I am displaying a modelformset and I would like the forms to be ordered by the contents of one of its fields. So I want to use the equivalent of SomeModel.objects.filter(whatever).order_by('somefield') for a (model)formset in a template.
How can I do this?
Note that can_order does not do what I want (it must be automatic, not user specified). I have also tried other things, like the dictsort filter, but that produces unpredictable output (i.e. not ordered by the specified field).
I even tried {% regroup formset by somefield as sorted_formset %}, but the resulting sorted_formset cannot be used (iterated) as a normal formset.
To complete the answers. There are two ways how you can control the order of forms in the formset: formsets respect order of given queryset (this is shown in other replies). Another way (if you want to have the order of the forms fully under control) is to define custom formset class and override __iter__ and __getitem__ methods:
from django.forms import BaseModelFormSet
class MyModelBaseFormset(BaseModelFormSet):
def __iter__(self):
"""Yields the forms in the order they should be rendered"""
return ...
def __getitem__(self, index):
"""Returns the form at the given index, based on the rendering order"""
return ...
MyModelFormset = modelformset_factory(model=MyModel, formset=MyModelBaseFormset, queryset=...)
This approach is described in the Django documentation:
Iterating over the formset will render the forms in the order they
were created. You can change this order by providing an alternate
implementation for the __iter__() method.
Formsets can also be indexed into, which returns the corresponding
form. If you override __iter__, you will need to also override
__getitem__ to have matching behavior.
https://docs.djangoproject.com/en/dev/topics/forms/formsets/#django.forms.formsets.BaseFormSet
The example of implementing these methods is for example in this SO thread: modelformset __iter__ overloading problem.
if you didn't defined Formset, this is the "inline code" version:
FS=inlineformset_factory(ParentClass,ChildClass)
formset=FS(instance=parentobject,
queryset=parentobject.childobject_set.order_by("-time_begin")
)
Thanks to #john-peters answer above, for pointing me in the right direction. But here is a better way:
MyFormset(inlineformset_factory(...)):
def get_queryset(self):
return super(MyFormset, self).get_queryset().order_by('myfieldname')
This way you do not have to copy or mess with django's code and potentially cause breakage down the road.. just take the queryset that django gives you and override the ordering. I have used this in my own code, it works.
EDIT. After working on this a bit I realize that although it appears to work fine, it somehow messes up the logic in BaseInlineFormset.get_queryset(), resulting in duplicate database queries. However, in the hopes that someone will comment on this and correct it, I will leave it here. Meanwhile, I have another solution which DOES WORK and does not result in redundant queries.. as follows:
MyFormset(inlineformset_factory(...)):
def __init__(self, *args, **kwargs):
super(MyFormset, self).__init__(*args, **kwargs)
self.queryset = self.queryset.order_by('myfieldname')
This modifies the queryset at a safe time, before anything is done with it. In my code I am also doing .select_related() here, which greatly speeds up my large modelformsets!
Thanks to rantanplan's comment I found a solution. I could not use the method as described in the link above because I don't know what the queryset is going to be (this is a complex form with nested formsets).
Anyway, I found a solution by overriding the get_queryset method from Django's BaseInlineFormSet Class.
I copied it below, including my mod, in case googlers find it helpful.
def get_queryset(self):
'''
Copied this method from Django code and modified the ordering statement
'''
if not hasattr(self, '_queryset'):
if self.queryset is not None:
qs = self.queryset
else:
qs = self.model._default_manager.get_query_set()
# If the queryset isn't already ordered we need to add an
# artificial ordering here to make sure that all formsets
# constructed from this queryset have the same form order.
if not qs.ordered:
# MY MOD IS HERE:
# qs = qs.order_by(self.model._meta.pk.name)
qs = qs.order_by('order_index')
#/MOD
# Removed queryset limiting here. As per discussion re: #13023
# on django-dev, max_num should not prevent existing
# related objects/inlines from being displayed.
self._queryset = qs
return self._queryset
A more simpler way but it might not apply in every situation but if you can afford it just define ordering in models Meta class:
class ExampleModel(models.Model):
...
class Meta:
ordering = ("name", )
Formset will respect the queryset's ordering which will respect the Meta class variable's value.
Related
I am diving to a django rest-api framework that someone else wrote and configured, and I came across a problem I could not find any good solution for.
There is a model containing field of type "YAMLField". While trying to retrieve this field member, it is converted to OrderedDict (not quite sure how and where this conversion is happening...).
Now, I have a queryset of this model. I understand how to filter a queryset based on simple attributes, but how can I filter it based on this dictionary?
For example, each entry in this queryset (which is MyModel instance) contains:
MyModel.myDictionary == {'firstKey': 'firstVal', 'secondKey':'secondVal}
Now I want to get all the entries from this queryset where:
myDictionary = {'firstKey': 'Something'}
Meaning, my dictionary to filter by, may contain only a subset of the keys.
