I see that there are other questions related to cross module variables, but they don't really fully answer my question.
I have an application that I have split into 3 modules + 1 main application, mainly for ease of readability and maintainability.
2 of these modules have threads with variables that need to be modified from other modules and other module threads.
Whilst I can modify a module's variable from the main code, I don't appear to be able to modify one module's variable from another module unless I import every module into every other module.
The example below where a&b are imported into main and a module a needs to access a variable in module b:
main
module a
var a
module b
var a
main
a.a = 1
b.a = 2
module a
b.a = 3
module b
a.a = 0
without importing module a into module b and importing module b into module a, can this be achieved globally through the main program ?
If I do have to import a and b into main, and then import a into b and b into a, what are the implications in terms of memory and resource usage / speed etc ?
I tried the suggestion from #abarnert:
#moda
vara = 10
#modb
print(str(vara))
#main
import moda
from moda import vara
import modb
however I get "name error vara is not defined"
If the code in the modules are defined as classes, and the main program creates instances of these classes, the main program can pass an instance of one module class to another, and changes to that instance will be reflected everywhere. There would be no need to import a or b into each other, because they would simply have references to each other.
If I do have to import a and b into main, and then import a into b and b into a, what are the implications in terms of memory and resource usage / speed etc ?
Absolutely none for memory—every module that imports a will get a reference to the exact same a module object. All you're doing is increasing its refcount, not creating new objects.
For speed, the time to discover that you're trying to import a module that already exists is almost nothing (it's just looking up the module name in a dictionary). It is slightly slower to access a.a than to just access a. But this is very rarely an issue. If it is, you're almost certainly going to want to copy that value into the locals of whatever function is accessing it over and over, at which point it won't matter which globals it came from.
without importing module a into module b and importing module b into module a, can this be achieved globally through the main program ?
Sure. All you have to do is import (with from a import a or import a.a as aa or whatever) or copy the variables from module a into main.
Note that just makes a new name for each value; it doesn't make references to the variables. There is no such thing as a reference to a variable in Python.
This works if the variables are holding constants, or if they're holding mutable values that you modify. It just doesn't do anything useful if the variables are names that you want to rebind to new values. (If you do need to do that, just wrap the values in something mutable—e.g., turn each variable into a 1-item list, so you can rebind a[0] instead of a, which means anyone else who has a reference to a can see your new a[0] value.)
If you insist on a "true global", even that isn't impossible. See builtins for details. But you almost certainly don't want this.
If you want to be able to modify a module-level variable from a different module then yes, you will need to import the other module. I would question why you need to do this. Perhaps you should be breaking your code into classes instead of separate modules.
For example you could choose to encapsulate the variables that need to be modified by both modules inside a separate class and pass a single instance of that class to all classes (or modules but you should really use classes) that need it.
See Circular (or cyclic) imports in Python for more information about cyclical imports.
Related
I have two specific situations where I don't understand how importing works in Python:
1st specific situation:
When I import the same module in two different Python scripts, the module isn't imported twice, right? The first time Python encounters it, it is imported, and second time, does it check if the module has been imported, or does it make a copy?
2nd specific situation:
Consider the following module, called bla.py:
a = 10
And then, we have foo.py, a module which imports bla.py:
from bla import *
def Stuff ():
return a
And after that, we have a script called bar.py, which gets executed by the user:
from foo import *
Stuff() #This should return 10
a = 5
Stuff()
Here I don't know: Does Stuff() return 10 or 5?
Part 1
The module is only loaded once, so there is no performance loss by importing it again. If you actually wanted it to be loaded/parsed again, you'd have to reload() the module.
The first place checked is sys.modules, the cache of all modules that have been imported previously. [source]
Part 2
from foo import * imports a to the local scope. When assigning a value to a, it is replaced with the new value - but the original foo.a variable is not touched.
So unless you import foo and modify foo.a, both calls will return the same value.
For a mutable type such as a list or dict it would be different, modifying it would indeed affect the original variable - but assigning a new value to it would still not modify foo.whatever.
If you want some more detailed information, have a look at http://docs.python.org/reference/executionmodel.html:
The following constructs bind names: formal parameters to functions, import statements, class and function definitions (these bind the class or function name in the defining block), and targets that are identifiers if occurring in an assignment, for loop header, in the second position of an except clause header or after as in a with statement.
The two bold sections are the relevant ones for you: First the name a is bound to the value of foo.a during the import. Then, when doing a = 5, the name a is bound to 5. Since modifying a list/dict does not cause any binding, those operations would modify the original one (b and foo.b are bound to the same object on which you operate). Assigning a new object to b would be a binding operation again and thus separate b from foo.b.
