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Python scraping HTTPError: 403 Client Error: Forbidden for url:

My python code used to work, but when I tried it today it did not work anymore.
I assume the website owner forbade non browsers requests recently.
code
import requests, bs4
res = requests.get('https://manga1001.com/日常-raw-free/')
res.raise_for_status()
print(res.text)
I read that adding header in the requests.get method may work, but I don't know which header info exactly I need to make it work.
error
---------------------------------------------------------------------------
HTTPError Traceback (most recent call last)
<ipython-input-15-ed1948d83d51> in <module>
3 # res = requests.get('https://manga1001.com/日常-raw-free/', headers=headers_dic)
4 res = requests.get('https://manga1001.com/日常-raw-free/')
----> 5 res.raise_for_status()
6 print(res.text)
7
~/opt/anaconda3/lib/python3.8/site-packages/requests/models.py in raise_for_status(self)
939
940 if http_error_msg:
--> 941 raise HTTPError(http_error_msg, response=self)
942
943 def close(self):
HTTPError: 403 Client Error: Forbidden for url: https://manga1001.com/%E6%97%A5%E5%B8%B8-raw-free/
Requests get a header argument
res = requests.get('https://manga1001.com/日常-raw-free/', headers="")
I think adding a proper value here could make it work, but I don't know what the value is.
I would really appreciate if you could tell you.
And if you know any other ways to make it work, that is also quite helpful.
Btw I have also tried the code below but it also didn't work.
code 2
from requests_html import HTMLSession
url = "https://search.yahoo.co.jp/realtime"
session = HTMLSession()
r = session.get(url)
r = r.html.render()
print(r)
FYI HTMLSession may not work on IDLE like Jupyter notebook so I tired it after saving it as a python file but it still did not work.

When I run first code without res.raise_for_status() then I can see in HTML with Why do I have to complete a CAPTCHA? and Cloudflare Ray ID which shows what is the problem. It uses Cloudflare to detect scripts/bots/hackers/spamers and it uses Captcha to check it. But if I use header 'User-Agent' with value from real browser or even with short 'Mozilla/5.0' then it get expected page.
It works for me with both pages.
import requests
headers = {
'User-Agent': 'Mozilla/5.0'
}
url = 'https://manga1001.com/日常-raw-free/'
#url = 'https://search.yahoo.co.jp/realtime'
res = requests.get(url, headers=headers)
print('status_code:', res.status_code)
print(res.text)
BTW:
If you will run it often for many links in short time then it may display again CAPTCHA and then you may need other methods to behave more like real human - ie. sleep() with random time, Session() to use cookies, first get main page (to get fresh cookies) and later get this page, add other headers.

I wanted to expand on the answer given by #Furas because I understand his fix will not be the solution in all cases. Yes, In this instance you're getting the 403 and Cloudflare/security captcha page when you make a request because of not "scoring" high enough on the security system (Your HTTP browser isn't similar enough to a real browser)
This creates a big question. What is a real browser and what score do I need to beat it? How do I increase my browser score and make my HTTP-request based browser look more real to the bot protection?
Firstly, it's important to understand that these 403/Security blocks are based on different levels on security. Something you do on one site may not work on the other due to different security configurations/version. Two sites may use the same security system and still the request you make may only work on one.
Why would they have different configurations and everyone not use the highest security available? Because with each additional security measure, there's more false-positives and challenges to pass, on a large scale or for an e-commerce store this can mean lost sales due to a poor user-experience or additional bugs/downtime which are introduced via the security program.
What is a real browser?
A real browser can perform SSL/TLS handshakes, parse and run Javascript and make TCP/requests. Along with this, the security programs will analyze the patterns and timings of everything from Layer 2 to see if you're a "real" human. When you use something like Python to make a request that is only performing a HTTP(s) request it's really easy for these security programs to recognise you as a bot without some heavy configuration.
One way that security systems combat bots is by putting a Javascript challenge as a proxy between the bot and a site, this requires running client-side Javascript which bots cannot do by default, not only do you need to run the client-side Javascript, it also needs to be similar to one that your own browser would generate, the challenge can typically consist of a few hundred individual "browser" challenges or/along with a manual captcha to fingerprint and track your browser to see if you're a human (This is the page you're seeing).
The typical and more lower-standard security systems/configurations can be beaten by using the correct headers (with capitalization, header order and HTTP versions. Like #Furas mentioned, using consistent sessions can also help create longer-lasting sessions before getting another 403. More advanced and higher-level security configurations can do tracking on lower-levels by looking at some flags (Such as WindowSize) of the TCP connection and JA3 fingerprinting analyzing the TLS handshake which will look at your cipher suites and ALPN amongst other things. Security systems can see characteristics which differentiate between browsers, browser-versions and operating systems and compare these all together to generate your realness score. Your IP can also be an important factor, requests can be cross-checked with other sites, intervals, older requests you tried before and much more, you can use proxies to divide your requests between and look less suspicious, but this can come with additional problems and affect your request also causing it to be fingerprinted and blocked.
To understand this better, here's a great site you can go to in your browser and also make a GET request to, check your browser "Rank" and look at the different values which can be seen just from the TLS request alone.
I hope this provides some insight into why a block might appear, although it's impossible to tell from a single URL since blocks can appear for such a variety of different reasons.

