count characters while writing with raw_input - python

I am using raw_input("> ") to write something. And after that I am using len() to get the character count.
something = raw_input("> ")
print something
print len(something)
Is it possible to get the character count while writing at the beginning or the end of the text I write? So at the moment when I write A test (6 characters) I would like to see "6" in real time (e.g. at the beginning before the "> "
How can I do this?

Python is in line buffered mode by default, thus raw_input does not return until you press the enter key. If you want to read a single char immediately, see Python read a single character from the user.
Then you can do it this way though the need is rather useless I think:
getch = _Getch() #_Getch is defined in the post I mentioned above
a=''
cnt=0
inputs=''
while True:
print '\r%6d> '%cnt, inputs,
a=getch()
if ord(a) == 13:
break
cnt+=1
inputs+=a
print '\nuser inputs:', inputs

Related

python 3 input without newline

I am new to coding. And I would like to know if there's a way for input function to not print newline character after the value is entered. Something like print function's argument end. Is there any way?
Well, you can't make input() trigger by anything besides 'Enter' hit (other way may be using sys.stdin and retrieving character one-by-one until you receive some stop marker, but it's difficult both for programmer and for user, I suppose). As a workaround I can the suggest the following: if you can know the length of line written before + length of user input, then you can use some system codes to move cursor back to the end of previous line, discarding the printed newline:
print("This is first line.")
prompt = "Enter second: "
ans = input(prompt)
print(f"\033[A\033[{len(prompt)+len(ans)}C And the third.")
\033[A moves cursor one line up and \033[<N>C moves cursor N symbols right. The example code produces the following output:
This is first line.
Enter second: USER INPUT HERE And the third.
Also note that the newline character is not printed by your program, it's entered by user.
name=input('Enter your name : ')
print('hello',name,end='')
I know about the end function which is abov

Function is not being called after input assigns a value (Python)

I have a small file with a bunch of phrases on each line. I want the user to type a number and that number will print the selected line.
def printSpecLine(x):
print('started')
with open('c:/lab/save.txt') as f:
for i, line in enumerate(f, 1):
if i == x:
break
print (line)
print('done')
f.close()
s = int(input("Enter a number: "))
printSpecLine(s)
I've ran this with no errors, but the function isn't being called at all. Printing "started" (second line) didn't even occur. Am I missing a step here?
The only explanation for this is that you are not actually inputting to the prompt! There doesn't seem to be any other reason why at least the first print wouldn't be made.
Remember that input() is blocking, so until you enter your number and press enter, the program will be halted where it is (i.e. not call the function).
Apparently the ide i was using has a problem with raw input and integers being converted. Sublime Text 3 doesn't take python input very well. Thank you for your answer.

Hangman in python: have lines be replaced?