It is also worth noting what exactly the import statement does:
import foo binds the module name to the module object in the current scope, so if you modify foo.whatever, you will work with the name in that module - any modifications/assignments will affect the variable in the module.
from foo import bar binds the given name(s) only (i.e. foo will remain unbound) to the element with the same name in foo - so operations on bar behave like explained earlier.
from foo import * behaves like the previous one, but it imports all global names which are not prefixed with an underscore. If the module defines __all__ only names inside this sequence are imported.
Part 3 (which doesn't even exist in your question :p)
The python documentation is extremely good and usually verbose - you find answer on almost every possible language-related question in there. Here are some useful links:
http://docs.python.org/reference/datamodel.html (classes, properties, magic methods, etc.) ()
http://docs.python.org/reference/executionmodel.html (how variables work in python)
http://docs.python.org/reference/expressions.html
http://docs.python.org/reference/simple_stmts.html (statements such as import, yield)
http://docs.python.org/reference/compound_stmts.html (block statements such as for, try, with)
To answer your first question:
No, python does not get 'imported' twice. When python loads a module, it checks for the module in sys.modules. If it is not in there, it is put in there, and loaded.
To answer your second question:
Modules can define what names they will export to a from camelot import * scenario, and the behavior is to create names for the existing values, not to reference existing variables (python does not have references).
On a somewhat related topic, doing a from camelot import * is not the same as a regular import.
I am currently trying to ship some bigger project. That is the reason why I decided to use submodules. Take a look at the project structure:
/sandbox
__init.py__
constants.py
/sub1
__init__.py
foo.py
In my constants.py file, I have declared a single global variable:
MYGLOBAL = 42
I want to use its value in foo.py. This file has 2 functions for testing:
def foofunc():
return 'I am foo.'
def constfunc():
return 'I am {MYGLOBAL}.'
Also, I put this code into /sandbox/sub1/__init__.py:
from .foo import *
from sandbox.constants import *
Now, when I use my interpreter, I try to use both functions like this:
>> import sandbox.sub1
>> sandbox.sub1.foofunc()
'I am foo.'
>> sandbox.sub1.MYGLOBAL
42
>> sandbox.sub1.constfunc()
NameError: name 'MYGLOBAL' is not defined
To my understanding, the global variable is in the same namespace as the functions, but somehow the function does not see it.
How can I access it? Python version is 3.6.
Thanks!
"Global" variables are not really global in Python, and are only available in the namespace of the modules in which they're defined.
You should import constants in foo.py so that MYGLOBAL can be made available as an attribute of the constants module object:
from sandbox import constants
def constfunc():
return f'I am {constants.MYGLOBAL}.'
A late answer to this very nice question (upvoted).
Here is one thing that will give you a better understanding of what is going on:
>>> sandbox.sub1.constfunc.__module__
'sandbox.sub1.foo'
>>> sandbox.sub1.constfunc.__globals__['MYGLOBAL']
KeyError: 'MYGLOBAL'
>>> sandbox.sub1.foo.MYGLOBAL = 5
>>> sandbox.sub1.constfunc.__globals__['MYGLOBAL']
5
>>> sandbox.sub1.constfunc()
'I am 5'
In other words,
"which module does this function actually belong in, and thus looks at to decide what module-global variables are available to it?"
You erroneously assumed it would be sandbox.sub1, but it's actually sandbox.sub1.foo. The reason is because the function's "parent module" is carried with the function object, even when this function object is copied to another module's "workspace".
With this understanding, there are several things you can do. One is as per the other answer here. An alternative solution might be to do this in __init__.py:
from . import foo
from .. import constants
foo.MYGLOBAL = constants.MYGLOBAL
etc.
Interesting things to note:
One thing to note is that the from X import Y as Z syntax is effectively equivalent to saying Z = X.Y. The reason this is an important insight is because it helps you realise that Z is not a 'reference' per se: if you change X.Y, Z will not automatically get updated.
If you change the Y in X to another value, and you want to update Z, you need to reimport it with the "from X import Y as Z" syntax.
Interestingly, you cannot simply do:
sandbox.sub1.constfunc.__module__ = sandbox.constants
and simply expect to 'replace' the function's module-global variables to those of sandbox.constants. There reason for this seems to be that the constfunc.__module__ attribute is simply a 'copy' of the original parent module, and changing it does not affect the actual parent module bound to the function (i.e., it does not dynamically 'rebind' the function to another module; though, since this is an internal variable, it may change in future python versions. Who knows. Don't rely on it.).
