I'm trying to email multiple recipients using the pyton script below. I've searched the forum for answers, but have not been able to implement any of them correctly. If anyone has a moment to review my script and spot/resolve the problem it would be greatly appreciated.
Here's my script, I gather my issue is in the 'sendmail' portion, but can't figure out how to fix it:
gmail_user = "sender#email.com"
gmail_pwd = "sender_password"
recipients = ['recipient1#email.com','recipient2#email.com']
def mail(to, subject, text, attach):
msg = MIMEMultipart()
msg['From'] = gmail_user
msg['To'] = ", ".join(recipients)
msg['Subject'] = subject
msg.attach(MIMEText(text))
part = MIMEBase('application', 'octet-stream')
part.set_payload(open(attach, 'rb').read())
Encoders.encode_base64(part)
part.add_header('Content-Disposition',
'attachment; filename="%s"' % os.path.basename(attach))
msg.attach(part)
mailServer = smtplib.SMTP("smtp.gmail.com", 587)
mailServer.ehlo()
mailServer.starttls()
mailServer.ehlo()
mailServer.login(gmail_user, gmail_pwd)
mailServer.sendmail(gmail_user, to, msg.as_string())
mailServer.close()
mail("recipient1#email.com, recipient2#email.com",
"Subject",
"Message",
"attchachment")
Any insight would be greatly appreciated.
Best,
Matt
It should be more like
mail(["recipient1#email.com", "recipient2#email.com"],
"Subject",
"Message",
"attchachment")
You already have a array of recipients declared,that too globally,You can use that without passing it as an argument to mail.
I wrote this bit of code to do exactly what you want. If you find a bug let me know (I've tested it and it works):
import email as em
import smtplib as smtp
import os
ENDPOINTS = {KEY: 'value#domain.com'}
class BoxWriter(object):
def __init__(self):
pass
def dispatch(self, files, box_target, additional_targets=None, email_subject=None, body='New figures'):
"""
Send an email to multiple recipients
:param files: list of files to send--requires full path
:param box_target: Relevant entry ENDPOINTS dict
:param additional_targets: other addresses to send the same email
:param email_subject: optional title for email
"""
destination = ENDPOINTS.get(box_target, None)
if destination is None:
raise Exception('Target folder on Box does not exist')
recipients = [destination]
if additional_targets is not None:
recipients.extend(additional_targets)
subject = 'Updating files'
if email_subject is not None:
subject = email_subject
message = em.MIMEMultipart.MIMEMultipart()
message['From'] = 'user#domain.com'
message['To'] = ', '.join(recipients)
message['Date'] = em.Utils.formatdate(localtime=True)
message['Subject'] = subject
message.attach(em.MIMEText.MIMEText(body + '\n' +'Contents: \n{0}'.format('\n'.join(files))))
for f in files:
base = em.MIMEBase.MIMEBase('application', "octet-stream")
base.set_payload(open(f, 'rb').read())
em.Encoders.encode_base64(base)
base.add_header('Content-Disposition', 'attachment; filename={0}'.format(os.path.basename(f)))
message.attach(base)
conn = smtp.SMTP('smtp.gmail.com', 587)
un = 'user#gmail.com'
pw = 'test1234'
conn.starttls()
conn.login(un, pw)
conn.sendmail('user#domain.com', recipients, message.as_string())
conn.close()
I was facing the same issue, I fixed this issue now. Here is my code -
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
import smtplib
import datetime
def sendMail():
message = MIMEMultipart()
message["To"] = "xxxxx#xxxx.com,yyyy#yyyy.com"
message["Cc"] = "zzzzzz#gmail.com,*********#gmail.com"
message["From"] = "xxxxxxxx#gmail.com"
message["Password"] = "***************"
server = 'smtp.gmail.com:587'
try:
now = datetime.datetime.now()
message['Subject'] = "cxxdRL Table status (Super Important Message) - "+str(now)
server = smtplib.SMTP(server)
server.ehlo()
server.starttls()
server.login(message["From"], message["Password"])
server.sendmail(message["From"], message["To"].split(",") + message["Cc"].split(","), message.as_string())
server.quit()
print('Mail sent')
except:
print('Something went wrong...')
sendMail()
Related
I would like to send two file attachments by email but I do not know how to do, any help?
