implementing functions in a game - python

I am having trouble with this part of my assignment. I have to declare a winner of the game and then input into a function. Once I have entered all the if statements I then have to create a function def playGame(). This has to include:
showRules()
user = getUserChoice()
computer = getComputerChoice()
declareWinner(user, computer)
I am not too sure how to do this. Please help.
Below is the code that I have completed so far: (Would I need to do an if statement for scissors as well?)
#Display game rules
print("Rules: Each player chooses either Rock, Paper, or Scissors.")
print("\tThe winner is determined by the following rules:")
print("\t\tScissors cuts Paper --> Scissors wins")
print("\t\tPaper covers Rock --> Paper wins")
print("\t\tRock smashes Scissors --> Rock Wins")
def userchoice():
choice = (input("Make your selection (Rock, Paper, or Scissors). ")).lower()
return choice
#obtain computer input
def getComputerchoice():
import random
rnum = random.randint(1,3)
if rnum == 1:
print("The computer has chosen Rock.")
if rnum == 2:
print("The computer has chosen Paper.")
if rnum == 3:
print("The computer has chosen Scissors.")
return rnum
#Declare winner
def declarewinner (user, rnum):
if userchoice == 1:
print("You have chosen rock.")
if getComputerchoice == 1:
print("Computer has chose rock as well.")
return 0
else:
print("The computer has chosen scissors. Rock breaks scissors. You WIN!")
return 1
if userchoice == 2:
print("You have chosen paper.")
if getComputerchoice == 1:
print("The computer has chosen rock. Paper covers rock. You WIN!")
return 1
elif getComputerchoice == 2:
print("The computer has chosen paper as well.")
return 0
else:
print("The computer has chosen scissors. Scissors cut paper. You LOSE!")
return 1
if userchoice == 3:
print("You have chosen scissors")
if getComputerchoice == 1:
print("The computer has chosen rock. Rock breaks scissors. You LOSE!")
return 1
elif getComputerchoice == 2:
print("The computer has chosen paper. Scissors cut paper. You WIN!")
return 1

how bout
class hand:
def __init__(self,rps):
self.rps = ["rock","paper","scissors"].index(rps.lower())
def __cmp__(self,other): #take advantage of pythons __cmp__ and override it
#this is the magic
wins_against = {0:2,1:0,2:1}
#if their equal return 0
if self.rps == other.rps: return 0
#if this hand wins return 1
if wins_against[self.rps] == other.rps:return 1
#else (This hand loses) return -1
return -1
def __str__(self):
return ["rock","paper","scissors"][self.rps]
print( hand("rock") > hand("paper") )
print( hand("scissors") > hand("paper") )
print( hand("rock") > hand("scissors") )
granted its probably overkill for this but it s a cool technique ... and if you can get it down now it may help you with future assignments
def get_cpu_pick():
return random.choice(["rock", "paper", "scissors"])
def get_player_pick():
valid_inputs = {
'r':'rock','p':'paper','s':'scissors'
}
user_choice = input("Select RPS:")
while user_choice.lower() not in valid_inputs:
user_choice = input("Select RPS:")
return valid_inputs.get(user_choice.lower())
def play():
user_hand = hand(get_player_pick())
cpu_hand = hand(get_cpu_pick())
if user_hand > cpu_hand:
print ("User Wins {0} v. {1}".format(user_hand,cpu_hand))
elif user_hand < cpu_hand:
print ("CPU Wins {0} v. {1}".format(user_hand,cpu_hand))
else:
print("TIE!!!")

