try:
commands
try:
commands
try:
commands
try:
commands
except:
commands
return to final commands
except:
commands
return to final commands
except:
commands
return to final commands
except:
commands
final commands
Which instruction have I to write in place of return to final commands to make that any except returns to the top-level instructions following the outer try? And is it an acceptable structure?
Edit: Here is a toy example (I know I can do it using ifs, it's only an example; suppose you have to write it using try/except).
# calculate arcsin(log(sqrt(x)-4))
x = choose one yourself
try
x1=sqrt(x)
return to final message
try
x1=log(x1-4)
return to final message
try
x2=arcsin(x1)
return to final message
except
message="Impossible to calculate arcsin: maybe an argument outside [-1,+1]?"
except
message="Impossible to calculate logarithm: maybe a not positive argument?"
except
message="impossible to calculate square root: maybe a negative argument?"
final message:
print message
At the very least you should be able to reduce this structure to only 2 nested levels by reraising the exception to avoid the rest of the block:
# calculate arcsin(log(sqrt(x)-4))
x = ?
message = None
try:
try:
x1 = sqrt(x)
except Exception:
message = "can't take sqrt"
raise
try:
x1 = log(x1-4)
except Exception:
message = "can't compute log"
raise
try:
x2 = arcsin(x1)
except Exception:
message = "Can't calculate arcsin"
raise
except Exception:
print message
Really, this is not the way to do it, at least in this example. The problem is that you are trying to use exceptions like return error codes. What you should be doing is putting the error message into the exception. Also, normally the outer try/except would be in a higher level function:
def func():
try:
y = calculate_asin_log_sqrt(x)
# stuff that depends on y goes here
except MyError as e:
print e.message
# Stuff that happens whether or not the calculation fails goes here
def calculate_asin_log_sqrt(x):
try:
x1 = sqrt(x)
except Exception:
raise MyError("Can't calculate sqrt")
try:
x1 = log(x1-4)
except Exception:
raise MyError("Can't calculate log")
try:
x2 = arcsin(x1)
except Exception:
raise MyError("Can't calculate arcsin")
return x2
Related
I have a nested try-except-finally block where I run several functions in succession (assuming the previous ones worked). I have a condition that I check at the start (which essentially checks if the function has already been run that day) and if this statement is false, I want to jump straight to the finally.
I can do this by simply forcing an error to occur (i.e. writing x=1/0 but it seems there should be a better way to do this).
My code looks like this:
error = False
conditions = False
try:
# Do stuff here
if not condition:
# Here I want to go directly to finally
except Exception:
error = True
else:
try:
# Do stuff here
except Exception:
error = True
else:
try:
# Do stuff here
except Exception:
error = True
finally:
if error:
# Report that an error occurred
else:
# Report that everything went well
How about this?
To use MisterMiyagi's excellent wording in the comments to this answer, it inverts the logic to proceed only when the condition is met.
error = False
conditions = False
try:
# Do stuff here
except Exception:
error = True
else:
if condition: # The inverted condition moved here.
try:
# Do stuff here
except Exception:
error = True
else:
try:
# Do stuff here
except Exception:
error = True
finally:
if error:
# Report that an error occurred
else:
# Report that everything went well
Let's say I have three functions that do different things but should react to a set of exceptions in the same way. One of them might look like:
def get_order_stat(self, Order_id):
status_returned = False
error_count = 0
while status_returned == False:
try:
stat_get = client.queryOrder(orderId=Order_id)
except MalformedRequest:
print('Order ID not yet findable, keep trying')
error_count += 1
time.sleep(int(1))
except InternalError:
print('Order check returned InternalError, keep trying')
error_count += 1
time.sleep(int(1))
except StatusUnknown:
print('Order check returned StatusUnknown, keep trying')
error_count += 1
time.sleep(int(1))
else:
status = stat_get['status']
status_returned = True
finally:
if error_count >= 10:
print('Error loop, give up')
break
return status
The vast majority of the code is the exception handling, and I'd like to avoid having to repeat it in every function that needs it. Is there a way to define something like an exception handling function containing the handling code? Ideally my function would end up effectively:
def get_order_stat(self, Order_id):
status_returned = False
while status_returned == False:
try:
stat_get = client.queryOrder(orderId=Order_id)
except:
handler_function()
else:
status = stat_get['status']
status_returned = True
return status
You practically already did it. Just define the handler_function() somewhere and it gets called when an Exception in the try block gets raised.
