I am having a weird problem with VLC in Python. Using the following things.
import vlc
self.Instance = vlc.Instance()
self.List = self.Instance.media_list_new()
self.Player_d = self.Instance.media_list_player_new()
I am using self.List.add_media(address of video) to populate the media list.
Then self.Player_d.set_media_list(self.List)
and self.Player_d.play()
The problem is that VLC starts in a weird (YUV something) window, without any controls. Then freezes after playing the list. I have to use Task Manager to shut it down.
Can anybody point out the problem? I want to play the VLC with all controls.
Secondly, is there anyway of checking if VLC is already running, if running, then to quit and start a new instance of VLC.
Any help would be appreciated.
I don't see anything about wxPython in your question, but if you're using it with the vlc module, then that could be your problem. I'm guessing they don't play nicely together. You probably need to run all the vlc stuff in a separate thread rather than in wx's main loop.
Related
I'm trying to play a video using VLC, and close the window after the video is finished. However, I can't close the player window. I tried releasing instances of the player and media, but it doesn't work. And I couldn't find anything else in the API documentation.
Note that I don't want to terminate the whole application after the player finished, so sys.exit is not an option.
The following code is what I'm doing.
import vlc
VIDEO_PATH="/path/to/video.mp4"
def get_end_callback(mediaplayer):
def end_callback(event):
print("End of playing reached")
mediaplayer.stop()
mediaplayer.get_media().release()
mediaplayer.release()
mediaplayer.get_instance().release()
return end_callback
def play():
vlc_instance = vlc.Instance(["--no-xlib"])
media_player = vlc.MediaPlayer(vlc_instance, VIDEO_PATH)
media_player.play()
event_manager = media_player.event_manager()
event_manager.event_attach(vlc.EventType.MediaPlayerEndReached, get_end_callback(media_player))
play()
input("press Enter to exit")
I'm testing it with python=3.9, python-vlc=3.0.12118, vlc=3.0.9.2, on Ubuntu=20.04. I also tried another machine with older OS and older VLC.
So LibVLC will spawn a window to draw on, if you don't provide one. You don't want that, as you won't be able to manage it easily.
Before calling media_player.play(), you want to call media_player.set_hwnd(window.handle) (for Windows) / media_player.set_xwindow(window.xid) (for Linux) with a window handle.
Creating and managing and deleting this window is up to you and it does not have to be your main window of your app.
Here you can find more complete yet minimal samples with Qt and GTK frameworks https://github.com/oaubert/python-vlc/tree/master/examples
I am making turn based game in python using Pyglet. The game has a player-vs-AI mode in which the bot calculates a move to play against the player. However, the function which calculates the bot's move takes around 3-5 seconds to run, blocking the game's UI. In order to get around this, I am running the bot's calculation on a second process using multiprocessing.Process. I got it to work well without blocking the UI, however every time I open the second process to run the function a new Pyglet window opens, then closes again when the process is closed. Is there any way to open a second process in a Pyglet program without a second window opening? Let me know if examples of my code is required, and I will try to come up with similar code to share. Thanks in advance to anyone who can help.
You can fix the problem by moving the initialization of the window inside of the main block
I am trying to wait for a song to finish to play the next song.
I am running python 3.4 on windows but am trying to be able to use it on Linux (raspberry pi).
I have used the command subprocess.call([PLAYER, SONG]) to open the mp3 file. It plays in vlc and then stops. I know that I have not incorporated anything for the program to tell python when its finished.
That's where you guys come in. I want to find a command that will wait until the song has finished and when the song is finished, the rest of the code will process.
I would like the command to be able to used on a Linux operating system and I am trying not to have to install any modules.
If modules are definitely needed, I will install them.
You may use VLC python bindings to get the different information about the VLC player.
There are different methods that can provide your different information. You may achieve your solution by using the get_state(self) method, it provides the state information of the player. So, when the song is completed the VLC state would be stopped.
