Selective Inheritance Python

Selective Inheritance Python - python

I am making a python program which is using classes, I want one class to only selectively inherit from another e.g:
class X(object):
def __init__(self):
self.hello = 'hello'
class Y(object):
def __init__(self):
self.moo = 'moo'
class Z():
def __init__(self, mode):
if mode == 'Y':
# Class will now Inherit from Y
elif mode == 'X':
# Class will now Inherit for X
How can I do this without making another class?

In Python classes can be created at run-time:
class X(object):
def __init__(self):
self.hello = 'hello'
class Y(object):
def __init__(self):
self.moo = 'moo'
def create_class_Z(mode):
base_class = globals()[mode]
class Z(base_class):
def __init__(self):
base_class.__init__(self)
return Z
ZX = create_class_Z('X')
zx = ZX()
print(zx.hello)
ZY = create_class_Z('Y')
zy = ZY()
print(zy.moo)

You can do this by overriding __new__ and changing the cls passed in (you're creating a new type by appending X or Y as a base class):
class X(object):
def __init__(self):
self.hello = 'hello'
class Y(object):
def __init__(self):
self.moo = 'moo'
class Z(object):
def __new__(cls, mode):
mixin = {'X': X, 'Y': Y}[mode]
cls = type(cls.__name__ + '+' + mixin.__name__, (cls, mixin), {})
return super(Z, cls).__new__(cls)
def __init__(self, mode, *args, **kwargs):
super(Z, self).__init__(*args, **kwargs)
Note that you need to bypass Z.__new__ using super to avoid infinite recursion; this is the standard pattern for __new__ special override methods.

I think you'd better define two members within Z,one is a class instance of X,another is a instance of Y.You can get the associated information stored in these instances while use different mode.

A solution using type:
class _Z(): pass #rename your class Z to this
def Z(mode): #this function acts as the constructor for class Z
classes = {'X': X, 'Y': Y, 'Foo': Bar} #map the mode argument to the base cls
#create a new type with base classes Z and the class determined by mode
cls = type('Z', (_Z, classes[mode]), {})
#instantiate the class and return the instance
return cls()

Related

How to inherit from pre-existing class instance in Python?

I have a class Parent:
class Parent:
def __init__(self, foo):
self.foo = foo
I then have another class Child which extends Parent. But I want Child to take a pre-existing instance of parent and use this as the parent to inherit from (instead of creating a new instance of Parent with the same constructor parameters).
class Child(Parent):
def __init__(self, parent_instance):
""" Do something with parent_instance to set this as the parent instance """
def get_foo(self):
return self.foo
Then I would ideally be able to do:
p = Parent("bar")
c = Child(p)
print(c.get_foo()) # prints "bar"

You could copy the content of the parents's __dict__ to the child's. You can use vars() builtin function to do so, and the dictionary's update() method.
class Child(Parent):
def __init__(self, parent_instance):
vars(self).update(vars(parent_instance))
def get_foo(self):
return self.foo
p = Parent("bar")
c = Child(p)
print(c.get_foo())
# prints "bar"

You can use your own constructor - provide a classmethod that takes an instance of a parent.
class Parent:
def __init__(self, foo):
self.foo = foo
class Child(Parent):
def get_foo(self):
return self.foo
#classmethod
def from_parent(cls, parent_instance):
return cls(parent_instance.foo)
p = Parent('bar')
c = Child.from_parent(p)
c.get_foo()

I'm not sure inheritance is the right solution here as it breaks the LSP in the __init__ method.
Maybe parents and children just share a common interface.
I'd prefer something like (python3.8):
from typing import Protocol
class FoeAware(Protocol):
#property
def foe(self):
...
class Parent:
def __init__(self, foe):
self._foe = foe
#property
def foe(self):
return self._foe
class Child:
def __init__(self, parent: FoeAware):
self.parent = parent
#property
def foe(self):
return self.parent.foe
p = Parent("bar")
c = Child(p)
c.foe # bar
The key point is that it takes advantage of polymorphism with a common interface FoeAware, which is preferable to an inheritance tree.

