So I am writting a program that inputs a 3 # digit and breaks it apart. I am having trouble figuring out how to then add the separate digits altogether?
For example: The user inputs 345
My program will break the #'s apart to 3,4,5 but how do I then add those numbers together?
this is my code thus far,
#set variable
val = raw_input("Type your three digit number please: ")
print 'The first digit is {}'.format(val[0])
print 'The second digit is {}'.format(val[1])
print 'The third digit is {}'.format(val[2])
#set variable
total = [val[0] +val [1] + val[2]]
total_value = total
print 'The sum of the three digits is' total_value
A short way to add all of the number's digits together is:
In [3]: sum(map(int, val))
Out[3]: 12
Here, map(int, val) iterates over the characters of val and converts each of them into an int, and sum(...) adds together all those ints.
The nice thing about this approach is that it works for any number of digits.
The reason your original code doesn't work is that val[0] etc are strings, so using + simply concatenates those strings back together. To add the numeric values, you would have to convert the characters to int first:
In [5]: int(val[0]) + int(val[1]) + int(val[2])
Out[5]: 12
You have to convert the individual components to numbers to be able to add them:
total = int(val[0]) + int(val[1]) + int(val[2])
Or, more concise:
total = sum(int(x) for x in val)
An elegant solution is to use python's builtin functions map and sum:
val = raw_input("Type your three digit number please: ")
total = sum(map(int, val))
print 'The sum of the three digits is', total
You just have to do this :
total = int(val[0]) + int(val[1]) + int(val[2])
Since the digits in val are characters, they have to be converted to integers first.
Note that there are no [ ] around the value affected to total as in your code (you don't want a list, you want a single value).
Try this:
res = raw_input("Enter value: ")
print sum(map(int, res))
i think the answer you looking for is something like this:
a = int(input("3 digit number:"))
x = a // 100
y = a // 10 % 10
z = a % 10
print (x + y + z)
i'm a total noob and its an ez question for noobs learning but when looking for an ez answer i couldn't find it anywhere (here) The question is Adding the sum of "THREE" digits...
I got hung up on if the digits were 5 or 6 long dunno what the code would look like if digits weren't defined.
answer:
a = int(input("enter a few numbers:"))
conversion = str(a)
number =[]
for i in conversion:
a = int(i)
number.append(a)
print (sum(number))
or as shown before me:
number = map(int, str(input('Enter a number: ')))
print(sum(number))
but i still have a ways to goes till i understand this properly
Related
This question already has answers here:
How to print something a specific number of times based on user input?
(3 answers)
Closed 1 year ago.
The code is supposed to print :) based on the number inputted (an integer 1 to 10). With any positive integer, the code is supposed to print that many smiley faces (ex. if 5 is entered, 5 smiley faces should be printed).
It's required that the code should use += to add onto the end of a string and should also decrement to count down and use a loop.
x = input("enter number 1 to 10: ")
for i in len(x):
print(":) " * x)
I don't think you can multiply int values and str values, and I can't find another way to do this.
First things first, input() function returns a string. You want x to be an integer, use the int() function:
x = int(input("enter number 1 to 10: "))
Second You can either use a for loop or the multiplication operator to print n number of smileys.
# Using for loop to print n smileys :
x = int(input("enter number 1 to 10: "))
for i in range(x):
print(":) ",end="")
# Using multiplication operator :
x = int(input("enter number 1 to 10: "))
print(":) "*x)
# x should be an integer
x = int(input("enter number 1 to 10: "))
# define "s" as an empty string
s = ''
# increment ":)" to "s" x times
for _ in range(x):
s += ':)'
print(s)
You're almost there! In fact, you can multiply string and integer values. This code does what you described:
print(':) '*int(input("Enter number 1 to 10: ")))
If you really want to use a for loop and +=, you could also do this
x, s = input("enter number 1 to 10: "), ''
for i in range(x):
s += ':) '
print(s)
Answer: How to print a string x times based on user input
Credits to: NoobCoder33333
times = input('Enter number from 1 to 10: ')
word = ":-)"
print('\n'.join([word] * int(times)))
I wish to create a Function in Python to calculate the sum of the individual digits of a given number
passed to it as a parameter.
My code is as follows:
number = int(input("Enter a number: "))
sum = 0
while(number > 0):
remainder = number % 10
sum = sum + remainder
number = number //10
print("The sum of the digits of the number ",number," is: ", sum)
This code works up until the last print command where I need to print the original number + the statement + the sum. The problem is that the original number changes to 0 every time (the sum is correct).
How do I calculate this but also show the original number in the print command?
Keep another variable to store the original number.
number = int(input("Enter a number: "))
original = number
# rest of the code here
Another approach to solve it:
You don't have to parse the number into int, treat it as a str as returned from input() function. Then iterate each character (digit) and add them.
number = input("Enter a number: ")
total = sum(int(d) for d in number)
print(total)
You can do it completely without a conversion to int:
ORD0 = ord('0')
number = input("Enter a number: ")
nsum = sum(ord(ch) - ORD0 for ch in number)
It will compute garbage, it someone enters not a number
number = input("Enter a number: ")
total = sum((int(x) for x in list(number)))
print("The sum of the digits of the number ", number," is: ", total)
As someone else pointed out, the conversion to int isn't even required since we only operate a character at a time.
