Python BaseHTTPServer stops rest of script - python

I am using BaseHTTPServer to serve a simple variable, the problem is that the rest after server.serve_forever() is not executing.
It does not seem that BaseHTTPServer is forking?
How can i get around this problem?
The variable (http output) BaseHTTPServer is serving is continiously updated by the other part of the script.
Here is a pastebin: http://pastebin.com/v4xEuHBs

from BaseHTTPServer import HTTPServer, BaseHTTPRequestHandler
import SocketServer
import os
def main():
try:
startserver(self)
def startserver(self):
newpid = os.fork()
if newpid == 0:
server = HTTPServer(('',8080), ThreadingHTTPServer)
server.serve_forever()
class ThreadingHTTPServer(SocketServer.ThreadingMixIn,BaseHTTPRequestHandler):
def do_GET(self):
self.loop = loop
self.send_response(200)
self.send_header('Content-type','text/html')
self.end_headers()
self.wfile.write('hello, world')
return

Related

How to create a http server that сontrol of the socketserver's main loop thread?

I created an http server. My task is to make sure that each new post request to the server is processed in a separate thread.I tried using socketserver.ThreadingTCPServer(),but this way I can't control the threads. I need to start a thread only after the previous one is completed or after 5 minutes have passed.How can I implement the server differently, but only so that requests are processed in a separate request and each new thread is processed after the previous one has completed?
from http.server import HTTPServer, BaseHTTPRequestHandler, ThreadingHTTPServer
import socketserver
import threading
class Handler(BaseHTTPRequestHandler):
def do_POST(self):
self.send_response(200)
self.end_headers()
query_args = parse_qs(urlparse(self.path).query)
print(query_args)
if __name__ == "__main__":
try:
with socketserver.ThreadingTCPServer(("", 8080), Handler) as httpd:
while True:
httpd.serve_forever()
except Exception as e:
httpd.server_close()

Web server in python in plainText

I am looking for a way to expose a text file with Python web server.
I get some python code to run a web server :
import http.server
import socketserver
port = 9500
address = ("", port)
handler = http.server.SimpleHTTPRequestHandler
httpd = socketserver.TCPServer(address, handler)
print(f"Serveur démarré sur le PORT {port}")
httpd.serve_forever()
It's working fine. but i would :
Run a web sever exposing textplain content (and not Html content).
Set manually the workpath and name of index file (default: index.html)
keep Python server Code simple and light
I found some help on the web :
handler.extensions_map['Content-type'] = 'text/plain'
or
handler.send_header('Content-Type','text/plain')
But none os this proposition work.
Could you help me to build a simple python code to do this ?
Thanks a lot,
Script for Python 2 with using only built-in modules, just place the absolute path of the file which you want to be served <INSERT_FILE>:
#!/usr/bin/python
from SimpleHTTPServer import SimpleHTTPRequestHandler
import BaseHTTPServer
from io import StringIO
import sys
import os
class MyHandler(SimpleHTTPRequestHandler):
def send_head(self):
# Place here the absolute path of the file
with open("<INSERT_FILE>", "r") as f:
body = unicode("".join( f.readlines()))
self.send_response(200)
self.send_header("Content-type", "text/html; charset=UTF-8")
self.send_header("Content-Length", str(len(body)))
#self.send_header("Server", "SimpleHTTP/1.1 Python/2.7.5")
self.end_headers()
# text I/O binary, and raw I/O binary
# initial value must be unicode or None
return StringIO(body)
if __name__ == "__main__":
HandlerClass = MyHandler
ServerClass = BaseHTTPServer.HTTPServer
Protocol = "HTTP/1.1"
server_address = ('', 5555)
HandlerClass.protocol_version = Protocol
httpd = ServerClass (server_address, HandlerClass)
print("serving on port 5555")
httpd.serve_forever()
For python3 (SimpleHTTPServer module has been merged into http.server), place absolute path <INSERT_FILE>:
from http.server import HTTPServer, BaseHTTPRequestHandler
class SimpleHTTPRequestHandler(BaseHTTPRequestHandler):
def do_GET(self):
self.send_response(200)
self.end_headers()
# place absolute path here
f_served = open('<INSERT_FILE>','rb')
f_content = f_served.read()
f_served.close()
self.wfile.write(f_content)
if __name__ == "__main__":
httpd = HTTPServer(('localhost', 5555), SimpleHTTPRequestHandler)
httpd.serve_forever()
I recommend using aiohttp with its lowlevel server, which is described here:
You can either return plain text, or you change the content type of your web.Response to text/html to send data that will be interpreted as html.
You can just replace the "OK" in the text="OK" with whatever plain text you wish. Or you replace it with the content of your *.html and change the content_type.
import asyncio
from aiohttp import web
async def handler(request):
return web.Response(text="OK")
async def main():
server = web.Server(handler)
runner = web.ServerRunner(server)
await runner.setup()
site = web.TCPSite(runner, 'localhost', 8080)
await site.start()
print("======= Serving on http://127.0.0.1:8080/ ======")
# pause here for very long time by serving HTTP requests and
# waiting for keyboard interruption
await asyncio.sleep(100*3600)
loop = asyncio.get_event_loop()
try:
loop.run_until_complete(main())
except KeyboardInterrupt:
pass
loop.close()

