Develop Reference

Reading xml with lxml lib geting strange string from xmlns tag

I am writing program to work on xml file and change it. But when I try to get to any part of it I get some extra part.
My xml file:
<?xml version="1.0" encoding="UTF-8"?>
<Package xmlns="http://soap.sforce.com/2006/04/metadata">
<types>
<members>sbaa__ApprovalChain__c.ExternalID__c</members>
<members>sbaa__ApprovalCondition__c.ExternalID__c</members>
<members>sbaa__ApprovalRule__c.ExternalID__c</members>
<name>CustomField</name>
</types>
<version>40.0</version>
</Package>
And I have my code:
from lxml import etree
import sys
tree = etree.parse('package.xml')
root = tree.getroot()
print( root[0][0].tag )
As output I expect to see members but I get something like this:
{http://soap.sforce.com/2006/04/metadata}members
Why do I see that url and how to stop it from showing up?

You have defined a default namespace (Wikipedia, lxml tutorial). When defined, it is a part of every child tag.
If you want to print the tag without the namespace, it's easy
tag = root[0][0].tag
print(tag[tag.find('}')+1:])
If you want to remove the namespace from XML, see this question.

Querying XML with Python

Consider the following XML code.
<?xml version="1.0"?>
<data>
<element>This is the first sentence.<button>Click</button>some more text.
</element>
</data>
I am using Python module xml.etree.ElementTree.
I know that I can access to elements and texts with the following Python code
import xml.etree.ElementTree as ET
name = 'data.xml'
tree = ET.parse(name)
root = tree.getroot()
element = root[0].tag
first_text = root[0].text #This is the first sentence
button = root[0][0].tag #button
buttontext = root[0][0].text #click
But how do I access to text "some more text" with Python?
I haven't found the solution yet...
You can also suggest some other Python module if it's better way to do that.
That XML-code is just an example.

you are looking for the .tail attribute of the <button> element: https://docs.python.org/3/library/xml.etree.elementtree.html#xml.etree.ElementTree.Element.tail

How to make my PyObjC application AppleScript-able

I want to create an application on OS X with Python, that is AppleScript-able.
First I used this tutorial to create an Application (it works!). Then I used this SO answer to add AppleScript support; I tried to translate the Objective-C stuff into Python. I added a plist-item to the options in setup.py:
OPTIONS = {
#...
'plist': {
'NSAppleScriptEnabled': True,
'OSAScriptingDefinition': 'SimpleXibDemo.sdef',
#...
}
}
I created SimpleXibDemo.sdef
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE dictionary SYSTEM "file://localhost/System/Library/DTDs/sdef.dtd">
<dictionary title="SimpleXibDemo">
<suite name="SimpleXibDemo Suite" code="SXiD" description="SimpleXibDemo Scripts">
<command name="increase" code="increxib" description="Increase the value">
<cocoa class="SimpleXibDemoIncreaseCommand"/>
<parameter name="by" type="integer" optional="yes">
<cocoa key="by"/>
</parameter>
<result description="Returns the new value" type="integer"/>
</command>
</suite>
</dictionary>
and I added the class SimpleXibDemoIncreaseCommand:
class SimpleXibDemoIncreaseCommand(NSScriptCommand):
def performDefaultImplementation(self):
args = self.evaluatedArguments()
nr = args.valueForKey("by")
viewController.increment()
return nr + 1
The application itself works, but when I run this AppleScript:
tell application "SimpleXibDemo"
set myResult to increase by 3
end tell
I get this error:
error "SimpleXibDemo got an error: Can’t continue increase." number -1708
I can't find any info on error number -1708. And when I open the application with Script Editor -> Open Dictionary, nothing happens.
What is the problem here? I'm a bit stuck :-/

Modify XML node using Python

I am taking an XML file as an input, have to search with a keyword i.e GENTEST05.
If found , then I need to pick up its parent node (in this example I want to pick up <ScriptElement>) and then replace the complete node <ScriptElement>blahblah</ScriptElement> with a new content.
...
...
<ScriptElement>
<ScriptElement>
<ScriptElement>
<ElementData xsi:type="anyData">
<DeltaTime>
<Area>
<Datatype>USER PROMPT [GENTEST05]</Datatype>
<Description />
<Multipartmessage>False<Multipartmessage>
<Comment>false</Comment>
</ElementData>
</ScriptElement>
<ScriptElement>
<ScriptElement>
...
...
...
I am trying to do this using Beautifulsoup. This is what I've done so far but not getting a proper way to proceed. Other than beautifulsoup, ElementTree or any other suggestion is welcome.
import sys
from BeautifulSoup import BeautifulStoneSoup as bs
xmlsoup = bs(open('file_xml' , 'r'))
a = raw_input('Enter Text')
paraText = xmlsoup.findAll(text=a)
print paraText
print paraText.findParent()

Ok here is some sample code to get you started. I used ElementTree because it's a builtin module and quite suitable for this type of task.
Here is the XML file I used:
<?xml version="1.0" ?>
<Script>
<ScriptElement/>
<ScriptElement/>
<ScriptElement>
<ElementData>
<DeltaTime/>
<Area/>
<Datatype>USER PROMPT [GENTEST05]</Datatype>
<Description/>
<Multipartmessage>False</Multipartmessage>
<Comment>false</Comment>
</ElementData>
</ScriptElement>
<ScriptElement/>
<ScriptElement/>
</Script>
Here is the python program:
import sys
import xml.etree.ElementTree as ElementTree
tree = ElementTree.parse("test.xml")
root = tree.getroot()
#The keyword to find and remove
keyword = "GENTEST05"
for element in list(root):
for sub in element.iter():
if sub.text and keyword in sub.text:
root.remove(element)
print ElementTree.tostring(root)
sys.exit()
I have kept the program simple so that you can improve on it. Since your XML has one root node, I am assuming you want to remove all parent elements of the keyword-matched element directly up to the root. In ElementTree, you can call root.remove() to remove the <ScriptElement> element that is the ancestory of the keyword-matched element.
This is just to get you started: this will only remove the first element, then print the resulting tree and quit.
Output:
<Script>
<ScriptElement />
<ScriptElement />
<ScriptElement />
<ScriptElement />
</Script>

List only one category Python xml

I am trying to write a python program that uses DOM to read xml file and print another xml structure that list from only one node with particular selected attribute "fun".
<?xml version="1.0" encoding="ISO-8859-1"?>
<website>
<url category="fun">
<title>Fun world</title>
<author>Jack</author>
<year>2010</year>
<price>100.00</price>
</url>
<url category="entertainment">
<title>Fun world</title>
<author>Jack</author>
<year>2010</year>
<price>100.00</price>
</url>
</website>
I couldn't select the list from the URL having category="fun".
I tried this code:
for n in dom.getElementsByTagName('url'):
s = n.attribute['category']
if (s.value == "fun"):
print n.toxml()
Can you guys help to me to debug my code?

nb: One of your tags opens "Website" and attempts to close "website" - so you'll want to fix that one...
You've mentioned lxml.
from lxml import etree as et
root = et.fromstring(xml)
fun = root.xpath('/Website/url[#category="fun"]')
for node in fun:
print et.tostring(node)

Use getAttribute:
for n in dom.getElementsByTagName('url'):
if (n.getAttribute('category') == "fun"):
print(n.toxml())