NEWBIE USING PYTHON (2.7.9)- When I export a gzipped file to a csv using:
myData = gzip.open('file.gz.DONE', 'rb')
myFile = open('output.csv', 'wb') with myFile:
writer = csv.writer(myFile)
writer.writerows(myData)
print("Writing complete")
It is printing in the csv with a comma deliminated in every character. eg.
S,V,R,","2,1,4,0,",",2,0,1,6,1,1,3,8,0,4,",",5,0,5,0,1,3,4,2,0,6,4,7,3,6,4,",",",",2,0,0,0,5,6,5,9,2,9,6,7,4,",",2,0,0,7,2,4,5,2,3,5,",",0,0,0,2,","
I,V,E,",",",",",",E,N,",",N,/,A,",",0,4,2,1,4,4,9,3,7,0,",":,I,R,_,",",N,/,A,",",U,N,A,N,S,W,",",",",",",",","
"
S,V,R,",",4,7,3,3,5,5,",",2,0,5,7,",",5,0,5,0,1,4,5,0,1,6,4,8,6,3,7,",",",",2,0,0,0,5,5,3,9,2,9,2,8,0,",",2,0,4,4,1,0,8,3,7,8,",",0,0,0,2,","
I,V,E,",",",",",",E,N,",",N,/,A,",",0,4,4,7,3,3,5,4,5,5,",",,:,I,R,_,",",N,/,A,",",U,N,A,N,S,W,",",",",",",",","
How do I get rid of the comma so that it is exported with the correct fields? eg.
SVR,2144370,20161804,50501342364,,565929674,2007245235,0002,1,PPDAP,PPLUS,DEACTIVE,,,EN,N/A,214370,:IR_,N/A,,,,,
SVR,473455,208082557,14501648637,,2000553929280,2044108378,0002,1,3G,CODAP,INACTIVE,,,EN,N/A,35455,:IR_,N/A,,,,,
You are only opening the gzip file. I think you are expecting the opened file to act automatically like an iterator. Which it does. However each line is a text string. The writerows expects an iterator with each item being an array of values to write with comma separation. Thus given an iterator with each item being a sting, and given that a string is an array of characters you get the result you found.
Since you didn't mention what the gzip data lines really contain I can't guess how to parse the lines into an array of reasonable chunks. But assuming a function called 'split_line' appropriate to that data you could do
with gzip.open('file.gz.Done', 'rb') as gzip_f:
data = [split_line(l) for l in gzip_f]
with open('output.csv', 'wb') as myFile:
writer = csv.writer(myFile)
writer.writerows(data)
print("Writing complete")
Of course at this point doing row by row and putting the with lines together makes sense.
See https://docs.python.org/2/library/csv.html
I think it's simply because gzip.open() will give you a file-like object but csvwriter.writerows() needs a list of lists of strings to do its work.
But I don't understand why you want to use the csv module. You look like you only want to extract the content of the gzip file and save it in a output file uncompressed. You could do that like that:
import gzip
input_file_name = 'file.gz.DONE'
output_file_name = 'output.csv'
with gzip.open(input_file_name, 'rt') as input_file:
with open('output.csv', 'wt') as output_file:
for line in input_file:
output_file.write(line)
print("Writing complete")
If you want to use the csv module because you're not sure your input data is properly formatted (and you want an error message right away) you could then do:
import gzip
import csv
input_file_name = 'file.gz.DONE'
output_file_name = 'output.csv'
with gzip.open(input_file_name, 'rt', newline='') as input_file:
reader_csv = csv.reader(input_file)
with open('output.csv', 'wt', newline='') as output_file:
writer_csv = csv.writer(output_file)
writer_csv.writerows(reader_csv)
print("Writing complete")
Is that what you were trying to do ? It's difficult to guess because we don't have the input file to understand.
If it's not what you want, could you care to clarify what you want?
Since I now have information the gzipped file is itself comma, separated values it simplifies thus..
with gzip.open('file.gz.DONE', 'rb') as gzip_f, open('output.csv', 'wb') as myFile:
myfile.write(gzip_f.read())
In other words it is just a round about gunzip to another file.
I am currently trying to write a csv file in python. The format is as following:
1; 2.51; 12
123; 2.414; 142
EDIT: I already get the above format in my CSV, so the python code seems ok. It appears to be an excel issue which is olved by changing the settigs as #chucksmash mentioned.
However, when I try to open the generated csv file with excel, it doesn't recognize decimal separators. 2.414 is treated as 2414 in excel.
csvfile = open('C:/Users/SUUSER/JRITraffic/Data/data.csv', 'wb')
writer = csv.writer(csvfile, delimiter=";")
writer.writerow(some_array_with_floats)
Did you check that the csv file is generated correctly as you want? Also, try to specify the delimeter character that your using for the csv file when you import/open your file. In this case, it is a semicolon.
For python 3, I think your above code will also run into a TypeError, which may be part of the problem.
I just made a modification with your open method to be 'w' instead of 'wb' since the array has float and not binary data. This seemed to generate the result that you were looking for.
csvfile = open('C:/Users/SUUSER/JRITraffic/Data/data.csv', 'w')
An ugly solution, if you really want to use ; as the separator:
import csv
import os
with open('a.csv', 'wb') as csvfile:
csvfile.write('sep=;'+ os.linesep) # new line
writer = csv.writer(csvfile, delimiter=";")
writer.writerow([1, 2.51, 12])
writer.writerow([123, 2.414, 142])
This will produce:
sep=;
1;2.51;12
123;2.414;142
which is recognized fine by Excel.
