I capture screen of my pygame program like this
data = pygame.image.tostring(pygame.display.get_surface(),"RGB")
How can I convert it into base64 string? (WITHOUT having to save it to HDD). Its important that there is no saving to HDD. I know I can save it to a file and then just encode the file to base64 but I cant seem to encode "on the fly"
thanks
If you want, you can save it to a StringIO, which is basically a virtual file stored as a string.
However, I'd really recommend using the base64 module, which has a method called base64.b64encode. It handles your 'on the fly' requirement well.
Code example:
import base64
data = pygame.image.tostring(pygame.display.get_surface(),"RGB")
base64data = base64.b64encode(data)
Happy coding!
Actually - pygame.image.tostring() is a pretty strange function (really dont understand the binary string it returns, I cant find anythin that can process it right).
There seems to be an enhancement issue on this at pygame bitbucket:
(https://bitbucket.org/pygame/pygame/issue/48/add-optional-format-argument-to)
I got around it like this:
data = cStringIO.StringIO()
pygame.image.save(pygame.display.get_surface(), data)
data = base64.b64encode(data.getvalue())
So in the end you get the valid and RIGHT base64 string. And it seems to work. Not sure about the format yet tho, will add more info tmrw
Related
I know there are a lot of encoding/decoding topics here and I tried it for hours, but I'm still not able to solve it. Hence I want to raise a question:
I have a string with hexadecimal values, which in the end is a text that I want to write to a text file with the correct encoding.
hexvalues = "476572E2A47465646574656B746F72"
In the end, the (german) result should be "Gerätedetektor"
Currently I am using binascii.unhexlify() for the decoding, but it still doesn't show me the "ä" like its supposed to be, and instead, I get:
>> result = binascii.unhexlify(hexvalues)
Gerâ¤tedetektor
I tried to do result.decode("utf-8") and a lot of other things but either the script crashes or it also doesn't return what I want to see.
In the end, I want to write the word in the correct way to a file.
Any help would be highly appreciated!
Edit:
As I wrote before, I tried many things so it is kind of hard to give the ONE code that I'm using but here is an excerpt from the current version:
#!/usr/bin/env python
# -*- coding: utf-8 -*-
import binascii
resultfile = "text_GER.txt"
fpx = open(resultfile, 'wb')
hexvalues = "476572E2A47465646574656B746F72"
result= binascii.unhexlify(hexvalues )
result= result.decode("utf-8")
print(result)
fpx.write(result)
This one makes the script crash, but no further indicators why it does.
If i skip
result= result.decode("utf-8")
then my result print of result looks like this:
b'Ger\xe2\xa4tedetektor'
I have a pdf file that breaks pyPdf: http://tovotu.de/tests/test.pdf
This is the sample script:
from pyPdf import PdfFileWriter, PdfFileReader
outputPdf = PdfFileWriter()
inpdf = open("test.pdf","rb")
inputPdf = PdfFileReader(inpdf)
[outputPdf.addPage(x) for x in inputPdf.pages]
with open("output.pdf","wb") as outpdf:
outputPdf.write(outpdf)
Error output is here: http://pastebin.com/0m38zhjQ
The error is the same when using PyPDF2 from GitHub. pdftk can handle this pdf just like any other pdf out there. Please note, that writing fails, but reading seems to work just fine!
Can you at least point me to the exact part of the pdf that causes that error? A workaround would be even nicer :)
Looks like a bug in PyPDF2. In this section:
if string.startswith(codecs.BOM_UTF16_BE):
retval = TextStringObject(string.decode("utf-16"))
retval.autodetect_utf16 = True
it assumes that any string starting with (0xFE, 0xFF) can be decoded as UTF-16. Your file contains a bytestring that begins that way but then contains invalid UTF-16.
The simplest fix is to comment out that if and unconditionally use the # This is probably a big performance hit here branch.
I snagged a Lorem Ipsupm generator last week, and I admit, it's pretty cool.
My question: can someone show me a tutorial on how the author of the above script was able to post the contents of a gzipped file into their code as a string? I keep getting examples of gzipping a regular file, and I'm feeling kind of lost here.