Also, the __module__ attribute is not used to create the constfunc.__globals__ dictionary for the function; this always seems to reflect the global dictionary of the 'parent module' directly. So simply replacing the sandbox.sub1.constfunc.__module__ variable doesn't automatically replace the constfunc.__globals__ dictionary, but updating sandbox.sub1.foo does.
I am trying to create a system where I can mutate the values of A as easily as possible. When I import A into various other modules and modify the fields of A
they seem to remain changed in the foreign module but are unchanged in A's native module.
# module name a.py
import b
class A:
x = 0
#classmethod
def call_mutate_A_from_B(cls):
b_object = b.B()
b_object.mutate_A() # change does not seem to stay in effect upon
# return
print(cls.x) # prints 0
def main():
A.call_mutate_A_from_B()
if __name__ == '__main__':
main()
# module name b.py
from a import A
class B: # in a different module
def mutate_A():
A.x = 2
Is this the expected behaviour? I don't think it is. Should I create an object representation of A not treat is as a static class?
To answer your first question: yes, this is the expected behavior. Let us say that a module A is imported by another module B. When we import A, two things happen:
All the object definitions of the imported module A are imported into B.
Any executable statements in A are executed (only once).
To elaborate on the first point, all the definitions of classes, functions, variables etc. from A are imported into B. It is safe to say that B now has its own working copies of module A's contents to work with. Changing any aspect of these copies will not have any effect on the original definitions, meaning that these changes will not be reflected in A (the imported module).
I hope this clears your question. You can read more about how modules work in the official Python docs.
I have two specific situations where I don't understand how importing works in Python:
1st specific situation:
When I import the same module in two different Python scripts, the module isn't imported twice, right? The first time Python encounters it, it is imported, and second time, does it check if the module has been imported, or does it make a copy?
2nd specific situation:
Consider the following module, called bla.py:
a = 10
And then, we have foo.py, a module which imports bla.py:
from bla import *
def Stuff ():
return a
And after that, we have a script called bar.py, which gets executed by the user:
from foo import *
Stuff() #This should return 10
a = 5
Stuff()
Here I don't know: Does Stuff() return 10 or 5?
Part 1
The module is only loaded once, so there is no performance loss by importing it again. If you actually wanted it to be loaded/parsed again, you'd have to reload() the module.
The first place checked is sys.modules, the cache of all modules that have been imported previously. [source]
Part 2
from foo import * imports a to the local scope. When assigning a value to a, it is replaced with the new value - but the original foo.a variable is not touched.
So unless you import foo and modify foo.a, both calls will return the same value.
For a mutable type such as a list or dict it would be different, modifying it would indeed affect the original variable - but assigning a new value to it would still not modify foo.whatever.
If you want some more detailed information, have a look at http://docs.python.org/reference/executionmodel.html:
The following constructs bind names: formal parameters to functions, import statements, class and function definitions (these bind the class or function name in the defining block), and targets that are identifiers if occurring in an assignment, for loop header, in the second position of an except clause header or after as in a with statement.
The two bold sections are the relevant ones for you: First the name a is bound to the value of foo.a during the import. Then, when doing a = 5, the name a is bound to 5. Since modifying a list/dict does not cause any binding, those operations would modify the original one (b and foo.b are bound to the same object on which you operate). Assigning a new object to b would be a binding operation again and thus separate b from foo.b.
It is also worth noting what exactly the import statement does:
import foo binds the module name to the module object in the current scope, so if you modify foo.whatever, you will work with the name in that module - any modifications/assignments will affect the variable in the module.
from foo import bar binds the given name(s) only (i.e. foo will remain unbound) to the element with the same name in foo - so operations on bar behave like explained earlier.
from foo import * behaves like the previous one, but it imports all global names which are not prefixed with an underscore. If the module defines __all__ only names inside this sequence are imported.
Part 3 (which doesn't even exist in your question :p)
The python documentation is extremely good and usually verbose - you find answer on almost every possible language-related question in there. Here are some useful links:
http://docs.python.org/reference/datamodel.html (classes, properties, magic methods, etc.) ()
http://docs.python.org/reference/executionmodel.html (how variables work in python)
http://docs.python.org/reference/expressions.html
http://docs.python.org/reference/simple_stmts.html (statements such as import, yield)
http://docs.python.org/reference/compound_stmts.html (block statements such as for, try, with)
To answer your first question:
No, python does not get 'imported' twice. When python loads a module, it checks for the module in sys.modules. If it is not in there, it is put in there, and loaded.
