I'm currently learning Django and I'm trying to add form to register a User.
Now my problem starts really early because I get a 404 whenever I try to access my registration page.
My 3 files are as follows:
views.py : just a hello world to display basically
from django.http import HttpResponse
def index(request):
return HttpResponse("Hello World")
def registration(request):
return HttpResponse("Registration page")
urls.py (in my project) :
from django.conf.urls import patterns, include, url
from django.contrib import admin
urlpatterns = patterns('',
(r'^$', include('myapp.urls')), # index with login/registration
(r'^grappelli/', include('grappelli.urls')), # grappelli URLS
(r'^admin/', include(admin.site.urls)), # admin site
)
and finally urls.py (in my app) :
from django.conf.urls import patterns, url
from myapp import views
urlpatterns = patterns('',
url(r'^$',views.index, name='index'),
url(r'^registration/$',views.registration, name='registration'),
)
When I go to my normal index (localhost:8000) It displays the hello world I wrote in the views.py file. However when I try to go the registration page it just returns me a 404 (localhost:8000/registration).
Now as I said I'm still learning this whole thing, but I don't get why It doesn't work properly. As far as i understand the r'^$' in the project file is pointing towards the localhost:8000 and the same regex in the app file tells it to load the index page in this location. Now as the program is still in localhost:8000, a r'^registration/' should be loading the other page in localhost:8000/registration right?
It would be really nice if you could explain to me why this doesn't work and where I did a mistake in my thoughts.
This is the error I get:
When i take
(r'^randomstringhere/', include('myapp.urls')), # index with login/registration
instead of
(r'^$', include('myapp.urls')), # index with login/registration
I can get to the registration page via localhost:8000/randomstringhere/registration. But Site is meant to have a selection where you can either Log in or register on localhost:8000 (or future domain www.randomdomainhere.com) and a registration/login form on localhost:8000/login, localhost:8000/registration (www.randomdomainhere.com/registration etc.)
At the end of each url you should add a $ symbol,
url(r'^registration/$',views.registration, name='registration'),
reffer this https://docs.djangoproject.com/en/1.4/topics/http/urls/
you are missing $ sign in the end of url.
It should be:
url(r'^registration/$',views.registration, name='registration'),
The $ symbol in django urls means end-of-string match character which is borrowed from regular expression. So, $ should be added at the end of your url on app's urls.
url(r'^registration/$',views.registration, name='registration'),
However we can write urls with the regular expressions that don’t have a $ (end-of-string match character) but we do have to include a trailing slash(/). For urls without $, you must enter the trailing slash while opening the url in your browser to match the regular expression.
Your app urls in project's urls.py is
url(r'^grappelli/', include('grappelli.urls')), # grappelli URLS
So, to access the registration page, you need to browse by
localhost:8000/grappelli/registration/
i.e. append the path in your app's url to the path in project's url for the app.
Learn more about urls here.
You need to remove $ from the first url as given below
urls.py (in my project) :
from django.conf.urls import patterns, include, url
from django.contrib import admin
urlpatterns = patterns('',
(r'^', include('myapp.urls')), # index with login/registration
(r'^grappelli/', include('grappelli.urls')), # grappelli URLS
(r'^admin/', include(admin.site.urls)), # admin site
)
A url starts with ^ and ends with $. so if $ is encountered django understands that the url has ended and there's nothing more infront of that. so in your case it will no more look for "registration". or if your url with "registration" doesnt matches to any urls specified at all.
Related
I have started learning Django, I'm not sure what the include() function means.
Here is mysite/urls.py. - project
from django.conf.urls import include, url
from django.contrib import admin
urlpatterns = [
url(r'^polls/', include('polls.urls')),
url(r'^admin/', admin.site.urls),
]
Here is polls/urls.py. - app in project
from django.conf.urls import url
from . import views
urlpatterns = [
url(r'^$', views.index, name='index'),
]
From django document, include() function was described as follows.
Whenever Django encounters include(), it chops off whatever part of the URL matched up to that point and sends the remaining string to the included URLconf for further processing.
I'm not sure what is that point, what is remaining string.
In case of the example above, what is remining string, what is url strings which was chopped off?
For example, from this URL:
polls/5/results
the URL rule:
url(r'^polls/', include('polls.urls')),
chops off the polls/ part of URL and sends the remaining string after polls/, whatever it might be, for example (see here more):
5/results/
to urls from the poll app's urls.py, where it will then be mapped to a view based on the URL rules defined in this file
Whenever it will encounter any url with /polls then it will include all the urls of polls app.
