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Format error when trying to parse datetime string using strptime

Trying to parse a datetime string to unix:
from calendar import timegm
from datetime import datetime
print(timegm(datetime.strptime(('2021-07-21 00:00:07.223977216+00:00'), '%Y-%m-%d %H:%M:%S.%f')))
Results in
ValueError: time data '2021-07-21 00:00:07.223977216+00:00' does not match format '%Y-%m-%d %H:%M:%S.%f+00:00'
Tried a lot, cant get anywhere so far ...

Your date is in ISO format, so you can use datetime.fromisoformat:
>>> from datetime import datetime
>>> datetime.fromisoformat("2021-07-21 00:00:07+00:00")
datetime.datetime(2021, 7, 21, 0, 0, 7, tzinfo=datetime.timezone.utc)

So if you look at the format of the date time you are providing, it does not have the fractional seconds the formatter is looking for:
# '2021-07-21 00:00:07+00:00' <- this date time
# '%Y-%m-%d %H:%M:%S.%f' <- in this format, is parsing like below
# 'YYYY-MM-DD HH:MM:SS.ff' (note the ff part is missing, then there's a +00:00 part leftover so the format is breaking)
If you don't need the microseconds, remove the '.%f' part from your format string. Otherwise, if you're parsing a series of values where some have the fractional part, you're going to need to give both options:
try:
timestamp = datetime.strptime(your_string_here, '%Y-%m-%d %H:%M:%S.%f')
except ValueError:
timestamp = datetime.strptime(your_string_here, '%Y-%m-%d %H:%M:%S')

How to fix date formatting using python3

I have data with the date format as follows:
date_format = 190410
year = 19
month = 04
date = 10
I want to change the date format, to be like this:
date_format = 10-04-2019
How do I solve this problem?

>>> import datetime
>>> date = 190410
>>> datetime.datetime.strptime(str(date), "%y%m%d").strftime("%d-%m-%Y")
'10-04-2019'
datetime.strptime() takes a data string and a format, and turns that into datetime object, and datetime objects have a method called strftime that turns datetime objects to string with given format. You can look what %y %m %d %Y are from here.

This is what you want(Notice that you have to change your format)
import datetime
date_format = '2019-04-10'
date_time_obj = datetime.datetime.strptime(date_format, '%Y-%m-%d')
print(date_time_obj)
Here is an other example
import datetime
date_time_str = '2018-06-29 08:15:27.243860'
date_time_obj = datetime.datetime.strptime(date_time_str, '%Y-%m-%d %H:%M:%S.%f')
print('Date:', date_time_obj.date())
print('Time:', date_time_obj.time())
print('Date-time:', date_time_obj)
You can also do this
from datetime import datetime, timedelta
s = "20120213"
# you could also import date instead of datetime and use that.
date = datetime(year=int(s[0:4]), month=int(s[4:6]), day=int(s[6:8]))
print(date)
There are many ways to achieve what you want.

how to convert todays datetime into timestamp

I am tryng to convert date-time into string.
I am searching answer of this question
when i do this
time.mktime(time.strptime('2017-05-01 14:07:19', '%Y-%m-%d %H:%M:%S'))
i am able convert datetime into time-stamp but I want to concert today's date into time-stamp like this:
timenow = datetime.datetime.now()
//timenow = 2017-05-01 14:07:19
time.mktime(time.strptime(timenow, '%Y-%m-%d %H:%M:%S'))
then it throws error TypeError: expected string or buffer even i tried like
time.mktime(time.strptime(str(timenow), '%Y-%m-%d %H:%M:%S'))
then it throws ValueError: unconverted data remains: .067000
How could i convert todays datetime into timestamp

import datetime
now = datetime.datetime.now()
print(now.strftime("%Y-%m-%d %H:%M:%S"))
print(now.timestamp())

Conversion time from string

I have a problem with time conversion in Python:
I try to do this:
from datetime import datetime
date_object = datetime.strptime('12:29:31.181', '%H:%M:%S')
And I receive an error: "ValueError: unconverted data remains: .181"
Can you help me?

You need to add %f for microseconds:
In [335]:
from datetime import datetime
date_object = datetime.strptime('12:29:31.181', '%H:%M:%S.%f')
print(date_object)
1900-01-01 12:29:31.181000
Your format string has to consume all the characters in the passed in string, if any are still remaining then the ValueError is raised.

how do you format date time in python

I have a variable that has value like this:
val='14/12/15 0000'
it is in two digit year/month/day hourminute format.
I need to convert this to epoch time.
I tried this
import datetime
datetime.datetime.strptime(val, "%y/%m/%d %HH%MM").strftime('%s')
I get this error:
ValueError: time data '14/12/15 0000' does not match format '%y/%m/%d %HH%MM'
what am I doing wrong here?

Hours (24 hr) are %H, not %HH, and minutes are %M, not %MM.
datetime.datetime.strptime(val, "%y/%m/%d %H%M").strftime('%s')

You can use easy_date to make it easy:
import date_converter
my_datetime = date_converter.string_to_string('14/12/15 0000', '%y/%m/%d %H%M', '%s')
Or even convert directly to a timestamp:
import date_converter
timestamp = date_converter.string_to_timestamp('14/12/15 0000', '%y/%m/%d %H%M')