I'm developing my first app in Django and facing some issues. The server runs smoothly and I can operate the admin panel without any issues.
However, all of the app pages including the default homepage show a "404 not found" error.
I have created a templates directory in project root
updated this line in settings.py for templates,
'DIRS': [os.path.join(BASE_DIR,'templates')],
View for the app
from django.shortcuts import render
from .models import *
# Create your views here.
def customers(request):
customers = Customer.objects.all()
return render(request, "customers.html", {'customers': customers})
urls for the app
from django.urls import path from . import views
urlpatterns = [path('customers',views.customers, name='customers')]
urls for the project
from django.contrib import admin from django.urls import path, include from django.conf import settings from django.conf.urls.static import static
urlpatterns = [
path('trips/',include('trips.urls')),
path('customers/',include('customers.urls')),
path('drivers/',include('drivers.urls')),
path('vehicles/',include('vehicles.urls')),
path('admin/', admin.site.urls), ]
urlpatterns = urlpatterns + static(settings.MEDIA_URL, document_root=settings.MEDIA_ROOT)
Help is appreciated
I can't see any problem with your case, you should be able to load http://localhost:8000/customers/customers. Maybe double customers was not you intention, then remove one of them (one in main urls.py one in app's).
Also when Django debug mode is active and you get a 404 because of URL mismatch, it shows you a list of URLs you have. To see it navigate to a non existing URL like http://localhost:8000/aaa. Then if you see customers/ there try http://localhost:8000/customers/. Go step by step to find the problem.
I am new to python django. I am facing an issue while passing parameter to view through URL in django.
code:
views.py
from django.shortcuts import render
from django.http import HttpResponse
def hello(request):
text = "HEllo"
return HttpResponse(text)
def viewArticle(request, articleId):
text = "HEllo : %d"%articleId
return HttpResponse(text)
urls.py
from django.conf.urls import url
from django.urls import path,include
from myapp import views
urlpatterns = [
path('hello/',views.hello,name='hello'),
path('article/(\d
+)/',views.viewArticle,name='article'),
]
image:
you need to change your url like this:
path('article/<int:articleId>/',views.viewArticle,name='article'),
Hope this work!
Here your are using path. And path uses route without regex.
You need to change url to,
path('article/<int:articleId>/',views.viewArticle,name='article'),
I am not able to map html files from the directory, however i've followed all the instructions.
Following is my project urls.py:-
from django.conf.urls import patterns, include, url
# Uncomment the next two lines to enable the admin:
# from django.contrib import admin
# admin.autodiscover()
urlpatterns = patterns('',
url(r'^articles/', include('article.urls')),
)
Views.py in app:-
from django.shortcuts import render_to_response
from article.models import Article
def articles(request):
return render_to_response('articles.html',{'articles':
Article.objects.all()})
def article(request, article_id=1):
return render_to_response('article.html',{'article':
Article.objects.get(id=article_id)})
Urls.py in app:
from django.conf.urls import patterns, include, url
urlpatterns = patterns('',
url(r'^all/$', 'artilce.views.articles'),
url(r'^get/(?P<article_id>\d+)/$', 'article.view.article'),
)
Settings.py shows exact location of template folder as:-
TEMPLATE_DIRS = (
'C:\Python27\Scripts\django_test\article\templates',
Kindly advise. It shows article on 404 page but couldn't map.
You need to use unix-style forward slashes for your path, even on Windows. See the doc page here: https://docs.djangoproject.com/en/1.6/ref/settings/#template-dirs
I am trying to use Django's account system, including the #login_required decorator. My settings.py file includes django.contrib.auth and I have done a syncdb.
Page not found (404)
Request Method: GET
Request URL: http://localhost:8000/accounts/login/?next=/
Using the URLconf defined in dashboard.urls, Django tried these URL patterns, in this order:
^$ [name='home']
The current URL, accounts/login/, didn't match any of these.
You're seeing this error because you have DEBUG = True in your Django settings file. Change that to False, and Django will display a standard 404 page.
I see the above after trying to #login_required-decorate my home view.
It seems to be choking because it is redirected to accounts/login/, which I have not prepared for in my urls.py.