Using getattr() to fetch the attribute from the parent instance
class Parent:
def __init__(self, foo):
self.foo = foo
class Child(Parent):
def __init__(self, parent_instance):
self.parent_instance = parent_instance
def get_foo(self):
return self.foo
def __getattr__(self, attr):
return getattr(self.parent_instance, attr)
par = Parent("bar")
ch = Child(par)
print(ch.get_foo())
#prints bar

Delegation design pattern with abstract methods in python

I have the following classes implementing a "Delegation Design Pattern" with an additional DelegatorParent class:
class DelegatorParent():
def __init__(self):
self.a = 'whatever'
class ConcreteDelegatee():
def myMethod(self):
return 'myMethod'
class Delegator(DelegatorParent):
def __init__(self):
self.delegatee = ConcreteDelegatee()
DelegatorParent.__init__(self)
def __getattr__(self, attrname):
return getattr(self.delegatee, attrname)
a = Delegator()
result = a.myMethod()
Everything looks fine.
Now I would like to put an abstract method in DelegatorParent, to ensure that "myMethod" is always defined.
from abc import ABCMeta, abstractmethod
class DelegatorParent():
__metaclass__ = ABCMeta
#abstractmethod
def myMethod(self):
pass
def __init__(self):
self.a = 'whatever'
class ConcreteDelegatee():
def myMethod(self):
return 'myMethod'
class Delegator(DelegatorParent):
def __init__(self):
self.delegatee = ConcreteDelegatee()
DelegatorParent.__init__(self)
def __getattr__(self, attrname):
return getattr(self.delegatee, attrname)
# This method seems unnecessary, but if I erase it an exception is
# raised because the abstract method's restriction is violated
def myMethod(self):
return self.delegatee.myMethod()
a = Delegator()
result = a.myMethod()
Can you help me find an "elegant" way to remove "myMethod" from "Delegator"... Intuition tells me that it is somehow redundant (considering that a custom getattr method is defined).
And more importantly, notice that with this implementation, if I forget to define myMethod in ConcreteDelegatee the program compiles, but it may crash in runtime if I call Delegator.myMethod(), which is exactly what I wanted to avoid by using abstract methods in DelegatorParent.
Obviously a simple solution would be to move #abstractmethod to the Delegator class, but I want to avoid doing that because in my program DelegatorParent is a very important class (and Delegator is just an auxiliary class).

You can decide to automatically implement abstract methods delegared to ConcreteDelegatee.
For each abstract method, check if it's name exist in the ConcreteDelegatee class and implement this method as a delegate to this class method.
from abc import ABCMeta, abstractmethod
class DelegatorParent(object):
__metaclass__ = ABCMeta
def __init__(self):
self.a = 'whatever'
#abstractmethod
def myMethod(self):
pass
class Delegatee(object):
pass
class ConcreteDelegatee(Delegatee):
def myMethod(self):
return 'myMethod'
def myMethod2(self):
return 'myMethod2'
class Delegator(DelegatorParent):
def __new__(cls, *args, **kwargs):
implemented = set()
for name in cls.__abstractmethods__:
if hasattr(ConcreteDelegatee, name):
def delegated(this, *a, **kw):
meth = getattr(this.delegatee, name)
return meth(*a, **kw)
setattr(cls, name, delegated)
implemented.add(name)
cls.__abstractmethods__ = frozenset(cls.__abstractmethods__ - implemented)
obj = super(Delegator, cls).__new__(cls, *args, **kwargs)
obj.delegatee = ConcreteDelegatee()
return obj
def __getattr__(self, attrname):
# Called only for attributes not defined by this class (or its bases).
# Retrieve attribute from current behavior delegate class instance.
return getattr(self.delegatee, attrname)
# All abstract methods are delegared to ConcreteDelegatee
a = Delegator()
print(a.myMethod()) # correctly prints 'myMethod'
print(a.myMethod2()) #correctly prints 'myMethod2'
This solves the main problem (prevent ConcreteDelegatee from forgetting to define myMethod). Other abstract methods are still checked if you forgot to implement them.
The __new__ method is in charge of the delegation, that frees your __init__ to do it.