Related

Rock, paper, scissors game in Python - some clarification needed

I am writing a simple game of rock, paper and scissors, where the user competes with a computer. There are 5 tries.
The problems I ran into are :
If I enter something apart from three options, it should return "Invalid Entry". Instead, the program stops
The program never prints "You won the game" or "You lost the game", it finishes after 5 attempts
Other feedback would also be appreciated
import random
def game():
win_count = 0
loose_count = 0
tries = 0
while tries < 5:
chosen = input("Make your choice: ")
if chosen == "scissors" or chosen == "Scissors":
element = "scissors"
elif chosen == "paper" or chosen == "Paper":
element = "paper"
elif chosen == "rock" or chosen == "Rock":
element = "rock"
else:
return "Invalid Entry"
computer_choices = ["scissors", "paper", "rock"]
computer_choice = random.choice(computer_choices)
if element == "scissors" and computer_choice == "paper":
print("Computer chose paper, you chose scissors, you win !")
win_count += 1
tries += 1
elif element == "paper" and computer_choice == "scissors":
print("Computer chose scissors, you chose paper, you loose !")
loose_count += 1
tries += 1
elif element == "paper" and computer_choice == "rock":
print("Computer chose rock, you chose paper, you win !")
win_count += 1
tries += 1
elif element == "rock" and computer_choice == "paper":
print("Computer chose paper, you chose rock, you loose !")
loose_count += 1
tries += 1
else:
print("Whoops, that's a draw, try again")
tries+=1
print("Your Wins: "+ str(win_count))
print("Computer Wins: "+str(loose_count))
if win_count > loose_count:
return "Congrats, you won the game!"
else:
return "Sorry, you lost"
game()
return statement does not print anything but they return the value from a function and as soon as a return statement executes the function ends up executing that's why whenever the user inputs something invalid the program stop.
Also not use the if statement from if chosen = paper or chosen = Paper instead use .lower() to lower the string.
I have made some changes to your code.
Try this code
import random
def game():
win_count = 0
loose_count = 0
tries = 0
while tries < 5:
element = input("Make your choice: ").lower()
computer_choices = ["scissors", "paper", "rock"]
if element not in computer_choices:
print("Invalid choice")
continue
computer_choice = random.choice(computer_choices)
if element == "scissors" and computer_choice == "paper":
print("Computer chose paper, you chose scissors, you win !")
win_count += 1
tries += 1
elif element == "paper" and computer_choice == "scissors":
print("Computer chose scissors, you chose paper, you loose !")
loose_count += 1
tries += 1
elif element == "paper" and computer_choice == "rock":
print("Computer chose rock, you chose paper, you win !")
win_count += 1
tries += 1
elif element == "rock" and computer_choice == "paper":
print("Computer chose paper, you chose rock, you loose !")
loose_count += 1
tries += 1
else:
print("Whoops, that's a draw, try again")
tries+=1
print("Your Wins: "+ str(win_count))
print("Computer Wins: "+str(loose_count))
if win_count > loose_count:
print("Congrats, you won the game!")
else:
print("Sorry, you lost")
game()

Searching for a certain word decided by a .format in a print()

Im new to python and i was told a good place to start was writing a rock paper scissors program.
This is what i have so far:
import random
term1 = "Rock"
term2 = "Paper"
term3 = "Scissors"
computerchose = [term1, term2, term3]
print("Welcome to Rock Paper Scissors!")
print("You will be versing the computer, Good luck!")
print("Rock \nPaper \nScissors")
input = input(print("please choose your weapon "))
words = input.split()
if term1 in words:
print("Oh you chose Rock did you?!? Well the computer chose {0}".format(random.choice(computerchose)))
if term2 in words:
print("Oh you chose Paper did you?!? Well the computer chose {0}".format(random.choice(computerchose)))
if term3 in words:
print("Oh you chose Scissors did you?!? Well he computer chose {0}".format(random.choice(computerchose)))
Im looking to try and make a win condition. My thought process for this was get the {0}.format answer and check it for term1,term2,term3 respectivly. If anyone could help me with this i would much appriciate it!
You should set a variable to the computer's choice once, and then compare it with the player's choice.
humanchoice = input("Please choose your weapon")
computerchoice = random.choice(computerchose)
if humanchoice == term1:
if computerchoice == term2:
winner = "computer"
elif computerchoice == term3:
winner = "human"
else: winner = "tie"
elif humanchoice == term2:
if computerchoice == term3:
winner = "computer"
elif computerchoice == term1:
winner = "human"
else:
winner = "tie"
elif humanchoice == term3:
if computerchoice == term1:
winner = "computer"
elif computerchoice == term2:
winner = "human"
else:
winner = "tie"
else:
print("That's not a valid weapon")

NameError: free variable 'player_one_rps' referenced before assignment in enclosing scope

