I am using the bottlenose for Amazon Product API. I simply created some codes and met the error below:
Code I created:
ak = "my access key"
sk = "My secret key"
import bottlenose
amazon = bottlenose.Amazon(ak, sk)
response=amazon.ItemLookup(ItemId="0596520999", ResponseGroup="Images", SearchIndex="Books", IdType="ISBN",Style="http://xml2json-xslt.googlecode.com/svn/trunk/xml2json.xslt") % reference from the README file of bottlenose
Here is the error I got:
Traceback (most recent call last):
File "C:/Python27/amazontest", line 6, in <module>
response=amazon.ItemLookup(ItemId="0596520999", ResponseGroup="Images", SearchIndex="Books", IdType="ISBN",Style="http://xml2json-xslt.googlecode.com/svn/trunk/xml2json.xslt")
File "C:\Users\supercoco\AppData\Roaming\Python\Python27\site-packages\bottlenose\api.py", line 104, in __call__
response = urllib2.urlopen(api_request)
File "C:\Python27\lib\urllib2.py", line 126, in urlopen
return _opener.open(url, data, timeout)
File "C:\Python27\lib\urllib2.py", line 400, in open
response = meth(req, response)
File "C:\Python27\lib\urllib2.py", line 513, in http_response
'http', request, response, code, msg, hdrs)
File "C:\Python27\lib\urllib2.py", line 438, in error
return self._call_chain(*args)
File "C:\Python27\lib\urllib2.py", line 372, in _call_chain
result = func(*args)
File "C:\Python27\lib\urllib2.py", line 521, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
HTTPError: HTTP Error 400: Bad Request
Is there anyone know what is the problem? I appreicate your answer!
Thanks
-CC
in
amazon = bottlenose.Amazon(ak, sk)
you need to add a third parameter: service Tag.
amazon = bottlenose.Amazon(ak, sk, service_tag)
Related
I’m facing an issue using Python3 Amazon API. I noticed that a lot of people have the same problem, but I looked for the solution everywhere without results.
I’m trying this simple piece of code:
from amazon.api import AmazonAPI
amazon = AmazonAPI (my_AMAZON_ACCESS_KEY, my_AMAZON_SECRET_KEY, my_AMAZON_ASSOC_TAG, region=’IT’)
products = amazon.search(Keywords = "book name", SearchIndex = "Books")
print(products)
#<amazon.api.AmazonSearch object at 0x7fcc238e7a20>
Until here it works.
for item in products:
print (item.title, item.isbn, item.price_and_currency)
here I get the following error:
File "amazon_loader.py", line 78, in getItemFromAmazon
for item in products:
File "/home/valentinim/.conda/envs/telepot/lib/python3.6/site-packages/amazon/api.py", line 544, in __iter__
for page in self.iterate_pages():
File "/home/valentinim/.conda/envs/telepot/lib/python3.6/site-packages/amazon/api.py", line 561, in iterate_pages
yield self._query(ItemPage=self.current_page, **self.kwargs)
File "/home/valentinim/.conda/envs/telepot/lib/python3.6/site-packages/amazon/api.py", line 573, in _query
response = self.api.ItemSearch(ResponseGroup=ResponseGroup, **kwargs)
File "/home/valentinim/.conda/envs/telepot/lib/python3.6/site-packages/bottlenose/api.py", line 274, in __call__
{'api_url': api_url, 'cache_url': cache_url})
File "/home/valentinim/.conda/envs/telepot/lib/python3.6/site-packages/bottlenose/api.py", line 235, in _call_api
return urllib2.urlopen(api_request, timeout=self.Timeout)
File "/home/valentinim/.conda/envs/telepot/lib/python3.6/urllib/request.py", line 223, in urlopen
return opener.open(url, data, timeout)
File "/home/valentinim/.conda/envs/telepot/lib/python3.6/urllib/request.py", line 532, in open
response = meth(req, response)
File "/home/valentinim/.conda/envs/telepot/lib/python3.6/urllib/request.py", line 642, in http_response
'http', request, response, code, msg, hdrs)
File "/home/valentinim/.conda/envs/telepot/lib/python3.6/urllib/request.py", line 570, in error
return self._call_chain(*args)
File "/home/valentinim/.conda/envs/telepot/lib/python3.6/urllib/request.py", line 504, in _call_chain
result = func(*args)
File "/home/valentinim/.conda/envs/telepot/lib/python3.6/urllib/request.py", line 650, in http_error_default
raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 403: Forbidden
I suppose it is an issue with python urrlib library and not with AmazonAPI. Moreover, I assume it is something about the identification when trying to request information from the downloaded AmazonSearch object, but I don’t know how to fix the problem.
