I'm having some brain failure in understanding reading and writing text to a file (Python 2.4).
# The string, which has an a-acute in it.
ss = u'Capit\xe1n'
ss8 = ss.encode('utf8')
repr(ss), repr(ss8)
("u'Capit\xe1n'", "'Capit\xc3\xa1n'")
print ss, ss8
print >> open('f1','w'), ss8
>>> file('f1').read()
'Capit\xc3\xa1n\n'
So I type in Capit\xc3\xa1n into my favorite editor, in file f2.
Then:
>>> open('f1').read()
'Capit\xc3\xa1n\n'
>>> open('f2').read()
'Capit\\xc3\\xa1n\n'
>>> open('f1').read().decode('utf8')
u'Capit\xe1n\n'
>>> open('f2').read().decode('utf8')
u'Capit\\xc3\\xa1n\n'
What am I not understanding here? Clearly there is some vital bit of magic (or good sense) that I'm missing. What does one type into text files to get proper conversions?
What I'm truly failing to grok here, is what the point of the UTF-8 representation is, if you can't actually get Python to recognize it, when it comes from outside. Maybe I should just JSON dump the string, and use that instead, since that has an asciiable representation! More to the point, is there an ASCII representation of this Unicode object that Python will recognize and decode, when coming in from a file? If so, how do I get it?
>>> print simplejson.dumps(ss)
'"Capit\u00e1n"'
>>> print >> file('f3','w'), simplejson.dumps(ss)
>>> simplejson.load(open('f3'))
u'Capit\xe1n'
Rather than mess with .encode and .decode, specify the encoding when opening the file. The io module, added in Python 2.6, provides an io.open function, which allows specifying the file's encoding.
Supposing the file is encoded in UTF-8, we can use:
>>> import io
>>> f = io.open("test", mode="r", encoding="utf-8")
Then f.read returns a decoded Unicode object:
>>> f.read()
u'Capit\xe1l\n\n'
In 3.x, the io.open function is an alias for the built-in open function, which supports the encoding argument (it does not in 2.x).
We can also use open from the codecs standard library module:
>>> import codecs
>>> f = codecs.open("test", "r", "utf-8")
>>> f.read()
u'Capit\xe1l\n\n'
Note, however, that this can cause problems when mixing read() and readline().
In the notation u'Capit\xe1n\n' (should be just 'Capit\xe1n\n' in 3.x, and must be in 3.0 and 3.1), the \xe1 represents just one character. \x is an escape sequence, indicating that e1 is in hexadecimal.
Writing Capit\xc3\xa1n into the file in a text editor means that it actually contains \xc3\xa1. Those are 8 bytes and the code reads them all. We can see this by displaying the result:
# Python 3.x - reading the file as bytes rather than text,
# to ensure we see the raw data
>>> open('f2', 'rb').read()
b'Capit\\xc3\\xa1n\n'
# Python 2.x
>>> open('f2').read()
'Capit\\xc3\\xa1n\n'
Instead, just input characters like á in the editor, which should then handle the conversion to UTF-8 and save it.
In 2.x, a string that actually contains these backslash-escape sequences can be decoded using the string_escape codec:
# Python 2.x
>>> print 'Capit\\xc3\\xa1n\n'.decode('string_escape')
Capitán
The result is a str that is encoded in UTF-8 where the accented character is represented by the two bytes that were written \\xc3\\xa1 in the original string. To get a unicode result, decode again with UTF-8.
In 3.x, the string_escape codec is replaced with unicode_escape, and it is strictly enforced that we can only encode from a str to bytes, and decode from bytes to str. unicode_escape needs to start with a bytes in order to process the escape sequences (the other way around, it adds them); and then it will treat the resulting \xc3 and \xa1 as character escapes rather than byte escapes. As a result, we have to do a bit more work:
# Python 3.x
>>> 'Capit\\xc3\\xa1n\n'.encode('ascii').decode('unicode_escape').encode('latin-1').decode('utf-8')
'Capitán\n'
Now all you need in Python3 is open(Filename, 'r', encoding='utf-8')
[Edit on 2016-02-10 for requested clarification]
Python3 added the encoding parameter to its open function. The following information about the open function is gathered from here: https://docs.python.org/3/library/functions.html#open
open(file, mode='r', buffering=-1,
encoding=None, errors=None, newline=None,
closefd=True, opener=None)
Encoding is the name of the encoding used to decode or encode the
file. This should only be used in text mode. The default encoding is
platform dependent (whatever locale.getpreferredencoding()
returns), but any text encoding supported by Python can be used.
