Djangonic way to get second order DB-info in Django? - python

I'm messing around with my first Django site and so far it's going good. I am now facing the challenge of getting some information from the DB. My model looks like this:
class Countries(models.Model):
country = models.CharField(max_length=100)
def __unicode__(self):
return self.country
class OrganisationTypes(models.Model):
organisation_type = models.CharField(max_length=100)
def __unicode__(self):
return self.organisation_type
class Organisations(models.Model):
organisation_name = models.CharField(max_length=200)
organisation_type = models.ForeignKey(OrganisationTypes)
country_of_origin = models.ForeignKey(Countries)
def __unicode__(self):
return self.organisation_name
class Locations(models.Model):
organisation = models.ForeignKey(Organisations)
country_of_location = models.ForeignKey(Countries)
tel_nr = models.CharField(max_length=15)
address = models.CharField(max_length=100)
def __unicode__(self):
return '%s - %s - %s - %s' % (self.organisation, self.country_of_location, self.tel_nr, self.address)
I now want to display a list of locations of which I want to display the organisation_name and the country_of_origin. To achieve this I wrote the following function:
def organisation_locations(requests, organisation_id):
org = Organisations.objects.get(id=organisation_id)
location_list = Locations.objects.filter(organisation=organisation_id).order_by('country_of_location')
output = '<br />'.join([str(loc.organisation)+' from '+str(org.country_of_origin) for loc in location_list])
return HttpResponse(output)
This works correctly, but it doesn't seem like the correct way of doing this. Since the Location table has a foreign key in the Organisations table which in turn has a foreign key in the Countries table I have this vague feeling that Django can do this in one "query" or lookup.
Am I correct in this feeling, or is my way indeed the correct way of doing this? All tips are welcome!

Can't you do:
location_list = Locations.objects\
.filter(organisation=organisation_id)\
.order_by('country_of_location')
output = '<br />'.join([str(loc.organisation)+' from '+str(loc.organisation.country_of_origin) for loc in location_list])
The organisation query isn't necessary. You can access organisation like this: localization.organisation.
What is not Djangonic in your code is the response. You should have a template and do return render_to_response :)

Related

NameError in Django simple search

I have a simple search in my Django project. I want to search through documents using their type and part of factory info in addition to search by name.
Here is my models.py:
class Docs(models.Model):
Date = models.DateField(default=date.today)
Name = models.CharField(max_length=50)
Type = models.ForeignKey(DocTypes)
Part = models.ForeignKey(Parts)
Link = models.FileField(upload_to='Docs/%Y/%m/%d')
class Parts(models.Model):
Name = models.CharField(max_length=50)
def __str__(self):
return str(self.Name)
class DocTypes(models.Model):
Type = models.CharField(max_length=50)
def __str__(self):
return str(self.Type)
My forms.py:
class DocsSearchForm(ModelForm):
class Meta:
model = Docs
fields = [ 'Name', 'Type', 'Part']
And this is part of my views.py, if no search was done then all documents are given
def showdocs(request):
if request.method == 'POST':
form = DocsSearchForm(request.POST)
documents = Docs.objects.filter(Name__contains=request.POST['Name']|
Type==request.POST['Type']|
Part==request.POST['Part'])
else:
form = DocsSearchForm()
documents = Docs.objects.all()
return render(
request,
'showdocs.html',
{'documents': documents, 'form':form}
So, the problem is the following: if I try to use a search then I have
NameError at /showdocs
name 'Type' is not defined.
POST values are:Part '1', Name 'Example', Type '1'.
If I delete
Type==request.POST['Type']|
Part==request.POST['Part']
then search by name works well. So I have a guess that problem is about searching by foreign key values, but have no ideas more. Will appreciate any help.
Try replacing the line with this
Docs.objects.filter(Name__contains=request.POST['Name'],
Type=request.POST['Type'],
Part=request.POST['Part']
)
It seems you have misunderstood the syntax. I don't know why you are trying to use | operator here.
That's not how Django filters work. You can't | them because they are not actually expressions, just keyword arguments. In this case, correct syntax would be:
Docs.objects.filter(
Name__contains=request.POST['Name'],
Type_Type=request.POST['Type'],
Part_Name=request.POST['Part'],
)`

How to filter object in django models?