Since you use ABCMeta, you must defined the abstract methods. One could remove your method from the __abstractmethods__ set, but it is a frozenset. Anyway, it involves listing all abstract methods.
So, instead of playing with __getattr__, you can use a simple descriptor.
For instance:
class Delegated(object):
def __init__(self, attrname=None):
self.attrname = attrname
def __get__(self, instance, owner):
if instance is None:
return self
delegatee = instance.delegatee
return getattr(delegatee, self.attrname)
class Delegator(DelegatorParent):
def __init__(self):
self.delegatee = ConcreteDelegatee()
DelegatorParent.__init__(self)
myMethod = Delegated('myMethod')
An advantage here: the developer has the explicit information that "myMethod" is delegated.
If you try:
a = Delegator()
result = a.myMethod()
It works! But if you forget to implement myMethod in Delegator class, you have the classic error:
Traceback (most recent call last):
File "script.py", line 40, in <module>
a = Delegator()
TypeError: Can't instantiate abstract class Delegator with abstract methods myMethod
Edit
This implementation can be generalized as follow:
class DelegatorParent():
__metaclass__ = ABCMeta
#abstractmethod
def myMethod1(self):
pass
#abstractmethod
def myMethod2(self):
pass
def __init__(self):
self.a = 'whatever'
class ConcreteDelegatee1():
def myMethod1(self):
return 'myMethod1'
class ConcreteDelegatee2():
def myMethod2(self):
return 'myMethod2'
class DelegatedTo(object):
def __init__(self, attrname):
self.delegatee_name, self.attrname = attrname.split('.')
def __get__(self, instance, owner):
if instance is None:
return self
delegatee = getattr(instance, self.delegatee_name)
return getattr(delegatee, self.attrname)
class Delegator(DelegatorParent):
def __init__(self):
self.delegatee1 = ConcreteDelegatee1()
self.delegatee2 = ConcreteDelegatee2()
DelegatorParent.__init__(self)
myMethod1 = DelegatedTo('delegatee1.myMethod1')
myMethod2 = DelegatedTo('delegatee2.myMethod2')
a = Delegator()
result = a.myMethod2()
Here, we can specify the delegatee name and delegatee method.

Here is my current solution. It solves the main problem (prevent ConcreteDelegatee from forgetting to define myMethod), but I'm still not convinced because I still need to define myMethod inside Delegator, which seems redundant
from abc import ABCMeta, abstractmethod
class DelegatorParent(object):
__metaclass__ = ABCMeta
def __init__(self):
self.a = 'whatever'
#abstractmethod
def myMethod(self):
pass
class Delegatee(object):
def checkExistence(self, attrname):
if not callable(getattr(self, attrname, None)):
error_msg = "Can't instantiate " + str(self.__class__.__name__) + " without abstract method " + attrname
raise NotImplementedError(error_msg)
class ConcreteDelegatee(Delegatee):
def myMethod(self):
return 'myMethod'
def myMethod2(self):
return 'myMethod2'
class Delegator(DelegatorParent):
def __init__(self):
self.delegatee = ConcreteDelegatee()
DelegatorParent.__init__(self)
for method in DelegatorParent.__abstractmethods__:
self.delegatee.checkExistence(method)
def myMethod(self, *args, **kw):
return self.delegatee.myMethod(*args, **kw)
def __getattr__(self, attrname):
# Called only for attributes not defined by this class (or its bases).
# Retrieve attribute from current behavior delegate class instance.
return getattr(self.delegatee, attrname)
# if I forget to implement myMethod inside ConcreteDelegatee,
# the following line will correctly raise an exception saying
# that 'myMethod' is missing inside 'ConcreteDelegatee'.
a = Delegator()
print a.myMethod() # correctly prints 'myMethod'
print a.myMethod2() #correctly prints 'myMethod2'

Access Child class variables in Parent class

I have a Parent class and a inherited child class, I would like to know how to access the child class variable in my Parent class..
I tried this and it fails -
class Parent(object):
def __init__(self):
print x
class Child(Parent):
x = 1;
x = Child();
Error:-
NameError: global name 'x' is not defined
This question is in relation to Django forms where we inherit the form class
and declare some class variables.
For example:-
My form looks like this
from django import forms
class EmployeeForm(forms.Form):
fname = forms.CharField(max_length=100)
lname = forms.CharField(max_length=100)
I believe the form fields are considered as class variable and somehow passed to the parent class..