To answer your second question:
Modules can define what names they will export to a from camelot import * scenario, and the behavior is to create names for the existing values, not to reference existing variables (python does not have references).
On a somewhat related topic, doing a from camelot import * is not the same as a regular import.
The __debug__ variable is handy in part because it affects every module. If I want to create another variable that works the same way, how would I do it?
The variable (let's be original and call it 'foo') doesn't have to be truly global, in the sense that if I change foo in one module, it is updated in others. I'd be fine if I could set foo before importing other modules and then they would see the same value for it.
If you need a global cross-module variable maybe just simple global module-level variable will suffice.
a.py:
var = 1
b.py:
import a
print a.var
import c
print a.var
c.py:
import a
a.var = 2
Test:
$ python b.py
# -> 1 2
Real-world example: Django's global_settings.py (though in Django apps settings are used by importing the object django.conf.settings).
I don't endorse this solution in any way, shape or form. But if you add a variable to the __builtin__ module, it will be accessible as if a global from any other module that includes __builtin__ -- which is all of them, by default.
a.py contains
print foo
b.py contains
import __builtin__
__builtin__.foo = 1
import a
The result is that "1" is printed.
Edit: The __builtin__ module is available as the local symbol __builtins__ -- that's the reason for the discrepancy between two of these answers. Also note that __builtin__ has been renamed to builtins in python3.
I believe that there are plenty of circumstances in which it does make sense and it simplifies programming to have some globals that are known across several (tightly coupled) modules. In this spirit, I would like to elaborate a bit on the idea of having a module of globals which is imported by those modules which need to reference them.
When there is only one such module, I name it "g". In it, I assign default values for every variable I intend to treat as global. In each module that uses any of them, I do not use "from g import var", as this only results in a local variable which is initialized from g only at the time of the import. I make most references in the form g.var, and the "g." serves as a constant reminder that I am dealing with a variable that is potentially accessible to other modules.
If the value of such a global variable is to be used frequently in some function in a module, then that function can make a local copy: var = g.var. However, it is important to realize that assignments to var are local, and global g.var cannot be updated without referencing g.var explicitly in an assignment.
Note that you can also have multiple such globals modules shared by different subsets of your modules to keep things a little more tightly controlled. The reason I use short names for my globals modules is to avoid cluttering up the code too much with occurrences of them. With only a little experience, they become mnemonic enough with only 1 or 2 characters.
It is still possible to make an assignment to, say, g.x when x was not already defined in g, and a different module can then access g.x. However, even though the interpreter permits it, this approach is not so transparent, and I do avoid it. There is still the possibility of accidentally creating a new variable in g as a result of a typo in the variable name for an assignment. Sometimes an examination of dir(g) is useful to discover any surprise names that may have arisen by such accident.
Define a module ( call it "globalbaz" ) and have the variables defined inside it. All the modules using this "pseudoglobal" should import the "globalbaz" module, and refer to it using "globalbaz.var_name"
This works regardless of the place of the change, you can change the variable before or after the import. The imported module will use the latest value. (I tested this in a toy example)
For clarification, globalbaz.py looks just like this:
var_name = "my_useful_string"
You can pass the globals of one module to onother:
In Module A:
import module_b
my_var=2
module_b.do_something_with_my_globals(globals())
print my_var
In Module B:
def do_something_with_my_globals(glob): # glob is simply a dict.
glob["my_var"]=3
Global variables are usually a bad idea, but you can do this by assigning to __builtins__:
__builtins__.foo = 'something'
print foo
Also, modules themselves are variables that you can access from any module. So if you define a module called my_globals.py:
# my_globals.py
foo = 'something'
Then you can use that from anywhere as well:
import my_globals
print my_globals.foo
Using modules rather than modifying __builtins__ is generally a cleaner way to do globals of this sort.
You can already do this with module-level variables. Modules are the same no matter what module they're being imported from. So you can make the variable a module-level variable in whatever module it makes sense to put it in, and access it or assign to it from other modules. It would be better to call a function to set the variable's value, or to make it a property of some singleton object. That way if you end up needing to run some code when the variable's changed, you can do so without breaking your module's external interface.
It's not usually a great way to do things — using globals seldom is — but I think this is the cleanest way to do it.
I wanted to post an answer that there is a case where the variable won't be found.
Cyclical imports may break the module behavior.