I have write down A model to store data. like this.
class Country(models.Model):
Countryname = models.CharField(max_length=200)
def __unicode__(self):
return self.Countryname
class CountryDiseases(models.Model):
country = models.ForeignKey(Country,on_delete=models.CASCADE)
pmid = models.CharField(default= 'No Data',max_length=254)
serogroup = models.CharField(default= 'No Data', max_length=254)
serotype = models.CharField(default= 'No Data', max_length=254)
biotype = models.CharField(default= 'No Data',max_length=254)
collection_year = models.CharField(default= 'No Data',max_length=254)
NoOfStrains = models.CharField(default= 'No Data', max_length=254)
def __unicode__(self):
return self.NoOfStrains
A url to render data like this:
url(r'^DATAPLO/(?P<pk>\d)/$', views.County_Details, name='County_Details'),
In short, i have a template that contains country list with a hyperlink,
when some one click on a country it should produce a list of all the data associated with the particular country like the given urls,
http://127.0.0.1:8000/DATAPLO/india
where "India" keyword will transferred to the given views and view will extract all the object through filter method:
C_Details = CountryDiseases.objects.filter(country__country=pk)
A view to extract and present data like this:
def County_Details(request,pk):
C_Details = CountryDiseases.objects.filter(country__country=pk)
#C_Details = CountryDiseases.objects.filter(country='india')
return render(request, 'DATAPLO/Country_Details.html', {'C_Details': C_Details})
it produces the urld like this:
http://127.0.0.1:8000/DATAPLO/india
http://127.0.0.1:8000/DATAPLO/USA
http://127.0.0.1:8000/DATAPLO/canada
but data has not been extracted.
I would probably change the name of the parameter (in the view and in the urls.py) to something like country_name, as country.pk is usually configured to return the same as country.id. And for the sake of convention I would change the name of the name field on the country to name rather than Countryname.
class Country(models.Model):
name = models.CharField(max_length=200)
def __unicode__(self):
return self.name
Then in your view, you can look up the CountryDiseases objects by the name field on the related Country model:
def County_Details(request, country_name):
C_Details = CountryDiseases.objects.filter(country__name=country_name)
return render(request, 'DATAPLO/Country_Details.html', {'C_Details': C_Details})
Or if you want to look up the country first, as well as the details, because you may have other information stored on the country model, then you can change the CountryDiseases lookup to reference the Country object directly:
def County_Details(request, country_name):
country = Country.objects.get(name=country_name)
C_Details = CountryDiseases.objects.filter(country=country)
return render(request, 'DATAPLO/Country_Details.html', {'C_Details': C_Details})
PS if capitalisation is going to be an issue, such as with 'india' vs 'India', you can use the lookup:
.filter(country__name__iexact=country_name) (for in the first code example) or
.get(name__iexact=country_name) (in the second, but there also you should ensure that you don't have clashes when saving the objects, as you're making a .get() query).

Django - cannot retrieve just one record in multi-part filter on model with multiple relations

I can't seem to isolate a single record from this query:
subcust = OwnerCustom.objects.get(carcustom=ncset, owner=sset)
This is the error:
OwnerCustom matching query does not exist
In the actual data, there is only actually one matching record in OwnerCustom for each record in CarCustom. It's supposed to be a kind of many-to-many where there are standard differences listed in CarCustom for each Car, and each owner may maintain their own customizations (overrides) or those default OwnerCustom entries.
Note, there are many different Owner of the same Car. And of course, I'm not actually doing cars, this is a renaming from the original purpose.
Here's the relevant models:
class Car(models.Model):
car_name = models.CharField(max_length=50)
class CarCustom(models.Model):
car = models.ForeignKey(Car, models.PROTECT)
class Owner(models.Model):
car = models.ForeignKey(Car, models.PROTECT)
class OwnerCustom(models.Model):
owner = models.ForeignKey(Owner, models.PROTECT)
carcustom = models.ForeignKey(CarCustom, models.PROTECT)
name = models.CharField(max_length=50)
And the code:
car_queryset = Car.objects.filter(car_name="fancy car")
for nset in car_queryset:
owner_queryset = Owner.objects.filter(car=nset)
for sset in owner_queryset :
carcustom_queryset = CarCustom.objects.filter(car=nset)
for ncset in carcustom_queryset:
subcust = OwnerCustom.objects.get(carcustom=ncset, owner=sset)
I've tried stuff like:
subcust = OwnerCustom.objects.filter(carcustom=ncset, owner=sset).first()
Which gives me a NoneType, and then tried:
subcust = OwnerCustom.objects.filter(carcustom=ncset, owner=sset)[:1].get()
Which gives "matching query does not exist" and this:
subcust = OwnerCustom.objects.filter(carcustom=ncset, owner=sset)[0]
Gives "list index out of range"
UPDATE: I CAN get a working function by using code like this, but I would think since there is only one (guaranteed by application) matching record possible for OwnerCustom.objects.filter(carcustom=ncset, owner=sset) that I could find a better way to fetch it:
car_queryset = Car.objects.filter(car_name="fancy car")
for nset in car_queryset:
owner_queryset = Owner.objects.filter(car=nset)
for sset in owner_queryset :
carcustom_queryset = CarCustom.objects.filter(car=nset)
for ncset in carcustom_queryset:
subcust_queryset = OwnerCustom.objects.filter(carcustom=ncset, owner=sset)
for subcust in subcust_queryset :
logger.info(subcust.name)