How do I get URLs that are being accessed in my browser in 'real time'?

I want to write a program that returns the current or last visited URL by me on my computer (Windows 10) browser. Is there any way in which I can get that URL?
I tried using Python and SQLite to access Chrome history database on C:\Users%USERNAME%\AppData\Local\Google\Chrome\User Data\Default\History and it worked, but if I'm using the browser, the database gets locked.
I know that by using Wireshark, one can see the packets when accessing an URL, but I cannot find the complete URL in those packets fields, only the server name (ie: stackoverflow.com).
I'd like to know whether there is a way in which I can see that information as it's done by Wireshark, but only to get the complete URL, nothing else. Thank you!

I found a solution to this by using mitmproxy: https://mitmproxy.org/. This video on YouTube helped me with the installation and setup process: https://www.youtube.com/watch?v=7BXsaU42yok. The video explains the installation on Mac, but it's not so different from Windows. Then you can use Python to capture and process the URLs contained within the HTTPS requests by using the flow.request.pretty_url property: https://docs.mitmproxy.org/stable/addons-scripting/.

Unable to get complete source code of web page using Python [duplicate]

I would like to try send requests.get to this website:
requests.get('https://rent.591.com.tw')
and I always get
<Response [404]>
I knew this is a common problem and tried different way but still failed.
but all of other website is ok.
any suggestion?

Webservers are black boxes. They are permitted to return any valid HTTP response, based on your request, the time of day, the phase of the moon, or any other criteria they pick. If another HTTP client gets a different response, consistently, try to figure out what the differences are in the request that Python sends and the request the other client sends.
That means you need to:
Record all aspects of the working request
Record all aspects of the failing request
Try out what changes you can make to make the failing request more like the working request, and minimise those changes.
I usually point my requests to a http://httpbin.org endpoint, have it record the request, and then experiment.
For requests, there are several headers that are set automatically, and many of these you would not normally expect to have to change:
Host; this must be set to the hostname you are contacting, so that it can properly multi-host different sites. requests sets this one.
Content-Length and Content-Type, for POST requests, are usually set from the arguments you pass to requests. If these don't match, alter the arguments you pass in to requests (but watch out with multipart/* requests, which use a generated boundary recorded in the Content-Type header; leave generating that to requests).
Connection: leave this to the client to manage
Cookies: these are often set on an initial GET request, or after first logging into the site. Make sure you capture cookies with a requests.Session() object and that you are logged in (supplied credentials the same way the browser did).
Everything else is fair game but if requests has set a default value, then more often than not those defaults are not the issue. That said, I usually start with the User-Agent header and work my way up from there.
In this case, the site is filtering on the user agent, it looks like they are blacklisting Python, setting it to almost any other value already works:
>>> requests.get('https://rent.591.com.tw', headers={'User-Agent': 'Custom'})
<Response [200]>
Next, you need to take into account that requests is not a browser. requests is only a HTTP client, a browser does much, much more. A browser parses HTML for additional resources such as images, fonts, styling and scripts, loads those additional resources too, and executes scripts. Scripts can then alter what the browser displays and load additional resources. If your requests results don't match what you see in the browser, but the initial request the browser makes matches, then you'll need to figure out what other resources the browser has loaded and make additional requests with requests as needed. If all else fails, use a project like requests-html, which lets you run a URL through an actual, headless Chromium browser.
The site you are trying to contact makes an additional AJAX request to https://rent.591.com.tw/home/search/rsList?is_new_list=1&type=1&kind=0&searchtype=1&region=1, take that into account if you are trying to scrape data from this site.
Next, well-built sites will use security best-practices such as CSRF tokens, which require you to make requests in the right order (e.g. a GET request to retrieve a form before a POST to the handler) and handle cookies or otherwise extract the extra information a server expects to be passed from one request to another.
Last but not least, if a site is blocking scripts from making requests, they probably are either trying to enforce terms of service that prohibit scraping, or because they have an API they rather have you use. Check for either, and take into consideration that you might be blocked more effectively if you continue to scrape the site anyway.