Example:
If you type /polls/hey
Then as soon as it sees /polls it will go to polls urls file and later it will search for:
hey/ matching over there.
Lets say there is one more entry in your polls/urls.py like
url(r'^articles/(?P<year>[0-9]{4})/$', views.year_archive),
here year is the query string parameter. so your url will look like
/polls/articles/2007 so in this case /polls/articles/ will matched up and 2007 will pass to year_archive method
In your example there is no chopped string, the URL comes back as simply polls/, but when you have another url such as '^new$' then that url is being chopped, merged with polls/ and it returns polls/new, hope this makes sense..
I'm having the 404 error when trying to handle a view that is not related to the main page. For example, if I initially start at the main page home, and want to navigate to another page called, otherpage, I receive a 404 otherpage.html not found.
The way I'm doing is based off intuition. So if there's a better way to do this, please mention it:
in the file:
prd/
views.py
url.py
otherstuffthatshouldbehere.py..
I have views.py (this is where I think the error is):
from django.shortcuts import render
def home(request):
context = {}
template = "index.html"
return render(request, template, context)
def otherpage(request):
context = {}
template = "otherpage.html"
return render(request, template, context)
Then urls.py:
from django.conf.urls import patterns, include, url
from django.contrib import admin
urlpatterns = patterns('',
url(r'^$', 'prd.views.home', name='home'),
url(r'^$', 'prd.views.otherpage', name='otherpage'),
url(r'^admin/', include(admin.site.urls)),
)
This returns a 404 for the otherpage.html. I have the template directory working fine. But how do I go about handling multiple views?
EDIT:
Upon adding:
url(r'^otherpage$', 'prd.views.otherpage', name='otherpage'),
I received this error:
Using the URLconf defined in prd.urls, Django tried these URL patterns, in this order:
^$ [name='home']
^about$ [name='about']
^projects$ [name='projects']
^admin/
The current URL, about.html, didn't match any of these.
The urlpatterns starts at the top and then goes down until it matches a URL based on the regex. In order for Django to serve up the page located at otherpage.html there has to be a URL defined in urlpatterns that matches otherpage.html otherwise you will get the 404.
In this case you have:
url(r'^$', 'prd.views.home', name='home'),
url(r'^$', 'prd.views.otherpage', name='otherpage'),
Note that nothing will ever get to otherpage here because home has the same pattern (regex) and will therefore always match first. You want to have a different URL for both those so that you can differentiate between them. Perhaps you could do something like:
url(r'^$', 'prd.views.home', name='home'),
url(r'^otherpage.html$', 'prd.views.otherpage', name='otherpage'),
After making this change you now have a match for otherpage and hopefully no more 404.
EDIT:
url(r'^otherpage.html$', 'prd.views.otherpage', name='otherpage'),
This matches www.example.com/otherpage.html but it will not match www.example.com/otherpage
To match www.example.com/otherpage you need to use:
url(r'^otherpage$', 'prd.views.otherpage', name='otherpage'),
Note the difference in the regex, there's no .html here. The regex matches exactly what you put in it.
I am pretty new to Django and when I laid my site out I did it in the following way:
The project is a "portal" of sorts,
App 1 "home" is the app that houses the homepage, login, registration
and other "site-wide" functionality
App 2 "inventory" is a basic asset inventory
App 3 "dashboard" is a set of status dashboards based on assets in the inventory
Right now I am trying to add the login functionality and I have a main project urls.py that looks like this:
File: /portal/urls.py
from django.conf import settings
from django.conf.urls import patterns, include, url
from django.contrib import admin
admin.autodiscover()
urlpatterns = patterns('',
url(r'^$', include('home.urls'), name='home'),
url(r'^admin/', include(admin.site.urls), name='admin'),
url(r'^inventory/', include('inventory.urls'), name='inventory'),
url(r'^dashboard/', include('dashboard.urls'), name='dashboard'),
url(r'^capacity/', include('capacity.urls'), name='capacity'),
)
My plan is to use the inclusion of .../home/urls.py to manage any site-wide functionality such as logging in, registering, etc.
Right now the home index view shows just fine, but anything else in .../home/urls.py gives me a 404
File: /home/urls.py
from django.conf.urls import patterns, url
from home import views
urlpatterns = patterns('',
url(r'^test/$', views.index, name='home_test'),
url(r'^ajax_login/$', views.ajax_login, name='ajax_login'),
url(r'^$', views.index, name='home_index'),
)
At this point I suppose my question is two-fold: Am I approaching this correctly? If so, how can I get the desired functionality? If not, how should I change the way things are set up/laid out to do it the correct "best practices" way?