For what it's worth, I have another module that is quite similar (it generates random names, companies, etc), and right now it reads from a couple different text files. I like this approach better; it requires one less sub-directory in my project to place data into, and it also presents a new way of doing things for me.
I'm quite new to streams, IO types, and the like. Feel free to dump the links on my lap. Snipptes are always appreciated too.
Assuming you are in a *nix environment, you just need gzip and a base64 encoder to generate the string. Lets assume your content is in file.txt, for the purpose of this example I created the file with random bytes with that specific name.
So you need to compress it first:
$ gzip file.txt
That will generate a file.txt.gz file that you now need to embed into your code. To do that, you need to encode it. A common way to do so is to use Base64 encoding, which can be done with the base64 program:
$ base64 file.txt.gz
H4sICGmHsE8AA2ZpbGUudHh0AAGoAFf/jIMKME+MgnEhgS4vd6SN0zIuVRhsj5fac3Q1EV1EvFJK
fBsw+Ln3ZSX7d5zjBXJR1BUn+b2/S3jHXO9h6KEDx37U7iOvmSf6BMo1gOJEgIsf57yHwUKl7f9+
Beh4kwF+VljN4xjBfdCiXKk0Oc9g/5U/AKR02fRwI+zYlp1ELBVDzFHNsxpjhIT43sBPklXW8L5P
d8Ao3i2tQQPf2JAHRQZYYn3vt0tKg7drVKgAAAA=
Now you have all what you need to use the contents of that file in your python script:
from cStringIO import StringIO
from base64 import b64decode
from gzip import GzipFile
# this is the variable with your file's contents
gzipped_data = """
H4sICGmHsE8AA2ZpbGUudHh0AAGoAFf/jIMKME+MgnEhgS4vd6SN0zIuVRhsj5fac3Q1EV1EvFJK
fBsw+Ln3ZSX7d5zjBXJR1BUn+b2/S3jHXO9h6KEDx37U7iOvmSf6BMo1gOJEgIsf57yHwUKl7f9+
Beh4kwF+VljN4xjBfdCiXKk0Oc9g/5U/AKR02fRwI+zYlp1ELBVDzFHNsxpjhIT43sBPklXW8L5P
d8Ao3i2tQQPf2JAHRQZYYn3vt0tKg7drVKgAAAA=
"""
# we now decode the file's content from the string and unzip it
orig_file_desc = GzipFile(mode='r',
fileobj=StringIO(b64decode(gzipped_data)))
# get the original's file content to a variable
orig_file_cont = orig_file_desc.read()
# and close the file descriptor
orig_file_desc.close()
Obviously, your program will depend on the base64, gzip and cStringIO python modules.
I'm not sure exactly what you're asking, but here's a stab...
The author of lipsum.py has included the compressed data inline in their code as chunks of Base64 encoded text. Base64 is an encoding mechanism for representing binary data using printable ASCII characters. It can be used for including binary data in your Python code. It is more commonly used to include binary data in email attachments...the next time someone sends you a picture or PDF document, take a look at the raw message and you'll see very much the same thing.
Python's base64 module provides routines for converting between base64 and binary representations of data...and once you have the binary representation of the data, it doesn't really matter how you got, whether it was by reading it from a file or decoding a string embedded in your code.
Python's gzip module can be used to decompress data. It expects a file-like object...and Python provides the StringIO module to wrap strings in the right set of methods to make them act like files. You can see that in lipsum.py in the following code:
sample_text_file = gzip.GzipFile(mode='rb',
fileobj=StringIO(base64.b64decode(DEFAULT_SAMPLE_COMPRESSED)))
This is creating a StringIO object containing the binary representation of the base64 encoded value stored in DEFAULT_SAMPLE_COMPRESSED.
All the modules mentioned here are described in the documentation for the Python standard library.
I wouldn't recommend including data in your code inline like this as a good idea in general, unless your data is small and relatively static. Otherwise, package it up into your Python package which makes it easier to edit and track changes.
Have I answered the right question?