One thing to note: I was using requests.get() to do some webscraping off of links I was reading from a file. What I didn't realise was that the links had a newline character (\n) when I read each line from the file.
If you're getting multiple links from a file instead of a Python data type like a string, make sure to strip any \r or \n characters before you call requests.get("your link"). In my case, I used
with open("filepath", 'w') as file:
links = file.read().splitlines()
for link in links:
response = requests.get(link)

In my case this was due to fact that the website address was recently changed, and I was provided the old website address. At least this changed the status code from 404 to 500, which, I think, is progress :)

Python - Capture auto-downloading file from aspx web page

I'm trying to export a CSV from this page via a python script. The complicated part is that the page opens after clicking the export button on this page, begins the download, and closes again, rather than just hosting the file somewhere static. I've tried using the Requests library, among other things, but the file it returns is empty.
Here's what I've done:
url = 'http://aws.state.ak.us/ApocReports/CampaignDisclosure/CDExpenditures.aspx?exportAll=True&amp%3bexportFormat=CSV&amp%3bisExport=True%22+id%3d%22M_C_sCDTransactions_csfFilter_ExportDialog_hlAllCSV?exportAll=True&exportFormat=CSV&isExport=True'
with open('CD_Transactions_02-27-2017.CSV', "wb") as file:
# get request
response = get(url)
# write to file
file.write(response.content)
I'm sure I'm missing something obvious, but I'm pulling my hair out.

It looks like the file is being generated on demand, and the url stays only valid as long as the session lasts.
There are multiple requests from the browser to the webserver (including POST requests).
So to get those files via code, you would have to simulate the browser, possibly including session state etc (and in this case also __VIEWSTATE ).
To see the whole communication, you can use developer tools in the browser (usually F12, then select NET to see the traffic), or use something like WireShark.
In other words, this won't be an easy task.
If this is open government data, it might be better to just ask that government for the data or ask for possible direct links to the (unfiltered) files (sometimes there is a public ftp server for example) - or sometimes there is an API available.

The file is created on demand but you can download it anyway. Essentially you have to:
Establish a session to save cookies and viewstate
Submit a form in order to click the export button
Grab the link which lies behind the popped-up csv-button
Follow that link and download the file
You can find working code here (if you don't mind that it's written in R): Save response from web-scraping as csv file

How do you open a URL with Python without using a browser?

I want to open a URL with Python code but I don't want to use the "webbrowser" module. I tried that already and it worked (It opened the URL in my actual default browser, which is what I DON'T want). So then I tried using urllib (urlopen) and mechanize. Both of them ran fine with my program but neither of them actually sent my request to the website!
Here is part of my code:
finalURL="http://www.locationary.com/access/proxy.jsp?ACTION_TOKEN=proxy_jsp$JspView$SaveAction&inPlaceID=" + str(newPID) + "&xxx_c_1_f_987=" + str(ZA[z])
print finalURL
print ""
br.open(finalURL)
page = urllib2.urlopen(finalURL).read()
When I go into the site, locationary.com, it doesn't show that any changes have been made! When I used "webbrowser" though, it did show changes on the website after I submitted my URL. How can I do the same thing that webbrowser does without actually opening a browser?
I think the website wants a "GET"

I'm not sure what OS you're working on, but if you use something like httpscoop (mac) or fiddler (pc) or wireshark, you should be able to watch the traffic and see what's happening. It may be that the website does a redirect (which your browser is following) or there's some other subsequent activity.
Start an HTTP sniffer, make the request using the web browser and watch the traffic. Once you've done that, try it with the python script and see if the request is being made, and what the difference is in the HTTP traffic. This should help identify where the disconnect is.

A HTTP GET doesn't need any specific code or action on the client side: It's just the base URL (http://server/) + path + optional query.
If the URL is correct, then the code above should work. Some pointers what you can try next:
Is the URL really correct? Use Firebug or a similar tool to watch the network traffic which gives you the full URL plus any header fields from the HTTP request.
Maybe the site requires you to log in, first. If so, make sure you set up cookies correctly.
Some sites require a correct "referrer" field (to protect themselves against deep linking). Add the referrer header which your browser used to the request.
The log file of the server is a great source of information to trouble shoot such problems - when you have access to it.