python can't start a new thread - python

I am building a multi threading application.
I have setup a threadPool.
[ A Queue of size N and N Workers that get data from the queue]
When all tasks are done I use
tasks.join()
where tasks is the queue .
The application seems to run smoothly until suddently at some point (after 20 minutes in example) it terminates with the error
thread.error: can't start new thread
Any ideas?
Edit: The threads are daemon Threads and the code is like:
while True:
t0 = time.time()
keyword_statuses = DBSession.query(KeywordStatus).filter(KeywordStatus.status==0).options(joinedload(KeywordStatus.keyword)).with_lockmode("update").limit(100)
if keyword_statuses.count() == 0:
DBSession.commit()
break
for kw_status in keyword_statuses:
kw_status.status = 1
DBSession.commit()
t0 = time.time()
w = SWorker(threads_no=32, network_server='http://192.168.1.242:8180/', keywords=keyword_statuses, cities=cities, saver=MySqlRawSave(DBSession), loglevel='debug')
w.work()
print 'finished'
When the daemon threads are killed?
When the application finishes or when the work() finishes?
Look at the thread pool and the worker (it's from a recipe )
from Queue import Queue
from threading import Thread, Event, current_thread
import time
event = Event()
class Worker(Thread):
"""Thread executing tasks from a given tasks queue"""
def __init__(self, tasks):
Thread.__init__(self)
self.tasks = tasks
self.daemon = True
self.start()
def run(self):
'''Start processing tasks from the queue'''
while True:
event.wait()
#time.sleep(0.1)
try:
func, args, callback = self.tasks.get()
except Exception, e:
print str(e)
return
else:
if callback is None:
func(args)
else:
callback(func(args))
self.tasks.task_done()
class ThreadPool:
"""Pool of threads consuming tasks from a queue"""
def __init__(self, num_threads):
self.tasks = Queue(num_threads)
for _ in range(num_threads): Worker(self.tasks)
def add_task(self, func, args=None, callback=None):
''''Add a task to the queue'''
self.tasks.put((func, args, callback))
def wait_completion(self):
'''Wait for completion of all the tasks in the queue'''
self.tasks.join()
def broadcast_block_event(self):
'''blocks running threads'''
event.clear()
def broadcast_unblock_event(self):
'''unblocks running threads'''
event.set()
def get_event(self):
'''returns the event object'''
return event
ALSo maybe the problem it's because I create SWorker objects in a loop?
What happens with the old SWorker (garbage collection ?) ?

There is still not enough code for localize the problem, but I'm sure that this is because you don't utilize the threads and start too much of them. Did you see canonical example from Queue python documentation http://docs.python.org/library/queue.html (bottom of the page)?
I can reproduce your problem with the following code:
import threading
import Queue
q = Queue.Queue()
def worker():
item = q.get(block=True) # sleeps forever for now
do_work(item)
q.task_done()
# create infinite number of workers threads and fails
# after some time with "error: can't start new thread"
while True:
t = threading.Thread(target=worker)
t.start()
q.join() # newer reached this
Instead you must create the poll of threads with known number of threads and put your data to queue like:
q = Queue()
def worker():
while True:
item = q.get()
do_work(item)
q.task_done()
for i in range(num_worker_threads):
t = Thread(target=worker)
t.daemon = True
t.start()
for item in source():
q.put(item)
q.join() # block until all tasks are done
UPD: In case you need to stop some thread, you can add a flag to it or send a special mark means "stop" for break while loop:
class Worker(Thread):
break_msg = object() # just uniq mark sign
def __init__(self):
self.continue = True
def run():
while self.continue: # can stop and destroy thread, (var 1)
msg = queue.get(block=True)
if msg == self.break_msg:
return # will stop and destroy thread (var 2)
do_work()
queue.task_done()
workers = [Worker() for _ in xrange(num_workers)]
for w in workers:
w.start()
for task in tasks:
queue.put(task)
for _ in xrange(num_workers):
queue.put(Worker.break_msg) # stop thread after all tasks done. Need as many messages as many threads you have
OR
queue.join() # wait until all tasks done
for w in workers:
w.continue = False
w.put(None)

Related

Kill all "workers" on "listener" error (multiprocessing, manager and queue set-up)

