time.

Solution
This works:
weather = {}
with open('weather.txt') as fobj:
for line in fobj:
data = line.strip().split(':')
weather.setdefault(data[0], []).append(tuple(data))
weather = {key: sorted(value, key=lambda x: x[1]) for key, value in weather.items()}
The result looks like this:
>>> weather
{'Hail ': [('Hail ', ' 1 ', ' xxx'),
('Hail ', ' 2 ', ' xxx'),
('Hail ', ' 3 ', ' xxx')],
'Rain ': [('Rain ', ' 1 ', ' xxx'),
('Rain ', ' 2 ', ' xxx'),
('Rain ', ' 3 ', ' xxx')]}
Variation
The above solution has, as requested, redundant information for Rain and Hail. This version does not store them as first element in tuple but only as key in the dictionary:
weather = {}
with open('weather.txt') as fobj:
for line in fobj:
data = line.strip().split(':')
weather.setdefault(data[0], []).append(tuple(data[1:]))
weather = {key: sorted(value) for key, value in weather.items()}
The sorting is simpler and the result looks like this:
>>> weather
{'Hail ': [(' 1 ', ' xxx'), (' 2 ', ' xxx'), (' 3 ', ' xxx')],
'Rain ': [(' 1 ', ' xxx'), (' 2 ', ' xxx'), (' 3 ', ' xxx')]}

Looping through dictionary and getting keys [duplicate]

This question already has answers here:
Iterating over dictionaries using 'for' loops
(15 answers)
Closed 7 years ago.
I'm trying to get the names in a dictionary and their corresponding key values.
Sorry if this has already been asked. This code is not working because I suck at programming and just starting. Please tell me what's wrong with it.
theBoard = {'top-L': ' ',
'top-M': ' ',
'top-R': ' ',
'mid-L': ' ',
'mid-M': ' ',
'mid-R': ' ',
'low-L': ' ',
'low-M': ' ',
'low-R': ' '
'Check for closed moves'
def openMoves:
for i in theBoard:
if theBoard[i] == ' ':
print "the move %s is open" % theBoard[i]
else:
print "the move %s is taken" % theBoard[i]
print openMoves()

theBoard = {'top-L': ' ',
'top-M': ' ',
'top-R': ' ',
'mid-L': ' ',
'mid-M': ' ',
'mid-R': ' ',
'low-L': ' ',
'low-M': ' ',
'low-R': ' '
} # <--- Close your dictionary
# <--- remove random string 'Check for c...'
def openMoves(): # <--- add parenthesis to function
for k, v in theBoard.items(): # <--- loop over the key, value pairs
if v == ' ':
print "the move %s is open" % k
else:
print "the move %s is taken" % k
openMoves() # <-- remove the print statement

theBoard = {'top-L': ' ',
'top-M': ' ',
'top-R': ' ',
'mid-L': ' ',
'mid-M': ' ',
'mid-R': ' ',
'low-L': ' ',
'low-M': ' ',
'low-R': ' '}
def openMoves():
for k,v in theBoard.items():
if v == ' ':
print "the move %s is open" %k
else:
print "the move %s is taken" %k
I think your tabbing is off too...