What can I add to urls.py or elsewhere so that the login_required decorator will do its usual behaviour?
Thanks,
Set the LOGIN_URL in your settings. The default value is '/accounts/login/'
The decorator also takes an optional login_url argument:
#login_required(login_url='/accounts/login/')
And, from the docs:
Note that if you don’t specify the login_url parameter, you’ll need to
ensure that the settings.LOGIN_URL and your login view are properly
associated. For example, using the defaults, add the following line to
your URLconf:
(r'^accounts/login/$', 'django.contrib.auth.views.login'),
path('accounts/login/', admin.site.urls),
Add this line in your urls.py project folder. Then it will work fine.
from django.contrib.auth.decorators import login_required
#login_required(login_url='/accounts/login/')
Add above two lines in your views.py file.
What worked for me in Django 2.2.1 - include re_path('^accounts/', admin.site.urls), in my project urls.py:
urls.py
from django.conf import settings
from django.conf.urls import include
from django.conf.urls import re_path
from django.conf.urls.static import static
from django.contrib import admin
from django.urls import path
urlpatterns = [
path('admin/', admin.site.urls),
re_path('^accounts/', admin.site.urls),
]
And in my views.py:
views.py
from django.contrib.auth.decorators import login_required
from django.views.generic import TemplateView
#method_decorator(login_required, name='dispatch')
class HomePageView(TemplateView):
"""
Home Page View
"""
template_name = 'amp/home.html'
Hope that helps.
UPDATE: To avoid warnings from django in regards to admin urls being loaded twice, I used a redirect instead in urls.py:
urls.py
urlpatterns = [
re_path('^accounts/', admin.site.urls),
re_path(r'^admin/', RedirectView.as_view(url='/accounts/', permanent=True))
]
More on redirect view here.
Following the tutorial found here exactly, I cannot create a custom 500 or 404 error page. If I do type in a bad url, the page gives me the default error page. Is there anything I should be checking for that would prevent a custom page from showing up?
File directories:
mysite/
mysite/
__init__.py
__init__.pyc
settings.py
settings.pyc
urls.py
urls.pyc
wsgi.py
wsgi.pyc
polls/
templates/
admin/
base_site.html
404.html
500.html
polls/
detail.html
index.html
__init__.py
__init__.pyc
admin.py
admin.pyc
models.py
models.pyc
tests.py
urls.py
urls.pyc
view.py
views.pyc
templates/
manage.py
within mysite/settings.py I have these enabled:
DEBUG = False
TEMPLATE_DEBUG = DEBUG
#....
TEMPLATE_DIRS = (
'C:/Users/Me/Django/mysite/templates',
)
within mysite/polls/urls.py:
from django.conf.urls import patterns, url
from polls import views
urlpatterns = patterns('',
url(r'^$', views.index, name='index'),
url(r'^(?P<poll_id>\d+)/$', views.detail, name='detail'),
url(r'^(?P<poll_id>\d+)/results/$', views.results, name='results'),
url(r'^(?P<poll_id>\d+)/vote/$', views.vote, name='vote'),
)
I can post any other code necessary, but what should I be changing to get a custom 500 error page if I use a bad url?
Under your main views.py add your own custom implementation of the following two views, and just set up the templates 404.html and 500.html with what you want to display.
With this solution, no custom code needs to be added to urls.py
Here's the code:
from django.shortcuts import render_to_response
from django.template import RequestContext
def handler404(request, *args, **argv):
response = render_to_response('404.html', {},
context_instance=RequestContext(request))
response.status_code = 404
return response
def handler500(request, *args, **argv):
response = render_to_response('500.html', {},
context_instance=RequestContext(request))
response.status_code = 500
return response
Update
handler404 and handler500 are exported Django string configuration variables found in django/conf/urls/__init__.py. That is why the above config works.