def sendmail():
sender_email = "sender#gmail.com"
receiver_email = "receiver#gmail.com"
message = MIMEMultipart()
message["From"] = sender_email
message['To'] = receiver_email
message['Subject'] = "Deine Monatseinteilung"
file = (f'{myPath}/File-2-2022.ics')
attachment = open(file,'rb')
obj = MIMEBase('application','octet-stream')
obj.set_payload((attachment).read())
encoders.encode_base64(obj)
obj.add_header('Content-Disposition',"attachment; filename= "+file)
message.attach(obj)
my_message = message.as_string()
email_session = smtplib.SMTP('smtp.gmail.com',587)
email_session.starttls()
email_session.login(sender_email,'xxxxxx')
email_session.sendmail(sender_email,receiver_email,my_message)
email_session.quit()
print(f"Deine monatseinteilung wurde an deine E-Mail-Adresse gesendet ({receiver_email})")
sendmail()
Try using this code snippet below:
import smtplib
from email.mime.application import MIMEApplication
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.utils import COMMASPACE, formatdate
def _send_email(send_from, send_to, subject, text, files=None):
assert isinstance(send_to, list)
msg = MIMEMultipart()
msg['From'] = send_from
msg['To'] = COMMASPACE.join(send_to)
msg['Date'] = formatdate(localtime=True)
msg['Subject'] = subject
msg.attach(MIMEText(text))
for f in files or []:
with open(f, "rb") as fil:
part = MIMEApplication(
fil.read(),
Name=basename(f)
)
part['Content-Disposition'] = 'attachment; filename="%s"' % basename(f)
msg.attach(part)
smtp = smtplib.SMTP(SERVER, PORT)
smtp.login(USER, PASS)
smtp.sendmail(send_from, send_to, msg.as_string())
smtp.close()
Then you can call the function like so:
send_from = "fakeemail3#domain.com"
send_to = ['fakeemail1#domain.com', 'fakeemail2#domain.com']
subject = "My Subject"
text = "This is a email."
files = ["pathtofile1", "pathtofile2"]
_send_email(send_from, send_to, subject, text, files)
I can't get this to attach multiple documents to an email. It attaches the first document and then sends the document. I am a noob when it comes to using the auto-email function. Could anyone explain this or show me how to fix this?
self.name = name
fromaddr = "Your Email"
toaddr = "Sending Email"
msg = MIMEMultipart()
#email address
msg['From'] = fromaddr
# Receivers email address
msg['To'] = toaddr
#subject
msg['Subject'] = ' Weekly Report'
#body of the mail
body = 'Hey, I\'m testing the automated email function, let me know if you get it and how does it look!'
#msg instance
msg.attach(MIMEText(body, 'plain'))
# open the file to be sent
a = 0
for i in self.name:
while a < len(self.name):
filename = i + '.pdf'
attachment = open(i + '.pdf', "rb")
a+=1
print(len(self.name))
print(a)
p = MIMEBase('application', 'octet-stream')
p.set_payload((attachment).read())
encoders.encode_base64(p)
p.add_header('Content-Disposition', "attachment; filename= %s" % filename)
msg.attach(p)
s = smtplib.SMTP('smtp.gmail.com', 587)
s.starttls()
s.login(fromaddr, "password")
text = msg.as_string()
s.sendmail(fromaddr, toaddr, text)
s.quit()
Try this (Reference:- https://dzone.com/articles/send-email-attachments-python)
import smtplib
import os
from email.MIMEMultipart import MIMEMultipart
from email.MIMEBase import MIMEBase
from email.MIMEText import MIMEText
from email.Utils import COMMASPACE, formatdate
from email import Encoders
def send_mail(send_from, send_to, subject, text, files=[], server="localhost"):
assert type(send_to)==list
assert type(files)==list
msg = MIMEMultipart()
msg['From'] = send_from
msg['To'] = COMMASPACE.join(send_to)
msg['Date'] = formatdate(localtime=True)
msg['Subject'] = subject
msg.attach( MIMEText(text) )
for f in files:
part = MIMEBase('application', "octet-stream")
part.set_payload( open(file,"rb").read() )
Encoders.encode_base64(part)
part.add_header('Content-Disposition', 'attachment; filename="%s"' % os.path.basename(f))
msg.attach(part)
smtp = smtplib.SMTP(server)
smtp.sendmail(send_from, send_to, msg.as_string())
smtp.close()
Is it possible to send automated email messages with Amazon Workmail through a Python script?