I could not find any solution or a straight forward way to do it, leading me to iterate the queryset and for each entry, iterate the dictionary.
This feels like too much overhead...
I think I had the same problem and someone told me an straightforward answer, which consists in adding "__{dictionary_key}" to your filtering request such as, in your case:
Model.objects.all().filter(myDictionary__firstKey="Something")
Though the asnwer is probably coming too late, I post it hoping that it can be useful for others in the future!
You need this is possible. For more information see django-rest-framework doc
class MultipleFieldLookupMixin(object):
"""
Apply this mixin to any view or viewset to get multiple field filtering
based on a `lookup_fields` attribute, instead of the default single field filtering.
"""
def get_object(self):
queryset = self.get_queryset() # Get the base queryset
queryset = self.filter_queryset(queryset) # Apply any filter backends
filter = {}
for field in self.lookup_fields:
filter[field] = self.kwargs[field]
return get_object_or_404(queryset, **filter) # Lookup the object
I have the following models:
class Recipe(models.Model):
fields...
class Ingredient(models.Model):
fields...
class UsesIngredient(models.Model):
recipe = models.ForeignKey(Recipe)
ingredient = models.ForeignKey(Ingredient)
amount = models.FloatField()
group = models.CharField()
I have a view which lets the user add any number of 'UsesIngredient' models for a certain recipe through a dynamic formset. The group attribute is automatically filled in an hidden from the user.
The problem is that when the users adds a new form in the formset, but doesn't fill in any of the fields, I don't want that form saved. However, django still tries to save the form because the 'group' attribute has 'changed' (because it has been automatically filled in when the extra form was created).
Is there any way to get around this?
Thanks!
Well, I still didn't feel completely comfortable with Tim Edgar's solution, so I kept looking. I guess I found what I was looking for.
The 'Form' class, has two undocumented methods that are of use in this case: 'has_changed()' and '_get_changed_data'.
During ModelFormSet validation, every form checks 'has_changed()'. If the form did not changed, validation is skipped and a correct form is assumed.
Likewise, during ModelFormSet saving, the save_new_objects checks every form to see if it has changed. If it didn't change, the form isn't saved.
So my solution was to override the has_changed() method to return False if only the 'group' attribute has changed, and all other fields are empty. This is my implementation:
class UsesIngredientForm(forms.ModelForm):
class Meta:
model = UsesIngredient
def has_changed(self, *args, **kwargs):
self._get_changed_data(*args, **kwargs)
# If group is in changed_data, but no other fields are filled in, remove group so
# the form will not be validated or saved
if 'group' in self._changed_data and len(self._changed_data) == 1:
contains_data = False
for name in ['ingredient', 'amount', 'unit']:
field = self.fields[name]
prefixed_name = self.add_prefix(name)
data_value = field.widget.value_from_datadict(self.data, self.files, prefixed_name)
if data_value:
contains_data = True
break
if not contains_data:
self._changed_data.remove('group')
return bool(self._changed_data)
Hope this helps anybody in the future!
EDIT:
I edited this answer to reflect Tim Edgars comment.
I realize that this implementation still uses 'private' methods, but I haven't found a cleaner implementation using just the publicly documented methods. But then maybe that is just my own incompetence :).
You could try making all your fields to require a value by setting blank=False. See more here. It should require validation that the values that you care about are not left blank.
If that doesn't work, you can try creating your own custom save method that does the validation that you care about.
def save(self, *args, **kwargs):
# Do your checks on the properties such as self.group, self.amount, etc
# If it is fine then call
super(UsesIngredient, self).save(*args, **kwargs)
After a few hours of searching I must admit that I am defeated.
I have read the Django docs but I really can't find a solution to my problem.
Consider the following line of code:
EmploymentFormSet = inlineformset_factory(Profile, Employment, form=EmploymentForm, extra=3)
This code lives in a classbased view which inherits from UpdateView and furthermore in the method get_context_data(self, *args, **kwargs):
This is pretty straight forward as the inlineformset_factory creates an EmploymentFormSet.
Now consider this
queryset = Employment.objects.filter(profile__pk=self.kwargs['pk']).values()
context['emp_formset'] = EmploymentFormSet(prefix='emp_form', initial=queryset, auto_id=True)
I thought by supplying initial=queryset, which only applies to unbound instances IIRC, it would populate my formset with as many as the queryset would contain.
So the queryset will in my case return 4 Employments but when using the extra parameter, the formset I'm constructing are only filled with as many as this parameter defines, in my example only 3 since I defined only 3 extras. Incrementing the extra will populate the forms incrementally.
I've tried subclassing the BaseInlineFormSet but I haven't really broken through the wall.
My question is how would I go about to populate the formset with as many forms as the queryset contains, I'm not really out for an exact solution but more of a pointer in the right the direction! :)
Thanks!
