Develop Reference

I have "no such element: Unable to locate element" error although ID is 100% correct

I am trying to click on "OK" button on a pop up using selenium and Python but i face an error "no such element: Unable to locate element" although being sure that my id is 100% correct.
> <a class="dxm-content dxm-hasText dx dxalink" href="javascript:;" role="menuitem" id="Dialog_PAC_Menu_DXI0_T"><span class="dx-vam dxm-contentText">OK</span></a>
My python selenium code:
Export2 = driver.find_element(By.XPATH,'//a[#id="Dialog_PAC_Menu_DXI0_T"]')
Export2.click()
Where exactly did I go wrong, i also tried full Xpath, wait till clickable, time sleep. everything!
i would appreciate if someone can help me with it.

Well, it looks like you found the answer and that was because your element was inside an iFrame so I will just post an answer here so others can find an easy answer if they view your question.
tmpheader = driver.find_element(By.CSS_SELECTOR, "#modal > iframe")
driver.switch_to.frame(tmpheader)
Export2 = driver.find_element(By.XPATH,'//a[#id="Dialog_PAC_Menu_DXI0_T"]')
Export2.click()
This switches our current driver that we are looking for into the first iFrame element on the page. If there is more than one iFrame you would need to check for more attributes in the first line to make sure you are looking at the correct one

Actually that's how I solved my issue as my element was inside an iFrame as John Gordon suggested.
driver.switch_to.frame(driver.find_element(By.TAG_NAME,'iframe'))
slider = driver.find_element(By.XPATH,"//*[contains(#id,'_xaf_dviImportExportFormat_Edit_dropdown_DD_B-1Img')]").click()

Unable to grab selenium element for one particular class name

So I am trying to find elements by CSS selector using the class name. One of my code works while the other does not.
Screenshot of the html code that works:
The code for the above screenshot, that works:
driver.get(url)
print('a') # to check if code has run till here
disabled_next = driver.find_elements(By.CSS_SELECTOR, '.page-link.next.disabled')
print(disabled_next)
Screenshot of the html code that does NOT work:
The code for the above screenshot, that does not work:
driver.get(url)
print('a')
enabled_next = driver.find_elements(By.CSS_SELECTOR, '.page-link.next')
print(enabled_next)
Just trying to understand why the second one does not work. It does not even print ('a'). The error I am getting is along the lines of this:
selenium.common.exceptions.WebDriverException: Message: unknown error: cannot determine loading status
from unknown error: unexpected command response
(Session info: chrome=103.0.5060.66)
I am using chromedriver103 with chrome version 103. I know there have been some issues relating to it. Could that be why? Or have I used the wrong format for '.page-link.next'.
Also, a semi-related question: How do I grab the text after <a class = "text here"? I would like to just grab "text here". So in my examples above I would love to grab "page-link next disabled" or "page-link next".
Thank you in advance!

This is not related to your code at all, your code should do fine. The error message pertains to the chromedriver version and the current chrome browser you are using. Try to double check the chromedriver and chrome browser you are using for testing.
cannot determine loading status

Looping through webelements with selenium Python

I am currently trying to automate a process using Selenium with python, but I have hit a roadblock with it. The list is part of a list which is under a tree. I have identified the base of the tree with the following xpath
item = driver.find_element_by_xpath("//*[#id='filter']/ul/li[1]//ul//li")
items = item.find_elements_by_tag_name("li")
I am trying to Loop through the "items" section but need and click on anything with an "input" tag
for k in items:
WebDriverWait(driver, 10).until(EC.element_to_be_clickable((k.find_element(By.TAG_NAME, "input")))).click()
When execute the above I get the following error:
"TypeError: find_element() argument after * must be an iterable, not WebElement"
For some reason .click() will not work if I use something like the below.
k.find_element_by_tag_name("input").click()
it only works if i use the webdriverwait. I have had to use the web driver wait method anytime i needed to click something on the page.
My question is:
What is the syntax to replicate items = item.find_elements_by_tag_name("li")
for WebDriverWait(driver, 10).until(EC.element_to_be_clickable((k.find_element(By.TAG_NAME, "input")))).click()
i.e how do I use a base path and append to the using the private methods find_elements(By.TAG_NAME)
Thanks in advance

I have managed to find a work around and get Selenium to do what i need.
I had to call the javascript execution, so instead of trying to get
WebDriverWait(driver, 10).until(EC.element_to_be_clickable((k.find_element(By.TAG_NAME, "input")))).click() to work, i just used
driver.execute_script("arguments[0].click();", k.find_element_by_tag_name("input"))
Its doing exactly what I needed it to do.

