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How do I get this If statement condition to work properly? [closed]

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I'm having a problem with the following piece of code:
decision = str(input("Would you like to change it?:"))
if decision.lower == 'yes':
new_holiday = input("What is your new favorite holiday?:")
The problem with this is that when I input 'yes' in the first prompt, instead of showing me the second one as I want, it just skips the if statement completely. Am I missing something here?

decision.lower generates a method <built-in method lower of str object at ...>. you should call decision.lower().
Change your code to the following:
decision = str(input("Would you like to change it?:"))
if decision.lower() == 'yes':
new_holiday = input("What is your new favorite holiday?:")

decision.lower() user this method which will return a lower cased string.
decision = input("Would you like to change it?:")
if decision.lower() == 'yes':
new_holiday = input("What is your new favorite holiday?:")

Python returns None to input [closed]

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Hey so I’m writing a text-adventure game in python and made a typingprint function to make the text look like it was typed out. But when I try to use this function with inputs it will reply with None.
import random
import time
import console
import sound
import sys
def typingPrint(text):
for character in text:
sys.stdout.write(character)
sys.stdout.flush()
time.sleep(0.05)
console.set_color()
typingPrint('Hello! My name is Sawyer and I will be your guide
throughout this game. Heres a helpful hint, every time you enter
room you will have to battle a enemy.')
time.sleep(3)
player_name = input(typingPrint('\nBefore we begin why don\'t
you tell me your name: '))
How can I fix this?

This is because your function doesn't return anything so there is no text in the input prompt. To solve it, you will need to first call your function, then the input -
typingPrint('Hello! My name is Sawyer and I will be your guide throughout this game. Heres a helpful hint every time you enter a room you will have to battle a enemy.')
time.sleep(3)
typingPrint('\nBefore we begin why dont you tell me your name: ')
player_name = input()

Why do I get "NameError: name 'B'/'C'/'V' is not defined"? [closed]

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Question = input("Welcome to the meal chooser program. The base cost is $9.99. Would you like to choose beef, chicken, or the vegetarian option?:")
if Question.casefold() == "beef":
print("Thank you. Your total cost is","$",'{:.2f}'.format(B))
elif Question.casefold() == "chicken":
print("Thank you. Your total cost is","$", '{:.2f}'.format(C))
elif Question.casefold() == "vegetarian":
print("Thank you. Your total cost is","$", '{:.2f}'.format(V))
B = 9.99*1.02
C = 9.99*1.025
V = 9.99*1.03
Whenever I run this and input chicken, beef, or vegetarian it prompts me with a message that says that the values of B, C, and V are not defined, but they are.

Code runs (barring jumps like function calls and class initializations) linearly, top down. Because you initialize your variables at the bottom, your code has not created the values when you arrive at your if-else block. If you put your variables first, the code will run fine.

Syntax error for down()? [closed]

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I'm a beginner computer science student and using python in computer science 1. My assignment is to write a program that creates a spirograph. I think that the code is all right to do that, but when i run it, an error message pops up that says syntax error and it highlights down(), which is a common turtle command. I have no idea why. It said syntax error for main(), but then i restarted python and now it says there's an error in down(). Here's the code:
from turtle import *
from math import *
def xValue(R,r,p,t):
x=(R-r)*cos(t)-(r+p)*cos((R-r)/r*t)
def yValue(R,r,p,t):
y=(R-r)*sin(t)-(r+p)*sin((R-r)/r*t)
def initialPosistion():
t=2*pi
up()
goto(xValue(R,r,p,t),yValue(R,r,p,t)
down()
def iterating(R,r,p):
t = 2*pi
while t < 0:
t = t-0.01
goto(xValue(R,r,p,t),yValue(R,r,p,t)
up()
def main():
R = 100
r = 4
p = int(input("Enter p(10-100): "))
if p < 10 or p > 100:
input("Incorrect value for p!")
iterating(R,r,p)
input("Hit enter to close...")
main()

Missed a closing ) at the end of this line:
goto(xValue(R,r,p,t),yValue(R,r,p,t))

Python autocomplete user input [closed]

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I have a list of teamnames. Let's say they are
teamnames=["Blackpool","Blackburn","Arsenal"]
In the program I ask the user which team he would like to do stuff with. I want python to autocomplete the user's input if it matches a team and print it.
So if the user writes "Bla" and presses enter, the team Blackburn should automatically be printed in that space and used in the rest of the code. So for example;
Your choice: Bla (User writes "Bla" and presses enter)
What it should look like
Your Choice: Blackburn (The program finishes the rest of the word)

teamnames=["Blackpool","Blackburn","Arsenal"]
user_input = raw_input("Your choice: ")
# You have to handle the case where 2 or more teams starts with the same string.
# For example the user input is 'B'. So you have to select between "Blackpool" and
# "Blackburn"
filtered_teams = filter(lambda x: x.startswith(user_input), teamnames)
if len(filtered_teams) > 1:
# Deal with more that one team.
print('There are more than one team starting with "{0}"'.format(user_input))
print('Select the team from choices: ')
for index, name in enumerate(filtered_teams):
print("{0}: {1}".format(index, name))
index = input("Enter choice number: ")
# You might want to handle IndexError exception here.
print('Selected team: {0}'.format(filtered_teams[index]))
else:
# Only one team found, so print that team.
print filtered_teams[0]

That depends on your usecase. If your program is commandline based, you can do that at least by using the readline module and pressing TAB. This link also provides some well explained examples on that since its Doug Hellmanns PyMOTW. If you are trying that via a GUI it depends on the API you are using. In that case you need to deliver some more details please.