I am doing a programming project. It gives a user (aimed for primary school students) a randomly generated question. When I do my division code the answer is a real/float variable meaning that unless the user has a .0 at the end of a whole number, their answer is processed as incorrect. My code is:
while True:
num1 = str((random.randint(0,12)))
num2 = str((random.randint(0,12)))
if num1 >= num2:
question = (num1 + " " + "/" + " " + num2)
print(question)
answer = str((int(num1) / int(num2)))
reply = str(input())
if reply == answer:
score = score + 1
print("Correct")
break
else:
print("Incorrect")
print("The answer was", answer)
break
else:
print("")
I understand that sometimes the answer will have a decimal point in it but is there a way of allowing a whole number to not have a .0 at the end. If not then how can I improve the code so I don't get this issue. Any help is appreciated. My python-idle version is 3.8
/ is float division in Python. If you want to get an int with the line answer = str((int(num1) / int(num2))) then you should be using // instead, which is integer division.
In my code I'm making a basic multiplying game.
But in my game,
When you get the answer right, it says you got it wrong
Here's my whole code:
import random
score = 0
while True:
num1 = random.choice(range(1,12))
num2 = random.choice(range(1,12))
answer = num1 * num2
a = input("Solve for " + str(num1) + "x" + str(num2))
if a == answer:
print("congrats you got it right")
score += 1
else:
print("Wrong sorry play again")
print("Score was: " + str(score))
break
When I get the right answer I get
Solve for 7x10 70
Wrong sorry play again
Score was: 0
Other languages might let you get away with this, but Python is strongly typed. The input function gets a string, not a number. Numbers can't be equal to strings. Either convert the number to a string or the string to a number before you compare them. You can use str or int to convert.
Function input returns what was typed as a string... in order to compare it with the answer, you need to either convert it to int:
if int(a) == answer:
or the other way around (convert answer to str):
if a == str(answer):
The first one may raise an exception if a is not parseable to an int.
Here the docs.
PS: I really wonder how ur random library picked a 1070 sampling from 0 to 11...
Or use int(input()):
import random
score = 0
while True:
num1 = random.choice(range(1,12))
num2 = random.choice(range(1,12))
answer = num1 * num2
a = int(input("Solve for " + str(num1) + "x" + str(num2)))
if a == answer:
print("congrats you got it right")
score += 1
else:
print("Wrong sorry play again")
print("Score was: " + str(score))
break
Here is the code that the syntax is on:
# Odd or Even?
print('Hello! What is your name?')
PlayerName = input()
print("Hello, " + PlayerName + "! Enter your number and I\'ll tell you if it\'s even or odd!")
PlayerNum = input()
Decimal = PlayerNum % 2
if Decimal == 0.5
print('Your number is odd!')
else
print('Your number is even!')
It gives syntax on line 7 (if Decimal == 0.5). Let me know if there are any other errors. I'm also using python 3. What's the problem?
Thanks
Your code should look like this:
print('Hello! What is your name?')
playerName = input()
print("Hello, " + playerName + "! Enter your number and I\'ll tell you if it\'s even or odd!")
playerNum = int(input())
if playerNum % 2 == 0:
print('Your number is even!')
else:
print('Your number is odd!')
You need to insert a colon after if and else conditions.
The input is read as a string, you need to convert it to int or float
You need to indent your code (I recommend 4 spaces)
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I am trying to produce a program where the program generates a quiz consisting of a series of random questions, using in each case any two numbers and addition, subtraction or multiplication. The system should ask the student’s
name, then ask 10 questions, output if the answer to each question is correct or not and produce a final score out of 10.
The code goes as follows:
#Material 2: Task 1 (V1.0)
from random import randint
from random import choice
Name = input('What is your name? ')
Score = 0
QuestionNo = 0
Operators = ['+','-','*']
num1 = 0
num2 = 0
print ('\nWhat are the answers to the following questions?\n')
while QuestionNo != 11:
num1 = randint(0,10)
num2 = randint(0,10)
Result = eval(str(num1) + (choice(Operators)) + str(num2))
print (Result)
Answer = int(input(str(num1) + (choice(Operators)) + str(num2) + '='))
if Answer == Result:
Score += 1
print ('Well Done! That is correct!')
elif Answer != Result:
print ('Whoops! That is wrong!')
QuestionNo += 1
if QuestionNo == 10:
print ('That is the end of the quiz '+ Name + '. Your score was: ' + str(Score) + ' out of 10!')
if Score == 10:
print ('Great job! You got everything right!')
elif Score == 0:
print ('You\'ve got to try harder next time!')
break
The issue is the lines -
Result = eval(str(num1) + (choice(Operators)) + str(num2))
print (Result)
Answer = int(input(str(num1) + (choice(Operators)) + str(num2) + '='))
As you can see, you are taking choice(Operators) again, when asking for input from user, this can give different operator that what was used for calculating the result. You would need to take choice(Operators) only once, and save it in a variable and use it for both evaluation as well as input.
while QuestionNo != 11:
num1 = randint(0,10)
num2 = randint(0,10)
opp = choice(Operators)
Result = eval(str(num1) + (opp) + str(num2))
print (Result)
Answer = int(input(str(num1) + (opp) + str(num2) + '='))
thanks for taking time to read this.
I have to create a program that generates 10 random maths questions based around =, - and *. I have the program working but everytime I run it after the main program it prints "none" even though that's not in my program.Any help at all would be much appreciated. Thank you.
import random
print ("Welcome")
name=input("What's your name?")
print("Nice to meet you", name, ",you will be given 10 multiplication, addition and subtraction questions.")