Maybe helpful: you can bind the Exception to a variable and use it for exception handling in the handler function:
except Exception as e:
handler_function(e)
Then you can for example do `print(e)̀ to give out the exception or do different handling for different exceptions in the function. Hope that helps!
You also can specify several exceptions in one line if you don't want to be general, but catch all specific exceptions with one statement:
except (ExceptionType1, ExceptionType2, ExceptionType3) as e:
handler_function(e)
I might write a decorator function for the exception handling; for instance using functool.wraps.
from functool import wraps
def retry(f):
#wraps(f)
def wrapper(*args, **kwargs):
error_count = 0
while error_count < 10:
try:
return f(*args, **kwargs)
except MalformedRequest:
print('Order ID not yet findable, keep trying')
except InternalError:
print('Order check returned InternalError, keep trying')
error_count += 1
time.sleep(int(1))
print('Error loop, give up')
return None
return wrapper
Then you can write a very simple API call function, and wrap it with the retry wrapper:
#retry
def get_order(order_id):
stat_get = client.queryOrder(orderId=order_id)
return stat_get['status']
In your original function, notice that you can move the contents of the try...else block into the main try block without affecting the logic (extracting the value from the query result won't raise one of the network-related exceptions), and then you can just return out of the try block instead of arranging to stop the loop. Then the contents of the try block are what I've broken out here into get_order(). I restructured the remaining loop a little and turned it into decorator form.
i need continue in program after except when variable is True but when variable is False need exit program.
I think there will be if else but I'm not sure how to use it.
for examlpe:
var = True
try:
print 2/0
except:
exit(1)
... continue executing
var = False
try:
print 2/0
except:
exit(1)
... exit
Thanks for comments.
This ought to do the trick, by the way you should probably use raise.
var = True
try:
print 2/0
except:
if not var:
# I recommend using raise, as it would show you the error
exit(1)
If you have a number of except groups which will need to use the var try this
Note that you can expand myexcept using decorators or closures in order to set up additional processing within the exception as well. Since a function is an object, you can use a different specialfunc() for every except: that you write. You can set up the myexcept to handle calls to specialfunc() with arguments as well using the variable arguments process as shown below
def specialfunc1():
# put the special function code here
def specialfunc2(arg1):
# put the processing here
def specialfunc3(arg1, arg2):
# put the processing here
def myexcept(var, e, specialfunc, *args)
print 'Exception caught for ', e
if var:
specialfunc(*args)
else:
raise # This raises the current exception to force an exit
try:
# code you are testing
2/0
except Error1, e:
myexcept(var, e, specialfunc1)
except Error2, e:
myexcept(var, e, specialfunc2(arg1))
except Error3, e:
myexcept(var, e, specialfunc3(arg1, arg2))
except: # this default forces the regular exception handler
# remaining code
I'm really new in Python and a have no experience with exceptions but I've read all the documentation and couldn't find an answer ... so I'm looking for a deeper view in except's semantics.
When we have for example:
try:
x = 2
except GreaterThanOne:
print("The value is greater than one")
In this case I want the message to be printed.Is there a way for the GreaterThanOne class(exception) to be defined to raise when the entered value is greater than one ?
Ok, let me be more specific ...
Every error raises by a specific rule which should be add in the error attributes, am I right ?
For example:
try:
myvalue = x / y
except ZeroDivisionError:
print("Some error message printed ...")
So when I use this code and enter for y to be 0 the exception ZeroDivisionError will raise ... Can I for example redefine ZeroDivisionError to raise like this but if y is set to be ... 2 or 3 or any other value ?
Input:
x = 10
y = 2
try:
myvalue = x / y
except ZeroDivisionError:
print("division by 2")
Output: division by 2
Here's an example that should help you understand. Run this in your Python interpreter and watch how the exception is raised and caught (or not caught) when you call set_val(2).
