Develop Reference

How do I write the time from datetime to a file in Python?

I'm trying to have my Python code write everything it does to a log, with a timestamp. But it doesn't seem to work.
this is my current code:
filePath= Path('.')
time=datetime.datetime.now()
bot_log = ["","Set up the file path thingy"]
with open ('bot.log', 'a') as f:
f.write('\n'.join(bot_log)%
datetime.datetime.now().strftime("%d-%b-%Y (%H:%M:%S.%f)"))
print(bot_log[0])
but when I run it it says:
Traceback (most recent call last):
File "c:\Users\Name\Yuna-Discord-Bot\Yuna Discord Bot.py", line 15, in <module>
f.write('\n'.join(bot_log)%
TypeError: not all arguments converted during string formatting
I have tried multiple things to fix it, and this is the latest one. is there something I'm doing wrong or missing? I also want the time to be in front of the log message, but I don't think it would do that (if it worked).

You need to put "%s" somewhere in the input string before string formatting. Here's more detailed explanation.
Try this:
filePath= Path('.')
time=datetime.datetime.now()
bot_log = "%s Set up the file path thingy\n"
with open ('bot.log', 'a') as f:
f.write(bot_log % datetime.datetime.now().strftime("%d-%b-%Y (%H:%M:%S.%f)"))
print(bot_log)

It looks like you want to write three strings to your file as separate lines. I've rearranged your code to create a single list to pass to writelines, which expects an iterable:
filePath= Path('.')
time=datetime.datetime.now()
bot_log = ["","Set up the file path thingy"]
with open ('bot.log', 'a') as f:
bot_log.append(datetime.datetime.now().strftime("%d-%b-%Y (%H:%M:%S.%f)"))
f.writelines('\n'.join(bot_log))
print(bot_log[0])
EDIT: From the comments the desire is to prepend the timestamp to the message and keep it on the same line. I've used f-strings as I prefer the clarity they provide:
import datetime
from pathlib import Path
filePath = Path('.')
with open('bot.log', 'a') as f:
time = datetime.datetime.now()
msg = "Set up the file path thingy"
f.write(f"""{time.strftime("%d-%b-%Y (%H:%M:%S.%f)")} {msg}\n""")
You could also look at the logging module which does a lot of this for you.

Python script that executes another python script

I'm pretty new to the world of python. I decided to do a project but came to a stop, after my script wouldn't execute the right way. In which I mean the script that I need to be executed on its own through another script keeps on giving me nothing or some syntax error instead of all the stuff that is supposed to be happening (converting files). The other script in question writes new lines into the other script to change the file name (to be converted) to the newest file. The file looks something like this:
import glob
import os.path
folder_path = r'C:\User\Desktop\Folder\Audio'
file_type = r'\*mp4'
files = glob.glob(folder_path + file_type)
max_file = max(files, key=os.path.getctime)
mp3_file = max_file.replace('.mp4', '')
with open ("file.py", 'w') as f:
f.write("")
with open ("file.py", 'w') as f:
f.write('from moviepy.editor import *\n' "mp4_file = '{}'\n"
"mp3_file = '{}.mp3'\n" 'videoclip = VideoFileClip(mp4_file)\n' 'audioclip = videoclip.audio\n'
'audioclip.write_audiofile(mp3_file)\n' 'audioclip.close()\n' 'videoclip.close()\n'.format(max_file, mp3_file))
exec(open("file.py").read())
Right now it gives this error:
Traceback (most recent call last):
File "C:\Users\Desktop\Folder\Audio\File Manager.py", line 19, in <module>
exec(open("file.py").read())
File "<string>", line 2
mp4_file = 'C:\User\Desktop\Folder\Audio\test.mp4'
^
SyntaxError: (unicode error) 'unicodeescape' codec can't decode bytes in position 2-3: truncated \UXXXXXXXX escape
I plan not on using that exact line of code to execute my python file since there are many alternatives, but if I was on the right trail, then I might as well. The other file that's supposed to be executed has generic file converting code:
from moviepy.editor import *
mp4_file = 'C:\User\Desktop\Folder\Audio\test.mp4'
mp3_file = 'C:\User\Desktop\Folder\Audio\test.mp3'
videoclip = VideoFileClip(mp4_file)
audioclip = videoclip.audio
audioclip.write_audiofile(mp3_file)
audioclip.close()
videoclip.close()
Other solutions mostly gave me a blank inactive shell; if the answer to this problem that it's impossible, then it might as well be, and I'll take that as a valid answer, but please explain why.

