Develop Reference

How do I create a cronjob for these commands?

I want to a up a cron job to run a python script each day within a virtual environment. So I've tried to set up a cron job but it does not seem to execute.
If I were to run the program from terminal normally, I would type:
source ig/venv/bin/activat enter to activate my virtual environment
cd ig/mybot/src/ navigate to my directory
python ultimate.py run my program
SO FAR this is my cron job. I've set it to 1 to run every minute just so I can see that it is working but nothing happens.
1 * * * * source ig/venv/bin/activate && cd ig/mybot/src/ && python ultimate.py
Edit: I have updated my program so no command line prompts are required. I am just needing to run these three simple commands.

You can wrap this up with another python script itself. Create a new python script and run it instead of cron.
Have a look into subprocess module.
Example:
Your command would become subprocess.call(['source','ig/venv/bin/activate'])
inside the wrapper python script.
Also, input("Enter the value") will prompt you for user input.
With the above two, your problem will be solved pythonically.

I'm not sure if it's a good idea, but you could do a script like this.
#!/usr/bin/env bash
PYTHON_PROJECT_DIR=/path/to/python/project/dir
pushd ${PYTHON_PROJECT_DIR}
VALUES="first line of stream\nsecondline of stream\n"
pipenv run /path/to/your/script.py < (echo -e $VALUES)
popd
pushd and popd are commands to move with the directory stack, so you'll be in the directory in the top of the stack, so by adding one directory, you move to the working directory, and by poping you'll get back to the initial position.
Using pipenv allows you to run the scripts in the virtual enviroment (It's not that hard to configure), that way you'll use the enviroment variables in the .env files for the project, and you'll only use the dependencies of this project. (python related).
If you pass the values like this, the python script when ever it requests a value from stdin it will use the values that you echoed (line by line, first line is first input and so on)
This could be a way.
Personally when ever I do cronjobs I like to run directly bash scripts, because, I could add extra logging, so having the wrapper script doesn't seem that unreasonable.
Another thing you could do, Is to get the python executable path (for the virtual enviroment), and use that as interpreter, by replacing the #!/usr/bin/env python to #!/path/to/pythons/virtual/env/interpreter
but you won't get the .env variables (may be there is a way to actually get them.

Issues with running a Python program with Cron

I am trying to run a Python script called probemon.py in cron (crontab -e) and cannot get it to work. The path to the file is /home/pi/probemon.py and this must be run with the sudo command usually (i.e. sudo python probemon.py). I have tried many methods, including:
52 23 * * * sudo python /home/pi/probemon/probemon.py
and yet nothing works. Any ideas about how to do this?

Try adding the command to the sudo-users crontab instead of trying to run it with a sudo from a normal users crontab. I think what happends is that "sudo ..." will ask for the sudo-password, and wait in this stage forever, since noone is providing one.

Auto run commands on Raspberry pi

i wanted to know what would be the best approach to solving this issue. I would like to run a bunch of commands to run some python scripts and a service when the raspberry pi loads into the desktop. Here are my commands:
cd /var/www/html/
python servocontrol.py
cd /var/www/html/Misc
python temp1.py
python seven_segment.py
sudo /etc/init.d/livestream.sh start
My initial method which i read on most post was to add it in the rc.local by:
sudo nano /etc/rc.local
And paste the exact commands in it as follows:
#
# By default this script does nothing.
# Print the IP address
_IP=$(hostname -I) || true
if [ "$_IP" ]; then
printf "My IP address is %s\n" "$_IP"
fi
sleep 15
cd /var/www/html/
python servocontrol.py
cd /var/www/html/Misc
python temp1.py
python seven_segment.py
sudo /etc/init.d/livestream.sh start
exit 0
Sadly it didn't work. Kindly if any one can point out what i am missing or if there are additional steps that need to be done for this to work. If there are other methods i am also open to them!
Thanks

you can use crontab on raspberry pi (The crontab (short for "cron table") is a list of commands that are scheduled to run at regular time intervals on your computer system. The crontab command opens the crontab for editing, and lets you add, remove, or modify scheduled tasks.)
AND you can create service for your script.
it's very easy just need 5 sec search to find instruction.