To get the above config to work, you should define the following variables in your urls.py file and point the exported Django variables to the string Python path of where these Django functional views are defined, like so:
# project/urls.py
handler404 = 'my_app.views.handler404'
handler500 = 'my_app.views.handler500'
Update for Django 2.0
Signatures for handler views were changed in Django 2.0:
https://docs.djangoproject.com/en/2.0/ref/views/#error-views
If you use views as above, handler404 will fail with message:
"handler404() got an unexpected keyword argument 'exception'"
In such case modify your views like this:
def handler404(request, exception, template_name="404.html"):
response = render_to_response(template_name)
response.status_code = 404
return response
Official answer:
Here is the link to the official documentation on how to set up custom error views:
https://docs.djangoproject.com/en/stable/topics/http/views/#customizing-error-views
It says to add lines like these in your URLconf (setting them anywhere else will have no effect):
handler404 = 'mysite.views.my_custom_page_not_found_view'
handler500 = 'mysite.views.my_custom_error_view'
handler403 = 'mysite.views.my_custom_permission_denied_view'
handler400 = 'mysite.views.my_custom_bad_request_view'
You can also customise the CSRF error view by modifying the setting CSRF_FAILURE_VIEW.
Default error handlers:
It's worth reading the documentation of the default error handlers, page_not_found, server_error, permission_denied and bad_request. By default, they use these templates if they can find them, respectively: 404.html, 500.html, 403.html, and 400.html.
So if all you want to do is make pretty error pages, just create those files in a TEMPLATE_DIRS directory, you don't need to edit URLConf at all. Read the documentation to see which context variables are available.
In Django 1.10 and later, the default CSRF error view uses the template 403_csrf.html.
Gotcha:
Don't forget that DEBUG must be set to False for these to work, otherwise, the normal debug handlers will be used.
Add these lines in urls.py
urls.py
from django.conf.urls import (
handler400, handler403, handler404, handler500
)
handler400 = 'my_app.views.bad_request'
handler403 = 'my_app.views.permission_denied'
handler404 = 'my_app.views.page_not_found'
handler500 = 'my_app.views.server_error'
# ...
and implement our custom views in views.py.
views.py
from django.shortcuts import (
render_to_response
)
from django.template import RequestContext
# HTTP Error 400
def bad_request(request):
response = render_to_response(
'400.html',
context_instance=RequestContext(request)
)
response.status_code = 400
return response
# ...
Django 3.0+ 4.0+
here is link how to customize error views
here is link how to render a view
in the urls.py (the main one, in project folder), put:
handler404 = 'my_app_name.views.custom_page_not_found_view'
handler500 = 'my_app_name.views.custom_error_view'
handler403 = 'my_app_name.views.custom_permission_denied_view'
handler400 = 'my_app_name.views.custom_bad_request_view'
and in the mentioned app (my_app_name) put in the views.py:
def custom_page_not_found_view(request, exception):
return render(request, "errors/404.html", {})
def custom_error_view(request, exception=None):
return render(request, "errors/500.html", {})
def custom_permission_denied_view(request, exception=None):
return render(request, "errors/403.html", {})
def custom_bad_request_view(request, exception=None):
return render(request, "errors/400.html", {})
NOTE: errors/404.html is the path if you place your files into the projects (not the apps) template foldertemplates/errors/404.html so please place the files where you want and write the right path.
NOTE 2: After page reload, if you still see the old template, change in settings.py DEBUG=True, save it, and then again to False and save again (that will restart the server and collect the new files).
From the page you referenced:
When you raise Http404 from within a view, Django will load a special view devoted to handling 404 errors. It finds it by looking for the variable handler404 in your root URLconf (and only in your root URLconf; setting handler404 anywhere else will have no effect), which is a string in Python dotted syntax – the same format the normal URLconf callbacks use. A 404 view itself has nothing special: It’s just a normal view.
So I believe you need to add something like this to your urls.py:
handler404 = 'views.my_404_view'
and similar for handler500.
If all you need is to show custom pages which have some fancy error messages for your site when DEBUG = False, then add two templates named 404.html and 500.html in your templates directory and it will automatically pick up this custom pages when a 404 or 500 is raised.
In Django 3.x, the accepted answer won't work because render_to_response has been removed completely as well as some more changes have been made since the version the accepted answer worked for.