Django does this with metaclasses. (Relevant Django source)
Here's a distilled example of the relevant code:
class Field(object):
def __init__(self, *args):
self.args = args
def __repr__(self):
return "Form(%s)" % (', '.join(map(repr, self.args)),)
class Meta(type):
def __new__(mcs, name, bases, attrs):
field_list = []
for k,v in attrs.items():
if isinstance(v, Field):
field_list.append(v)
cls = type.__new__(mcs, name, bases, attrs)
cls.fields = field_list
return cls
class Form(object):
__metaclass__ = Meta
class MyForm(Form):
fe1 = Field("Field1", "Vars1")
fe2 = Field("Field2", "Vars2")
x = "This won't appear"
form_fields = MyForm.fields
print(form_fields)
There are many questions on here about Python metaclasses (example), so I won't try to re-explain the concept.
In this case, when you create the class MyForm, each of the class attributes are checked for being instances of Field. If they are, they're added to a list (field_list).
The class is created, then an attribute .fields is added to the class, which is field_list, the list of Field elements.
You can then access the form fields through <FormSubclass>.fields or in the case of this example, MyForm.fields.
Edit:
It's worth noting that you can accomplish very similar functionality, without the metaclass syntactic sugar with something like:
class Field(object):
def __init__(self, *args):
self.args = args
def __repr__(self):
return "Form(%s)" % (', '.join(map(repr, self.args)),)
class Form(object):
def __init__(self):
self._fields = None
def fields(self):
if self._fields is None:
field_list = []
for k in dir(self):
v = getattr(self, k)
if isinstance(v, Field):
field_list.append(v)
self._fields = field_list
return self._fields
class MyForm(Form):
def __init__(self):
Form.__init__(self)
self.fe1 = Field("Field1", "Vars1")
self.fe2 = Field("Field2", "Vars2")
self.x = "This won't appear"
form_fields = MyForm().fields()
print(form_fields) # [Form('Field1', 'Vars1'), Form('Field2', 'Vars2')]

Short answer : you dont access subclasse's attributes from a parent class - because the parent class can not know what attributes a child class might have.
Long answer : ... unless the parent class defines a protocol allowing subclasses to let the parent class knows about at least part of it's own attributes.
Django's form framework (as well as django's orm FWIW) use such a protocol: the base Form class has a custom metaclass that collects the form.fields declared in a subclass - and do quite some black magic. FWIW, Django is oss so you could have answered the question yourself just reading the source code: https://github.com/django/django/blob/master/django/forms/forms.py

You need to refer to self.x to access Child class variables:
class Parent(object):
def __init__(self):
print(self.x)
class Child(Parent):
x = 1
if __name__ == '__main__':
child_instance = Child()

This might not help you in regards to Django Forms, but another alternative is to work with abstract classes. You would exchange attributes with methods/properties. It also prevents you from using the parent class by itself.
from abc import ABC, abstractmethod
class Parent(ABC):
#property
#abstractmethod
def x(self):
pass
def __init__(self):
print(self.x)
class Child(Parent):
#property
def x(self):
return 1
if __name__ == '__main__':
child_instance = Child() # prints "1"
parent_instance = Parent() # fails

Well, if I got you right... Maybe you're thinking of getting a field from the child class to work on the parent class. Well, that's polymorphism and it's done by overriding the parent class.
Let's assume you have :
A parent has x, now to increase x from the child and make it reflect in the parent, check the code below to get it.
class Parent:
def __init__(self, x):
self.x = x
def Print(self):
print(f"{self.x}")
class Child(Parent):
def __init__(self, x):
Parent.__init__(self, x)
x += 1
self.x = x
""""""
c1 = Child(2)
c1.Print()
#output: 3
""""""
c2 = Child(8)
c2.Print()
#output: 9

Python : How to "merge" two class

I want to add some attributes and methods into various class. The methods and attributes that I have to add are the same but not the class to assign them, so I want to construct a class who assign new methods and attributes for a class given in argument.
I try this but it's not working:
(I know that is a very wrong way to try to assign something to self, it's just to show what I want to do)
class A:
def __init__(self):
self.a = 'a'
def getattA(self):
return self.a
class B:
def __init__(self, parent) :
self = parent
# This is working :
print self.getattA()
def getattB(self):
return self.getattA()
insta = A()
instb = B(insta)
# This is not working :
print instb.getattB()
The result is :
a
Traceback (most recent call last):
File "D:\Documents and settings\Bureau\merge.py", line 22, in <module>
print instb.getattB()
File "D:\Documents and settings\Bureau\merge.py", line 16, in getattB
return self.getattA()
AttributeError: B instance has no attribute 'getattA'
And I expected to got 'a' for the call of instb.gettattB()
To resume I want to inherit class B from class A giving class A in argument of class B because my class B will be a subclass of various class, not always A.