BaseHTTPRequestHandler - Limit accepted range of IPs

I am using a python script to do my webserver using the BaseHTTPServer module. I would like to only accept requests from a specific range of IPs. How do I do that?
EDIT:
I've added an code example below. How do I use the X-Forwarded-For instead of self.client_address?
import time
import sys
import threading
from BaseHTTPServer import BaseHTTPRequestHandler,HTTPServer
from SocketServer import ThreadingMixIn
import urlparse
import json
from uuid import uuid4
from datetime import datetime
PORT_NUMBER = 8080
class myHandler(BaseHTTPRequestHandler):
def do_GET(self):
query_id = uuid4()
query = urlparse.parse_qs(urlparse.urlparse(self.path).query)
if not "q" in query or len(query["q"][0])==0:
self.send_error(404,'Query not found in %s' % self.path)
return
text = query["q"][0]
client_ip = self.client_address[0]
print("QUERY FROM {}: {}".format(client_ip, text))
class ThreadedHTTPServer(ThreadingMixIn, HTTPServer):
"""Handle requests in a separate thread."""
def main(_):
if not FLAGS.server:
print('please specify server host:port')
return
try:
server = ThreadedHTTPServer(('', PORT_NUMBER), myHandler)
print('Started httpserver on port %d' % PORT_NUMBER)
server.serve_forever()
except KeyboardInterrupt:
print('^C received, shutting down the web server')
server.socket.close()

Testing web server through linux terminal

I was just curious, how can I write a python test code so that I can test the GET/POST methods?
I am unable to figure out a way so that running the server and testing these methods can be done at the same time. Can someone help, thanks
from os import curdir
from os.path import join as pjoin
from http.server import BaseHTTPRequestHandler, HTTPServer
class StoreHandler(BaseHTTPRequestHandler):
store_path = pjoin(curdir, 'store.json')
def do_GET(self):
if self.path == '/store.json':
with open(self.store_path) as fh:
self.send_response(200)
self.send_header('Content-type', 'text/json')
self.end_headers()
self.wfile.write(fh.read().encode())
def do_POST(self):
if self.path == '/store.json':
length = self.headers['content-length']
data = self.rfile.read(int(length))
with open(self.store_path, 'w') as fh:
fh.write(data.decode())
self.send_response(200)
server = HTTPServer(('', 8080), StoreHandler)
server.serve_forever()
import requests
r = requests.get("http://127.0.0.1:8080/store.json")
print(r.status_code)
this will give back 200 as specified in your code