I'm quite new to coding, and I've been trying to make a text-based game with a menu. The game itself works fine, but once I try to incorporate a menu, i get the error "NameError: free variable 'player_one_rps' referenced before assignment in enclosing scope".
I have been googling it like a mad for some time now, but the few answers I find uses too advanced code for me to understand it yet.
(I tried changing the scopes and indents, I tried calling different functions at different indents, I tried assigning an argument to the functions, also, to have the main menu as the last function in the code – the list goes on..)
Here is the code for the menu and game option 1:
def main():
print("\t\t*** Welcome to this totally adequate game! ***")
def game_menu():
"""Displays game menu and prompts user for input"""
menu_choice = input("""What do you want to do?
1 - One player: rock, paper, scissor, lizard, spock
2 - Two player: rock, paper, scissor, lizard, spock
3 - Surprise! Bonus feature
4 - User guide
5 - Quit
Enter the menu number to access: """)
while True:
if menu_choice == "1":
print("One player: rock, paper, scissor, lizard, spock")
player_one_rps()
break
elif menu_choice == "2":
print("Two player: rock, paper, scissor, lizard, spock")
player_two_rps()
break
elif menu_choice == "3":
print("Surprise! Bonus feature")
dad_jokes()
break
elif menu_choice == "4":
print("User guide")
user_info()
elif menu_choice == "5":
print("Quit game")
exit()
elif menu_choice != 1 - 5:
print("Error, choose a valid number")
# print(menu_choice)
game_menu()
main()
# First game
def player_one_rps():
"""One player rock, paper, scissor, lizard, spock - game"""
import random
def instructions():
"""Displays menu and simple instructions on how to play"""
print("Welcome to rock, paper, scissor, lizard, spock!")
play = input("\nNavigate by \"yes\", \"no\", and numbers.\nNew game?:").lower()
if play == "yes":
print("1. Rock")
print("2. Paper")
print("3. Scissors")
print("4. Lizard")
print("5. Spock")
elif play != "no":
print("an error has occured. Please type \"yes\" or \"no\":")
instructions()
def get_user_choice():
"""Prompts the player to pick a 'weapon'"""
choice = int(input("What do you choose?: "))
if choice > 5:
print("Invalid number, please try again....")
get_user_choice()
elif choice < 1:
print("Invalid number, please try again....")
get_user_choice()
elif choice == 1:
print("You chose rock")
elif choice == 2:
print("You chose paper")
elif choice == 3:
print("You chose scissor")
elif choice == 4:
print("You chose lizard")
elif choice == 5:
print("You chose spock")
return choice
def get_pc_choice():
"""The computer chooses a random weapon"""
choice = random.randint(1, 5)
if choice == 1:
print("PC chose rock")
elif choice == 2:
print("PC chose paper")
elif choice == 3:
print("PC chose scissor")
elif choice == 4:
print("PC chose lizard")
elif choice == 5:
print("PC chose spock")
return choice
def winner(user_choice, pc_choice, user_wins, pc_wins, ties):
"""Calculates if the player or computer won the match"""
if user_choice == 1 and pc_choice == 3 or pc_choice == 4:
print("\nYou win.")
user_wins = user_wins.append(1)
elif user_choice == 2 and pc_choice == 1 or pc_choice == 5:
print("\nYou win.")
user_wins = user_wins.append(1)
elif user_choice == 3 and pc_choice == 2 or pc_choice == 4:
print("\nYou win.")
user_wins = user_wins.append(1)
elif user_choice == 4 and pc_choice == 2 or pc_choice == 5:
print("\nYou win.")
user_wins = user_wins.append(1)
elif user_choice == 5 and pc_choice == 1 or pc_choice == 3:
print("\nYou win.")
user_wins = user_wins.append(1)
elif user_choice == pc_choice:
print("\nTie")
ties = ties.append(1)
else:
print("\nPC won")
pc_wins = pc_wins.append(1)
return
def game_total(user_wins, pc_wins, ties):
"""Displays the total score"""
user_wins = sum(user_wins)
pc_wins = sum(pc_wins)
ties = sum(ties)
print("Your final score: ", user_wins)
print("PC\'s final Score: ", pc_wins)
print("Total ties: ", ties)
def main_one_p():
"""Main instructions for how the game runs"""
user_choice = 0
user_wins = []
pc_choice = 0
pc_wins = []
ties = []
final_user_wins = 0
final_pc_wins = 0
final_ties = 0
Continue = "yes"
instructions()
while Continue == "yes":
user_choice = get_user_choice()
pc_choice = get_pc_choice()
winner(user_choice, pc_choice, user_wins, pc_wins, ties)
Continue = input("Would you like to play again: ").lower()
if Continue == "no":
print("This is the final scores.")
break
game_total(user_wins, pc_wins, ties)
main_one_p()
player_one_rps()
game_menu() # Returns player to the main menu
(sorry if it is quite long)
Could anyone help point me in the direction of my mistake? Explanations and tips on how to fix it would also be greatly appreciated :)
In general, I'm thankful for all feedback, as i really want to become better at coding.
The global function must have a higher declarative code than where it is called. Simply reposition the function. The function game_menu must be below the function play_one_rps. The other functions are the same.