The Best answer is in the comments, it was useful for me so I decided to show it in an answer (thank to sr2222):
The way to dynamicaly declare inherance in Python is the type() built-in function.
For my example :
class A(object) :
def __init__(self, args):
self.a = 'a'
self.args = args
def getattA(self):
return self.a, self.args
class B(object) :
b = 'b'
def __init__(self, args) :
self.b_init = args
def getattB(self):
return self.b
C = type('C', (A,B), dict(c='c'))
instc = C('args')
print 'attributes :', instc.a, instc.args, instc.b, instc.c
print 'methodes :', instc.getattA(), instc.getattB()
print instc.b_init
The code return :
attributes : a args b c
methodes : ('a', 'args') b
Traceback (most recent call last):
File "D:\Documents and settings\Bureau\merge2.py", line 24, in <module>
print instc.b_init
AttributeError: 'C' object has no attribute 'b_init'
My class C inerhite attributes and methods of class A and class B and we add c attribute. With the instanciation of C (instc = C('args')) The init for A is call but not for B.
Very useful for me because I have to add some attributes and methodes (the same) on different class.

I was having trouble with calling different constructors, using super doesn't necessarily make sense in a case like this, I opted to inherit and call each constructor on the current object manually:
class Foo(object):
def __init__(self, foonum):
super(Foo, self).__init__()
self.foonum = foonum
class Bar(object):
def __init__(self, barnum):
super(Bar, self).__init__()
self.barnum = barnum
class DiamondProblem(Foo, Bar):
# Arg order don't matter, since we call the `__init__`'s ourself.
def __init__(self, barnum, mynum, foonum):
Foo.__init__(self, foonum)
Bar.__init__(self, barnum)
self.mynum = mynum

How about this?
class A:
def __init__(self):
self.a = 'a'
def getatt(self):
return self.a
class B:
def __init__(self, parent) :
self.parent = parent
def __getattr__(self, attr):
return getattr(self.parent, attr)
def getattB(self):
return self.parent.getatt()
insta = A()
instb = B(insta)
print instb.getattB()
print instb.getatt()
But method in class A can not access attr in class B.
Another way:
import functools
class A:
def __init__(self):
self.a = 'a'
def getatt(self):
return self.a
class B:
def __init__(self, parent):
for attr, val in parent.__dict__.iteritems():
if attr.startswith("__"): continue
self.__dict__[attr] = val
for attr, val in parent.__class__.__dict__.iteritems():
if attr.startswith("__"): continue
if not callable(val): continue
self.__dict__[attr] = functools.partial(val, self)
def getattB(self):
return self.getatt()
insta = A()
instb = B(insta)
print instb.__dict__
print instb.getattB()
print instb.getatt()
Slow with init but call fast.

Since B is not a subclass of A, there is no path in B to getatt() in A

I guess i have a easier method
class fruit1:
def __init__(self):
self.name = "apple"
self.color = "blue"
class fruit2:
def __init__(self):
self.name = "banana"
self.size = 100
def merge(ob1, ob2):
ob1.__dict__.update(ob2.__dict__)
return ob1
f1 = fruit1()
f2 = fruit2()
fruit = merge(f1, f2)
print("name:",fruit.name," color:",fruit.color, " size:",fruit.size)
#output: name: banana color: blue size: 100

I'm not certain what you are trying to do, but the code below is giving my the output I think you are expecting. notice:
a is initialized outside the constructor in A
B is declared as a subclass of A
Code:
class A:
a='' #Initialize a
def __init__(self):
self.a = 'a'
def getatt(self):
return self.a
class B(A): #Declare B as subclass
def __init__(self, parent) :
self = parent
print self.getatt()
def getattB(self):
return self.getatt()
insta = A()
instb = B(insta)
print instb.getattB()

Helper function below conducts the merge of the dataclass instances, the attributes orders is derived from *args order:
from dataclasses import dataclass
#dataclass
class A:
foo: str
bar: str
def merge_dataclasses(*args):
if len({e.__class__.__name__ for e in args}) > 1:
raise NotImplementedError('Merge of non-homogeneous entries no allowed.')
data = {}
for entry in args[::-1]:
data.update(vars(entry))
return entry.__class__(**data)
print(merge_dataclasses(A(foo='f', bar='bar'), A(foo='b_foo', bar='b_bar')))