Multithreaded web server in python

I'm trying to create multithreaded web server in python, but it only responds to one request at a time and I can't figure out why. Can you help me, please?
#!/usr/bin/env python2
# -*- coding: utf-8 -*-
from SocketServer import ThreadingMixIn
from BaseHTTPServer import HTTPServer
from SimpleHTTPServer import SimpleHTTPRequestHandler
from time import sleep
class ThreadingServer(ThreadingMixIn, HTTPServer):
pass
class RequestHandler(SimpleHTTPRequestHandler):
def do_GET(self):
self.send_response(200)
self.send_header('Content-type', 'text/plain')
sleep(5)
response = 'Slept for 5 seconds..'
self.send_header('Content-length', len(response))
self.end_headers()
self.wfile.write(response)
ThreadingServer(('', 8000), RequestHandler).serve_forever()
Check this post from Doug Hellmann's blog.
from BaseHTTPServer import HTTPServer, BaseHTTPRequestHandler
from SocketServer import ThreadingMixIn
import threading
class Handler(BaseHTTPRequestHandler):
def do_GET(self):
self.send_response(200)
self.end_headers()
message = threading.currentThread().getName()
self.wfile.write(message)
self.wfile.write('\n')
return
class ThreadedHTTPServer(ThreadingMixIn, HTTPServer):
"""Handle requests in a separate thread."""
if __name__ == '__main__':
server = ThreadedHTTPServer(('localhost', 8080), Handler)
print 'Starting server, use <Ctrl-C> to stop'
server.serve_forever()
I have developed a PIP Utility called ComplexHTTPServer that is a multi-threaded version of SimpleHTTPServer.
To install it, all you need to do is:
pip install ComplexHTTPServer
Using it is as simple as:
python -m ComplexHTTPServer [PORT]
(By default, the port is 8000.)
In python3, you can use the code below (https or http):
from http.server import HTTPServer, BaseHTTPRequestHandler
from socketserver import ThreadingMixIn
import threading
USE_HTTPS = True
class Handler(BaseHTTPRequestHandler):
def do_GET(self):
self.send_response(200)
self.end_headers()
self.wfile.write(b'Hello world\t' + threading.currentThread().getName().encode() + b'\t' + str(threading.active_count()).encode() + b'\n')
class ThreadingSimpleServer(ThreadingMixIn, HTTPServer):
pass
def run():
server = ThreadingSimpleServer(('0.0.0.0', 4444), Handler)
if USE_HTTPS:
import ssl
server.socket = ssl.wrap_socket(server.socket, keyfile='./key.pem', certfile='./cert.pem', server_side=True)
server.serve_forever()
if __name__ == '__main__':
run()
You will figure out this code will create a new thread to deal with every request.
Command below to generate self-sign certificate:
openssl req -x509 -newkey rsa:4096 -nodes -out cert.pem -keyout key.pem -days 365
If you are using Flask, this blog is great.
It's amazing how many votes these solutions that break streaming are getting. If streaming might be needed down the road, then ThreadingMixIn and gunicorn are no good because they just collect up the response and write it as a unit at the end (which actually does nothing if your stream is infinite).
Your basic approach of combining BaseHTTPServer with threads is fine. But the default BaseHTTPServer settings re-bind a new socket on every listener, which won't work in Linux if all the listeners are on the same port. Change those settings before the serve_forever() call. (Just like you have to set self.daemon = True on a thread to stop ctrl-C from being disabled.)
The following example launches 100 handler threads on the same port, with each handler started through BaseHTTPServer.
import time, threading, socket, SocketServer, BaseHTTPServer
class Handler(BaseHTTPServer.BaseHTTPRequestHandler):
def do_GET(self):
if self.path != '/':
self.send_error(404, "Object not found")
return
self.send_response(200)
self.send_header('Content-type', 'text/html; charset=utf-8')
self.end_headers()
# serve up an infinite stream
i = 0
while True:
self.wfile.write("%i " % i)
time.sleep(0.1)
i += 1
# Create ONE socket.
addr = ('', 8000)
sock = socket.socket (socket.AF_INET, socket.SOCK_STREAM)
sock.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)
sock.bind(addr)
sock.listen(5)
# Launch 100 listener threads.
class Thread(threading.Thread):
def __init__(self, i):
threading.Thread.__init__(self)
self.i = i
self.daemon = True
self.start()
def run(self):
httpd = BaseHTTPServer.HTTPServer(addr, Handler, False)
# Prevent the HTTP server from re-binding every handler.
# https://stackoverflow.com/questions/46210672/
httpd.socket = sock
httpd.server_bind = self.server_close = lambda self: None
httpd.serve_forever()
[Thread(i) for i in range(100)]
time.sleep(9e9)
A multithreaded https server in python3.7
from http.server import BaseHTTPRequestHandler, HTTPServer
from socketserver import ThreadingMixIn
import threading
import ssl
hostName = "localhost"
serverPort = 8080
class MyServer(BaseHTTPRequestHandler):
def do_GET(self):
self.send_response(200)
self.send_header("Content-type", "text/html")
self.end_headers()
self.wfile.write(bytes("<html><head><title>https://pythonbasics.org</title></head>", "utf-8"))
self.wfile.write(bytes("<p>Request: %s</p>" % self.path, "utf-8"))
self.wfile.write(bytes("<p>Thread: %s</p>" % threading.currentThread().getName(), "utf-8"))
self.wfile.write(bytes("<p>Thread Count: %s</p>" % threading.active_count(), "utf-8"))
self.wfile.write(bytes("<body>", "utf-8"))
self.wfile.write(bytes("<p>This is an example web server.</p>", "utf-8"))
self.wfile.write(bytes("</body></html>", "utf-8"))
class ThreadingSimpleServer(ThreadingMixIn,HTTPServer):
pass
if __name__ == "__main__":
webServer = ThreadingSimpleServer((hostName, serverPort), MyServer)
webServer.socket = ssl.wrap_socket(webServer.socket, keyfile='./privkey.pem',certfile='./certificate.pem', server_side=True)
print("Server started http://%s:%s" % (hostName, serverPort))
try:
webServer.serve_forever()
except KeyboardInterrupt:
pass
webServer.server_close()
print("Server stopped.")
you can test it in a browser: https://localhost:8080
the running result is:
enter image description here
enter image description here
remind that you can generate your own keyfile and certificate use
$openssl req -newkey rsa:2048 -keyout privkey.pem -x509 -days 36500 -out certificate.pem
To learn details about creating self-signed certificate with openssl:https://www.devdungeon.com/content/creating-self-signed-ssl-certificates-openssl

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