My code keeps hanging and when I can the run I get a SMTP server connection error. How can I fix this? I presume, its the SMTP configuration, but does anyone know what that is?
import smtplib
from email.mime.text import MIMEText
from email.mime.multipart import MIMEMultipart
from email.mime.base import MIMEBase
from email import encoders
import os.path
import csv
from random import randint
from time import sleep
def send_email(email_recipient,
email_subject,
email_message,
attachment_location=''):
email_mime_sender = 'xxxxx <xxxxx#yyyyyy.co.uk>'
email_sender = 'xxxxx'
email_password = 'xxxxx'
msg = MIMEMultipart()
msg['From'] = email_mime_sender
msg['To'] = email_recipient
msg['Subject'] = email_subject
msg.attach(MIMEText(email_message, 'plain'))
if attachment_location != '':
filename = os.path.basename(attachment_location)
attachment = open(attachment_location, "rb")
part = MIMEBase('application', 'octet-stream')
part.set_payload(attachment.read())
encoders.encode_base64(part)
part.add_header('Content-Disposition',
"attachment; filename= %s" % filename)
msg.attach(part)
try:
server = smtplib.SMTP_SSL('smtp.mail.eu-west-1.awsapps.com', 465)
server.ehlo()
server.starttls()
server.login(email_sender, email_password)
text = msg.as_string()
server.sendmail(email_sender, email_recipient, text)
print('Email sent to %s' % email_recipient)
server.quit()
except:
print("SMTP server connection error")
return True
def main():
file = 'test.csv'
with open(file, "rb") as f:
next(f)
for line in f:
line = line.replace("\n", "")
line = line.replace("\r", "")
split_line = line.split(",")
email_subject = 'Can I ask you a few questions?'
raw_email_message = [
'Test',
'Test'
]
email_message = '\n\n'.join(raw_email_message)
send_email(split_line[1], email_subject, email_message, '')
sleep(randint(1, 3))
main()
Removing server.starttls() from the this block fixed it:
try:
server = smtplib.SMTP_SSL('smtp.mail.eu-west-1.awsapps.com', 465)
server.ehlo()
server.login(email_user, email_password)
text = msg.as_string()
server.sendmail(email_sender, email_recipient, text)
print('Email sent to %s' % email_recipient)
server.quit()
except Exception as e:
print(e)
print("SMTP server connection error")
return True
import smtplib
import mechanize
import os
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.mime.base import MIMEBase
from email import encoders
def sem():
if not os.path.isfile('key.txt'):
print('below details are req to send report')
gmail_user = input('enter your email=')
gmail_app_password = input('enter your email password=')
print('pls accept the login in your gmail account ')
ke = open('key.txt',mode="w+")
ke.write(gmail_user)
ke.write(':')
ke.write(gmail_app_password)
ke.close()
if not os.path.isfile('sto.txt'):
gmai = input('enter the email to send report=')
ke = open('sto.txt',mode="w+")
ke.write(gmai)
ke.close()
with open('key.txt',mode="r")as f:
ds=f.readlines()
d=''.join(ds)
r=d.split(':')
with open('sto.txt',mode="r")as f:
ds=f.readlines()
f=ds
print(f)
gmail_user = r[0]
gmail_app_password = r[1]
sent_from = gmail_user
sent_to = ds
sent_subject = "hey amo lio ,how are ?"
sent_body = ("Hey, what's up? friend!")
email_text = """\
To: %s
Subject: %s
%s
""" % (", ".join(sent_to), sent_subject, sent_body)
mail = MIMEMultipart()
mail["Subject"] = sent_subject
mail["From"] = sent_from
mail["To"] = sent_to
mail.attach[MIMEText(sent_body,'html')]
ctype, encoding = mimetypes.guess_type(_file)
maintype, subtype = ctype.split('/', 1)
fp = open("./data/mood.txt")
msg = MIMEText(fp.read(), _subtype=subtype)
fp.close()
filename = os.path.basename(_file)
msg.add_header('Content-Disposition', 'attachment', filename=filename)
mail.attach(msg)
print('done')
server.sendmail(sent_from, sent_to, mail.as_string())
try:
server = smtplib.SMTP_SSL('smtp.gmail.com', 465)
server.ehlo()
server.login(gmail_user, gmail_app_password)
server.sendmail(sent_from, sent_to, email_text)
server.close()
print('Email sent!')
except Exception as exception:
print("Error: %s!\n\n" % exception)
sem()
How can I attach the helloword.txt file in this email? This code is working fine, I just want to send an attachment along with it. This code lets me me send the body without any attachment. Also, how do I encrypt the key.txt file which store email address and password, and to send email it it requires the password to be entered (diff pass)?
You need to use the 'MIMEMultipart' module to attach files.
