NameError: name 'app' is not defined with Flask - python

I have the following structure in my project
\ myapp
\ app
__init__.py
views.py
run.py
And the following code:
run.py
from app import create_app
if __name__ == '__main__':
app = create_app()
app.run(debug=True, host='0.0.0.0', port=5001)
views.py
#app.route("/")
def index():
return "Hello World!"
_init_.py
from flask import Flask
def create_app():
app = Flask(__name__)
from app import views
return app
I'm trying to use the factory design pattern to create my app objects with different config files each time, and with a subdomain dispatcher be able to create and route different objects depending on the subdomain on the user request.
I'm following the Flask documentation where they talk about, all of this:
Application Context
Applitation Factories
Application with Blueprints
Application Dispatching
But I couldn't make it work, it seems that with my actual project structure there are no way to pass throw the app object to my views.py and it throw and NameError
NameError: name 'app' is not defined

After do what Miguel suggest (use the Blueprint) everything works, that's the final code, working:
_init.py_
...
def create_app(cfg=None):
app = Flask(__name__)
from api.views import api
app.register_blueprint(api)
return app
views.py
from flask import current_app, Blueprint, jsonify
api = Blueprint('api', __name__)
#api.route("/")
def index():
# We can use "current_app" to have access to our "app" object
return "Hello World!"

Related

flask server won't run if I named my application factory function other than "create_app"

My server will run if I name application factory function as create_app like this:
def create_app():
app = Flask(__name__)
#app.route('/')
def hello():
return 'Hello, World!'
return app
but naming it other than create_app, will throw an error Failed to find Flask application or factory
def foo_app():
app = Flask(__name__)
#app.route('/')
def hello():
return 'Hello, World!'
return app
changing the case will also throw the same error, like this:
def Create_app():
app = Flask(__name__)
#app.route('/')
def hello():
return 'Hello, World!'
return app
Is this behavior is normal? or is there something wrong in my setup?
this is my project layout:
...\projects\mainfoo
|--packagefoo
| |--__init__.py
|--venvfiles
in the cmd,
...\projects\mainfoo>set FLASK_APP=packagefoo
...\projects\mainfoo>set FLASK_ENV=development
...\projects\mainfoo>flask run
I just follow this tutorial Project Layout & Application setup
From the flask documentation
$ export FLASK_APP=hello
$ flask run
While FLASK_APP supports a variety of options for specifying your
application, most use cases should be simple. Here are the typical
values:
(nothing)
The name “app” or “wsgi” is imported (as a “.py” file, or
package), automatically detecting an app (app or application) or
factory (create_app or make_app).
FLASK_APP=hello
The given name is imported, automatically detecting an
app (app or application) or factory (create_app or make_app).
You cannot customize this behavior, as its a specification in flask to follow.

Flask app doesn't recognize flask_restful resources

I'm trying to build an API with flask_restful, but I don't know how to connect classes that inherit from Resource, with the actual app.
I have the following structure
page
├───api
│ └───__init__.py
│ └───resources.py
└───__init__.py
page/api/resources.py:
from flask_restful import Resource
from page import api
#api.resource("/hello-world")
class HelloWorld(Resource):
def get(self):
return {"hello": "World"}
page/init.py:
from flask import Flask
from flask_restful import Api
from page.config import Config1
api = Api()
def create_app(config_class=Config1):
app = Flask(__name__)
app.config.from_object(config_class)
api.init_app(app)
return app
run.py (outside of the page package):
from page import create_app
if __name__ == "__main__":
app = create_app()
app.run(debug=True)
test:
import requests
BASE = "http://127.0.0.1:5000/"
response = requests.get(BASE + "hello-world")
print(response.json())
Obviously, making a request to "/hello-world" doesn't work. How can I "make Flask aware" of the resources, so that I get a valid response.
Probably there is a much clever way of doing this but for me, the solution would be to remove the decorator #api.resource decorator at page/api/resources.py and make the following changes at page/init.py
from flask import Flask
from page.config import Config1
def create_app(config_class=Config1):
app = Flask(__name__)
app.config.from_object(config_class)
return app
I would also move the run.py inside the page folder and rename it to app.py according to Flask documentation. This app.py should have your routes so change it to something like this:
from page import create_app
from page.api.resources import HelloWorld
from flask_restfull import api
app = create_app()
api = Api(app)
api.add_resource(HelloWorld, '/hello-world')
And to run it just type flask run inside the page folder.