I tried also Python2, no differences.
I am trying to parse some data from 'https://datausa.io/profile/geo/jacksonville-fl/#intro', but I am not sure how to access it from python. My code is:
adress, headers = urllib.request.urlretrieve(' https://datausa.io/profile/geo/jacksonville-fl/#intro')
handle = open(adress)
and it returns the error:
Traceback (most recent call last):
File "C:/Users/Jared/AppData/Local/Programs/Python/Python36-32/capstone1.py", line 16, in <module>
adress, headers = urllib.request.urlretrieve(' https://datausa.io/profile/geo/jacksonville-fl/#intro')
File "C:\Users\Jared\AppData\Local\Programs\Python\Python36-32\lib\urllib\request.py", line 248, in urlretrieve
with contextlib.closing(urlopen(url, data)) as fp:
File "C:\Users\Jared\AppData\Local\Programs\Python\Python36-32\lib\urllib\request.py", line 223, in urlopen
return opener.open(url, data, timeout)
File "C:\Users\Jared\AppData\Local\Programs\Python\Python36-32\lib\urllib\request.py", line 532, in open
response = meth(req, response)
File "C:\Users\Jared\AppData\Local\Programs\Python\Python36-32\lib\urllib\request.py", line 642, in http_response
'http', request, response, code, msg, hdrs)
File "C:\Users\Jared\AppData\Local\Programs\Python\Python36-32\lib\urllib\request.py", line 570, in error
return self._call_chain(*args)
File "C:\Users\Jared\AppData\Local\Programs\Python\Python36-32\lib\urllib\request.py", line 504, in _call_chain
result = func(*args)
File "C:\Users\Jared\AppData\Local\Programs\Python\Python36-32\lib\urllib\request.py", line 650, in http_error_default
raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 403: Forbidden
Please explain what is wrong or tell me a better way to access the page. Also, does the ' .io ' suffix affecthow python handles it?
Thanks.
This worked for me:
import requests
url = "https://datausa.io/profile/geo/jacksonville-fl/#intro"
req = requests.request("GET",url)
I'm trying to run a script to grab dada from an API and feed to a mongodb database. And I keep getting this error but if I test one sing url it works.
Any suggestions?
full script http://pastebin.com/Xap5vYYC
Traceback (most recent call last):
File "hmsParser.py", line 112, in <module>
smReply = urlopen(smUrl).read().decode("utf8")
File "/Library/Frameworks/Python.framework/Versions/3.5/lib/python3.5/urllib/request.py", line 162, in urlopen
return opener.open(url, data, timeout)
File "/Library/Frameworks/Python.framework/Versions/3.5/lib/python3.5/urllib/request.py", line 471, in open
response = meth(req, response)
File "/Library/Frameworks/Python.framework/Versions/3.5/lib/python3.5/urllib/request.py", line 581, in http_response
'http', request, response, code, msg, hdrs)
File "/Library/Frameworks/Python.framework/Versions/3.5/lib/python3.5/urllib/request.py", line 509, in error
return self._call_chain(*args)
File "/Library/Frameworks/Python.framework/Versions/3.5/lib/python3.5/urllib/request.py", line 443, in _call_chain
result = func(*args)
File "/Library/Frameworks/Python.framework/Versions/3.5/lib/python3.5/urllib/request.py", line 589, in http_error_default
raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 404: NOT FOUND
I'm using Django and i'm trying to run this lib 'translate' or 'goslate' so I can translate text from google translate in runtime and free.
