I have a text widget in my python Tkinter script and i am trying to get the value that the user enter. My intention is to write the data from the text widget together with other values from the script(ie. x,y,z) to the txt file(faultlog.txt) as a single line with semi-column separated. This is what i tried.
...
text=Text(width=30,height=1)
text.place(x=15,y=75)
data=text.get(1.0,END)
lines=[]
lines.append('{};{};{};{} \n'.format(data,x,y,z))
faultlog=open("faultlog","a")
faultlog.writelines(lines)
faultlog.close()
...
Instead of giving me a single line output in the text file, python is writing this to the txt file (assuming the data that user enter is "abcdefgh")
abcdefgh
;x;y;z
just to make things clear, this is what i want
abcdefgh;x;y;z
What did i do wrong? I hope the question is clear enough, i am a beginner so please make the answer simple.
When you get all text of the widget, there is also included a "\n" at the end. You can remove this last character like this:
data=text.get(1.0,END)[:-1]
Note that this always works independently of the length of the text length:
>>> "\n"[:-1]
''
>>> ""[:-1]
''
Related
I am trying to create a Twitter bot that posts a random line from a text file. I have gone as far as generating the random lines, which print one at a time, and giving the bot access to my Twitter app, but I can't for the life of me figure out how to use a printed line as a status.
I am using Tweepy. My understanding is that I need to use api.update_status(status=X), but I don't know what X needs to be for the status to match the most recently printed line.
This is the relevant section of what I have so far:
from random import choice
x = 1
while True:
file = open('quotes.txt')
content = file.read()
lines = content.splitlines()
print(choice(lines))
api.update_status(status=(choice(lines)))
time.sleep(3600)
The bot is accessing Twitter no problem. It is currently posting another random quote generated by (choice(lines)), but I'd like it to match what prints immediately before.
I may not fully understand your question, but from the very top, where it says, "How to use the most recently printed line as an input", I think I can answer that. Whenever you use the print() command, store the argument into a string variable that overwrites its last value. Then it saves the last printed value.
Instead of directly printing a choice:
print(choice(lines))
create a new variable and use it in your print() and your api.update_status():
selected_quote = choice(lines)
print(selected_quote)
api.update_status(status=selected_quote)
I'm using Python 2.7, Windows 7, and Word 2003. Those three cannot change (well except for maybe the python version). I work in Law and the attorneys have roughly 3 boiler plate objections (just a large piece of text, maybe 5 paragraphs) that need to be inserted into a word document at a specific spot. Now instead of going through and copying and pasting the objection where its needed, my idea is for the user to go through the document adding a special word/phrase (place holder if you will) that wont be found anywhere in the document. Then run some code and have python fill in the rest. Maybe not the cleverest way to go about it, but I'm a noob. I've been practicing with a test page and inserted the below text as place holders (the extra "o" stands for objection)
oone
otwo
othree
Below is what I have so far. I have two questions
Do you have any other suggestions to go about this?
My code does insert the string in the correct order, but the formatting goes out the window and it writes in my string 6 times instead of 1. How can I resolve the formatting issue so it simply writes the text into the spot the place holder is at?
import sys
import fileinput
f = open('work.doc', 'r+')
obj1 = "oone"
obj2 = "otwo"
obj3 = "othree"
for line in fileinput.input('work.doc'):
if obj1 in line:
f.write("Objection 1")
elif obj2 in line:
f.write("Objection 2")
elif obj3 in line:
f.write("Objection 3")
else:
f.write("No Objection")
f.close
You could use python-uno to load the document into OpenOffice and manipulate it using the UNO interface. There is some example code on the site I just linked to which can get you started.
I created a word document which contains the text
Hello. You owe me ${debt}. Please pay me back soon.
in Times New Roman size 12. The file name is debtTemplate.docx. I would like to replace {debt} by an actual number (1.20) using python-docx. I tried that following code:
from docx import Document
document = Document("debtTemplate.docx")
paragraphs = document.paragraphs
debt = "1.20"
paragraph = paragraphs[0]
text = paragraph.text
newText = text.format(debt=debt)
paragraph.clear()
paragraph.add_run(newText)
document.save("debt.docx")
This results in a new document with the desired text, but in Calabri font size 11. I would like the font to be like the original: Times New Roman size 12.
