Develop Reference

Python Selenium: Find child of sibling in a table and click it

I have a table and I want to click every checkbox on a row containing the word empty.
The checkbox is a child of a sibling in the HTML-code (I hope I'm using the correct terms). Screenshot of HTML-code.
I've managed to make a list of of all elements containing empty with this:
empty = driver.find_elements_by_xpath("//*[contains(text(),'empty')]")
How can I use this list to find the checkbox in the same row?
I'm using Selenium with Python.

try one of these this xpath :
//tr[td[contains(text(),'empty')]]//input
//td[contains(text(),'empty')]/preceding-sibling::td/input

Search for a specific element in multiple pages and click using Python Selenium

Hi im trying to navigate from page 1 to page 5 (the element can be in any of the pages)and find and click on a specific element using python selenium.
The following is the element from the page:
<span _ngcontent-mtx-c123"" class"ng-star-inserted">ABC Company</span>
i tried by using : driver.find_element_by_name("ABC Company").click() but this doesnt work.
Another Way i tried:
1. element_path="//span[contains(text(),'ABC Company')]"
2. while True:
3. if(driver.find_elements_by_xpath(element_xpath)): driver.find_element_by_xpath(element_xpath).click()
4. else: driver.find_element_by_xpath("xpath to goto next page").click()
I need the code to find element from the next pages until its found and then click it.
is there any other way to do this???
Thanks in Advance

First, you need to check if the element is present and only if it does - click it. Otherwise you will get exception while trying clicking non-existing element.
driver.find_elements returns a list of web elements matching the passed locator. So if there are such elements it will return non-empty list interpreted as True by Python. Otherwise empty list is returned interpreted as False.
As about the locator for the element you are looking for: you can locate the element according to the text it contains. It can be done with XPath.
As following:
element_xpath = "//span[contains(text(),'ABC Company')]"
if(driver.find_elements_by_xpath(element_xpath)):
driver.find_element_by_xpath(element_xpath).click()
If you need to update the XPath locator dynamically you can pass the text as parameter. Let's say you have a list of texts, you can iterate on them as following:
for txt in texts:
element_xpath = "//span[contains(text(),'{}')]".format(txt)
if(driver.find_elements_by_xpath(element_xpath)):
driver.find_element_by_xpath(element_xpath).click()

I am currently trying to click multiple links that will cause files to download. However I am unable to click more than one file

I am trying to create code that will click multiple links on a webpage that will inturn download files. However, I have written an XPath that contains all the links. When trying to click I get this error: "click() takes 1 positional argument but 2 were given".
Is there any way to click all links in the desired XPath with .click() function in selenium?
This is what I am trying with 10 files:
browser.find_element_by_xpath("//a[starts-with(#href,'sys_attachment.do') and #class='linked formlink']").click('href')
Is there a better way to download all of these with the XPath? Thanks.

You should use find_elements_by instead of element so you can loop over the list of elements, and click on each one, ex:
clickList = browser.find_elements_by_xpath("//a[starts-with(#href,'sys_attachment.do') and #class='linked formlink']")
for count, elem in enumerate(clickList):
# I am refreshing the list in case the DOM is changed
currentList = browser.find_elements_by_xpath("//a[starts-with(#href,'sys_attachment.do') and #class='linked formlink']")
currentList[count].click()

If you want to find many elements then use find_elemenets_... with s in word elements and you get list with many elements. And then you have to use for-loop to use click() (without arguments) on every element separatelly.
all_items = browser.find_elements_by_xpath("//a[starts-with(#href,'sys_attachment.do') and #class='linked formlink']")
for item in all_items:
item.click()
Problem is when click changes page because then items stop exist and you would have to go back, find again all items and click next element on list - but you have to remeber index of previously clicked item.

Python selenium get location of an element

So I have this site and I'm trying to obtain the location and size of an element based on this xpath "//div[#class='titlu']"
How you can see that is visible and has nothing special.
Now the problem I've faced is that when I'm doing the search for xpath like this
e = self.driver.find_element_by_xpath(xpath) the location and size
of e are both 0
Also, for some reason, if I'm trying to get the text like this:
e.text is going to show me an empty string, and I need to get the actual text in this way e.get_attribute("textContain")
So do you have any idea how can I get the location and size of this element?

There are two elements matching this xpath. driver.find_element_by_xpath returns the first one while you are looking for the second one. Use the ancestor <div> with id attribute for unique xpath
"//div[#id='content-detalii']//div[#class='titlu']"

Xpath clicking not working at all

Quick info: I'm using Mac OS, Python 3.
I have like 800 links that need to be clicked on a page (and many more pages to go so need automation).
They were hidden because you only see those links when you hover over.
I fixed that by injecting CSS rule (just saying in case its the reason it's not working).
When I try to find elements by xpath it does not want to click the links afterwards and it also doesn't find all of them always just 4 (even when more are displayed in view).
HTML:
Display
When i click ok copy xpath in inspect it gives me:
//*[#id="tiles"]/li[3]/div[2]/ul/li[2]/a
But it doesn't work when I use it like this:
driver.find_elements_by_xpath('//*[#id="tiles"]/li[3]/div[2]/ul/li[2]/a')
So two questions:
How do I get them all?
How do I get it to click on each of them?
The pattern in the XPath is the same, with the /li[3] being the only number that changes, for this I created a for loop to create them all based on the count on page which I did successfully.
So if it can be done with the XPaths generated by myself that are corresponding to when I copy XPath in inspector then I only need question 2 answered.
PS.: this is HTML of parent of that first HTML:
<li onclick="openPopup(event, 'collect', {item_id: 165214})" class="collect" data-item-id="165214">Display</li>

This XPath,
//a[.="Display"]
will select all a links with anchor text equal to "Display".

As per your question, the HTML you have shared and your code attempts there is no necessity to get the <li> tags. Instead we will get the <a> tags in a list. So to answer your first question How do I get them all you can use the following line of code :
all_Display = driver.find_elements_by_xpath("//*[#id='tiles']//li/div[2]/ul/li[#class='collect']/a[#title='Display']")
Next to click on each of them you have to create a loop to iterate through all the <a> tag as follows :
all_Display = driver.find_elements_by_xpath("//*[#id='tiles']//li/div[2]/ul/li[#class='collect']/a[#title='Display']")
for each_Display in all_Display :
each_Display.click()

Using an XPath with elements by position is not ideal. Instead use a CSS selector to match the attributes for the targeted elements.
Something like:
all_Display = driver.find_elements_by_css_selector("#tiles li[onclick][data-item-id] a[title]")
You can then click them in a loop if none of them is loading a new page:
for element in all_Display:
element.click()