I need to make a program that the user will enter in any number and then try guess the sum of those digits.
How do i sum up the digits and then compare then to his guess?
I tried this:
userNum = raw_input("Please enter a number:\n")
userGuess = raw_input("The digits sum is:\n")
if sum(userNum, userGuess):
print"Your answer is True"
else:
print "Your answer is False"
and it didnt work
You have 2 problems here :
raw_input() doesn't return an integer, it returns a string. You can't add strings and get an int. You need to find a way to convert your strings to integers, THEN add them.
You are using sum() while using + whould be enough.
Try again, and come back with your results. Don't forget to include error messages and what you think happened.
Assuming you are new to Python and you've read the basics you would use control flow statements to compare the sum and the guess.
Not sure if this is 100% correct, feel free to edit, but it works. Coded it according to his(assuming) beginner level. This is assuming you've studied methods, while loops, raw_input, and control flow statements. Yes there are easier ways as mentioned in the comments but i doubt he's studied map Here's the code;
def sum_digits(n):
s = 0
while n:
s += n % 10
n /= 10
return s
sum_digits(mynumber)
mynumber = int(raw_input("Enter a number, "))
userguess = int(raw_input("Guess the digit sum: "))
if sum_digits(mynumber) == userguess:
print "Correct"
else:
print "Wrong"
Credit to this answer for the method.
Digit sum method in Python
the python code is :
def digit_sum(n):
string = str(n)
total = 0
for value in string:
total += int(value)
return total
and the code doesnot use the API:
def digit_sum1(n):
total=0
m=0
while n:
m=n%10
total+=m
n=(n-m)/10
return total
Firstly you neet to use something such as int(raw_input("Please enter a number:\n")) so the input returns an integer.
Rather than using sum, you can just use + to get the sum of two integers. This will work now that your input is an integer.
Basically I would use a generator function for this
It will iterate over the string you get via raw_input('...') and create a list of the single integers
This list can then be summed up using sum
The generator would look like this:
sum([ int(num) for num in str(raw_input('Please enter a number:\n')) ])
Generators create lists (hence the list-brackets) of the elements prior to the for statement, so you could also take the double using:
[ 2 * int(num) for num in str(raw_input('Please enter a number:\n')) ]
[ int(num) for num in str(123) ] would result in [1,2,3]
but,
[ 2 * int(num) for num in str(123) ] would result in [2,4,6]
Related
First baby steps into Python and I'm stuck. I want to print the absolute value of an integer that is input by the user. If the integer that is input is a negative value, I want it to return a positive value. I'm converting the string to an integer fine, I'm storing the input 'number' fine, but if I input a negative number it's not doing the eval of the if statement and converting to a positive number by * -1 as you see below. I'm at a loss, should I be defining another variable somewhere here?
number = int(input('Please enter a number: '))
if number <= 0:
number = number * -1
I performed the tests on my machine and the operation went correctly. Is it returning an error for you?
As a suggestion, you can also use the abs() function instead of multiplying by -1 to return the absolute value of a number.
Example :
abs(-5) ---> 5
abs(5) ---> 5
try this:
num = int(input("Please enter a number:"))
if num <= 0:
num = abs(num)
Python has a lot of built-in functions that help do simple tasks like this.
The abs() function returns the absolute value of any float/int/etc. you put into it.
You can also do this all in one line if you wish, you would use the same abs() function. This time around it can be in a try-except block which will handle any bad input like "18asdfnsjkdf" for example.
try:
num = abs(int(input("Enter a number:")))
except ValueError:
pass
Your code works, add a print statement and be careful of indentation issues:
number = int(input('Please enter a number: '))
if number <= 0:
number = number * -1
print(number)
Output is:
Please enter a number: -5
5
Have a little problem. I'm writing a simple program that takes an input of numbers (for example, 1567) and it adds the odd numbers together as well as lists them in the output. Here is my code:
import math
def oddsum(n):
y=n%10
if(y==0):
return
if(y%2!=0):
oddsum(int(n/10))
print (str(y),end="")
print (" ",end="")
else:
oddsum(int(n/10))
def main():
n=int(input("Enter a value : "))
print("The odd numbers are ",end="")
oddsum(n)
s = 0
while n!=0:
y=n%10
if(y%2!=0):
s += y
n //= 10
print("The sum would be ",end=' ')
print("=",s)
return
main()
It outputs just fine, in the example it will print 1 5 and 7 as the odd numbers. However, when it calculates the sum, it just says "7" instead of 13 like it should be. I can't really understand the logic behind what I'm doing wrong. If anyone could help me out a bit I'd appreciate it :)
I understand it's an issue with the "s += y" as it's just adding the 7 basically, but I'm not sure how to grab the 3 numbers of the output and add them together.
As #Anthony mentions, your code forever stays at 156 since it is an even num.
I would suggest you directly use the string input and loop through each element.
n = input("Enter a value : ") #'1567'
sum_of_input = sum(int(i) for i in n if int(i)%2) #1+5+7=13
[print(i, end="") for i in n if int(i)%2] #prints '157'
Note that int(i)%2 will return 1 if it is odd.
1567 % 10 will return 7. You might want to add the numbers you printed in oddsum to a list, and use the sum function on that list to return the right answer.
The immediate issue is that n only changes if the remainder is odd. eg 1,567 will correctly grab 7 and then n=156. 156 is even, so s fails to increment and n fails to divide by 10, instead sitting forever at 156.
More broadly, why aren't you taking advantage of your function? You're already looping through to figure out if a number is odd. You could add a global parameter (or just keep passing it down) to increment it.