Unable to click on the Link Text, have tried Find_ELEMENT_BY_LINK_TEXT and quite a few other things , but its not working

SCREENSHOT OF THE HTML
Here is the screenshot of html code with which I am struggling , I want to click on the Smart Watches in the left-Nav and I am using the following code to click on it
driver.implicitly_wait(30)
driver.find_element_by_link_text('Smart Watches').click()
But I am getting the following error and I am clueless why i just cant find it on page
selenium.common.exceptions.NoSuchElementException: Message: no such
element: Unable to locate element: {"method":"link
text","selector":"Smart Watches"} (Session info:
chrome=60.0.3112.113) (Driver info: chromedriver=2.29.461591
(62ebf098771772160f391d75e589dc567915b233),platform=Windows NT
6.2.9200 x86_64)
I have also tried the explicit code and Expected conditions as follows -:
wait = WebDriverWait(driver, 20)
link = wait.until(expected_conditions.presence_of_element_located((By.LINK_TEXT,'"Smart Watches"')))
link.click()
But even its giving me Timeout exception
Here is the link of the page where I am stuck since morning
https://www.kogan.com/au/shop/phones/
I am very new to coding , any help would be helpful !! I just want to know why find_element_by_link_text is not working here , it looks weird to me!!
Thanks in advance

The problem is that when you use find_element_by_link_text(), it must be an exact match to the text contained in the link. In your HTML picture, you can see "Smart Watches" but what you aren't seeing is the SPAN just below but still inside the A is closed. Most likely if you expand it, you will see additional text that you must include if you are going to use find_element_by_link_text().
Another option is find_element_by_partial_link_text() which is more like a contains() instead of equals(). Depending on the page, it may find too many matches. You would have to try and see if it works.
Yet another option is using an XPath. There are a lot of different ways to create an XPath for this depending on exactly what you want.
This is the most general and thus most likely to find unwanted links but it may work. It's pretty much the same as find_element_by_partial_link_text()
//a[contains(.,'Smart Watches')
Other options include
//a[starts-with(.,'Smart Watches')
//li[#data-filter-facet='smart-watches']/a[contains(.,'Smart Watches')
//li[#data-filter-facet='smart-watches']/a[starts-with(.,'Smart Watches')
... and so on...

You can try this way...
Accessing text: find_element_by_xpath["//a[contains(text(), 'Smart Watches')]"].click()

Don't know why it is not wotks but partial link text works. Please see my java code for the same:
WebDriver driver=new FirefoxDriver();
driver.get("https://www.kogan.com/au/shop/phones/");
WebElement watch=driver.findElement(By.partialLinkText("Smart Watch"));
WebDriverWait waitElement=new WebDriverWait(driver, 30);
waitElement.until(ExpectedConditions.elementToBeClickable(watch));
watch.click();

You need to add double quotation marks, as it is in the html code:
driver.find_element_by_link_text('"Smart Watches"').click()

most of the time it might happen that link is taking some more time to load after your page has loaded. rather than using implicit wait use explicit wait.
wait = WebDriverWait(driver, 30)
link = wait.until(expected_conditions.presence_of_element_located((By.LINK_TEXT,"Smart Watches")))
link.click()
it could also be the case that link is inside another frame, in this case you will have to switch to this frame.

selenium get element by css selector

I am trying to get user details from each block as given
driver.get("https://www.facebook.com/public/karim-pathan")
wait = WebDriverWait(driver, 10)
li_link = []
for s in driver.find_elements_by_class_name('clearfix'):
print s
print s.find_element_by_css_selector('_8o._8r.lfloat._ohe').get_attribute('href')
print s.find_element_by_tag_name('img').get_attribute('src')
it says:
unable to find element with css selector
any hint appreciable.

Just a mere guess based on assumption that you are not logged in. You are getting exception cause for all class clearfix, element with ._8o._8r.lfloat._ohe does not exists. So your code isn't reaching the required elements. Anyhow, if you are trying to fetch href and img source of results, you need not iterate over all clearfix cause as suggested by #leo.fcx, your css is incorrect, trying the css provided by leo, you can achieve the desired result as:
driver.get("https://www.facebook.com/public/karim-pathan")
for s in driver.find_elements_by_css_selector('._8o._8r.lfloat._ohe'): // there didn't seemed to iterate over each class of clearfix
print s.get_attribute('href')
print s.find_element_by_tag_name('img').get_attribute('src')
P.S. sorry for any syntax, never explored python binding :)

Since you are using all class-names that the element applies, adding a . to the beginning of your CSS selector should fix it.
Try this:
s.find_element_by_css_selector('._8o._8r.lfloat._ohe')
instead of:
s.find_element_by_css_selector('_8o._8r.lfloat._ohe')

Adding to what #leo.fcx pointed about the selector, wait for search results to become visible:
wait.until(EC.visibility_of_element_located((By.ID, "all_search_results")))