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I am trying to figure out how to compare a string to the 0th element in the list (technically the bottom). The list is also a class instance and looks like this:
#define class called GEL
class GEL:
def __init__(self,eventtime,type):
self.eventtime=eventtime
self.type=type
myList=[]
And when I add something to the list:
myList.append(GEL(time,type)) ##Type can be either 'Arrival' or 'Departure'
For which the list will be (1.343432,'Arrival')
So I want to compare 'Arrival' with the type item in the list.
for i in range(5): ##loop for insertions and deletions
Type=[a.type for a in myList] ##Actually goes to the last type, but want first
if 'Arrival' in Type:
##DO STUFF
else:
##HELLO WORLD
#sortlist
myList.pop(0)
What would be the correct way just get the first type in the list?
Sorry for the poor jargon, am still learning Python.
EDIT: I think I may have solved. It gets me what I want. If anyone could tell me if this would be ok:
if 'Arrival' in Type[0]:
I think you just need this
if mylist[0].type == 'Arrival':
Related
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THE PROBLEM
Hi, I am currently learning python and opencv. I want to get only name of the dog species from the above pic, which removing the first 10 strings and numbers after the dog species.
For example:
[('n00000000-Maltese_dog', 252')] to 'Maltese_dog'.
I would appreciated if you can provide me any information of removing 'n' elements from tuple, or any help.
Thank you! Hope yall have a great day
Don't think of it in terms of removing items, think of extracting the data you want.
For each tuple, t, in the list take the first item t[0] and then take a slice of the string t[0][10:]. You can use a list comprehension to make a new list of all the strings:
l = [
('n00000000-Maltese_dog', '252'),
('n10030000-Australian terrier', '252')
]
[t[0][10:] for t in l]
# ['Maltese_dog', 'Australian terrier']
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Id codes at a company come in the form x-y-zzzzzz, where x is a digit and y is a letter and zzzzzz represents a string of 6 letters. Write a function which takes in a code as an input (e.g. 3-a-abaabb) and returns the zzzzzz part (e.g. abaabb).
I have no idea how to start and solve this question. any help would be much appreciated. My IDE is pycharm (solving python coding problems) I basically need to create a function which takes the code as an input and will return the last 6 letters
You can use str.spit('-') then search count in code with repeat is equal or not, like below:
def fnd_code(code):
repeat, char, search = code.split('-')
return search.count(char) == int(repeat)
print(fnd_code('3-a-abaabb'))
print(fnd_code('4-a-abaabb'))
Output:
True
False
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I'm doing a python project and I don't know how to turn a list into a variable.
Here is my code so far:
list = ['Name1']
I want to turn the list into a variable. Is there a way I can do it?
l = ['Name1']
name = l[0]
After this, name will be 'Name1'.
Yes, for example using astype():
variable_string = list.astype(str)
I don't think you can actually change a list to a 'variable' as a list is already a variable.
You have kind of two paths.
Somehow get the index of the variable you want to get and pass this into a variable
E.g. If I wanted a first object in the list I would do:
my_variable = list[0]
Just use the list index as your variable
print(list[0])
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import json
data = json.load(open("files1\data.json"))
def definitioner(w):
return data(w)
word = input("Enter the word you are looking for: ")
print(definitioner(word))
I am doing a course on UDEMY and after trying it myself it didn't work so I even copied the code to see if it was my code, couldn't figure out what the issue was, any help would be appreciated. I am running Python 3.8
Thanks.
You are calling data(w) like it's a function, but data is a dictionary. Use data.get(w) instead:
def definitioner(w):
return data.get(w)
That also allows you to specify what you would like returned by default if the word is not present, by adding a second argument:
def definitioner(w):
return data.get(w, 'Word not found!')
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I have a list of data that reads
[['name','emailtype','phonetype'],['john','yahoomail', 'mobile'],['mark','yahoo','landline']]
I can manually pick out the values i.e print dL[0][0] prints name and dL[1][0] emailtype.
Is it possible to isolate all the names from the list. i.e john and mark. With a program / module and then print them
and produce them into something like this:
1) John
2) Mark
so that I can ask for a raw_input and then if I press 1 as selection it produces john as the answer.
so that it reads similar to the nicely written data that I can manually type as above.
You want to slice the list (to ignore the first row), then use a list comprehension to pick out just the first element of each nested list:
[row[0] for row in nested_list[1:]]