Sample code:
import vlc
def setup_player(filename):
vlc_instance = vlc.Instance()
media = vlc_instance.media_new(filename)
player = vlc_instance.media_player_new()
player.set_media(media)
player.play()# Start the player
print player.get_state()# Print player's state
player.stop()# Stop the player
print player.get_state()# Print player's state
setup_player('filename')#Put media file name/location here
I hope it was helpful.
Any ideas about controling windows media player in Python? I found the following code on the net which runs fine but no audio is played. am using win7 64 bit machine
# this program will play MP3, WMA, MID, WAV files via the WindowsMediaPlayer
from win32com.client import Dispatch
mp = Dispatch("WMPlayer.OCX")
#tune = mp.newMedia("./SleepAway.mp3")
tune = mp.newMedia("./plays.wav")
mp.currentPlaylist.appendItem(tune)
mp.controls.play()
raw_input("Press Enter to stop playing")
mp.controls.stop()
As I have mentioned in comments, I have had an identical problem. I tried a ridiculous number of different approaches. None of them really worked, so I was stuck using os.startfile to open windows media player to play my sound files. However, just today I had an idea which has led to an alternative solution. It is a bit hack-ish, but it works. Technically I still open windows media player with this approach, but I do so using subprocess, and thus I can use the greater control over the process allowed by that to supress the window. This makes it seem like it plays without a secondary application. Why I had to do something so bizarre to get a simple result I have no idea, but it is the only thing that worked. Here is my code for it if you want.
import subprocess
import threading
def windowsmedia(filename):
startupinfo = subprocess.STARTUPINFO()
startupinfo.dwFlags |= subprocess.STARTF_USESHOWWINDOW
a = subprocess.call('C:\\Program Files (x86)\\Windows Media Player\\wmplayer.exe /play /close "C:/Users/Student/Documents/notes/file.mp3"',startupinfo=startupinfo)
def startmp3(filename):
mythread = threading.Thread(target=windowsmedia,args=[filename])
mythread.start()
time.sleep(15) #You might want to extend this... I just give it 15 seconds to complete before killing the process. It shouldn't be too hard to read the exact length from the file and wait that, or add an interrupt, but that was somewhat unnecessary for my purposes.
pkill("wmplayer") #This is a function of my own but it basically just kills the process. It shouldn't be too hard to reproduce.
Again it is truly regrettable that I had to do something so weird for just playing a sound but as far as you have described it this is the same issue and I hope this helps.
Thought, it might help others who are still facing this issue.
All you had to do is to call PlayItem() API after Play().
from win32com.client import Dispatch
from time import sleep
mp = Dispatch("WMPlayer.OCX")
tune = mp.newMedia("./plays.wav")
mp.currentPlaylist.appendItem(tune)
mp.controls.play()
sleep(1)
mp.controls.playItem(tune)
raw_input("Press Enter to stop playing")
mp.controls.stop()
It helps me to use Windows Media COM. When I tried it, I need to make 2 small modification to make it working in Python Flask.
CoInitialize to make it single thread i.e. pythoncom.CoInitialize() and pythoncom.CoUninitialize()
PumpWaitMessage to keep MediaPlayer working i.e while mp.PlayState != 1: pythoncom.PumpWaitingMessages()
I'm developing a media player. Right now it's a simple window with a button to load .wav files. The problem is I would like to implement a pause button now. But, when playing a audio file the GUI isn't accessible again (no buttons can be pushed) till the file is done playing. How can I make the GUI dynamic while an audio file is playing?
I'm using PyAudio, and their implementation doesn't allow this.
Probably you have to use threads for that. You have to play your audio file in a different thread than the gui mainloop so that the GUI keeps responding user input.
IMHO, wxpython is not so complicated and has some utility functions that would help to do what you want. Check the wxpython demo, you have several examples there.
You can alternatively use pygame mixer for the purpose , I made the same in pyqt and I did'nt require to implement threading . You can get the documentation of pygame mixer at https://www.pygame.org/docs/ref/mixer.html
Happy Coding .
Try this out:
Check the code https://drive.google.com/file/d/0B7ccI33Aew5fNVhwZ2puYTBuUFU/view?usp=sharing
I have used pygame also.Hope this helps.