Some other answers are also there but I'm presenting a little cleaner answer:
In your main urls.py file:
handler404 = 'yourapp.views.handler404'
handler500 = 'yourapp.views.handler500'
In yourapp/views.py file:
def handler404(request, exception):
context = {}
response = render(request, "pages/errors/404.html", context=context)
response.status_code = 404
return response
def handler500(request):
context = {}
response = render(request, "pages/errors/500.html", context=context)
response.status_code = 500
return response
Ensure that you have imported render() in yourapp/views.py file:
from django.shortcuts import render
Side note: render_to_response() was deprecated in Django 2.x and it has been completely removed in verision 3.x.
No additional view is required. https://docs.djangoproject.com/en/3.0/ref/views/
Just put the error files in the root of templates directory
404.html
400.html
403.html
500.html
And it should use your error page when debug is False
settings.py:
DEBUG = False
TEMPLATE_DEBUG = DEBUG
ALLOWED_HOSTS = ['localhost'] #provide your host name
and just add your 404.html and 500.html pages in templates folder.
remove 404.html and 500.html from templates in polls app.
In Django 2.* you can use this construction in views.py
def handler404(request, exception):
return render(request, 'errors/404.html', locals())
In settings.py
DEBUG = False
if DEBUG is False:
ALLOWED_HOSTS = [
'127.0.0.1:8000',
'*',
]
if DEBUG is True:
ALLOWED_HOSTS = []
In urls.py
# https://docs.djangoproject.com/en/2.0/topics/http/views/#customizing-error-views
handler404 = 'YOUR_APP_NAME.views.handler404'
Usually i creating default_app and handle site-wide errors, context processors in it.
Make an error, on the error page find out from where django is loading templates. I mean the path stack. In base template_dir add these html pages 500.html , 404.html. When these errors occur the respective template files will be automatically loaded.
You can add pages for other error codes too, like 400 and 403.
As one single line (for 404 generic page):
from django.shortcuts import render_to_response
from django.template import RequestContext
return render_to_response('error/404.html', {'exception': ex},
context_instance=RequestContext(request), status=404)
# views.py
def handler404(request, exception):
context = RequestContext(request)
err_code = 404
response = render_to_response('404.html', {"code":err_code}, context)
response.status_code = 404
return response
# <project_folder>.urls.py
handler404 = 'todo.views.handler404'
This works on django 2.0
Be sure to include your custom 404.html inside the app templates folder.
Try moving your error templates to .../Django/mysite/templates/.
I am note sure about this one, but I think these need to be "global" to the website.
In Django root urls.py file, add the below lines
from django.conf.urls import (handler400, handler403, handler404, handler500)
handler400 = 'app.views.bad_request'
handler403 = 'app.views.permission_denied'
handler404 = 'app.views.page_not_found'
handler500 = 'app.views.server_error'
In your app's views.py file, create the respective functions.
def server_error(request, exception=None):
# return render(request, '500.html')
return redirect('/')
Finally, in your settings.py file, set DEBUG = False
I had an additional
TEMPLATE_DIRS
within my settings.py and that was causing the problem.
This answer was posted as an edit to the question Django, creating a custom 500/404 error page by the OP reZach under CC BY-SA 3.0.
In urls.py, enter this code:
from django.conf.urls import (handler400, handler403, handler404, handler500)
handler404 = 'my_app.views.page_not_found_view'
then add this code in your views.py
from django.shortcuts import render,get_object_or_404
def page_not_found_view(request, exception):
return render(request, '404.html', status=404)
Dont forget to set DEBUG = False and also set ALLOWED_HOSTS = [127.0.0.1] while you are testing in your laptop.
You don't need to do anything fancy, just create a 404.html file in your templates. Go to settings.py and set:
DEBUG = False
ALLOWED_HOSTS = ["*"]
It will automatically overwrite the default.
Django > 2.2
from django.shortcuts import render_to_response, render
from django.template import RequestContext
def handler500(request, *args, **argv):
context = {}
print(request.body, '==========')
response = render(request, '500.jinja', context=context)
response.status_code = 500
return response
in urls.py
handler500 = 'apps.core.views.handler500'