Corrections
You are using different quotes while writing to the file, from single quotes ' to double ", update it to be more consistent.
The error is suggesting that while writing to the file it is also writing some unicode characters which it cannot read hence the unicode error (look at where the carrot ^ is pointing at, it's a blank space since it's not a printable character).
Suggestions
Don't just write to a file and then immediately read from it. Different operating systems have different behaviour for such repeated access which will give you strange issues (this is not your issue tho)
Just create a function extractMp3FromVideoFile which takes two arguements max_file and mp3_file
Instead of writing to a file and increasing the HDD IO simply put the file's code into a variable and then exec it.
Solution
import glob
import os.path
folder_path = r'C:\User\Desktop\Folder\Audio'
file_type = r'\*mp4'
files = glob.glob(folder_path + file_type)
max_file = max(files, key=os.path.getctime)
mp3_file = max_file.replace('.mp4', '')
code = "from moviepy.editor import *\nmp4_file = '{}'\nmp3_file = '{}.mp3'\nvideoclip = VideoFileClip(mp4_file)\naudioclip = videoclip.audio\naudioclip.write_audiofile(mp3_file)\naudioclip.close()\nvideoclip.close()\n".format(max_file, mp3_file)
exec(code)

Korean txt file encoding with utf-8

I'm trying to process a Korean text file with python, but it fails when I try to encode the file with utf-8.
#!/usr/bin/python
#-*- coding: utf-8 -*-
f = open('tag.txt', 'r', encoding='utf=8')
s = f.readlines()
z = open('tagresult.txt', 'w')
y = z.write(s)
z.close
=============================================================
Traceback (most recent call last):
File "C:\Users\******\Desktop\tagging.py", line 5, in <module>
f = open('tag.txt', 'r', encoding='utf=8')
TypeError: 'encoding' is an invalid keyword argument for this function
[Finished in 0.1s]
==================================================================
And when I just opens a Korean txt file encoded with utf-8, the fonts are broken like this. What can I do?
\xc1\xc1\xbe\xc6\xc1\xf6\xb4\xc2\n',
'\xc1\xc1\xbe\xc6\xc7\xcf\xb0\xc5\xb5\xe7\xbf\xe4\n',
'\xc1\xc1\xbe\xc6\xc7\xcf\xbd\xc3\xb4\xc2\n',
'\xc1\xcb\xbc\xdb\xc7\xd1\xb5\xa5\xbf\xe4\n',
'\xc1\xd6\xb1\xb8\xbf\xe4\

I don't know Korean, and don't have sample string to try, but here are some advices for you:
1
f = open('tag.txt', 'r', encoding='utf=8')
You have a typo here, utf-8 not utf=8, this explains for the exception you got.
The default mode of open() is 'r' so you don't have to define it again.
2 Don't just use open, you should use context manager statement to manage the opening/closing file descriptor, like this:
with open('tagresult.txt', 'w') as f:
f.write(s)

In Python 2 the open function does not take an encoding parameter. Instead you read a line and convert it to unicode. This article on kitchen (as in kitchen sink) modules provides details and some lightweight utilities to work with unicode in python 2.x.

Python 3 bytecode format

I want to read a .pyc file. However, I cannot find any documentation on the format.
The only one I found does not work for Python 3 (although it does for Python 2):
>>> f = open('__pycache__/foo.cpython-34.pyc', 'rb')
>>> f.read(4)
b'\xee\x0c\r\n'
>>> f.read(4)
b'\xf8\x17\x08W'
>>> marshal.load(f)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
ValueError: bad marshal data (unknown type code)
marshal only consumes one byte: \x00, which indeed is not a valid first character for marshall (as a comparison, the first byte of Python 2 bytecode for the same empty module is c)
So, how can I decode what comes after the header?

Try this. It worked a while back. They added another int32 in v3.
def load_file(self, source):
if isinstance(source, str):
import os.path
if not os.path.exists(source):
raise IOError("Cannot load_file('"
+ source
+ "'): does not exist")
with open(source, "rb") as fh:
header_bytes = fh.read(12)
# ignore header
self.code = marshal.load(fh)
return self.code

Have you looked at the dissembler?
https://docs.python.org/3/library/dis.html

Python file open from path containing numbers

i have the following problem during file open:
Using PyQt QFileDialog I get path for files from user which I would like to read it
def read_file(self):
self.t_file = (QFileDialog.getOpenFileNames(self, 'Select File', '','*.txt'))
Unfortunately I cannot open a file if the path has numbers in it:
Ex:
'E:\test\02_info\test.txt'
I tried
f1 = open(self.t_file,'r')
Could anyone help me to read files from such a path format?
Thank you in advance.
EDIT:
I get the following error:
Traceback (most recent call last):
File "<pyshell#27>", line 1, in <module>
f1 = open(self.t_file,'r')
IOError: [Errno 22] invalid mode ('r') or filename: 'E:\test\x02_info\test.txt'

The problem is caused by your use of getOpenFileNames (which returns a list of files) instead of getOpenFileName (which returns a single file). You also seem to have converted the return value wrongly, but since you haven't shown the relevant code, I will just show you how it should be done (assuming you are using python2):
def read_file(self):
filename = QFileDialog.getOpenFileName(self, 'Select File', '','*.txt')
# convert to a python string
self.t_file = unicode(filename)