See the codecs module for the list of supported encodings.
So by adding encoding='utf-8' as a parameter to the open function, the file reading and writing is all done as utf8 (which is also now the default encoding of everything done in Python.)
So, I've found a solution for what I'm looking for, which is:
print open('f2').read().decode('string-escape').decode("utf-8")
There are some unusual codecs that are useful here. This particular reading allows one to take UTF-8 representations from within Python, copy them into an ASCII file, and have them be read in to Unicode. Under the "string-escape" decode, the slashes won't be doubled.
This allows for the sort of round trip that I was imagining.
This works for reading a file with UTF-8 encoding in Python 3.2:
import codecs
f = codecs.open('file_name.txt', 'r', 'UTF-8')
for line in f:
print(line)
# -*- encoding: utf-8 -*-
# converting a unknown formatting file in utf-8
import codecs
import commands
file_location = "jumper.sub"
file_encoding = commands.getoutput('file -b --mime-encoding %s' % file_location)
file_stream = codecs.open(file_location, 'r', file_encoding)
file_output = codecs.open(file_location+"b", 'w', 'utf-8')
for l in file_stream:
file_output.write(l)
file_stream.close()
file_output.close()
Aside from codecs.open(), io.open() can be used in both 2.x and 3.x to read and write text files. Example:
import io
text = u'á'
encoding = 'utf8'
with io.open('data.txt', 'w', encoding=encoding, newline='\n') as fout:
fout.write(text)
with io.open('data.txt', 'r', encoding=encoding, newline='\n') as fin:
text2 = fin.read()
assert text == text2
To read in an Unicode string and then send to HTML, I did this:
fileline.decode("utf-8").encode('ascii', 'xmlcharrefreplace')
Useful for python powered http servers.
Well, your favorite text editor does not realize that \xc3\xa1 are supposed to be character literals, but it interprets them as text. That's why you get the double backslashes in the last line -- it's now a real backslash + xc3, etc. in your file.
If you want to read and write encoded files in Python, best use the codecs module.
Pasting text between the terminal and applications is difficult, because you don't know which program will interpret your text using which encoding. You could try the following:
>>> s = file("f1").read()
>>> print unicode(s, "Latin-1")
Capitán
Then paste this string into your editor and make sure that it stores it using Latin-1. Under the assumption that the clipboard does not garble the string, the round trip should work.
You have stumbled over the general problem with encodings: How can I tell in which encoding a file is?
Answer: You can't unless the file format provides for this. XML, for example, begins with:
<?xml encoding="utf-8"?>
This header was carefully chosen so that it can be read no matter the encoding. In your case, there is no such hint, hence neither your editor nor Python has any idea what is going on. Therefore, you must use the codecs module and use codecs.open(path,mode,encoding) which provides the missing bit in Python.
As for your editor, you must check if it offers some way to set the encoding of a file.
The point of UTF-8 is to be able to encode 21-bit characters (Unicode) as an 8-bit data stream (because that's the only thing all computers in the world can handle). But since most OSs predate the Unicode era, they don't have suitable tools to attach the encoding information to files on the hard disk.
The next issue is the representation in Python. This is explained perfectly in the comment by heikogerlach. You must understand that your console can only display ASCII. In order to display Unicode or anything >= charcode 128, it must use some means of escaping. In your editor, you must not type the escaped display string but what the string means (in this case, you must enter the umlaut and save the file).
That said, you can use the Python function eval() to turn an escaped string into a string:
>>> x = eval("'Capit\\xc3\\xa1n\\n'")
>>> x
'Capit\xc3\xa1n\n'
>>> x[5]
'\xc3'
>>> len(x[5])
1
As you can see, the string "\xc3" has been turned into a single character. This is now an 8-bit string, UTF-8 encoded. To get Unicode:
>>> x.decode('utf-8')
u'Capit\xe1n\n'
Gregg Lind asked: I think there are some pieces missing here: the file f2 contains: hex:
0000000: 4361 7069 745c 7863 335c 7861 316e Capit\xc3\xa1n
codecs.open('f2','rb', 'utf-8'), for example, reads them all in a separate chars (expected) Is there any way to write to a file in ASCII that would work?