How to use flask-caching in my structure of project

My code structure. I tried but kept getting error cannot import name 'caching'. I guess my method isn't correct as caching will not have app initiation when I import caching in external file.
xyz
-app.py
-run.py
-urls
-v2.py
-resource
-views.py
-external.py
run.py
from app import create_app
if __name__ == "__main__":
career_app = create_app()
career_app.run(host=HOST,
port=PORT,
debug=True)
app.py
from flask import Flask
from flask_caching import Cache
caching = Cache(config={'CACHE_TYPE': 'simple'})
def create_app():
"""Create web app."""
app = Flask(__name__)
configure_app(app)
caching.init_app(app)
setup_blueprints(app)
return app
external.py
from app import caching
v1.py
v2_api.add_resource(UserConfigView, '/user/config',
endpoint='user_config_view')
It is a simple factory app setup
ext.py
from flask_caching import Cache
cache = Cache()
app.py
def create_app():
app = Flask(__name__)
register_extensions(app)
...
def register_extensions(app):
cache.init_app(app, config=settings.params.CACHE_CONFIG)

How to run Flask app by flask run with blueprint template

In a Python authorization app, in my main py I have the following code:
# main.py
from flask import Blueprint, render_template
from flask_login import login_required, current_user
theapp = Blueprint('main', __name__)
#theapp.route('/')
def index():
return render_template('index.html')
When I try:
FLASK_APP=main.py
FLASK_DEBUG=1
flask run
I get the following error:
Error: Could not locate a Flask application. You did not provide the "FLASK_APP" environment variable, and a "wsgi.py" or "app.py" module was not found in the current directory.
Basically a Blueprint is a way for you to organize your flask application into smaller and reusable applications. I am not sure why you have used it here in the main.py.
You could do that some other file, for example, you have a set of endpoints to implement login functionality in a separate file then what you should be doing is:
Assume you have a login.py .Sample Code looks like follows:
from flask import Blueprint
bp = Blueprint('login_bp', __name__)
def login_bp():
return bp
And the following code goes into you main.py , you need to start the Flask Server using .run()
from flask import Flask
from flask import Blueprint, render_template
from login import login_bp #Assume you have a module login and I am importing login_bp from login.py
theapp = Flask(__name__) #Creating Flask instance
theapp.register_blueprint(login_bp()) # Registering Blueprint here
#theapp.route('/')
def index():
return render_template('index.html')
theapp.run(host="0.0.0.0", port=2019, debug=True) #Starting the Flask Server
Hope this works, please do look out for documents and code example to get deeper insights.

How do I properly declare subdomains in Flask using Blueprint?

I have been following the methods provided in this post:
https://stackoverflow.com/questions/12167729/flask-subdomains-with-blueprint-getting-404
Here is my relevant code:
__init__.py
from flask import Flask, render_template
app = Flask(__name__, static_url_path="", static_folder="static"
import myApp.views
views.py
from flask import Flask, render_template, request, Blueprint
from myApp import app
app.config['SERVER_NAME'] = 'myapp.com'
app.url_map.default_subdomain = "www"
#app.route("/")
def index():
return "This is index page."
test = Blueprint('test', 'test', subdomain='test')
#test.route("/")
def testindex():
return "This is test index page."
app.register_blueprint(test)
if __name__ == "__main__":
app.run()
Using this method I am able to get subdomains 'test' and 'www' working, but now I am unable to access my website via IP address.
Any guidance into the right direction would be appreciated!

Categories

Resources