better write rock paper scissors (python)

Hey guys I'm new to python and I have made this simple rock paper scissors game but I wonder if there is a better way to program this without a super long if else statement.
import random
options = ["scissors", "paper", "rock"]
i = random.randint(0, (len(options) - 1))
playedHand = input("PLay rock, paper or scissors please: ")
computerPlayedHand = options[i]
if playedHand == "rock" and computerPlayedHand == "scissors":
print("the computer had scissors, you win")
elif playedHand == "rock" and computerPlayedHand == "paper":
print("the computer had paper, you lose")
elif playedHand == "rock" and computerPlayedHand == "rock":
print("the computer also had rock, its a tie")
elif playedHand == "paper" and computerPlayedHand == "rock":
print("the computer had rock, you win")
elif playedHand == "paper" and computerPlayedHand == "scissors":
print("the computer had scissors, you lose")
elif playedHand == "paper" and computerPlayedHand == "paper":
print("the computer also had paper, its a tie")
elif playedHand == "scissors" and computerPlayedHand == "paper":
print("the computer had paper, you win")
elif playedHand == "scissors" and computerPlayedHand == "scissors":
print("the computer also had scissors, its a tie")
elif playedHand == "scissors" and computerPlayedHand == "rock":
print("the computer had rock, you lose")
else:
print("please only state rock, paper or scissors")
Here is what I threw together trying to reuse your code where possible.
The key part is noticing that the options list can be treated as a cycle where an option always beats the next option. You can check this by finding the indices and then using modulo to make the indices cyclic.
import random
options = ["scissors", "paper", "rock"] # everything loses to the previous thing
comp_index = random.randint(0, (len(options) - 1))
playedHand = input("Play rock, paper or scissors please: ")
computerPlayedHand = options[comp_index]
try:
player_index = options.index(playedHand)
except ValueError:
print("please only state rock, paper or scissors")
else:
if player_index == comp_index:
res = "the computer also had {}, its a tie"
# the key part
elif (player_index - comp_index) % 3 == 1:
res = "the computer had {}, you lose"
else:
res = "the computer had {}, you win"
print(res.format(computerPlayedHand))
Using a dictionary to represent which hand beat which can significantly shorten your code. But since we are there, let's make this even neater with an object-oriented solution.
import random
class Hand:
_ordering = {
'rock': 'scissor',
'scissor': 'paper',
'paper': 'rock'
}
def __init__(self, kind):
if kind in self._ordering:
self.kind = kind
else:
raise ValueError(
"It's rock, paper, scissor... Not rock, {}, scissor.".format(kind)
)
#classmethod
def random_hand(cls):
return cls(random.choice(list(cls._ordering)))
def beats(self, other):
return self._ordering[self.kind] == other.kind
playedHand = Hand(input("Play rock, paper or scissors please: "))
computerPlayedHand = Hand.random_hand()
if playedHand.beats(computerPlayedHand):
print('You won! The computer had {}.'.format(computerPlayedHand.kind))
elif computerPlayedHand.beats(playedHand):
print('You lost... The computer had {}.'.format(computerPlayedHand.kind))
else:
print("It's a tie.")
You don't need to use any "if" statements other than typical error management. Look at the following example:
import random
def play():
table = [[2, 0, 1],
[1, 2, 0],
[0, 1, 2]]
options = ["Rock", "Paper", "Scissors"]
results = ["Defeat", "Win", "Tie"]
conv = {"R": 0 , "P": 1, "S": 2}
while True:
i = random.randint(0, (len(options) - 1))
p = input("Play rock, Paper or Scissors please (R, P, S): ")
if p not in conv.keys():
print("Unavailable option. Left the Game.")
return
print("Computer played %s. You have a %s"%(options[i], results[table[conv[p]][i]]))
play()
If you have a table like this:
# Rock Paper Scissor
# Rock 2 0 1
# Paper 1 2 0
# Scissor 0 1 2
...you can make the user play in rows, and the computer in columns. The result is being indexed directly by whatever is the number in the table. Thus playing the game in the example would look like this:
Here's another possible version:
import random
try:
options = [('rock', 'scissors'), ('paper', 'rock'), ('scissors', 'paper')]
human_choice = int(input("Play rock(0), paper(1) or scissors(2) please: "))
human_hand = options[human_choice]
computer_hand = options[random.randint(0, (len(options) - 1))]
text = "the computer {} {}, {}"
if human_hand[0] == computer_hand[0]:
print(text.format("also had", computer_hand[0], "it's a tie"))
elif human_hand[1] == computer_hand[0]:
print(text.format("had", computer_hand[0], "you win"))
else:
print(text.format("had", computer_hand[0], "you lose"))
except Exception as e:
print("please only state rock, paper or scissors")