I'm using multiprocessing to run workers on different files in parallel. Worker's results are put into queue. A listener gets the results from the queue and writes them to the file.
Sometimes listener might run into errors (of various origins). In this case, the listener silently dies, but all other processes continue running (rather surprisingly, worker errors causes all processes to terminate).
I would like to stop all processes (workers, listener, e.t.c.) when listener catches an error. How this can be done?
The scheme of my code is as follows:
def worker(file_path, q):
## do something
q.put(1.)
return True
def listener(q):
while True:
m = q.get()
if m == 'kill':
break
else:
try:
# do something and write to file
except Exception as err:
# raise error
tb = sys.exc_info()[2]
raise err.with_traceback(tb)
def main():
manager = mp.Manager()
q = manager.Queue(maxsize=3)
with mp.Pool(5) as pool:
watcher = pool.apply_async(listener, (q,))
files = ['path_1','path_2','path_3']
jobs = [ pool.apply_async(worker, (p,q,)) for p in files ]
# fire off workers
for job in jobs:
job.get()
# kill the listener when done
q.put('kill')
# run
if __name__ == "__main__":
main()
I tried introducing event = manager.Event() and using it as a flag in main():
## inside the pool, after starting workers
while True:
if event.is_set():
for job in jobs:
job.terminate()
No success. Calling os._exit(1) in listener exception block rises broken pipe error, but processes are not killed.
I also tried setting daemon = True,
for job in jobs:
job.daemon = True
Did not help.
In fact, to handle listener exceptions, I'm using a callable, as required by apply_async (so that they are not entirely silenced). This complicates the situation, but not much.
Thank you in advance.
As always there are many ways to accomplish what you're after, but I would probably suggest using an Event to signal that the processes should quit. I also would not use a Pool in this instance, as it only really simplifies things for simple cases where you need something like map. More complicated use cases quickly make it easier to just build you own "pool" with the functionality you need.
from multiprocessing import Process, Queue, Event
from random import random
def might_fail(a):
assert(a > .001)
def worker(args_q: Queue, result_q: Queue, do_quit: Event):
try:
while not do_quit.is_set():
args = args_q.get()
if args is None:
break
else:
# do something
result_q.put(random())
finally: #signal that worker is exiting even if exception is raised
result_q.put(None) #signal listener that worker is exiting
def listener(result_q: Queue, do_quit: Event, n_workers: int):
n_completed = 0
while n_workers > 0:
res = result_q.get()
if res is None:
n_workers -= 1
else:
n_completed += 1
try:
might_fail(res)
except:
do_quit.set() #let main continue
print(n_completed)
raise #reraise error after we signal others to stop
do_quit.set() #let main continue
print(n_completed)
if __name__ == "__main__":
args_q = Queue()
result_q = Queue()
do_quit = Event()
n_workers = 4
listener_p = Process(target=listener, args=(result_q, do_quit, n_workers))
listener_p.start()
for _ in range(n_workers):
worker_p = Process(target=worker, args=(args_q, result_q, do_quit))
worker_p.start()
for _ in range(1000):
args_q.put("some/file.txt")
for _ in range(n_workers):
args_q.put(None)
do_quit.wait()
print('done')