I solved it by constructing this method
def set_extra_forms(extra_forms, **kwargs):
EmploymentFormSet = inlineformset_factory(Profile, Employment, form=EmploymentForm, extra=extra_forms)
return EmploymentFormSet(**kwargs)
Now I do believe this is the way to go but I have to refactor the code in order to make it more dynamic right now its connected to one class and one class only but it works like a charm.
Define the formset inside a view
def employment_view(request, pk=None):
#Define extra forms variable
extra_forms = Employment.objects.filter(profile__pk=self.kwargs['pk']).count()
#Define formset inside the view function
EmploymentFormSet = inlineformset_factory(Profile, Employment, form=EmploymentForm, extra=extra_forms)
#Use this in context
context['emp_formset'] = EmploymentFormSet()
I'm looking for the easiest way to combine List and Create functionally with generic class views.
I want to have a page that has an item list and a form to add a new item on the bottom.
I thought that mixin architecture would allow to combine necessary classes but I had no luck yet.
This almost works:
class ResourceListView(ListView, BaseCreateView):
context_object_name = 'resources'
model = Resource
form_class = ResourceForm
But form isn't accessible inside template and the thing crashes on invalid output (when form is valid, it's fine).
This may have to do with multiple inheritance but I'm not really into Python yet so it gets too confusing.
Is there a simple way to combine some of the mixins into a view-and-create View, or do I have to roll out my own?
Note: I no longer advocate this solution, as this is a much cleaner one.
By trial and error (and looking at Django source), I wrote this:
class ListCreateView(ListView, BaseCreateView):
def get_context_data(self, **kwargs):
self.object = None
self.object_list = self.get_queryset()
form_class = self.get_form_class()
form = self.get_form(form_class)
kwargs.update({'object_list': self.object_list, 'form': form})
context = super(ListCreateView, self).get_context_data(**kwargs)
return context
Works fine both for creating and listing (although it may issue a few extra database calls, not sure).
Is it possible to use create_object view to create a new object and automatically assign request.user as foreign key?
P.E:
class Post(models.Model):
text = models.TextField()
author = models.ForeignKey(User)
What I want is to use create_object and fill author with request.user.
In many ways, all the solutions to this will be more trouble than they are worth. This one qualifies as a hack. It is possible for a django update to leave you high and dry if they change the way create_update is implemented. For simplicity sake, I'll assume that you are trying to set a default user, not silently force the user to be the logged in user.
Write a context processor:
from django.views.generic.create_update import get_model_and_form_class
def form_user_default(request):
if request.method == 'GET':
model, custom_form = get_model_and_form_class(Post,None)
custom_form.author = request.user
return {'form':custom_form}
else: return {}
What this will do is override the form object that create_update passes to the template. What it's technically doing is re-creating the form after the default view has done it.
Then in your url conf:
url(r'pattern_to_match', 'django.views.generic.create_update.create_object', kwargs={'context_processors':form_user_default})
Again, I had to delve into the source code to figure out how to do this. It might really be best to try writing your own view (but incorporate as many Django custom objects as possible). There's no "simple default" way to do this, because in the django paradigm forms are more closely tied to the model layer than to views, and only views have knowledge of the request object.
You may want to consider a closure.
from django.forms import ModelForm
from django.views.generic.create_update import create_object, update_object
def make_foo_form(request):
class FooForm(ModelForm):
class Meta:
model = Foo
fields = ['foo', 'bar']
def save(self, commit=True):
f = super(FooForm, self).save(commit=False)
if not f.pk: f.user = request.user
if commit: f.save()
return f
return FooForm
def create_foo(request):
FooForm = make_foo_form(request)
return create_object(form_class=FooForm)
There is some inefficiency here, since you need to create the ModelForm object on each request, but it does allow you to inject functionality into the generic view.
You need to decide whether the added complexity for the form creation is worth maintaining simplicity on the view side.
A benefit here, though, is that this also works with the update case with practically no extra effort:
def update_foo(request, object_id):
FooForm = make_foo_form(request)
return update_object(form_class=FooForm, object_id=object_id)
Obviously, you can use this approach for more complex cases as well.
If a user is authenticated, their user object is the request.user object.
I'm not familiar with create_object... I'm still a beginner to django and have only just started my first real project with it.
Note that you should check to make sure a user is logged in before using this. This can be done with request.user.is_authenticated().
There is no good way to hook into the saving of an object when using the current Django generic views. Once they are rewritten as classes, you'll be able to subclass the view and hook in at the proper place without having to rewrite the whole view.
I already use my own class-based generic views for this reason.
I would suggest to make a wrapper for the create_object, as this author suggest
http://www.b-list.org/weblog/2006/nov/16/django-tips-get-most-out-generic-views/
in the view you'll have access to the user info.
Afterwards, you will need to use the extra_context to pass the user to the template. Finally at the template you can add a hidden field with the user info. I haven't tried it, but I have been thinking of it for quite some time. Hope this solution suits you!
;) cheers!