One easy way to merge two or more classes is through the tool set dyndesign:
from dyndesign import mergeclasses
class Base:
def __init__(self, init_value):
self.param = init_value
def m1(self):
print(f"Method `m1` of class `Base`, and {self.param=}")
def m2(self):
print(f"Method `m2` of class `Base`")
class Ext:
def m1(self):
print(f"Method `m1` of class `Ext`, and {self.param=}")
MergedClass = mergeclasses(Base, Ext)
merged_instance = MergedClass("INITIAL VALUE")
merged_instance.m1()
# Method `m1` of class `Ext`, and self.param='INITIAL VALUE'
merged_instance.m2()
# Method `m2` of class `Base`

Emphasizing ThorSummoner's's answer and Hong's comment; this method appears to be cleaner than the excepted answer. Notice Hong's use of super().init(self) in all but the last object added to the merge class.
class Foo(object):
def __init__(self, foonum):
super(Foo, self).__init__(self)
self.foonum = foonum
class Bar(object):
def __init__(self, barnum):
super(Bar, self).__init__(self)
self.barnum = barnum
class Oops(object):
def __init__(self, oopsnum):
super(Oops, self).__init__()
self.oopsnum = oopsnum
class DiamondProblem(Foo, Bar, Oops):
def __init__(self, mynum, foonum, barnum, oopsnum):
Foo.__init__(self, foonum)
Bar.__init__(self, barnum)
Oops.__init__(self, oopsnum)
self.mynum = mynum
def main():
dia = DiamondProblem(1, 10, 20, 30)
print(f"mynum: {dia.mynum}")
print(f"foonum: {dia.foonum}")
print(f"barnum: {dia.barnum}")
print(f"oopsnum: {dia.oopsnum}")

Python using methods from other classes

If I have two classes, and one of them has a function that I want to use in my other class, what do I use so that I don't have to rewrite my function?

There are two options:
instanciate an object in your class, then call the desired method on it
use #classmethod to turn a function into a class method
Example:
class A(object):
def a1(self):
""" This is an instance method. """
print "Hello from an instance of A"
#classmethod
def a2(cls):
""" This a classmethod. """
print "Hello from class A"
class B(object):
def b1(self):
print A().a1() # => prints 'Hello from an instance of A'
print A.a2() # => 'Hello from class A'
Or use inheritance, if appropriate:
class A(object):
def a1(self):
print "Hello from Superclass"
class B(A):
pass
B().a1() # => prints 'Hello from Superclass'

There are several approaches:
Inheritance
Delegation
Super-sneaky delegation
The following examples use each for sharing a function that prints a member.
Inheritance
class Common(object):
def __init__(self,x):
self.x = x
def sharedMethod(self):
print self.x
class Alpha(Common):
def __init__(self):
Common.__init__(self,"Alpha")
class Bravo(Common):
def __init__(self):
Common.__init__(self,"Bravo")
Delegation
class Common(object):
def __init__(self,x):
self.x = x
def sharedMethod(self):
print self.x
class Alpha(object):
def __init__(self):
self.common = Common("Alpha")
def sharedMethod(self):
self.common.sharedMethod()
class Bravo(object):
def __init__(self):
self.common = Common("Bravo")
def sharedMethod(self):
self.common.sharedMethod()
Super-sneaky Delegation
This solution is based off of the fact that there is nothing special about Python member functions; you can use any function or callable object so long as the first parameter is interpreted as the instance of the class.
def commonPrint(self):
print self.x
class Alpha(object):
def __init__(self):
self.x = "Alpha"
sharedMethod = commonPrint
class Bravo(object):
def __init__(self):
self.x = "Bravo"
sharedMethod = commonPrint
Or, a similarly sneaky way of achieving delegation is to use a callable object:
class Printable(object):
def __init__(self,x):
self.x = x
def __call__(self):
print self.x
class Alpha(object):
def __init__(self):
self.sharedMethod = Printable("Alpha")
class Bravo(object):
def __init__(self):
self.sharedMethod = Printable("Bravo")

you create a class from which both classes inherit.
There is multiple inheritance, so if they already have a parent it's not a problem.
class master ():
def stuff (self):
pass
class first (master):
pass
class second (master):
pass
ichi=first()
ni=second()
ichi.stuff()
ni.stuff()

Develop Reference

Python is a programming language that lets you work quickly and integrate systems more effectively.

Selective Inheritance Python - python

I think you'd better define two members within Z,one is a class instance of X,another is a instance of Y.You can get the associated information stored in these instances while use different mode.

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