Answer: That depends on what you mean. ASCII can't represent characters > 127. So you need some way to say "the next few characters mean something special" which is what the sequence "\x" does. It says: The next two characters are the code of a single character. "\u" does the same using four characters to encode Unicode up to 0xFFFF (65535).
So you can't directly write Unicode to ASCII (because ASCII simply doesn't contain the same characters). You can write it as string escapes (as in f2); in this case, the file can be represented as ASCII. Or you can write it as UTF-8, in which case, you need an 8-bit safe stream.
Your solution using decode('string-escape') does work, but you must be aware how much memory you use: Three times the amount of using codecs.open().
Remember that a file is just a sequence of bytes with 8 bits. Neither the bits nor the bytes have a meaning. It's you who says "65 means 'A'". Since \xc3\xa1 should become "à" but the computer has no means to know, you must tell it by specifying the encoding which was used when writing the file.
The \x.. sequence is something that's specific to Python. It's not a universal byte escape sequence.
How you actually enter in UTF-8-encoded non-ASCII depends on your OS and/or your editor. Here's how you do it in Windows. For OS X to enter a with an acute accent you can just hit option + E, then A, and almost all text editors in OS X support UTF-8.
You can also improve the original open() function to work with Unicode files by replacing it in place, using the partial function. The beauty of this solution is you don't need to change any old code. It's transparent.
import codecs
import functools
open = functools.partial(codecs.open, encoding='utf-8')
I was trying to parse iCal using Python 2.7.9:
from icalendar import Calendar
But I was getting:
Traceback (most recent call last):
File "ical.py", line 92, in parse
print "{}".format(e[attr])
UnicodeEncodeError: 'ascii' codec can't encode character u'\xe1' in position 7: ordinal not in range(128)
and it was fixed with just:
print "{}".format(e[attr].encode("utf-8"))
(Now it can print liké á böss.)
I found the most simple approach by changing the default encoding of the whole script to be 'UTF-8':
import sys
reload(sys)
sys.setdefaultencoding('utf8')
any open, print or other statement will just use utf8.
Works at least for Python 2.7.9.
Thx goes to https://markhneedham.com/blog/2015/05/21/python-unicodeencodeerror-ascii-codec-cant-encode-character-uxfc-in-position-11-ordinal-not-in-range128/ (look at the end).
I have a very simple piece of code that's converting a csv....also do note i reference notepad++ a few times but my standard IDE is vs-code.
with codecs.open(filePath, "r", encoding = "UTF-8") as sourcefile:
lines = sourcefile.read()
with codecs.open(filePath, 'w', encoding = 'cp1252') as targetfile:
targetfile.write(lines)
Now the job I'm doing requires a specific file be encoded to windows-1252 and from what i understand cp1252=windows-1252. Now this conversion works fine when i do it using the UI features in notepad++, but when i try using python codecs to encode this file it fails;
UnicodeEncodeError: 'charmap' codec can't encode character '\ufffd' in position 561488: character maps to <undefined>
When i saw this failure i was confused, so i double checked the output from when i manually convert the file using notepad++, and the converted file is encoded in windows-1252.....so what gives? Why can a UI feature in notepad++ able to do the job when but codecs seems not not be able to? Does notepad++ just ignore errors?
Looks like your input text has the character "�" (the actual placeholder "replacement character" character, not some other undefined character), which cannot be mapped to cp1252 (because it doesn't have the concept).
Depending on what you need, you can:
Filter it out (or replace it, or otherwise handle it) in Python before writing out lines to the output file.
Pass errors=... to the second codecs.open, choosing one of the other error-handling modes; the default is 'strict', you can also use 'ignore', 'replace', 'xmlcharrefreplace', 'backslashreplace' or 'namereplace'.
Check the input file and see why it's got the "�" character; is it corrupted?
Probably Python is simply more explicit in its error handling. If Notepad++ managed to represent every character correctly in CP-1252 then there is a bug in the Python codec where it should not fail where it currently does; but I'm guessing Notepad++ is silently replacing some characters with some other characters, and falsely claiming success.