are you want execute a script in server start?
you can use #reboot in cron

Python Script not running in cron

I am trying to run a Python script from cron. I am using crontab to run the command as a user instead of root. My Python script has the shebang at the top #! /usr/bin/env python and I did chmod +x it to make the script executable.
The script does work when running it from a shell but not when using crontab. I did check the /var/log/cron file and saw that the script runs but that absolutely nothing from stdout or stderr prints anywhere.
Finally, I made a small script that prints the date and a string and called that every minute that worked but this other script does not. I am not sure why I am getting these variable results...
Here is my entry in crontab
SHELL=/bin/bash
#min #hour day-of-month month day-of-week command
#-------------------------------------------------------------------------
*/5 * * * * /path/to/script/script.py
Here is the source code of my script that will not run from crontab but will run from the shell it is in when called like so ./script.py. The script is executable after I use the chmod +x command on it, by the way...:
#! /usr/bin/env python
#create a file and write to it
import time
def create_and_write():
with open("py-write-out.out", "a+") as w:
w.write("writing to file. hello from python. :D\n")
w.write("the time is: " + str(time.asctime()) + "\n")
w.write("--------------------------------\n")
def main():
create_and_write()
if __name__ == "__main__":
main()
EDIT
I figured out what was going wrong. I needed to put the absolute file paths in the script otherwise it would write to some directory I had not planned for.

Ok, I guess this thread is still going to help googlers.
I use a workaround to run python scripts with cron jobs. In fact, python scripts need to be handled with delicate care with cron job.
So I let a bash script take care of all of it.I create a bash script which has the command to run the python script. Then I schedule a cron job to run bash script. You can even use a redirector to log the output of bash command executing the python script.For example
#reboot /home/user/auto_delete.sh
auto_delete.sh may contain following lines:-
#!/bin/sh
echo $(date) >> bash_cron_log.txt
/usr/bin/python /home/user/auto_delete.py >> bash_cron_log.txt
So I don' need to worry about Cron Jobs crashing on python scripts.

You can resolve this yourself by following these steps:
Modify the cron as /path/to/script/script.py > /tmp/log 2> &1
Now, let the cron run
Now read the file /tmp/log
You will find out the reason of the issue you are facing, so that you can fix it.
In my experience, the issue is mostly with the environment.
In cron, the env variables are not set. So you may have to explicitly set the env for your script in cron.

I would like to emphasise one more thing. I was trying to run a python script in cron using the same trick (using shell script) and this time it didn't run. It was #reboot cron. So I used redirection in crontab as I mentioned in one of the above comments. And understood the problem.
I was using lot many file handlers in python script and cron runs the script from user's home directory. In that case python could not find the files used for file handlers and will crash.
What I used for troubleshooting was that I created a crontab as below. It would run the start.sh and throw all the stderror or stdoutput to file status.txt and I got error in status.txt saying that the file I used for file handler was not found. That was right because python script was executed by cron from user's home directory and then the script starts searching for files in home directory only.
#reboot /var/www/html/start.sh > /cronStatus/status.txt 2>&1
This will write everything happening during cron execution to status.txt file. You can see the error over there. I will again advice running python scripts using bash scripts for cronjobs. SOLUTION:- Either you use full path for all the files being used in script (which wasn't feasible for me, since I don't want script to be location dependent). Or you execute script from correct directory
So I created my cron as below-
#reboot cd /var/www/html/ && /var/www/html/start.sh
This cron will first change directory to correct location and then start the script. Now I don't have to worry about hardcoding full path for all files in script. Yeah, it may sound being lazy though ;)
And my start.sh looks like-
#!/bin/sh
/usr/bin/python /var/www/html/script.py
Hope it helps
Regards,
Kriss

I had a similar issue but with a little bit different scenario: I had a bash script (run.sh) and a Python script (hello.py). When I typed
sh run.sh
from the script directory, it worked; if I added the sh run.sh command in my crontab, it did not work.
To troubleshoot the issue I added the following line in my run.sh script:
printenv > env.txt
In this way you are able to see the environment variable used when you (or the crontab) run the script. By analyzing the differences between the env.txt generated from the manual run and the crontab run I noticed that the PWD variable was different. In my case I was able to resolve by adding the following line at the top of my .sh script:
cd /PYTHON_SCRIPT_ABSOLUTE_PATH/
Hope this could help you!

Another reason may be that the way we judged executed or not executed is wrong.

is there a way to use fabric run() and sudo() at a time?

I'm trying to automate a test in python 2.7 (in eclipse on linux ubuntu 12.04).
The test checks configurations on another pc, so I'm using fabric for the ssh connection.
I need to execute a script:
run("cd somepath && ./execute_script.sh")
The problem is that my script needs a sudo to run, but changing the command to this:
sudo("cd somepath && ./execute_script.sh")
does not work since "cd" doesn't work in combination with sudo.
I also cannot split the command in two parts, because that would create 2 shells, and the second one would forget the path I've been going to in the first one.
If I do it like this:
run("cd somepath && sudo ./execute_script.sh")
the test wouldn't work completely automatic since you would have to enter the password at a time.
Is there a way to some sort of combine run() and sudo()?

How about:
from fabric.api import cd,sudo
with cd('somepath'):
sudo('./execute_script.sh')