Python rock paper scissors score counter

I am working on a rock paper scissors game. Everything seems to be working well except the win/loss/tie counter. I have looked at some of the other games people have posted on here and I still cannot get mine to work. I feel like I am soooooo close but I just can't get it! thanks for any help guys. this is my first time posting in here so I am sorry if I messed up the formatting.
I edited the code but still cannot get the program to recognize the counter without using global variables. at one point of my editing I managed to get it to count everything as a tie... i dont know how and I lost it somewhere along my editing. lol. -thanks again everyone!
here is what I get when I run the program:
Prepare to battle in a game of paper, rock, scissors!
Please input the correct number according
to the object you want to choose.
Select rock(1), paper(2), or scissors(3): 1
Computer chose PAPER .
You chose ROCK .
You lose!
Play again? Enter 'y' for yes or 'n' for no. y
Prepare to battle in a game of paper, rock, scissors!
Please input the correct number according
to the object you want to choose.
Select rock(1), paper(2), or scissors(3): 2
Computer chose PAPER .
You chose PAPER .
It's a tie!
Play again? Enter 'y' for yes or 'n' for no. y
Prepare to battle in a game of paper, rock, scissors!
Please input the correct number according
to the object you want to choose.
Select rock(1), paper(2), or scissors(3): 3
Computer chose SCISSORS .
You chose SCISSORS .
It's a tie!
Play again? Enter 'y' for yes or 'n' for no. n
Your total wins are 0 .
Your total losses are 0 .
Your total ties are 0 .
#import the library function "random" so that you can use it for computer
#choice
import random
#define main
def main():
#assign win, lose, and tie to zero for tallying
win = 0
lose = 0
tie = 0
#control loop with 'y' variable
play_again = 'y'
#start the game
while play_again == 'y':
#make a welcome message and give directions
print('Prepare to battle in a game of paper, rock, scissors!')
print('Please input the correct number according')
print('to the object you want to choose.')
#Get the player and computers choices and
#assign them to variables
computer_choice = get_computer_choice()
player_choice = get_player_choice()
#print choices
print('Computer chose', computer_choice, '.')
print('You chose', player_choice, '.')
#determine who won
winner_result(computer_choice, player_choice)
#ask the user if they want to play again
play_again = input("Play again? Enter 'y' for yes or 'n' for no. ")
#print results
print('Your total wins are', win, '.')
print('Your total losses are', lose, '.')
print('Your total ties are', tie, '.')
#define computer choice
def get_computer_choice():
#use imported random function from library
choice = random.randint(1,3)
#assign what the computer chose to rock, paper, or scissors
if choice == 1:
choice = 'ROCK'
elif choice == 2:
choice = 'PAPER'
else:
choice = 'SCISSORS'
#return value
return choice
#define player choice
def get_player_choice():
#assign input to variable by prompting user
choice = int(input("Select rock(1), paper(2), or scissors(3): "))
#Detect invalid entry
while choice != 1 and choice != 2 and choice != 3:
print('The valid numbers are rock(type in 1), paper(type in 2),')
print('or scissors(type in 3).')
choice = int(input('Enter a valid number please: '))
#assign what the player chose based on entry
if choice == 1:
choice = 'ROCK'
elif choice == 2:
choice = 'PAPER'
else:
choice = 'SCISSORS'
#return value
return choice
#determine the winner from the variables
def winner_result(computer_choice, player_choice):
#if its a tie, add 1 to tie variable and display message
if computer_choice == player_choice:
result = 'tie'
print("It's a tie!")
#if its a win, add to win tally and display message
elif computer_choice == 'SCISSORS' and player_choice == 'ROCK':
result = 'win'
print('ROCK crushes SCISSORS! You win!')
elif computer_choice == 'PAPER' and player_choice == 'SCISSORS':
result = 'win'
print('SCISSORS cut PAPER! You win!')
elif computer_choice == 'ROCK' and player_choice == 'PAPER':
result = 'win'
print('PAPER covers ROCK! You win!')
#if it does not match any of the win criteria then add 1 to lose and
#display lose message
else:
result = 'lose'
print('You lose!')
def result(winner_result,player_choice, computer_choice):