Num1 = random.randint(1,12)
Num2 = random.randint(1,12)
sign = random.randint(1,3)
if sign == 1: # If the random number generated is 1
question = Num1 + Num2
rightanswer1 = Num1 + Num2
answer1=input(print("What is", question ,"?"))
if answer1 == rightanswer1:
print("Well Done!")
if answer1 != rightanswer1:
print("Sorry, that's incorrect, the answer was", rightanswer1)
if sign == 2:
question = Num1 - Num2
rightanswer2 = Num1 - Num2
answer2=input(print("What is", Num1, "-", Num2 ,"?"))
if answer2 == rightanswer2:
print("Well done!")
elif answer2 != rightanswer2:
print("Sorry, that's incorrect, the answer was", rightanswer2)
if sign == 3:
question = Num1 * Num2
rightanswer3 = Num1 * Num2
answer3=input(print("What is", Num1, "x", Num2 ,"?"))
if answer3 == rightanswer3:
print("Well done!")
elif answer3 != rightanswer3:
print("Sorry, that's incorrect, the answer was", rightanswer3)`
> Welcome
> What's your name? John
> Nice to meet you John ,you will be given 10 multiplication, addition and subtraction questions.
> What is 12 x 3 ?
> None 36
> Sorry, that's incorrect, the answer was 36
I think you are using python 3. In python 3 input is like raw_input in python 2. So you get the string as input. So convert it into int
var = int(input("Enter a number: "))
So in your code make it as
print("What is", Num1, "x", Num2 ,"?")
answer3 = input()
answer3 = int(answer3)
See this:
whats-the-difference-between-raw-input-and-input-in-python3-x
I'm reluctant to just give you an answer that just does it for you, so instead i'll provide you with a few hints to improve things. (i.e. this isn't an answer, just too large of a comment - and more like a codereview answer)
First off, you use a structure like this:
if x == 1:
#do something
if x == 2:
#do something else
...
In this case, which it makes no difference, it is easier to read if you use the if syntax as intended:
if <condition>:
#do this if the above test is true.
elif <more conditions>:
#do this only if the first test is false and this one is true
elif <more conditions>:
#same as above, except for the second test must be false too
else:
#do this if all the above tests are false
So you could use this something like:
if sign == 1:
...
elif sign == 2:
...
elif sign == 3:
...
else:
# something weird happened...
Which would make that section of the program easier to follow.
The same thing can be done with the if answer1 == rightanswer1: sections;
if answer1 == rightanswer1:
#correct!
else:
#incorrect.
That would be a clearer was to do it. You seem to have used the if...elif style in a couple of them, but not the first one.
Once you have this, it will be a little clearer.
The next way you could improve things is by removing duplicated code. You don't need separate branches for each sign, you can just roll it all into one:
number1 = randint(1,12)
number2 = randint(1,12)
op = randint(1,3)
question_string = "%d %s %d = ?" % (number1, number2, ["+", "-", "*"][op])
result = None
if op == 1:
result = number1 + number2
elif op == 2:
result = number1 - number2
elif op == 3:
result = number1 * number2
This will do most of the logic for you, and generate the strings you want, without duplicating all of the other code.
Small changes like this can make things much more readable.
It's printing None because the print() function returns None and you're passing that value of None from print() as the prompt to your input() functions. Eg,
answer3=input(print("What is", Num1, "x", Num2 ,"?"))
So print("What is", Num1, "x", Num2 ,"?") prints its stuff, and returns None, which then gets printed as the prompt by input().
A simple way to fix this is to just move your print() function calls out of your input() functions.
Eg,
print("What is", Num1, "x", Num2 ,"?")
answer3=input()
However, there's another major problem with your program: the rightanswer variables are ints, but the inputted answers are strings. To compare them properly they need to be the same type. So you should either convert the inputted answers to int, or alternatively, convert the rightanswers to str.
There are two problems with how you use the input function:
You misuse the prompt argument
You forget to convert the result
First, have a better look at the reference of the input function
The prompt argument
input takes a string as argument that will be displayed ("prompted") to the user to indicate that the program is waiting an input. The print function also displays a string to the user, but it doesn't return anything. It does its job and that's all (and in Python a function that returns nothing, returns None). That's what input gets to display, so it displays None. You should use format instead. It will format and return the formatted string that input can display:
answer1_as_str=input("What is {} ?".format(question))))
or
answer2_as_str=input("What is {:d} - {:d} ?".format(Num1, Num2)))
The return value
input returns the user input as a string contrary to python 2 (i.e. exactly as entered). So you have to convert the input to the desired type if you need it. If you type 10 for example, the input will return "10". If you need an int, you have to convert it yourself.
answer1 = int(answer1_as_str)
It looks like you don't really understand how input() works. You might also want to review the different datatypes and conditional statements. Other than that, it was a very good attempt. Here's my solution:
from random import randint
print("Welcome")
name = input("What's your name?\n")
print("Nice to meet you " + name + ", you will be given 10 multiplication, addition and subtraction questions.")
for i in range(10):
print("\nProblem " + str(i+1))
num1 = randint(1,12)
num2 = randint(1,12)
sign = randint(1,3)
if sign == 1:
question = str(num1) + " + " + str(num2)
answer = num1 + num2
elif sign == 2:
question = str(num1) + " - " + str(num2)
answer = num1 - num2
else:
question = str(num1) + " x " + str(num2)
answer = num1 * num2
user_answer = input("What is " + question + "? ")
if user_answer == str(answer):
print("Well done!")
else:
print("Sorry, that's incorrect, the answer was", answer)