for goslate:
this is my function
import goslate
gs = goslate.Goslate()
translate = gs.translate(txt,target,source)
when I work locally it's working great and I'm getting the translation for the given 'txt'
I deploy my django app to herokuapp.com I got an error
this is the error:
Traceback (most recent call last):
File "<console>", line 1, in <module>
File "/app/.heroku/python/lib/python2.7/site-packages/goslate.py", line 409, in translate
return _unwrapper_single_element(self._translate_single_text(text, target_language, source_language))
File "/app/.heroku/python/lib/python2.7/site-packages/goslate.py", line 334, in _translate_single_text
results = list(self._execute(make_task(i) for i in split_text(text)))
File "/app/.heroku/python/lib/python2.7/site-packages/goslate.py", line 203, in _execute
yield each()
File "/app/.heroku/python/lib/python2.7/site-packages/goslate.py", line 332, in <lambda>
return lambda: self._basic_translate(text, target_language, source_lauguage)[0]
File "/app/.heroku/python/lib/python2.7/site-packages/goslate.py", line 251, in _basic_translate
response_content = self._open_url(url)
File "/app/.heroku/python/lib/python2.7/site-packages/goslate.py", line 181, in _open_url
response = self._opener.open(request, timeout=self._TIMEOUT)
File "/app/.heroku/python/lib/python2.7/urllib2.py", line 437, in open
response = meth(req, response)
File "/app/.heroku/python/lib/python2.7/urllib2.py", line 550, in http_response
'http', request, response, code, msg, hdrs)
File "/app/.heroku/python/lib/python2.7/urllib2.py", line 469, in error
result = self._call_chain(*args)
File "/app/.heroku/python/lib/python2.7/urllib2.py", line 409, in _call_chain
result = func(*args)
File "/app/.heroku/python/lib/python2.7/urllib2.py", line 656, in http_error_302
return self.parent.open(new, timeout=req.timeout)
File "/app/.heroku/python/lib/python2.7/urllib2.py", line 437, in open
response = meth(req, response)
File "/app/.heroku/python/lib/python2.7/urllib2.py", line 550, in http_response
'http', request, response, code, msg, hdrs)
File "/app/.heroku/python/lib/python2.7/urllib2.py", line 475, in error
return self._call_chain(*args)
File "/app/.heroku/python/lib/python2.7/urllib2.py", line 409, in _call_chain
result = func(*args)
File "/app/.heroku/python/lib/python2.7/urllib2.py", line 558, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
HTTPError: HTTP Error 503: Service Unavailable
why locally it's working great and on heroku it's not? how can I fix it?
or a new translation lib that it's free
I found the problem,
google translate block the request from heroku
i need to use proxy server so google translate will not think that i'm a robot
there is an free app that i found in heroku named "fixie" i think it will do the trick
I know we can handle redirection with requests and urllib2 packages. I do not want to use requests as it is not a prebuilt package. Please help me with urllib2 to handle a URL which takes a 302 and then moves to 404. I am not concerned about the 404 and I would like to track whether it is a 301 or 302.
I referred this doc but it still throws the 404.
Here is my code
import urllib2
class My_HTTPRedirectHandler(urllib2.HTTPRedirectHandler):
def http_error_302(self, req, fp, code, msg, headers):
return urllib2.HTTPRedirectHandler.http_error_302(self, req, fp, code, msg, headers)
my_opener = urllib2.build_opener(My_HTTPRedirectHandler)
urllib2.install_opener(my_opener)
response =urllib2.urlopen("MY URL")
print response.read()
Here is my response
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/lib/python2.7/urllib2.py", line 126, in urlopen
return _opener.open(url, data, timeout)
File "/usr/lib/python2.7/urllib2.py", line 406, in open
response = meth(req, response)
File "/usr/lib/python2.7/urllib2.py", line 519, in http_response
'http', request, response, code, msg, hdrs)
File "/usr/lib/python2.7/urllib2.py", line 438, in error
result = self._call_chain(*args)
File "/usr/lib/python2.7/urllib2.py", line 378, in _call_chain
result = func(*args)
File "<stdin>", line 3, in http_error_302
File "/usr/lib/python2.7/urllib2.py", line 625, in http_error_302
return self.parent.open(new, timeout=req.timeout)
File "/usr/lib/python2.7/urllib2.py", line 406, in open
response = meth(req, response)
File "/usr/lib/python2.7/urllib2.py", line 519, in http_response
'http', request, response, code, msg, hdrs)
File "/usr/lib/python2.7/urllib2.py", line 444, in error
return self._call_chain(*args)
File "/usr/lib/python2.7/urllib2.py", line 378, in _call_chain
result = func(*args)
File "/usr/lib/python2.7/urllib2.py", line 527, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
urllib2.HTTPError: HTTP Error 404: Not Found
It's better to use httplib and HTTP/1.1 HEAD method. That way no response body is received.
What’s the best way to get an HTTP response code from a URL?