Python dynamic MultiThread with Queue - Class

I have been struggling to implement a proper dynamic multi-thread system until now. The idea is to spin up multiple new pools of sub-threads from the main (each pool have its own number of threads and queue size) to run functions and the user can define if the main should wait for the sub-thread to finish up or just move to the next line after starting the thread. This multi-thread logic will help to extract data in parallel and at a fast frequency.
The solution to my issue is shared below for everyone who wants it. If you have any doubts and questions, please let me know.
# -*- coding: utf-8 -*-
"""
Created on Mon Jul 5 00:00:51 2021
#author: Tahasanul Abraham
"""
#%% Initialization of Libraries
import sys, os, inspect
currentdir = os.path.dirname(os.path.abspath(inspect.getfile(inspect.currentframe())))
parentdir = os.path.dirname(currentdir)
sys.path.insert(0,parentdir)
parentdir_1up = os.path.dirname(parentdir)
sys.path.insert(0,parentdir_1up)
from queue import Queue
from threading import Thread, Lock
class Worker(Thread):
def __init__(self, tasks):
Thread.__init__(self)
self.tasks = tasks
self.daemon = True
self.lock = Lock()
self.start()
def run(self):
while True:
func, args, kargs = self.tasks.get()
try:
if func.lower() == "terminate":
break
except:
try:
with self.lock:
func(*args, **kargs)
except Exception as exception:
print(exception)
self.tasks.task_done()
class ThreadPool:
def __init__(self, num_threads, num_queue=None):
if num_queue is None or num_queue < num_threads:
num_queue = num_threads
self.tasks = Queue(num_queue)
self.threads = num_threads
for _ in range(num_threads): Worker(self.tasks)
# This function can be called to terminate all the worker threads of the queue
def terminate(self):
self.wait_completion()
for _ in range(self.threads): self.add_task("terminate")
return None
# This function can be called to add new work to the queue
def add_task(self, func, *args, **kargs):
self.tasks.put((func, args, kargs))
# This function can be called to wait till all the workers are done processing the pending works. If this function is called, the main will not process any new lines unless all the workers are done with the pending works.
def wait_completion(self):
self.tasks.join()
# This function can be called to check if there are any pending/running works in the queue. If there are any works pending, the call will return Boolean True or else it will return Boolean False
def is_alive(self):
if self.tasks.unfinished_tasks == 0:
return False
else:
return True
#%% Standalone Run
if __name__ == "__main__":
import time
def test_return(x,d):
print (str(x) + " - pool completed")
d[str(x)] = x
time.sleep(5)
# 2 thread and 10000000000 FIFO queues
pool = ThreadPool(2,1000000000)
r ={}
for i in range(10):
pool.add_task(test_return, i, r)
print (str(i) + " - pool added")
print ("Waiting for completion")
pool.wait_completion()
print ("pool done")
# 1 thread and 2 FIFO queues
pool = ThreadPool(1,2)
r ={}
for i in range(10):
pool.add_task(test_return, i, r)
print (str(i) + " - pool added")
print ("Waiting for completion")
pool.wait_completion()
print ("pool done")
# 2 thread and 1 FIFO queues
pool = ThreadPool(2,1)
r ={}
for i in range(10):
pool.add_task(test_return, i, r)
print (str(i) + " - pool added")
print ("Waiting for completion")
pool.wait_completion()
print ("pool done")
Making a new Pool
Using the above classes, one can make a pool of their own choise with the number of parallel threads they want and the size of the queue. Example of creating a pool of 10 threads with 200 queue size.
pool = ThreadPool(10,200)
Adding work to Pool
Once a pool is created, one can use that pool.add_task to do sub-routine works. In my example version i used the pool to call a function and its arguments. Example, I called the test_return fucntion with its arguments i and r.
pool.add_task(test_return, i, r)
Waiting for the pool to complete its work
If a pool is given some work to do, the user can either move to other code lines or wait for the pool to finish its work before the next lines ar being read. To wait for the pool to finish the work and then return back, a call for wait_completion is required. Example:
pool.wait_completion()
Terminate and close down the pool threads
Once the requirement of the pool threads are done, it is possible to terminate and close down the pool threads to save up memory and release the blocked threads. This can be done by calling the following function.
pool.terminate()
Checking if there are any pending works from the pool
There is a function that can be called to check if there are any pending/running works in the queue. If there are any works pending, the call will return Boolean True, or else it will return Boolean False. To check if the pool is working or not call the folling function.
pool.is_alive()

Python server: How can I continously queue tasks while making sure only one at a time is processed