Maybe try converting the result back to UTF-8 and compare the files byte by byte if the data is not easy to inspect manually.
Uncode U+FFFD is a reserved character which serves as a placeholder for a character which cannot be represented in Unicode; often, it's an indication of a conversion problem previously, when presumably this data was imperfectly input or converted at an earlier point in time.
(And yes, Windows-1252 is another name for Windows code page 1252.)
Why notepad++ "succeeds"
Notepad++ does not offer you to convert your file to cp1252, but to reinterpret it using this encoding. What lead to your confusion is that they are actually using the wrong term for this. This is the encoding menu in the program:
When "Encode with cp1252" is selected, Notepad decodes the file using cp1252 and shows you the result. If you save the character '\ufffd' to a file using utf8:
with open('f.txt', 'w', encoding='utf8') as f:
f.write('\ufffd')`
and use "Encode with cp1252" you'd see three characters:
That means that Notepad++ does not read the character in utf8 and then writes it in cp1252, because then you'd see exactly one character. You could achieve similar results to Notepad++ by reading the file using cp1252:
with open('f.txt', 'r', encoding='cp1252') as f:
print(f.read()) # Prints �
Notepad++ lets you actually convert to only five encodings, as you can see in the screenshot above.
What should you do
This character does not exist in the cp1252 encoding, which means you can't convert this file without losing information. Common solutions are to skip such characters or replace them with other similar characters that exist in your encoding (see encoding error handlers)
You are dealing with the "utf-8-sig" encoding -- please specify this one as the encoding argument instead of "utf-8".
There is information on it in the docs (search the page for "utf-8-sig").
To increase the reliability with which a UTF-8 encoding can be detected, Microsoft invented a variant of UTF-8 (that Python 2.5 calls "utf-8-sig") for its Notepad program: Before any of the Unicode characters is written to the file, a UTF-8 encoded BOM (which looks like this as a byte sequence: 0xef, 0xbb, 0xbf) is written. [...]
I need to read specified rows and columns of csv file and write into txt file.But I got an unicode decode error.
import csv
with open('output.csv', 'r', encoding='utf-8') as f:
reader = csv.reader(f)
your_list = list(reader)
print(your_list)
The reason for this error is perhaps that your CSV file does not use UTF-8 encoding. Find out the original encoding used for your document.
First of all, try using the default encoding by leaving out the encoding parameter:
with open('output.csv', 'r') as f:
...
If that does not work, try alternative encoding schemes that are commonly used, for example:
with open('output.csv', 'r', encoding="ISO-8859-1") as f:
...
If you get a unicode decode error with this code, it is likely that the csv file is not utf-8 encoded... The correct fix is to find what is the correct encoding and use it.
If you only want quick and dirty workarounds, Python offers the errors=... option of open. From the documentation of open function in the standard library:
'strict' to raise a ValueError exception if there is an encoding error. The default value of None has the same effect.
'ignore' ignores errors. Note that ignoring encoding errors can lead to data loss.
'replace' causes a replacement marker (such as '?') to be inserted where there is malformed data.
'surrogateescape' will represent any incorrect bytes as code points in the Unicode Private Use Area ranging from U+DC80 to U+DCFF. These private code points will then be turned back into the same bytes when the surrogateescape error handler is used when writing data. This is useful for processing files in an unknown encoding.
'xmlcharrefreplace' is only supported when writing to a file. Characters not supported by the encoding are replaced with the appropriate XML character reference &#nnn;.
'backslashreplace' replaces malformed data by Python’s backslashed escape sequences.
'namereplace' (also only supported when writing) replaces unsupported characters with \N{...} escape sequences.
I often use errors='replace', when I only want to know that there were erroneous bytes or errors='backslashreplace' when I want to know what they were.
I've noticed recently that Python behaves in such non-obvious way when appending to the file using utf-8-sig encoding. See below:
>>> import codecs, os
>>> os.path.isfile('123')
False
>>> codecs.open('123', 'a', encoding='utf-8-sig').write('123\n')
>>> codecs.open('123', 'a', encoding='utf-8-sig').write('123\n')
The following text ends up to the file:
<BOM>123
<BOM>123
Isn't that a bug? This is so not logical.
Could anyone explain to me why it was done so?