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
mail = MIMEMultipart()
mail["Subject"] = sent_subject
mail["From"] = sent_from
mail["To"] = sent_to
mail.attach(MIMEText(sent_body,'html'))
ctype, encoding = mimetypes.guess_type(_file)
maintype, subtype = ctype.split('/', 1)
fp = open("/path/to/attachment/file.txt")
# If file mimetype is video/audio use respective email.mime module.
# Here assuming 'maintype' == 'text' we will use MIMEText
msg = MIMEText(fp.read(), _subtype=subtype)
fp.close()
filename = os.path.basename(_file)
msg.add_header('Content-Disposition', 'attachment', filename=filename)
mail.attach(msg)
server.sendmail(sent_from, sent_to, mail.as_string())
import smtplib
import mechanize
import os
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
from email.mime.base import MIMEBase
from email import encoders
from email.mime.multipart import MIMEMultipart
from email.mime.text import MIMEText
import mimetypes
import pdb
def email:
sender_address = gmail_user
#make it input
receiver_address = gmail_user
#Setup the MIME
fromaddr = gmail_user
sendto = gmail_app_password
sender_pass = gmail_app_password = input('enter your email password')
msg = MIMEMultipart()
msg['From'] = fromaddr
msg['To'] = sendto
msg['Subject'] = 'This is cool'
body = "this is the body of the text message"
msg.attach(MIMEText(body, 'plain'))
filename = 'mood.txt'
attachment = open('./data/mood.txt', 'rb')
part = MIMEBase('application', "octet-stream")
part.set_payload((attachment).read())
encoders.encode_base64(part)
part.add_header('Content-Disposition', 'attachment; filename= %s' % filename)
msg.attach(part)
smtpObj = smtplib.SMTP('smtp.gmail.com', 587)
smtpObj.ehlo()
smtpObj.starttls()
smtpObj.login(gmail_user, gmail_app_password)
text = msg.as_string()
smtpObj.sendmail(fromaddr, sendto , text)
smtpObj.quit() # attach the instance 'p' to instance 'msg'
here is perfect working code for sending email
I am trying to get the results of a MYSQL query into the body of an email and also as a csv or xls attachment.
My code below works and sends the email only problem is if the results from the MYSQL query are more than a row only the first row shows up in the email.
import smtplib
from email.MIMEMultipart import MIMEMultipart
from email.MIMEBase import MIMEBase
from email.MIMEText import MIMEText
from email import Encoders
import os
import MySQLdb
import string
import datetime
import time
today = (time.strftime("%m/%d/%Y"))
#print today
db = MySQLdb.connect(host="-----.com", # your host, usually localhost
user="----", # your username
passwd="-------", # your password
db="dailies") # name of the data base
cursor49=db.cursor()
cursor49.execute("SELECT PLACEMENT_NAME FROM dailies.pub_cpm join placement ON placement.PLACEMENT_id = pub_cpm.PLACEMENT_ID where date(pub_cpm.created) = date(now())")
results49 = cursor49.fetchone()
# Commit your changes in the database
db.commit()
# disconnect from server
db.close()
results50 = "Latest Pub CPM Name(s): %s" % (results49)
gmail_user = "------#gmail.com"
gmail_pwd = "g---a"
mailServer = smtplib.SMTP("smtp.gmail.com", 587)
to = ['-----#g-----']
msg = MIMEMultipart()
msg['From'] = gmail_user
msg['To'] = ", ".join(to)
msg['Subject'] = "Database Alerts: %s" % (today)
body = results50
msg.attach(MIMEText(body, 'plain'))
mailServer.ehlo()
mailServer.starttls()
mailServer.ehlo()
text = msg.as_string()
mailServer.login(gmail_user, gmail_pwd)
mailServer.sendmail(gmail_user, to, text)
# Should be mailServer.quit(), but that crashes...
mailServer.close()
There are a couple changes you need to make. First, you need to change your fetchone() call to a fetchall() call. This will return all results from your SELECT query.
Next, you want to write these to a CSV file. Let's do that using the results from our query above:
results49 = cursor.fetchall()
fp = open('/tmp/file_name.csv', 'w') # You pick a name, it's temporary
attach_file = csv.writer(fp)
attach_file.writerows(results49)
fp.close()
At this point, you have a file in /tmp/file_name.csv (or what ever path and name you picked) that contains your CSV results. The final step is to attach this to an email.
msg = MIMEMultipart()
msg['From'] = gmail_user
msg['To'] = ", ".join(to)
msg['Subject'] = "Database Alerts: %s" % (today)
body = results50
part = MIMEBase('application', "octet-stream")
part.set_payload(open("/tmp/file_name.csv", "rb").read()) # This is the same file name from above
Encoders.encode_base64(part)
part.add_header('Content-Disposition', 'attachment; filename="/tmp/file_name.csv"')
msg.attach(part)
I changed your msg.attach() function and utilized code from another question.
Once this is done, you still have a file in /tmp/file_name.csv. You can delete this safely at this point.