I have two tasks of which one is called every two seconds and the other one is called at random times. Both need to access an object that can't be called before the previous call is finished (if that happens I need to reboot the hardware device manually).
The object is from a class which allows the communication with a hardware device via sockets.
To do so I created a thread class, in order to run everything in the background and no other tasks are blocked. Within this class I implemented a queue: Two different functions put Tasks into the queue and a worker is supposed to execute the tasks !!NOT!! simultaneously.
As this entire project is a server it should run continuously.
Well here is my code and it obviously is not working. I would be very happy if anyone has a clue on how to solve this.
Update: 26.10.2020
In order to make my issue more clear I updated the code based on the answer from Artiom Kozyrev.
import time
from threading import Lock, Thread
import threading
from queue import Queue
class ThreadWorker(Thread):
def __init__(self, _lock: Lock, _queue: Queue, name: str):
# daemon=False means that process waits until all threads are finished
# (not only main one and garbage collector)
super().__init__(name=name, daemon=False)
# lock prevents several worker threads do work simultaneously
self.lock = _lock
# tasks are send from the main thread via Queue
self.queue = _queue
def do_work(self, job):
# lock context manager prevents other worker threads from working in the same time
with self.lock:
time.sleep(3)
print(f"{threading.current_thread().getName()}: {job * 10}")
def run(self):
while True:
job = self.queue.get()
# "poison pillow" - stop message from queue
if not job:
break
self.do_work(job)
def TimeStamp(msg):
tElapsed = (time.time() - tStart) # Display Thread Info
sElap = int(tElapsed)
msElap = int((tElapsed - sElap) * 1000)
usElap = int((tElapsed - sElap - msElap / 1000) * 1000000)
print(msg , ': ', sElap, 's', msElap, 'ms', usElap, 'us')
def f1():
TimeStamp("f1 start")
time.sleep(2)
TimeStamp("f1 finished")
def f2():
TimeStamp("f2 start")
time.sleep(6)
TimeStamp("f2 finished")
def insertf1():
for i in range(10):
q.put(f1())
time.sleep(2)
def insertf2():
for i in range(10):
time.sleep(10)
q.put(f2())
q = Queue()
lock = Lock()
workers = [ThreadWorker(lock, q, f"Th-worker-{i}") for i in range(5)] # create workers
for w in workers:
w.start()
tStart = time.time()
threading.Thread(target=insertf1, daemon=True).start()
threading.Thread(target=insertf2, daemon=True).start()
The output is:
f1 start : 0 s 0 ms 0 us
f1 finished : 2 s 2 ms 515 us
f1 start : 4 s 9 ms 335 us
f1 finished : 6 s 9 ms 932 us
f1 start : 8 s 17 ms 428 us
f2 start : 10 s 12 ms 794 us
f1 finished : 10 s 28 ms 633 us
f1 start : 12 s 29 ms 182 us
f1 finished : 14 s 34 ms 411 us
f2 finished : 16 s 19 ms 330 us
f1 started before f2 was finished, which is what needs to be avoided.
To do so you need to combine Queue and Lock. Lock will prevent worker-threads from working in the same time. Find code example below:
import time
from threading import Lock, Thread
import threading
from queue import Queue
class ThreadWorker(Thread):
def __init__(self, _lock: Lock, _queue: Queue, name: str):
# daemon=False means that process waits until all threads are finished
# (not only main one and garbage collector)
super().__init__(name=name, daemon=False)
# lock prevents several worker threads do work simultaneously
self.lock = _lock
# tasks are send from the main thread via Queue
self.queue = _queue
def do_work(self, job):
# lock context manager prevents other worker threads from working in the same time
with self.lock:
time.sleep(3)
print(f"{threading.current_thread().getName()}: {job * 10}")
def run(self):
while True:
job = self.queue.get()
# "poison pillow" - stop message from queue
if not job:
break
self.do_work(job)
if __name__ == '__main__':
q = Queue()
lock = Lock()
workers = [ThreadWorker(lock, q, f"Th-worker-{i}") for i in range(5)] # create workers
for w in workers:
w.start()
# produce tasks
for i in range(10):
q.put(i)
# stop tasks with "poison pillow"
for i in range(len(workers)):
q.put(None)
Edit based on additions to the question (Lock added)
The main idea is that you should not run f1 and f2 without Lock.
import time
from threading import Lock, Thread
import threading
from queue import Queue
class ThreadWorker(Thread):
def __init__(self, _lock: Lock, _queue: Queue, name: str):
# daemon=False means that process waits until all threads are finished
# (not only main one and garbage collector)
super().__init__(name=name, daemon=False)
# lock prevents several worker threads do work simultaneously
self.lock = _lock
# tasks are send from the main thread via Queue
self.queue = _queue
def do_work(self, f):
# lock context manager prevents other worker threads from working in the same time
with self.lock:
time.sleep(3)
print(f"{threading.current_thread().getName()}: {f()}")
def run(self):
while True:
job = self.queue.get()
# "poison pillow" - stop message from queue
if not job:
break
self.do_work(job)
def TimeStamp(msg):
tElapsed = (time.time() - tStart) # Display Thread Info
sElap = int(tElapsed)
msElap = int((tElapsed - sElap) * 1000)
usElap = int((tElapsed - sElap - msElap / 1000) * 1000000)
print(msg, ': ', sElap, 's', msElap, 'ms', usElap, 'us')
def f1():
TimeStamp("f1 start")
time.sleep(1)
TimeStamp("f1 finished")
return f"Func-1-{threading.current_thread().getName()}"
def f2():
TimeStamp("f2 start")
time.sleep(3)
TimeStamp("f2 finished")
return f"Func-2-{threading.current_thread().getName()}"
def insertf1():
for i in range(5):
q.put(f1) # do not run f1 here! Run it in worker thread with Lock
def insertf2():
for i in range(5):
q.put(f2) # do not run f2 here! Run it in worker thread with Lock
q = Queue()
lock = Lock()
workers = [ThreadWorker(lock, q, f"Th-worker-{i}") for i in range(5)] # create workers
for w in workers:
w.start()
tStart = time.time()
threading.Thread(target=insertf1, daemon=True).start()
threading.Thread(target=insertf2, daemon=True).start()