I'm working on writing a simple Hangman game in Python from what I know so far (I'm doing Learn Python the Hard Way) and so far I have this:
from sys import argv
import random
script_name, dict_file = argv
hang_list = open(dict_file).read().splitlines()
hang_list = filter(None, hang_list)
word = random.choice(hang_list)
guesses = ''
def compare_words():
global guesses
new_word = ''
for char in word:
if char in guesses:
new_word += char
else:
new_word += "_"
return new_word
def test_letter():
global guesses
letter = raw_input("Guess a letter: ")
guesses += letter
new_word = compare_words()
print "\nCurrent guesses: %s" % guesses
print "%s\n\n" % new_word
if new_word == word:
print "You won!"
else:
test_letter()
test_letter()
I've yet to implement the scoring system (piece of cake) but I have an issue with the layout. As you can tell, this will print "Current guesses: " and the new word each time; however, what I want is four lines that look like:
Guess a letter:
Guesses: abczy
__c__b_
And have those three lines keep updating. However, I am having trouble figuring out how to make the print replace stdout. I believe I need to use the \r escape character, yet I've tried placing that in various places but can't get it to work. So, how should I modify this to get it to replace? I would prefer not to just clear, as then it still makes things a bit messy; I want to just replace what's there. Thanks!
It would be a bit tricky to make this work for all terminals, but if yours understands ANSI escape codes like mine does, this might work:
...
if new_word == word:
print "You won!"
else:
print '\033[F'*7
print ' '*17 + '\b'*17 + '\033[F'
test_letter()
This relies on the ANSI code F: move the cursor up one line; backspaces (\b) alone have no effect once the beginning of the line is reached.
The first print takes you back up to the input line and the second deletes the character that was previously entered.
You can use the escape characters \033c and this will erase the code in a terminal window and put the cursor at the top left.
For example this code:
import time
print("text 1")
time.sleep(1)
print('\033c')
time.sleep(1)
print("text 2")
This code will print "text 1" wait one second, clear the console, wait one second and then print "text 2".
So you could use the code
def test_letter():
print("\033c")
global guesses
letter = raw_input("Guess a letter: ")
guesses += letter
new_word = compare_words()
print "\nCurrent guesses: %s" % guesses
print "%s\n\n" % new_word
if new_word == word:
print "You won!"
else:
test_letter()
What this code will do is clear the console, ask the person to guess a number, display that four line piece of code that you wanted and then clear the console again.
I hope this helps!
If you want to replace the content of a specific line, from a specific position, you can use ANSI Escape Codes. To do this, make sure that you're using stdout.write() rather than print(). You can access this method by using the following import statement:
from sys import stdout
Then, in order to navigate the "cursor" (where text printed with this method will go), use the escape code \u001b[<L>;<C>H (or \u001b[<L>;<C>F where <L> and <C> represent the respective line number and character index of the desired position. For example, if you wanted to set the cursor to line 3; character 2, you would do the following.
stdout.write(u"\u001b[3;2H")
Note the u proceeding the double-quoted string. This is required in Python 2.x, since it contains special characters, but can be omitted in Python 3 and above.
Once you have set the cursor to be at the desired position, anything you write will replace the characters that currently reside there. This is important, because if the replacement string is shorter than the original, you may end up with trailing legacy characters. The simplest way to deal with this is to pad the printing string in spaces.
After doing this you should probably move the cursor back to the end of stdout, using the same method, and flush the output with stdout.flush().
Example
Let's say I had the following output on the terminal:
Name: Shakespeare
Score: 0
Some text...
I could change the score to 1 by running the following:
stdout.write(u"\u001b[2;8H")
stdout.write("1")
stdout.write(u"\u001b[5;0H")
stdout.flush()
Again, the u is optional in Python 3 and up.
Notes
This line-and-character-number method applies to all output currently being displayed in the terminal. This means that if you have anything left from another program or command, for example
$ python game.py
so it is best to clear the output at the start of your program, with something like print(u"\033c"), or os.system("clear"), otherwise you may end up writing to the wrong line.
Also, if your going to use stdout.write() anywhere else, remember to put \n at the end if you want to go to the next line.
The \r character is a carriage return, which means it will return the cursor to the start of the current line. That's OK if you want to redraw the line the cursor is on, but no good if you want to redraw other lines.
To do what you want, you need to use a terminal library like curses on Linux or the console API on Windows. If you are just working on Linux and want a simpler way to access colours, cursor movement and input without echo, you could do worse than try out blessed (https://pypi.python.org/pypi/blessed/).
If you need a cross platform API to do this sort of thing, there is no pure Python way to handle it all yet, but I am working on one. The Screen class in https://github.com/peterbrittain/asciimatics cover all the features above in a cross-platform manner.

syntax error with .format() (Python 3.2.3)

So I am trying to write a program that writes a word, fills 20 spaces with markup(< or >), then writes that same word backwards. It also takes user input.
Can anyone tell me what im doing wrong
while test2 == 1 :
test = input("Enter a word to format. Entering QUIT will exit the program:")
if test == ("quit"):
print("You have quit the program.")
break
else:
print("{0:*<20}{1:*>20})".format(
"test")(["test"::-1])
Syntactically you have a " in the wrong place in your last print statement.
print("{0:*<20}{1:*>20}").format("test")(["test"::-1])
^
You also some other syntax errors with your format() arguments, this will work for the literal string "test" but you'll need to replace it with a variable to use it with actual user input:
print("{0:*<20}{1:*>20}").format("test","test"[::-1])
Your last line has errors, try the follwing to get 20 spaces between the words
In [1]: s = "test"
In [2]: print('{0:<20}{1}'.format(s,s[::-1]))
test tset
You can also use print('{0}{1}{2}'.format(s," "*20,s[::-1])) which is subjectively cleaner.

How to not issue a new line in Python 3 when entering text with input()

I'm making a basic utility in Python 3 where the user inputs a command and gets feedback printed out into the console. When entering data using the input() or sys.stdin.readline() functions this is what the command-line session may look like (including \r and \n characters)
1. What is your name:\n
2. <user input>\n
3. Your name is <variable>.\n
But, I would like to display a \r character after the user hits enter instead of the \n character, as shown on line 2. After the user had typed everything in and hit enter it would look like this
1. What is your name:\n
2. Your name is <variable>.\n
(because line 2 would have a \r character after the entered data, returning the cursur back to the far left)
Does anybody know of a way I might accomplish this?
Well, I discovered this method although I am almost cirtain that the msvcrt module is for Windows only.
import msvcrt
import sys
def msgInput(prompt):
print(prompt, end='')
data= b''
while True:
char= msvcrt.getch()
if char != b'\r':
print(char.decode(), end='')
sys.stdout.flush()
data= data+char
else:
print('\r', end='')
break
return data.decode()
If anybody knows of any cross-platform methods, please share.
Update - Unfortunately this method has many limitations, such as the user cannot navigate the entered text with the arrow keys.
Well, I believe I found the solution you wanted:
strng=input("Enter String - ")
Where strng is just a variable to hold the input response. This will return the string in the interpreter Enter String - (without any quote) and allow you to save the response in the variable strng.

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