Django - filtering in views

I am working on an basic application and I`m stuck at a displaying some info.
Please take a look:
Models:
class Companies(models.Model):
name = models.CharField()
address = models.CharField()
def __unicode__(self):
return self.name
class Payments(models.Model):
company = models.ForeignKey(Companies)
year = models.CharField(choices=YEAR)
month = models.CharField(choices=MONTHS)
date = models.DateField(auto_now_add=True)
I want a view in which to display ONLY the companies that did not pay the monthly fee.
So I`ve started like this:
def checks(request):
i = datetime.datetime.now()
an_c = i.strftime('%Y')
comp = Companies.objects.all()
pay1 = Payments.objects.filter(an=an_c, month='01')
But in the template I do not know how to filter the "comp" list.
I want to display in the template all the records from "comp" except that ones with the id/pk which can be find in the "pay1.company"
You wouldn't do that in the template. Do the whole thing in the view:
pay1 = Payments.objects.filter(an=an_c, month='01')
comp = Companies.objects.exclude(payments__in=pay1)
(Style note: Django model classes are usually named in the singular, not the plural.)

Finding objects without relationship in django

I am learning Django, and want to retrieve all objects that DON'T have a relationship to the current object I am looking at.
The idea is a simple Twitter copycat.
I am trying to figure out how to implement get_non_followers.
from django.db import models
RELATIONSHIP_FOLLOWING = 1
RELATIONSHIP_BLOCKED = 2
RELATIONSHIP_STATUSES = (
(RELATIONSHIP_FOLLOWING, 'Following'),
(RELATIONSHIP_BLOCKED, 'Blocked'),
)
class UserProfile(models.Model):
name = models.CharField(max_length=200)
website = models.CharField(max_length=200)
email = models.EmailField()
relationships = models.ManyToManyField('self', through='Relationship',
symmetrical=False,
related_name='related_to')
def __unicode__ (self):
return self.name
def add_relationship(self, person, status):
relationship, created = Relationship.objects.get_or_create(
from_person=self,
to_person=person,
status=status)
return relationship
def remove_relationship(self, person, status):
Relationship.objects.filter(
from_person=self,
to_person=person,
status=status).delete()
return
def get_relationships(self, status):
return self.relationships.filter(
to_people__status=status,
to_people__from_person=self)
def get_related_to(self, status):
return self.related_to.filter(
from_people__status=status,
from_people__to_person=self)
def get_following(self):
return self.get_relationships(RELATIONSHIP_FOLLOWING)
def get_followers(self):
return self.get_related_to(RELATIONSHIP_FOLLOWING)
def get_non_followers(self):
# How to do this?
return
class Relationship(models.Model):
from_person = models.ForeignKey(UserProfile, related_name='from_people')
to_person = models.ForeignKey(UserProfile, related_name='to_people')
status = models.IntegerField(choices=RELATIONSHIP_STATUSES)
This isn't particularly glamorous, but it gives correct results (just tested):
def get_non_followers(self):
UserProfile.objects.exclude(to_people=self,
to_people__status=RELATIONSHIP_FOLLOWING).exclude(id=self.id)
In short, use exclude() to filter out all UserProfiles following the current user, which will leave the user themselves (who probably shouldn't be included) and all users not following them.
i'v been searching for a method or some way to do that for like an hour, but i found nothing.
but there is a way to do that.
you can simply use a for loop to iterate through all objects and just remove all objects that they have a special attribute value.
there is a sample code here:
all_objects = className.objects.all()
for obj in all_objects:
if obj.some_attribute == "some_value":
all_objects.remove(obj)
Solution to the implementation of get_non_followers:
def get_non_following(self):
return UserProfile.objects.exclude(to_person__from_person=self, to_person__status=RELATIONSHIP_FOLLOWING).exclude(id=self.id)
This answer was posted as an edit to the question Finding objects without relationship in django by the OP Avi Meir under CC BY-SA 3.0.
current_userprofile = current_user.get_profile()
rest_of_users = Set(UserProfile.objects.filter(user != current_userprofile))
follow_relationships = current_userprofile.relationships.filter(from_person=current_user)
followers = Set();
for follow in follow_relationships:
followers.add(follow.to_person)
non_followeres = rest_of_users.difference(followers)
Here non_followers is the list of userprofiles you desire. current_user is the user whose non_followers you are trying to find.
I haven't tested this out, but it think it should do what you want.
def get_non_followers(self):
return self.related_to.exclude(
from_people__to_person=self)

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