# accumulate the appropriate winner of game total
if result == 'win':
win += 1
elif result == 'lose':
lose += 1
else:
tie += 1
return result
main()
Your winner_result function returns before it increments the win counters. If you remove all the return statements from it, the counters should be updated. The return statements aren't needed anyway because the if/elif/else structure ensures that only one of the possible outcomes will be executed.
As Junuxx says in a comment, you also need to assign values to the winner_result variable properly, i.e. winner_result = 'win' instead of winner_result == 'win'. I'd also rename the winner_result variable or the function, because it's confusing to have both use the same name.
And the win/lose/tie variables are currently local, which means that main and winner_result will have their own copies of these variables, so main's values will always be zero. What you can do is make them global variables: Assign them to zero in the global scope (outside any function), and add the line global win, lose, tie inside the function winner_result.
Obviously been a few years since this question was answered but it came up while I was looking the same info. Here's my code if anyone is interested.
#! usr/bin/python3
import random
def game():
computer_count = 0
user_count = 0
while True:
base_choice = ['scissors', 'paper', 'rock']
computer_choice = random.choice(base_choice)
user_choice = input('(scissors, paper, rock) Type your choice: ').strip().lower()
print()
computer_wins = 'The computer wins!'
you_win = 'You win!'
print(f'You played {user_choice}, the computer played {computer_choice}')
if user_choice == 'scissors' and computer_choice == 'rock' or \
user_choice == 'paper' and computer_choice == 'scissors' or \
user_choice == 'rock' and computer_choice == 'paper':
print(computer_wins)
computer_count += 1
elif user_choice == 'rock' and computer_choice == 'scissors' or \
user_choice == 'scissors' and computer_choice == 'paper' or \
user_choice == 'paper' and computer_choice == 'rock':
print(you_win)
user_count += 1
else:
if user_choice == computer_choice:
print('Its a draw!')
computer_count += 1
user_count += 1
print(f'Computer: {computer_count} - You: {user_count}')
print()
game()
I was trying to do the same project, and I have found a solution that works well for me.
from random import randint
win_count = 0
lose_count = 0
tie_count = 0
# create a list of play options
t = ["Rock", "Paper", "Scissors"]
# assign a random play to the computer
computer = t[randint(0, 2)]
# set player to false
player = False
print()
print("To stop playing type stop at any time.")
print()
while player == False:
# set player to True
player = input("Rock, Paper or Scissors? ")
if player.lower() == "stop":
print()
print(
f"Thanks for playing! Your final record was {win_count}-{lose_count}-{tie_count}")
print()
break
if player.title() == computer:
print()
print("Tie!")
tie_count += 1
print()
elif player.title() == "Rock":
if computer == "Paper":
print()
print(f"You lose. {computer} covers {player.title()}.")
lose_count += 1
print()
else:
print()
print(f"You win! {player.title()} smashes {computer}.")
win_count += 1
print()
elif player.title() == "Paper":
if computer == "Scissors":
print()
print(f"You lose. {computer} cuts {player.title()}.")
lose_count += 1
print()
else:
print()
print(f"You win!, {player.title()} covers {computer}.")
win_count += 1
print()
elif player.title() == ("Scissors"):
if computer == "Rock":
print()
print(f"You lose. {computer} smashes {player.title()}.")
lose_count += 1
print()
else:
print()
print(f"You win! {player.title()} cuts {computer}.")
win_count += 1
print()
else:
print()
print("Sorry, we couldn't understand that.")
print()
# player was set to True, but we want it to be false to continue loop
print(f"Your record is {win_count}-{lose_count}-{tie_count}")
print()
player = False
computer = t[randint(0, 2)]
This works (kinda)
there are many issues with the code at the top of the page.
Firstly, Scoring doesn't work.
Secondly, nothing is indented meaning that nothing inside of the other def functions will work.
Thirdly, The other def functions are referred to in the first def main statement which causes Python to show an invalid syntax due to Python not knowing the other functions as they were referred to before they were introduced to python.

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