For example:
first.py
import second
var = 1
second.py
import first
print(first.var) # will throw an error because the order of execution happens before var gets declared.
main.py
import first
On this is example it should be obvious, but in a large code-base, this can be really confusing.
I wondered if it would be possible to avoid some of the disadvantages of using global variables (see e.g. http://wiki.c2.com/?GlobalVariablesAreBad) by using a class namespace rather than a global/module namespace to pass values of variables. The following code indicates that the two methods are essentially identical. There is a slight advantage in using class namespaces as explained below.
The following code fragments also show that attributes or variables may be dynamically created and deleted in both global/module namespaces and class namespaces.
wall.py
# Note no definition of global variables
class router:
""" Empty class """
I call this module 'wall' since it is used to bounce variables off of. It will act as a space to temporarily define global variables and class-wide attributes of the empty class 'router'.
source.py
import wall
def sourcefn():
msg = 'Hello world!'
wall.msg = msg
wall.router.msg = msg
This module imports wall and defines a single function sourcefn which defines a message and emits it by two different mechanisms, one via globals and one via the router function. Note that the variables wall.msg and wall.router.message are defined here for the first time in their respective namespaces.
dest.py
import wall
def destfn():
if hasattr(wall, 'msg'):
print 'global: ' + wall.msg
del wall.msg
else:
print 'global: ' + 'no message'
if hasattr(wall.router, 'msg'):
print 'router: ' + wall.router.msg
del wall.router.msg
else:
print 'router: ' + 'no message'
This module defines a function destfn which uses the two different mechanisms to receive the messages emitted by source. It allows for the possibility that the variable 'msg' may not exist. destfn also deletes the variables once they have been displayed.
main.py
import source, dest
source.sourcefn()
dest.destfn() # variables deleted after this call
dest.destfn()
This module calls the previously defined functions in sequence. After the first call to dest.destfn the variables wall.msg and wall.router.msg no longer exist.
The output from the program is:
global: Hello world!
router: Hello world!
global: no message
router: no message
The above code fragments show that the module/global and the class/class variable mechanisms are essentially identical.
If a lot of variables are to be shared, namespace pollution can be managed either by using several wall-type modules, e.g. wall1, wall2 etc. or by defining several router-type classes in a single file. The latter is slightly tidier, so perhaps represents a marginal advantage for use of the class-variable mechanism.
This sounds like modifying the __builtin__ name space. To do it:
import __builtin__
__builtin__.foo = 'some-value'
Do not use the __builtins__ directly (notice the extra "s") - apparently this can be a dictionary or a module. Thanks to ΤΖΩΤΖΙΟΥ for pointing this out, more can be found here.
Now foo is available for use everywhere.
I don't recommend doing this generally, but the use of this is up to the programmer.
Assigning to it must be done as above, just setting foo = 'some-other-value' will only set it in the current namespace.
I use this for a couple built-in primitive functions that I felt were really missing. One example is a find function that has the same usage semantics as filter, map, reduce.
def builtin_find(f, x, d=None):
for i in x:
if f(i):
return i
return d
import __builtin__
__builtin__.find = builtin_find
Once this is run (for instance, by importing near your entry point) all your modules can use find() as though, obviously, it was built in.
find(lambda i: i < 0, [1, 3, 0, -5, -10]) # Yields -5, the first negative.
Note: You can do this, of course, with filter and another line to test for zero length, or with reduce in one sort of weird line, but I always felt it was weird.
I could achieve cross-module modifiable (or mutable) variables by using a dictionary:
# in myapp.__init__
Timeouts = {} # cross-modules global mutable variables for testing purpose
Timeouts['WAIT_APP_UP_IN_SECONDS'] = 60
# in myapp.mod1
from myapp import Timeouts
def wait_app_up(project_name, port):
# wait for app until Timeouts['WAIT_APP_UP_IN_SECONDS']
# ...
# in myapp.test.test_mod1
from myapp import Timeouts
def test_wait_app_up_fail(self):
timeout_bak = Timeouts['WAIT_APP_UP_IN_SECONDS']
Timeouts['WAIT_APP_UP_IN_SECONDS'] = 3
with self.assertRaises(hlp.TimeoutException) as cm:
wait_app_up(PROJECT_NAME, PROJECT_PORT)
self.assertEqual("Timeout while waiting for App to start", str(cm.exception))
Timeouts['WAIT_JENKINS_UP_TIMEOUT_IN_SECONDS'] = timeout_bak
When launching test_wait_app_up_fail, the actual timeout duration is 3 seconds.