# Defining our Exception subclass:
class GreaterThanOne(Exception):
pass
# The global value we pretend to care about:
val = 0
# Function to set a value but possibly raise our new Exception
def set_val(new_val):
if new_val > 1:
raise GreaterThanOne("%d > 1" % new_val)
val = new_val
# Catching exception:
try:
set_val(0)
set_val(1)
set_val(2)
except GreaterThanOne:
print "Whoops - one of those values was greater than one"
# Not catching exception:
set_val(0)
set_val(1)
set_val(2)
set_val(3)
an try-except block catches exception in this block.
try:
#some stuff here
except ExceptionClass as e:
#Exception handling here
the class after the except keyword indicates which kind of exception you want to catch. Usually you give a specific class, like ValueError or KeyError. You can also use the Exception class, to catch any exception. Because all the other exceptionclasses inhert from Exception.
so if you want to use this construct, an exception needs to be raised, Either by a function / method you call, or you raise it yourself with the raise keyword.
like this:
try:
raise KeyError('Just for test')
except KeyError as e:
#Exception handling here
The try except doesn't automagically inspect the whole code between it, it just looks for exceptions... Or to be more specific, it looks for those exceptions you tell it to look for.
Of course you can also inspect the exception instance.
try:
raise KeyError('Just for test')
except KeyError as e:
print e.args
For more information, please see:
http://docs.python.org/2/tutorial/errors.html
I want to do:
try:
do()
except:
do2()
except:
do3()
except:
do4()
If do() fails, execute do2(), if do2() fails too, exceute do3() and so on.
best Regards
If you really don't care about the exceptions, you could loop over cases until you succeed:
for fn in (do, do2, do3, do4):
try:
fn()
break
except:
continue
This at least avoids having to indent once for every case. If the different functions need different arguments you can use functools.partial to 'prime' them before the loop.
I'd write a quick wrapper function first() for this.
usage: value = first([f1, f2, f3, ..., fn], default='All failed')
#!/usr/bin/env
def first(flist, default=None):
""" Try each function in `flist` until one does not throw an exception, and
return the return value of that function. If all functions throw exceptions,
return `default`
Args:
flist - list of functions to try
default - value to return if all functions fail
Returns:
return value of first function that does not throw exception, or
`default` if all throw exceptions.
TODO: Also accept a list of (f, (exceptions)) tuples, where f is the
function as above and (exceptions) is a tuple of exceptions that f should
expect. This allows you to still re-raise unexpected exceptions.
"""
for f in flist:
try:
return f()
except:
continue
else:
return default
# Testing.
def f():
raise TypeError
def g():
raise IndexError
def h():
return 1
# We skip two exception-throwing functions and return value of the last.
assert first([f, g, h]) == 1
assert first([f, g, f], default='monty') == 'monty'
It seems like a really odd thing to want to do, but I would probably loop over the functions and break out when there were no exception raised:
for func in [do, do2, do3]:
try:
func()
except Exception:
pass
else:
break
Here is the simplest way I found, just embed the try under the previous except.
try:
do()
except:
try:
do2()
except:
do3()
You should specify the type of the exception you are trying to catch each time.
try:
do()
except TypeError: #for example first one - TypeError
do_2()
except KeyError: #for example second one - KeyError
do_3()
and so on.
if you want multiple try statments you can do it like this, including the except statement. Extract (refactor) your statements. And use the magic of and and or to decide when to short-circuit.
def a():
try: # a code
except: pass # or raise
else: return True
def b():
try: # b code
except: pass # or raise
else: return True
def c():
try: # c code
except: pass # or raise
else: return True
def d():
try: # d code
except: pass # or raise
else: return True
def main():
try:
a() and b() or c() or d()
except:
pass
import sys
try:
f = open('myfile.txt')
s = f.readline()
i = int(s.strip())
except OSError as err:
print("OS error: {0}".format(err))
except ValueError:
print("Could not convert data to an integer.")
except:
print("Unexpected error:", sys.exc_info()[0])
raise