Thanks in advance!
EDIT
Got it working thanks to dt0xff and holdenweb, accepted holdenweb's answer since it was more accurate including the need to put the home url inclusion below the rest.
Here is my new portal/urls.py file for reference
File: /portal/urls.py
from django.conf import settings
from django.conf.urls import patterns, include, url
from django.contrib import admin
admin.autodiscover()
urlpatterns = patterns('',
url(r'^admin/', include(admin.site.urls), name='admin'),
url(r'^inventory/', include('inventory.urls'), name='inventory'),
url(r'^dashboard/', include('dashboard.urls'), name='dashboard'),
url(r'^capacity/', include('capacity.urls'), name='capacity'),
url(r'^', include('home.urls'), name='home'),
)
The issue is with your first pattern, which will only match the empty URL. So any empty URL will cause the home/urls.py URLs to be analyzed, but only the empty one will match even in that.
Unfortunately if there is no common prefix then that pattern "^" will match every URL (since they all start at the beginning ...).
So you should either use a common prefix for all the pages, or put the home URL specification at the end to give the other URLs a chance to match before it is tested.
Django looks in urls like this:
Get list of root urls - portal/urls
Find first, which matches to current url
If it is include, go to included urls, cutting off matched part
Your problem is here
url(r'^$', include('home.urls'), name='home'),
I mean, here
'^$'
You want url to match "start and then end of url". It works good with root(dunno.com/), but not with others, because url will contain something more...
So, just remove $ and you are fine
url(r'^', include('home.urls'), name='home'),
you never need to add regex($) at project/urls.py
I'm working through https://docs.djangoproject.com/en/1.4/intro/tutorial02/ .
after changing the urls.py to
from django.conf.urls import patterns, include, url
# Uncomment the next two lines to enable the admin:
from django.contrib import admin
admin.autodiscover()
urlpatterns = patterns('',
# Examples:
# url(r'^$', 'mysite.views.home', name='home'),
# url(r'^mysite/', include('mysite.foo.urls')),
# Uncomment the admin/doc line below to enable admin documentation:
# url(r'^admin/doc/', include('django.contrib.admindocs.urls')),
# Uncomment the next line to enable the admin:
url(r'^admin/', include(admin.site.urls)),
)
I get the following when I start the runserver:
404 error
Using the URLconf defined in mysite.urls, Django tried these URL patterns, in this order:
^admin/
The current URL, , didn't match any of these.
Is there anything obvious that I'm doing wrong?
Thanks in advance,
Bill
You don't have a base url defined. You need something like -
urlpatterns = patterns('',
# ...
url(r'^$', HomeView.as_view())
)
You should be able to see your site at - localhost:8000/admin/ (assuming you're running your dev server with python manage.py runserver).
Django checks all the URL's you've defined in your url conf file and looks for one that matches the url you've entered in the browser. If it finds a URL that matches then it serves up the http response returned by the url's corresponding view (HomeView in the code above). The urls.py file is matching url's to views. Views return the http response.
Looking at the error message you've got (and the code you've included from the url.py file), you can see that there's only one url defined in your app - admin/. Trying to get a page at any other url will fail.
For more information have a look at the docs for django's URL Dispatcher.
I have the following code in the urls.py in mysite project.
/mysite/urls.py
from django.conf.urls.defaults import *
urlpatterns = patterns('',
(r'^gallery/$', include('mysite.gallery.urls')),
)
This results in a 404 page when I try to access a url set in gallery/urls.py.
/mysite/gallery/urls.py
from django.conf.urls.defaults import *
urlpatterns = patterns('',
(r'^gallery/browse/$', 'mysite.gallery.views.browse'),
(r'^gallery/photo/$', 'mysite.gallery.views.photo'),
)
404 error
Using the URLconf defined in mysite.urls, Django tried these URL patterns, in this order:
^gallery/$
The current URL, gallery/browse/, didn't match any of these.
Also, the site is hosted on a media temple (dv) server and using mod_wsgi
Remove the $ from the regex of main urls.py
urlpatterns = patterns('',
(r'^gallery/', include('mysite.gallery.urls')),
)
You don't need gallery in the included Urlconf.
urlpatterns = patterns('',
(r'^browse/$', 'mysite.gallery.views.browse'),
(r'^photo/$', 'mysite.gallery.views.photo'),
)
Read the django docs for more information
Note that the regular expressions in this example don't have a $ (end-of-string match character) but do include a trailing slash. Whenever Django encounters include(), it chops off whatever part of the URL matched up to that point and sends the remaining string to the included URLconf for further processing.