python threading with sync queue

I have a script that follows the same logic in this sample.
Basically I insert items into a global queue and spawn threads with a while loop that gets and item from the queue and the calls task_done.
I can get the threads to join if my while loop is checking that the queue is not empty, but I wanted to try and incorporate a flag that I could set myself to exit the loop. When I try to do this, joining the thread blocks forever.
Here is the non-working sample that doesnt join the threads:
import threading
import queue
class Mythread(threading.Thread):
def __init__(self):
super().__init__()
self.signal = False
def run(self):
global queue
while not self.signal:
item = q.get()
print(item)
q.task_done()
def stop(self):
self.signal = True
q = queue.Queue
for i in range(5000):
q.put(i)
threads = []
for i in range(2):
t = Mythread()
threads.append(t)
for t in threads:
t.start()
q.join()
for t in threads:
print(t.signal) <---- False
t.stop()
print(t.signal) <---- True
t.join() <---- Blocks forever
Here is the one that works using queue empty
import threading
import queue
class Mythread(threading.Thread):
def __init__(self):
super().__init__()
def run(self):
global queue
while not q.empty():
item = q.get()
print(item)
q.task_done()
q = queue.Queue
for i in range(5000):
q.put(i)
threads = []
for i in range(2):
t = Mythread()
threads.append(t)
for t in threads:
t.start()
q.join()
for t in threads:
t.join() <---- Works fine
print(t.is_alive()) <--- returns False
Any ideas?
q.get blocks so it won't reach your while condition

Process vs. Thread with regards to using Queue()/deque() and class variable for communication and "poison pill"

