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The pseudocode is like this:
def a_func(parent_node, child_node):
parent_node.add(child_node)
// check validity
return child_node
node1 = a_func(pnode, Node(attr_x = "a new node")
node2 = a_func(pnode, Node(node1.get_attr("attr_x"))
It's used in tree structure. a_func insert nodeX into a parent nodeY and return nodeX. Does anyone have ideas about a suitable name for it?
I would name the function something like enlistForParent or maybe addToParent or even setParentForNode I believe all these versions imply that the return value is the child note and also make the effect of calling the function clear.
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I have code:
def users_list_reaction(users_dict, prefix_dictionary, event):
login = event.widget.get()
prefix_str = users_dict.get(f'{login}')
for i in prefix_str[0]:
if i == ' ':
pass
else:
for x in i:
prefix_dictionary[x].select()
But I only need to pass two of the three arguments. I have error TypeError: users_list_reaction() missing 1 required keyword-only argument: 'event'. None how answer will not help, because the event is a tkinter library widget and it is needed to get information from the combobox. I don't want use global users_dict . What to do?
I tried to search for information on the Internet, but I don’t understand how to formulate it correctly, because I didn’t find an answer to mine
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This is the current code, tried to print but it return None..can some1 enlightened me how to do it?
def calculate(Amount1, Amount2):
def inner(square,cube):
square=Amount1**2
cube=Amount2**3
return (inner(Amount1,Amount2))
print(calculate(2,4))
Expected result (4,64)
def calculate(Amount1, Amount2):
def inner(square,cube):
square=Amount1**2
cube=Amount2**3
return((square, cube))
return (inner(Amount1,Amount2))
print(calculate(2,4))
you forgot to return the values from your inner function
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This is a simplified example. But basically, I have function within a function. I want to pass the argument from the top-level function to the embedded function, but it doesn't work. How do I solve this?
Thank you
def Check(file_name, mh_criticalval):
test_file=file_name
def eval_value(excel_sht, excel_col, mh_value):
if excel_sht.cell(row=i, column=excel_col) > mh_value:
cell_cny_b=excel_sht.cell(
row=i,
column=excel_col
).value='OK'
eval_value(sht, 9, mh_criticalval)
Check('test.xlsm',1)
Method 1: De-Nesting
The most obvious method here is to remove the nested functions. Doing this is simple:
def eval_mh(excel_sht, excel_col, mh_value):
if excel_sht.cell(row=i, column=excel_col)>mh_value:
cell_cny_b=excel_sht.cell(row=i, column=excel_col).value='OK'
def CheckDiag(file_name, mh_criticalval):
test_file=file_name
eval_mh(sht, 9, mh_criticalval)
CheckDiag('test.xlsm',1)
All we did here was move the inner function out. However, if you still wanted them to be nested, try the following.
Method 2: Local/Global Variable Exploitation
Here, we replace all instances of mh_value with mh_criticalval
def CheckDiag(file_name, mh_criticalval):
test_file=file_name
def eval_mh(excel_sht, excel_col):
if excel_sht.cell(row=i, column=excel_col)>mh_criticalval:
cell_cny_b=excel_sht.cell(row=i, column=excel_col).value='OK'
eval_mh(sht, 9)
CheckDiag('test.xlsm',1)
Method 3: Why 2 functions?
In this method, we remove the function entirely!
def CheckDiag(file_name, mh_criticalval):
test_file=file_name
if sht.cell(row=i, column=9)>mh_criticalval:
cell_cny_b=sht.cell(row=i, column=9).value='OK'
eval_mh(sht, 9)
CheckDiag('test.xlsm',1)
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here I want to call web service function only once throughout the program.
how to accomplish this anybody suggest me
import sys,os
def web_service(macid):
# do something
if "__name__" = "__main__" :
web_service(macid)
This is how I would to that:
i_run_once_has_been_run = False
def i_run_once(macid):
global i_run_once_has_been_run
if i_run_once_has_been_run:
return
# do something
i_run_once_has_been_run = True
#Vaulstein's decorator function would work too, and may even be a bit more pythonic - but it seems like a bit overkill to me.
Using class,
class CallOnce(object):
called = False
def web_service(cls, macid):
if cls.called:
print "already called"
return
else:
# do stuff
print "called once"
cls.called = True
return
macid = "123"
call_once_object = CallOnce()
call_once_object.web_service(macid)
call_once_object.web_service(macid)
call_once_object.web_service(macid)
Result is,
I have no name!#sla-334:~/stack_o$ python once.py
called once
already called
already called
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The snippet of code is below. I want my object name to be equal to element[0]. My scripts successfully generates the objects, but fails to 'name them' I cannot understand why.
master_inventory = []
def import_catalogue():
with open("./catalogue.txt", "r") as raw_catalogue:
for page in raw_catalogue:
page = page.split('\r')
for line in page:
element = line.split('\t\t\t')
element[0] = Antique(element[0], element[1], element[2], element[3], element[4], element[5], element[6], element[7], element[8], element[9])
master_inventory.append(element[0])
import_catalogue()
print master_inventory[1]
>>> <__main__.Antique instance at 0x10980f320>
print master_inventory[1].sku
>>> A00001
You should implement the __str__ function in the Antique class, so you choose how you want to display your object's name. e.g.:
class Antique():
…
def __str__(self):
return "Antique({},{},{})".format(self.foo, self.bar, self.foobar)
…