I'm working on a problem that involves putting in an input, integer n, that when doing so will print off the following 4 "multiples" of the integer. I need to do this for 3 integers, n = 5, n = 0, n = 3.
Original Question:
Implement a program that requests a positive
integer n from the user and prints the first four multiples of n: Test
your module for n = 5; n = 0 and n = 3.
The output of the code should look like:
>>>
Enter n: 5
5
10
15
20
So, what I've come up with so far is this
n = (input("Enter n:"))
This allows me to input an integer value.
Next using print(n), this will print the value I input (Ex. number 5), but I'm not sure how to print off multiples of it after. I realize it's a loop question, most likely involving if or in, but I'm not sure where to go after this.
You've pretty much figured out the question on your own. The correct code is:
n = int(input("Enter n:"))
for i in range(4):
print(n*(i+1))
So, what this for loop does for you is repeat your print statement 4 times, where you give i the values of the expression range(4).
If you just print(range(4)), you'll see that it evaluates to [0,1,2,3]. That's why I had to add 1 to it each time.
The int() function call is needed because input() returns a string, not a number. So if we want the mathematical operators to do what we expect, we need to first convert it to a number (in this case, an integer).
This is the general logic:
n = (input("enter n:"))
for(int i = 1; i <= 4; i++){
print(int(float((n))*i);
}
if you want the list to start with 0 you can do this, it has an error but it can be fixed...
number = int(input("Give a number:"))
for multiples in range(10):
getal1 = number * multiples
print("\t The", str(multiples + 1) + "e multiple of," + number, "is", str(getal1) + ".")
Ok, so I've got a couple issues with a program (for school again) that I'm using to add up all the digits of a number. I've got some of the program down, except 2 things. First, how to use a variable (thelength below) in replacement of a number to call a specific digit of the input (I'm not sure if this is even possible, but it would be helpful). And second, how to add up different numbers in a string. Any ideas?
Here's what I have so far:
number = str(int(input("Please type a number to add up: ")))
length = len(number)
thelength = 0
total = 0
thenumbers = []
while thelength < length:
#The issue is me trying to use thelength in the next two lines, and the fact that number is now a string
total += number[thelength]
thenumbers.append(number[thelength])
thelength += 1
for num in thenumbers:
print(num[0])
print("+")
print("___")
print(total)
Thanks for any help I can get!
I don't know what "call a specific digit of the input" means, but the error in your code is here:
total += number[thelength]
total is an int, and you're trying to add a string to it, convert the digit to an integer first.
total += int(number[thelength])
Result:
1
2
3
+
___
6
import re
import sys
INPUT_VALIDATOR = re.compile("^[0-9]+$")
input_str = input("Please type a natural number to add up: ")
if INPUT_VALIDATOR.match(input_str) is None:
print ("Your input was not a natural number (a positive whole number greater or equal to zero)!")
print ("This displeases me, goodbye puny human.")
sys.exit(1)
total = 0
for digit_str in input_str:
print(digit_str)
total += int(digit_str)
print("+")
print("___")
print(total)
If you don't need to print the digits as you go, it's even easier:
# (Add the same code as above to get and validate the input string)
print(sum(int(digit_str) for digit_str in input_str))
number = int(input("Please type a number to add up: "))
total = 0
while number > 0:
total += number % 10
total /= 10
print(total)
num % 10 pretty much gets the last digit of a number
then we divide it by 10 to truncate the number by its last digit
we can loop through the number as long as it's above 0 and take the digital sum by using the method outlined above
Every thing that you need is convert the digits to int and sum them :
>>> s='1247'
>>> sum(map(int,s))
14
But as you get the number from input it could cause a ValueErorr , for refuse that you can use a try-except :
try :
print sum(map(int,s))
except ValueErorr :
print 'please write a valin number :'
Also if you are using python 2 use raw_input for get the number or if you are using python 3 just use input because the result of both is string !
I am currently using Python to create a program that accepts user input for a two digit number and will output the numbers on a single line.
For Example:
My program will get a number from the user, lets just use 27
I want my program to be able to print "The first digit is 2" and "The second digit is 7"
I know I will have to use modules (%) but I am new to this and a little confused!
Try this:
val = raw_input("Type your number please: ")
for i, x in enumerate(val, 1):
print "#{0} digit is {1}".format(i, x)
It was not clear from your question whether you are looking to use % for string substitution, or % for remainder.
For completeness, the mathsy way using modulus operator on ints would look like this:
>>> val = None
>>> while val is None:
... try:
... val = int(raw_input("Type your number please: "))
... except ValueError:
... pass
...
Type your number please: potato
Type your number please: 27
>>> print 'The first digit is {}'.format(val // 10)
The first digit is 2
>>> print 'The second digit is {}'.format(val % 10)
The second digit is 7
Think about the two digit number as though it were a string. It is easier to grab each digit this way. Using str() will change the integer to a string. Modulos allow you to place these strings into your text.
Assuming the user inputs 27 into the variable called num, the code is:
print 'The first digit is %s and the second digit is %s' % (str(num)[0], str(num)[1])
Another way of coding Python:
val = raw_input("Type your number please: ")
for i in list(val):
print i
Note: val is read as string. For integer manipulation, use list(str(integer-value)) instead
two_digit_number = input("Type a two digit number: ")
print("The first digit is " + two_digit_number[0] + " The second digit is " +
two_digit_number[1])
You don't need modules to solve this question.