I would like to create either a Thread or a Process which runs forever in a While True loop.
I need to send and receive data to the worker in the form for queues, either a multiprocessing.Queue() or a collections.deque(). I prefer to use collections.deque() as it is significantly faster.
I also need to be able to kill the worker eventually (as it runs in a while True loop. Here is some test code I've put together to try and understand the differences between Threads, Processes, Queues, and deque ..
import time
from multiprocessing import Process, Queue
from threading import Thread
from collections import deque
class ThreadingTest(Thread):
def __init__(self, q):
super(ThreadingTest, self).__init__()
self.q = q
self.toRun = False
def run(self):
print("Started Thread")
self.toRun = True
while self.toRun:
if type(self.q) == type(deque()):
if self.q:
i = self.q.popleft()
print("Thread deque: " + str(i))
elif type(self.q) == type(Queue()):
if not self.q.empty():
i = self.q.get_nowait()
print("Thread Queue: " + str(i))
def stop(self):
print("Trying to stop Thread")
self.toRun = False
while self.isAlive():
time.sleep(0.1)
print("Stopped Thread")
class ProcessTest(Process):
def __init__(self, q):
super(ProcessTest, self).__init__()
self.q = q
self.toRun = False
self.ctr = 0
def run(self):
print("Started Process")
self.toRun = True
while self.toRun:
if type(self.q) == type(deque()):
if self.q:
i = self.q.popleft()
print("Process deque: " + str(i))
elif type(self.q) == type(Queue()):
if not self.q.empty():
i = self.q.get_nowait()
print("Process Queue: " + str(i))
def stop(self):
print("Trying to stop Process")
self.toRun = False
while self.is_alive():
time.sleep(0.1)
print("Stopped Process")
if __name__ == '__main__':
q = Queue()
t1 = ProcessTest(q)
t1.start()
for i in range(10):
if type(q) == type(deque()):
q.append(i)
elif type(q) == type(Queue()):
q.put_nowait(i)
time.sleep(1)
t1.stop()
t1.join()
if type(q) == type(deque()):
print(q)
elif type(q) == type(Queue()):
while q.qsize() > 0:
print(str(q.get_nowait()))
As you can see, t1 can either be ThreadingTest, or ProcessTest. Also, the queue passed to it can either be a multiprocessing.Queue or a collections.deque.
ThreadingTest works with a Queue or deque(). It also kills run() properly when the stop() method is called.
Started Thread
Thread deque: 0
Thread deque: 1
Thread deque: 2
Thread deque: 3
Thread deque: 4
Thread deque: 5
Thread deque: 6
Thread deque: 7
Thread deque: 8
Thread deque: 9
Trying to stop Thread
Stopped Thread
deque([])
ProcessTest is only able to read from the queue if it is of type multiprocessing.Queue. It doesn't work with collections.deque. Furthermore, I am unable to kill the process using stop().
Process Queue: 0
Process Queue: 1
Process Queue: 2
Process Queue: 3
Process Queue: 4
Process Queue: 5
Process Queue: 6
Process Queue: 7
Process Queue: 8
Process Queue: 9
Trying to stop Process
I'm trying to figure out why? Also, what would be the best way to use deque with a process? And, how would I go about killing the process using some sort of stop() method.
You can't use a collections.deque to pass data between two multiprocessing.Process instances, because collections.deque is not process-aware. multiprocessing.Queue writes its contents to a multiprocessing.Pipe internally, which means that data in it can be enqueued in once process and retrieved in another. collections.deque doesn't have that kind of plumbing, so it won't work. When you write to the deque in one process, the deque instance in the other process won't be affected at all; they're completely separate instances.
A similar issue is happening to your stop() method. You're changing the value of toRun in the main process, but this won't affect the child at all. They're completely separate instances. The best way to end the child would be to send some sentinel to the Queue. When you get the sentinel in the child, break out of the infinite loop:
def run(self):
print("Started Process")
self.toRun = True
while self.toRun:
if type(self.q) == type(deque()):
if self.q:
i = self.q.popleft()
print("Process deque: " + str(i))
elif type(self.q) == type(Queue()):
if not self.q.empty():
i = self.q.get_nowait()
if i is None:
break # Got sentinel, so break
print("Process Queue: " + str(i))
def stop(self):
print("Trying to stop Process")
self.q.put(None) # Send sentinel
while self.is_alive():
time.sleep(0.1)
print("Stopped Process")
Edit:
If you actually do need deque semantics between two process, you can use a custom multiprocessing.Manager() to create a shared deque in a Manager process, and each of your Process instances will get a Proxy to it:
import time
from multiprocessing import Process
from multiprocessing.managers import SyncManager
from collections import deque
SyncManager.register('deque', deque)
def Manager():
m = SyncManager()
m.start()
return m
class ProcessTest(Process):
def __init__(self, q):
super(ProcessTest, self).__init__()
self.q = q
self.ctr = 0
def run(self):
print("Started Process")
self.toRun = True
while self.toRun:
if self.q._getvalue():
i = self.q.popleft()
if i is None:
break
print("Process deque: " + str(i))
def stop(self):
print("Trying to stop Process")
self.q.append(None)
while self.is_alive():
time.sleep(0.1)
print("Stopped Process")
if __name__ == '__main__':
m = Manager()
q = m.deque()
t1 = ProcessTest(q)
t1.start()
for i in range(10):
q.append(i)
time.sleep(1)
t1.stop()
t1.join()
print(q)
Note that this probably isn't going to be faster than a multiprocessing.Queue, though, since there's an IPC cost for every time you access the deque. It's also a much less natural data structure for passing messages the way you are.

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