And on a even more efficient scale, you don't need recursion to do this. You could take advantage of python's abilities to do lists. Convert your number (1567) into a string ('1567') and then loop through the string characters:
total = 0
for c in '1567':
c_int = int(c)
if c_int%2!= 0:
total += c_int
print(c)
print(total)
I have an assignment as follows
Write a program that repeatedly asks the user to enter a number, either float or integer until a value -88 is entered. The program should then output the average of the numbers entered with two decimal places. Please note that -88 should not be counted as it is the value entered to terminate the loop
I have gotten the program to ask a number repeatedly and terminate the loop with -99 but I'm struggling to get it to accept integer numbers (1.1 etc) and calculate the average of the numbers entered.
the question is actually quite straightforward, i'm posting my solution. However, please show us your work as well so that we could help you better. Generally, fro beginners, you could use the Python built-in data types and functions to perform the task. And you should probably google more about list in python.
def ave_all_num():
conti = True
total = []
while conti:
n = input('Input value\n')
try:
n = float(n)
except:
raise ValueError('Enter values {} is not integer or float'.format(n))
if n == -88:
break
total.append(n)
return round(sum(total)/len(total),2)
rslt = ave_all_num()
Try the following python code. =)
flag = True
lst=[]
while(flag):
num = float(raw_input("Enter a number. "))
lst+=[num]
if(num==-88.0): flag = False
print "Average of numbers: ", round( (sum(lst[:-1])/len(lst[:-1])) , 2)
enter code hereThank you for the prompt replies. Apologies. This is the code i was working on:
`#Assignment2, Question 3
numbers=[]
while True:
num=int(input("Enter any number:"))
if num==float:
continue
if num==-88:
break
return print(" the average of the numbers entered are:",sum(numbers)/len(numbers)`
How do I add numbers in between two numbers the user inputted in Python 2.7. So a person would input 75 and 80 and I want my program to add the numbers in between those two numbers. I am very new to programming and python so any help would be awesome!
This example excludes 75 and 80. If you need to include them replace with print sum(range(n1,n2+1))
n1=input('Enter first number ')
n2=input('Enter second number ')
print sum(range(min(n1,n2)+1,max(n1,n2)))
#DSM is right!
n1=input('Enter first number ')
n2=input('Enter second number ')
print (n2-n1+1)*(n2+n1)/2
to capture user input use number1 = raw_input('Input number'). From there I'm not exactly sure what you mean from adding numbers between the two? If you want 76+77+78+79 in that example
number1 = raw_input('Input number')
number2 = raw_input('Second number')
result = 0
for n in range(int(number1)+1, int(number2)):
result+=n
print result
Here's a quick sample that should handle a few different situations. Didn't go that in-depth since I don't know the scope of the situation. Realistically you should do some form of type-checking and loop until valid input is entered. However this should get you started:
def sumNums(a, b):
total = 0
if a < b:
total = sum(range(a+1, b))
elif b < a:
total = sum(range(b+1, a))
return total
num1 = int(raw_input("First Number: "))
num2 = int(raw_input("Second Number: "))
print sumNums(num1, num2)
However I'm sure there's a more comprehensive way using lists and sum() but it seems like you only need a basic working example.
easy you just go
def add(x,y):
if True:
return add(x, y)
else:
return None
add([1,2,3,4][0], [1,2,3,4][2])
This question already has answers here:
Using Python, reverse an integer, and tell if palindrome
(14 answers)
Closed 8 years ago.
How would I have the user input a number and then have the computer spit their number out in reverse?
num = int(input("insert a number of your choice "))
for i in
That is all I have so far...
I am using 3.3.4
Here's an answer that spits out a number in reverse, instead of reversing a string, by repeatedly dividing it by 10 and getting the remainder each time:
num = int(input("Enter a number: "))
while num > 0:
num, remainder = divmod(num, 10)
print remainder,
Oh and I didn't read the requirements carefully either! It has to be a for loop. Tsk.
from math import ceil, log10
num = int(input("Enter a number: "))
for i in range(int(ceil(math.log10(num)))): # => how many digits in the number
num, remainder = divmod(num, 10)
print remainder,
You don't need to make it int and again make it str! Make it straight like this:
num = input("insert a number of your choice ")
print (num[::-1])
Or, try this using for loop:
>>> rev = ''
>>> for i in range(len(num), 0, -1):
... rev += num[i-1]
>>> print(int(rev))
Best way to loop over a python string backwards says the most efficient/recommended way would be:
>>> for c in reversed(num):
... print(c, end='')
Why make it a number? 'In reverse' implies a string. So don't cast it to int but use it as string instead and just loop over it backwards.
You've got here a variety of different answers, many of which look similar.
for i in str(num)[::-1]:
print i
This concise variation does a few things worth saying in english, namely:
Cast num to a string
reverse it (with [::-1], an example of slicing, a pythonic idiom that I recommend you befriend)
finally, loop over the resultant string (since strings are iterable, you can loop over them)
and print each character.
Almost all the answers use [::-1] to reverse the list -- as you read more code, you will see it more places. I recommend reading more about it on S.O. here.
I hate to do your problem for you since you didn't really try to actually solve it or say what you're specifically having a problem with, but:
num = str(input("..."))
output = [num[-i] for i in range(len(num))]
print(output)
output = input("Insert number of your choice: ")[::-1]
print("Your output!: %s" % output)
In python 3.x+ input is automatically a string, doing [::-1] reverses the order of the string