I personally would go with , as the separator in which case you do not need the first line, so you can basically:
import csv
with open('a.csv', 'wb') as csvfile:
writer = csv.writer(csvfile) # default delimiter is `,`
writer.writerow([1, 2.51, 12])
writer.writerow([123, 2.414, 142])
And excel will recognize what is going on.
A way to do this is to specify dialect=csv.excel in the writer. For example:
a = [[1, 2.51, 12],[123, 2.414, 142]]
csvfile = open('data.csv', 'wb')
writer = csv.writer(csvfile, delimiter=";", dialect=csv.excel)
writer.writerows(a)
csvfile.close()
Unless Excel is already configured to use semicolon as its default delimiter, it will be necessary to import data.csv using Data/FromText and specify semicolon as the delimiter in the Text Import Wizard step 2 screen.
Very little documentation is provided for the Dialect class at csv.Dialect. More information about it is at Dialects in the PyMOTW's "csv – Comma-separated value files" article on the Python csv module. More information about csv.writer() is available at https://docs.python.org/2/library/csv.html#csv.writer.
I am extremely new to python 3 and I am learning as I go here. I figured someone could help me with a basic question: how to store text from a CSV file as a variable to be used later in the code. So the idea here would be to import a CSV file into the python interpreter:
import csv
with open('some.csv', 'rb') as f:
reader = csv.reader(f)
for row in reader:
...
and then extract the text from that file and store it as a variable (i.e. w = ["csv file text"]) to then be used later in the code to create permutations:
print (list(itertools.permutations(["w"], 2)))
If someone could please help and explain the process, it would be very much appreciated as I am really trying to learn. Please let me know if any more explanation is needed!
itertools.permutations() wants an iterable (e.g. a list) and a length as its arguments, so your data structure needs to reflect that, but you also need to define what you are trying to achieve here. For example, if you wanted to read a CSV file and produce permutations on every individual CSV field you could try this:
import csv
with open('some.csv', newline='') as f:
reader = csv.reader(f)
w = []
for row in reader:
w.extend(row)
print(list(itertools.permutations(w, 2)))
The key thing here is to create a flat list that can be passed to itertools.permutations() - this is done by intialising w to an empty list, and then extending its elements with the elements/fields from each row of the CSV file.
Note: As pointed out by #martineau, for the reasons explained here, the file should be opened with newline='' when used with the Python 3 csv module.
If you want to use Python 3 (as you state in the question) and to process the CSV file using the standard csv module, you should be careful about how to open the file. So far, your code and the answers use the Python 2 way of opening the CSV file. The things has changed in Python 3.
As shengy wrote, the CSV file is just a text file, and the csv module gets the elements as strings. Strings in Python 3 are unicode strings. Because of that, you should open the file in the text mode, and you should supply the encoding. Because of the nature of CSV file processing, you should also use the newline='' when opening the file.
Now extending the explanation of Burhan Khalid... When reading the CSV file, you get the rows as lists of strings. If you want to read all content of the CSV file into memory and store it in a variable, you probably want to use the list of rows (i.e. list of lists where the nested lists are the rows). The for loop iterates through the rows. The same way the list() function iterates through the sequence (here through the sequence of rows) and build the list of the items. To combine that with the wish to store everything in the content variable, you can write:
import csv
with open('some.csv', newline='', encoding='utf_8') as f:
reader = csv.reader(f)
content = list(reader)
Now you can do your permutation as you wish. The itertools is the correct way to do the permutations.
import csv
data = csv.DictReader(open('FileName.csv', 'r'))
print data.fieldnames
output = []
for each_row in data:
row = {}
try:
p = dict((k.strip(), v) for k, v in p.iteritems() if v.lower() != 'null')
except AttributeError, e:
print e
print p
raise Exception()
//based on the number of column
if p.get('col1'):
row['col1'] = p['col1']
if p.get('col2'):
row['col2'] = p['col2']
output.append(row)
Finally all data stored in output variable
Is this what you need?
import csv
with open('some.csv', 'rb') as f:
reader = csv.reader(f, delimiter=',')
rows = list(reader)
print('The csv file had {} rows'.format(len(rows)))
for row in rows:
do_stuff(row)
do_stuff_to_all_rows(rows)
The interesting line is rows = list(reader), which converts each row from the csv file (which will be a list), into another list rows, in effect giving you a list of lists.
If you had a csv file with three rows, rows would be a list with three elements, each element a row representing each line in the original csv file.
If all you care about is to read the raw text in the file (csv or not) then:
with open('some.csv') as f:
w = f.read()
will be a simple solution to having w="csv, file, text\nwithout, caring, about columns\n"
You should try pandas, which work both with Python 2.7 and Python 3.2+ :
import pandas as pd
csv = pd.read_csv("your_file.csv")
Then you can handle you data easily.
More fun here
First, a csv file is a text file too, so everything you can do with a file, you can do it with a csv file. That means f.read(), f.readline(), f.readlines() can all be used. see detailed information of these functions here.
But, as your file is a csv file, you can utilize the csv module.
# input.csv
# 1,david,enterprise
# 2,jeff,personal
import csv
with open('input.csv') as f:
reader = csv.reader(f)
for serial, name, version in reader:
# The csv module already extracts the information for you
print serial, name, version
More details about the csv module is here.