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I want get all link in one web page ,this function only one link but need get all link ! of course i know need The One Ring true but i don't know use
i need get all link
def get_next_target(page):
start_link = page.find('<a href=')
start_quote = page.find('"', start_link)
end_quote = page.find('"', start_quote + 1)
url = page[start_quote + 1:end_quote]
return url, end_quote
This is where a HTML parser comes in handy. I recommend BeautifulSoup:
from bs4 import BeautifulSoup as BS
def get_next_target(page)
soup = BS(page)
return soup.find_all('a', href=True)
You may use lxml for that:
import lxml.html
def get_all_links(page):
document = lxml.html.parse(page)
return document.xpath("//a")
site = urllib.urlopen('http://somehwere/over/the/rainbow.html')
site_data = site.read()
for link in BeautifulSoup(site_data, parseOnlyThese=SoupStrainer('a')):
if link.has_attr('href'):
print(link['href'])
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I am making python script which getting text data from online site.
this is simple web scraping script and the language is only python.
I don't use selenium and use only beautifulsoup.
and I can scrape text from <p> or <div> or even <h> and <a>
but when I try to get text from <td>, the code is not working.
I shared my code below.
from threading import Thread
from bs4 import BeautifulSoup
from lxml import etree
detailPage = requests.get(SUBURL, headers=HEADERS)
detailsoup = BeautifulSoup(detailPage.content, "html.parser")
detaildom = etree.HTML(str(detailsoup))
name = detaildom.xpath('//*[#id="productTitle"]')[0].text
asin = detaildom.xpath('//*[#id="productDetails_detailBullets_sections1"]/tbody/tr[1]/td')[0].text
here, getting name is working, asin return empty string.
You can find the table by its ID productDetails_detailBullets_sections1 and find the <td> which contains the "ASIN".
Using a CSS selector:
soup = BeautifulSoup(requests.get(url, headers=headers).content, "html.parser")
print("ASIN:", soup.select_one("#productDetails_db_sections tr > td").get_text(strip=True))
Using .find():
soup = BeautifulSoup(requests.get(url, headers=headers).content, "html.parser")
table_info = soup.find(id="productDetails_detailBullets_sections1").find("tr")
print("ASIN:", table_info.find('td').get_text(strip=True))
Output (in both solutions):
ASIN: B079LWYC17
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I need a way to extract url from the list at this web page https://iota-nodes.net/
using Python. I tried BeautifulSoup but without success.
My code is:
from bs4 import BeautifulSoup, SoupStrainer
import requests
url = "https://iota-nodes.net/"
page = requests.get(url)
data = page.text
soup = BeautifulSoup(data)
for link in soup.find_all('a'):
print(link.get('href'))
No need for BeautifulSoup, as the data is coming from an AJAX request. Something like this should work:
import requests
response = requests.get('https://api.iota-nodes.net/')
data = response.json()
hostnames = [node['hostname'] for node in data]
Note that the data comes from an API endpoint being https://api.iota-nodes.net/.
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My question is about searching through html format with Python.
I am using this code:
with urllib.request.urlopen("http://") as url:
data = url.read().decode()
now this returns the whole HTML code from the page and I want to extract all email-addresses.
Can somebody lend me a hand here?
Thanks in advance
Using beautifulsoup BeautifulSoup And Requests you could do this:
import requests
from bs4 import BeautifulSoup
import re
response = requests.get("your_url")
response_text = response.text
beautiful_response = BeautifulSoup(response_text, 'html.parser')
email_regex = r'[a-zA-Z0-9_.+-]+#[a-zA-Z0-9-]+\.[a-zA-Z0-9-.]+'
list_of_emails = re.findall(email_regex, beautiful_response .text)
list_of_emails_decoded = []
for every_email in list_of_emails:
list_of_emails_decoded.append(every_email.encode('utf-8'))
Remember that you should not use regex for actual HTML parsing (Thanks #Patrick Artner), but you can use beautiful soup to extract all visible text or comments on a web page. Then you can use this text (which is just a string) to look for email addresses. Here is how you can do it:
from bs4 import BeautifulSoup
from bs4.element import Comment
import urllib
import re
def tag_visible(element):
if element.parent.name in ['style', 'script', 'head', 'title', 'meta', '[document]']:
return False
if isinstance(element, Comment):
return False
return True
def text_from_html(body):
soup = BeautifulSoup(body, 'html.parser')
texts = soup.findAll(text=True)
visible_texts = filter(tag_visible, texts)
return u" ".join(t.strip() for t in visible_texts)
with urllib.request.urlopen("https://en.wikipedia.org/wiki/Email_address") as url:
data = url.read().decode()
text = text_from_html(data)
print(re.findall(r"[a-zA-Z0-9.!#$%&'*+/=?^_`{|}~-]+#[a-zA-Z0-9](?:[a-zA-Z0-9-]{0,61}[a-zA-Z0-9])?(?:\.[a-zA-Z0-9](?:[a-zA-Z0-9-]{0,61}[a-zA-Z0-9])?)*", text))
The two helper functions just grab all text that can be seen on the page, and then the ridiculously long regex just pulls all email addresses from that text. I used wikipedia.com's article on emails as an example, and here is the output:
['John.Smith#example.com', 'local-part#domain', 'jsmith#example.com', 'john.smith#example.org', 'local-part#domain', 'John..Doe#example.com', 'fred+bah#domain', 'fred+foo#domain', 'fred#domain', 'john.smith#example.com', 'john.smith#example.com', 'jsmith#example.com', 'JSmith#example.com', 'john.smith#example.com', 'john.smith#example.com', 'prettyandsimple#example.com', 'very.common#example.com', 'disposable.style.email.with+symbol#example.com', 'other.email-with-dash#example.com', 'fully-qualified-domain#example.com', 'user.name+tag+sorting#example.com', 'user.name#example.com', 'x#example.com', 'example-indeed#strange-example.com', 'admin#mailserver1', "#!$%&'*+-/=?^_`{}|~#example.org", 'example#s.solutions', 'user#localserver', 'A#b', 'c#example.com', 'l#example.com', 'right#example.com', 'allowed#example.com', 'allowed#example.com', '1234567890123456789012345678901234567890123456789012345678901234+x#example.com', 'john..doe#example.com', 'example#localhost', 'john.doe#example', 'joeuser+tag#example.com', 'joeuser#example.com', 'foo+bar#example.com', 'foobar#example.com']
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What I am trying to do is find all the hyper links of a web page here is what I have so far but it does not work
from urllib.request import urlopen
def findHyperLinks(webpage):
link = "Not found"
encoding = "utf-8"
for webpagesline in webpage:
webpagesline = str(webpagesline, encoding)
if "<a href>" in webpagesline:
indexstart = webpagesline.find("<a href>")
indexend = webpagesline.find("</a>")
link = webpagesline[indexstart+7:indexend]
return link
return link
def main():
address = input("Please enter the adress of webpage to find the hyperlinks")
try:
webpage = urlopen(address)
link = findHyperLinks(webpage)
print("The hyperlinks are", link)
webpage.close()
except Exception as exceptObj:
print("Error:" , str(exceptObj))
main()
There are multiple problems in your code. One of them is that you are trying to find links with present, empty and the only one href attribute: <a href>.
Anyway, if you would use an HTML parser (well, to parse HTML), things would get much more easy and reliable. Example using BeautifulSoup:
from bs4 import BeautifulSoup
from urllib.request import urlopen
soup = BeautifulSoup(urlopen(address))
for link in soup.find_all("a", href=True):
print(link["href"], link.get_text())
Without BeautifulSoap you can use RegExp and simple function.
from urllib.request import urlopen
import re
def find_link(url):
response = urlopen(url)
res = str(response.read())
my_dict = re.findall('(?<=<a href=")[^"]*', res)
for x in my_dict:
# simple skip page bookmarks, like #about
if x[0] == '#':
continue
# simple control absolute url, like /about.html
# also be careful with redirects and add more flexible
# processing, if needed
if x[0] == '/':
x = url + x
print(x)
find_link('http://cnn.com')
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I want to use a HTML parser like beautiful soup (python) to get the contents of a specific div, store all data within it in my local server by running a python script that will be executed regularly on my web server by cron.
Also, I need to be able to show those contents exactly as they were shown in the webpage before on my web site.
If the contents of the div is text alone, it would be easy enough but it is a combination of text and image.
Although there are occasionally swf files, I do not wish to import them.
Let's say the div in question is called 'cont'.
What would be the best way to do this?
Luckily i have a spider which does exactly what you need to do.
from soup import BeautifulSoup as bs
from scrapy.http import Request
from scrapy.spider import BaseSpider
from hn.items import HnItem
class HnSpider(BaseSpider):
name = 'hn'
allowed_domains = []
start_urls = ['http://news.ycombinator.com']
def parse(self, response):
if 'news.ycombinator.com' in response.url:
soup = bs(response.body)
items = [(x[0].text, x[0].get('href')) for x in
filter(None, [
x.findChildren() for x in
soup.findAll('td', {'class': 'title'})
])]
for item in items:
print item
hn_item = HnItem()
hn_item['title'] = item[0]
hn_item['link'] = item[1]
try:
yield Request(item[1], callback=self.parse)
except ValueError:
yield Request('http://news.ycombinator.com/' + item[1], callback=self.parse)
yield hn_item
Refer the Github link to know more.