How about this: Zips and encodes a string, prints it out encoded, then decodes and unzips it again.
from StringIO import StringIO
import base64
import gzip
contents = 'The quick brown fox jumps over the lazy dog'
zip_text_file = StringIO()
zipper = gzip.GzipFile(mode='wb', fileobj=zip_text_file)
zipper.write(contents)
zipper.close()
enc_text = base64.b64encode(zip_text_file.getvalue())
print enc_text
sample_text_file = gzip.GzipFile(mode='rb',
fileobj=StringIO(base64.b64decode(enc_text)))
DEFAULT_SAMPLE = sample_text_file.read()
sample_text_file.close()
print DEFAULT_SAMPLE
Old question but I had to do this recent for AWS logs. In Python3 use BytesIO instead of StringIO:
import base64
from io import BytesIO
DEFAULT_SAMPLE_COMPRESSED = "Some base 64 encoded and gzip compressed string"
sample_text_file = gzip.GzipFile(
mode='rb',
fileobj=BytesIO(base64.b64decode(DEFAULT_SAMPLE_COMPRESSED))
)
binary_text = sample_text_file.read() # This will be the final string as bianry
text = binary_text .decode() # This will make the binary text a string.
In my django application, I provide a form that allows users to upload a file. The file can be in a variety of formats (Excel, CSV), come from a variety of platforms (Mac, Linux, Windows), and be encoded in a variety of encodings (ASCII, UTF-8).
For the purpose of this question, let's assume that I have a view which is receiving request.FILES['file'], which is an instance of InMemoryUploadedFile, called file. My problem is that InMemoryUploadedFile objects (like file):
Do not support UTF-8 encoding (I see a \xef\xbb\xbf at the beginning of the file, which as I understand is a flag meaning 'this file is UTF-8').
Do not support universal newlines (which probably the majority of the files uploaded to this system will need).
Complicating the issue is that I wish to pass the file in to the python csv module, which does not natively support Unicode. I will happily accept answers that avoid this issue - once I get django playing nice with UTF-8 I'm sure I can bludgeon csv into doing the same. (Similarly, please ignore the requirement to support Excel - I am waiting until CSV works before I tackle parsing Excel files.)
I have tried using StringIO,mmap,codec, and any of a wide variety of ways of accessing the data in an InMemoryUploadedFile object. Each approach has yielded differing errors, none so far have been perfect. This shows some of the code that I feel came the closest:
import csv
import codecs
class CSVParser:
def __init__(self,file):
# 'file' is assumed to be an InMemoryUploadedFile object.
dialect = csv.Sniffer().sniff(codecs.EncodedFile(file,"utf-8").read(1024))
file.open() # seek to 0
self.reader = csv.reader(codecs.EncodedFile(file,"utf-8"),
dialect=dialect)
try:
self.field_names = self.reader.next()
except StopIteration:
# The file was empty - this is not allowed.
raise ValueError('Unrecognized format (empty file)')
if len(self.field_names) <= 1:
# This probably isn't a CSV file at all.
# Note that the csv module will (incorrectly) parse ALL files, even
# binary data. This will catch most such files.
raise ValueError('Unrecognized format (too few columns)')
# Additional methods snipped, unrelated to issue
Please note that I haven't spent too much time on the actual parsing algorithm so it may be wildly inefficient, right now I'm more concerned with getting encoding to work as expected.
The problem is that the results are also not encoded, despite being wrapped in the Unicode codecs.EncodedFile file wrapper.
EDIT: It turns out, the above code does in fact work. codecs.EncodedFile(file,"utf-8") is the ticket. It turns out the reason I thought it didn't work was that the terminal I was using does not support UTF-8. Live and learn!
As mentioned above, the code snippet I provided was in fact working as intended - the problem was with my terminal, and not with python encoding.
If your view needs to access a UTF-8 UploadedFile, you can just use utf8_file = codecs.EncodedFile(request.FILES['file_field'],"utf-8") to open a file object in the correct encoding.
I also noticed that, at least for InMemoryUploadedFiles, opening the file through the codecs.EncodedFile wrapper does NOT reset the seek() position of the file descriptor. To return to the beginning of the file (again, this may be InMemoryUploadedFile specific) I just used request.FILES['file_field'].open() to send the seek() position back to 0.