I know that you can add a style variable to paragraph.add_run(), so I tried that but nothing work. Eg paragraph.add_run(newText,style="Strong") didn't even change anything.
Does anyone know what I can do?
EDIT: here's a modified version of my code that I had hoped would work but didn't.
from docx import Document
document = Document("debtTemplate.docx")
document.save("debt.docx")
paragraphs = document.paragraphs
debt = "1.20"
paragraph = paragraphs[0]
style = paragraph.style
text = paragraph.text
newText = text.format(debt=debt)
paragraph.clear()
paragraph.add_run(newText,style)
document.save("debt.docx")
This page in the docs should help you understand why the style is not having an effect. It's a pretty easy fix: http://python-docx.readthedocs.org/en/latest/user/styles.html
I like a couple other things about what you've found though:
Using the str.format() method to do placeholder replacement is a nice, easy way to do lightweight text replacement. I'll have to add that to the documentation as an approach to simple custom document generation.
In the XML for a paragraph, there is an optional element called <w:defRPr> which Word uses to indicates the default formatting for any new text added to the paragraph, like if you started typing after placing your insertion point at the end of the paragraph. Right now, python-docx ignores that element. That's why you're getting the default Calibri 11 instead of the Times New Roman 12 you started with. But a useful feature might be to use that element, if present, to assign run properties to any new runs added at the end of the paragraph. If you want to add that as a feature request to the GitHub tracker we'll take a look at getting it implemented.
I am trying to learn to use Whoosh. I have a large collection of html documents I want to search. I discovered that the text_content() method creates some interesting problems for example I might have some text that is organized in a table that looks like
<html><table><tr><td>banana</td><td>republic</td></tr><tr><td>stateless</td><td>person</td></table></html>
When I take the original string and and get the tree and then use text_content to get the text in the following manner
mytree = html.fromstring(myString)
text = mytree.text_content()
The results have no spaces (as should be expected)
'bananarepublicstatelessperson'
I tried to insert new lines using string.replace()
myString = myString.replace('</tr>','</tr>\n')
I confirmed that the new line was present
'<html><table><tr><td>banana</td><td>republic</td></tr>\n<tr><td>stateless</td><td>person</td></table></html>'
but when I run the same code from above the line feeds are not present. Thus the resulting text_content() looks just like above.
This is a problem from me because I need to be able to separate words, I thought I could add non-breaking spaces after each td and line breaks after rows as well asd line breaks after body elements etc to get text that reasonably conforms to my original source.
I will note that I did some more testing and found that line breaks inserted after paragraph tag closes were preserved. But there is a lot of text in the tables that I need to be able to search.
Thanks for any assistance
You could use this solution:
import re
def striphtml(data):
p = re.compile(r'<.*?>')
return p.sub('', data)
>>> striphtml('I Want This <b>text!</b>')
>>> 'I Want This text!'
Found here: using python, Remove HTML tags/formatting from a string
I'm trying to read text from a .ssv file and put them into variables so that I can submit them to an html web form.
The first piece of text is the the name of a survey, while the following pieces of text (can be any number) are questions. How can I accomplish my goal using python?
Thanks.
My data is like this:
survey1,question1,question2,question3,question4,...
I want to read those into an html form.
The answer so far tells me how to get the variables stored into python, but how would I send those to the html < form>? I'm looking online everywhere but don't really see how it's done. A link to a page telling me how, or an explanation would be amazing.
Added tags
It is hard to tell from your question what it is that you want precisely, however you should use open. Here is an example:
#filename.txt
survey1,question1,question2,question3,question4
survey2,question1,question2,question3,question4
survey3,question1,question2,question3,question4
survey4,question1,question2,question3,question4
survey5,question1,question2,question3,question4
#your_script.py
values = []
with open('filename.txt', 'r') as f:
for line in f: #splits on ',' as per your question example
line = line.split(',')
values.append((line[0],line[1:]))
>>> print(values)
[
(survey1,[question1,question2,question3,question4])
(survey2,[question1,question2,question3,question4])
(survey3,[question1,question2,question3,question4])
(survey4,[question1,question2,question3,question4])
(survey5,[question1,question2,question3,question4])
]
Then if you want to get the fourth question for the third survey, you can do:
values[2][3]
and then you can pass that to your html form. Preferably using a for loop for passing all the values.
OR
survey_1_questions = values[0]