Why didn't they manage to prepend BOM only when file doesn't exist and needs to be created?
No, it's not a bug; that's perfectly normal, expected behavior. The codec cannot detect how much was already written to a file; you could use it to append to a pre-created but empty file for example. The file would not be new, but it would not contain a BOM either.
Then there are other use-cases where the codec is used on a stream or bytestring (e.g. not with codecs.open()) where there is no file at all to test, or where the developer wants to enforce a BOM at the start of the output, always.
Only use utf-8-sig on a new file; the codec will always write the BOM out whenever you use it.
If you are working directly with files, you can test for the start yourself; use utf-8 instead and write the BOM manually, which is just an encoded U+FEFF ZERO WIDTH NO-BREAK SPACE:
import io
with io.open(filename, 'a', encoding='utf8') as outfh:
if outfh.tell() == 0:
# start of file
outfh.write(u'\ufeff')
I used the newer io.open() instead of codecs.open(); io is the new I/O framework developed for Python 3, and is more robust than codecs for handling encoded files, in my experience.
Note that the UTF-8 BOM is next to useless, really. UTF-8 has no variable byte order, so there is only one Byte Order Mark. UTF-16 or UTF-32, on the other hand, can be written with one of two distinct byte orders, which is why a BOM is needed.
The UTF-8 BOM is mostly used by Microsoft products to auto-detect the encoding of a file (e.g. not one of the legacy code pages).
I'm reading in a CSV file that has UTF8 encoding:
ifile = open(fname, "r")
for row in csv.reader(ifile):
name = row[0]
print repr(row[0])
This works fine, and prints out what I expect it to print out; a UTF8 encoded str:
> '\xc3\x81lvaro Salazar'
> '\xc3\x89lodie Yung'
...
Furthermore when I simply print the str (as opposed to repr()) the output displays ok (which I don't understand eitherway - shouldn't this cause an error?):
> Álvaro Salazar
> Élodie Yung
but when I try to convert my UTF8 encoded strs to unicode:
ifile = open(fname, "r")
for row in csv.reader(ifile):
name = row[0]
print unicode(name, 'utf-8') # or name.decode('utf-8')
I get the infamous:
Traceback (most recent call last):
File "scripts/script.py", line 33, in <module>
print unicode(fullname, 'utf-8')
UnicodeEncodeError: 'ascii' codec can't encode character u'\xc1' in position 0: ordinal not in range(128)
So I looked at the unicode strings that are created:
ifile = open(fname, "r")
for row in csv.reader(ifile):
name = row[0]
unicode_name = unicode(name, 'utf-8')
print repr(unicode_name)
and the output is
> u'\xc1lvaro Salazar'
> u'\xc9lodie Yung'
So now I'm totally confused as these seem to be mangled hex values. I've read this question:
Reading a UTF8 CSV file with Python
and it appears I am doing everything correctly, leading me to believe that my file is not actually UTF8, but when I initially print out the repr values of the cells, they appear to to correct UTF8 hex values. Can anyone either point out my problem or indicate where my understanding is breaking down (as I'm starting to get lost in the jungle of encodings)
As an aside, I believe I could use codecs to open the file and read it directly into unicode objects, but the csv module doesn't support unicode natively so I can use this approach.
Your default encoding is ASCII. When you try to print a unicode object, the interpreter therefore tries to encode it using the ASCII codec, which fails because your text includes characters that don't exist in ASCII.
The reason that printing the UTF-8 encoded bytestring doesn't produce an error (which seems to confuse you, although it shouldn't) is that this simply sends the bytes to your terminal. It will never produce a Python error, although it may produce ugly output if your terminal doesn't know what to do with the bytes.
To print a unicode, use print some_unicode.encode('utf-8'). (Or whatever encoding your terminal is actually using).
As for the u'\xc1lvaro Salazar', nothing here is mangled. The character Á is at the unicode codepoint C1 (which has nothing to do with it's UTF-8 representation, but happens to be the same value as in Latin-1), and Python uses \x hex escapes instead of \u unicode codepoint notation for codepoints that would have 00 as the most significant byte to save space (it could also have displayed this as \u00c1.)
To get a good overview of how Unicode works in Python, I suggest http://nedbatchelder.com/text/unipain.html