I use the csv.DictReader and it appears to be working well. I attached my code snippet, but it is basically the same as another answer here.
import csv as csv_mod
import codecs
file = request.FILES['file']
dialect = csv_mod.Sniffer().sniff(codecs.EncodedFile(file,"utf-8").read(1024))
file.open()
csv = csv_mod.DictReader( codecs.EncodedFile(file,"utf-8"), dialect=dialect )
For CSV and Excel upload to django, this site may help.
I am trying to parse some .txt files. These files serve as containers for a variable number of 'children' files that are set off or identified within the container with SGML tags. With python I can easily separate the children files. However I am having trouble writing the binary content back out as a binary file (say a gif or jpg). In the simplest case the container might have an embedded html file followed by a graphic that is called by the html. I am assuming that my problem is because I am reading the original .txt file using open(filename,'r'). But that seems the only option to find the sgml tags to split the file.
I would appreciate any help to identify some relevant reading material.
I appreciate the suggestions but I am still struggling with the most basic questions. For example when I open the file with wordpad and scroll down to the section tagged as a gif I see this:
<FILENAME>h65803h6580301.gif
<DESCRIPTION>GRAPHIC
<TEXT>
begin 644 h65803h6580301.gif
M1TE&.#EA(P)I`=4#`("`#,#`P$!`0+^_OW]_?_#P\*"#H.##X-#0T&!#8!`0
M$+"PL"`#('!P<)"0D#`P,%!04#\_/^_O[Y^?GZ^OK]_?WX^/C\_/SV]O;U]?
I can handle finding the section easily enough but where does the gif file begin. Does the header start with 644, the blanks after the word begin or the line beginning with MITE?
Next, when the file is read into python does it do anything to the binary code that has to be undone when it is read back out?
I can find the lines where the graphics begin:
filerefbin=file('myfile.txt','rb')
wholeFile=filerefbin.read()
import re
graphicReg=re.compile('<DESCRIPTION>GRAPHIC')
locationGraphics=graphicReg.finditer(wholeFile)
graphicsTags=[]
for match in locationGraphics:
graphicsTags.append(match.span())
I can easily use the same process to get to the word begin, or to identify the filename and get to the end of the filename in the 'first' line. I have also successefully gotten to the end of the embedded gif file. But I can't seem to write out the correct combination of things so when I double click on h65803h6580301.gif when it has been isolated and saved I get to see the graphic.
Interestingly, when I open the file in rb, the line endings appear to still be present even though they don't seem to have any effect in notebpad. So that is clearly one of my problems I might need to readlines and join the lines together after stripping out the \n
I love this site and I love PYTHON
This was too easy once I read bendin's post. I just had to snip the section that began with the word begin and save that in a txt file and then run the following command:
import uu
uu.decode(r'c:\test2.txt',r'c:\test.gif')
I have to work with some other stuff for the rest of the day but I will post more here as I look at this more closely. The first thing I need to discover is how to use something other than a file, that is since I read the whole .txt file into memory and clipped out the section that has the image I need to work with the clipped section instead of writing it out to test2.txt. I am sure that can be done its just figuring out how to do it.
What you're looking at isn't "binary", it's uuencoded. Python's standard library includes the module uu, to handle uuencoded data.
The module uu requires the use of temporary files for encoding and decoding. You can accomplish this without resorting to temporary files by using Python's codecs module like this:
import codecs
data = "Let's just pretend that this is binary data, ok?"
uuencode = codecs.getencoder("uu")
data_uu, n = uuencode(data)
uudecode = codecs.getdecoder("uu")
decoded, m = uudecode(data_uu)
print """* The initial input:
%(data)s
* Encoding these %(n)d bytes produces:
%(data_uu)s
* When we decode these %(m)d bytes, we get the original data back:
%(decoded)s""" % globals()
You definitely need to be reading in binary mode if the content includes JPEG images.
As well, Python includes an SGML parser, http://docs.python.org/library/sgmllib.html .
There is no example there, but all you need to do is setup do_ methods to handle the sgml tags you wish.
You need to open(filename,'rb') to open the file in binary mode. Be aware that this will cause python to give You confusing, two-byte line endings on some operating systems.