Develop Reference

How to hide a part of the frame through button pressing

I have a window with two parts. One part is to do some settings. I want to hide it until the user press a setting button. is it possible to hide a part of the frame that contains many widgets?
I have seen many examples to hide a widget in tkinter (eg. pack_forget and grid_forget). In my case, I am trying to hide a part of the frame through a button press (that contains more than one widgets). Any suggestions please
I can't use more than one frames because of some issues.
import tkinter as tk
def startFn():
pass
#fn body
def stopFn():
pass
#fn body
def FnToShow():
pass
#fn body ???
def FnToHide():
pass
#fn body ???
root = tk.Tk()
root.geometry('600x400')
#two containers like this.
#trying to hide container_2 untill the user press settingBtn
container_1 = tk.Frame(root, borderwidth=2, relief="solid")
container_2 = tk.Frame(root, borderwidth=2, relief="solid")
startBtn = tk.Button(container_1, text = "Start", command =startFn)
startBtn.grid(row=4, column=4)
stopBtn = tk.Button(container_1, text = "Stop", command= stopFn)
stopBtn.grid(row=5, column=4)
settingBtn = tk.Button(container_1, text = "Settings", command= FnToShow)
settingBtn.grid(row=6, column=4)
setting_1 = tk.Label(container_2, text = "Setting-1", fg='#000000')
setting_1.grid(row=3, column=10)
setting_2 = tk.Label(container_2, text = "Setting-2", fg='#000000')
setting_2.grid(row=4, column=10)
closeSettingBtn = tk.Button(container_2, text = "close Settings", command= FnToHide)
closeSettingBtn.grid(row=5, column=10)
container_1.pack(side="left", expand=True, fill="x", padx=1, pady=1)
container_2.pack(side="right",expand=True, fill="x", padx=1, pady=1)
root.mainloop()

You could show/hide the entire container_2 using the functions FnToShow and FnToHide:
something like this:
import tkinter as tk
def startFn():
pass
def stopFn():
pass
def FnToShow():
container_2.pack(side="right",expand=True, fill="x", padx=1, pady=1)
def FnToHide():
container_2.pack_forget()
root = tk.Tk()
root.geometry('600x400')
container_1 = tk.Frame(root, borderwidth=2, relief="solid")
container_2 = tk.Frame(root, borderwidth=2, relief="solid")
startBtn = tk.Button(container_1, text="Start", command =startFn)
startBtn.grid(row=4, column=4)
stopBtn = tk.Button(container_1, text="Stop", command= stopFn)
stopBtn.grid(row=5, column=4)
settingBtn = tk.Button(container_1, text="Settings", command= FnToShow)
settingBtn.grid(row=6, column=4)
setting_1 = tk.Label(container_2, text="Setting-1", fg='#000000')
setting_1.grid(row=3, column=10)
setting_2 = tk.Label(container_2, text="Setting-2", fg='#000000')
setting_2.grid(row=4, column=10)
closeSettingBtn = tk.Button(container_2, text="close Settings", command= FnToHide)
closeSettingBtn.grid(row=5, column=10)
container_1.pack(side="left", expand=True, fill="x", padx=1, pady=1)
root.mainloop()

Off-set position of tkinter scale using the .grid manager

I am currently writing a simple piece of inventory management software for a school python assessment. My GUI involves listing out all of the items in stock, and giving the user the ability to stock/sell multiple items at once. This was achieved by placing an entry (amount to buy) and a scale widget (amount to sell) next to each item, and utilizing an "apply" button to enact the changes (For context, the scenario is a comic book store):
https://i.imgur.com/7cesQm5.png
This is the code that I have used to create the new widgets from each file (all of which are contained in a dictionary, pulled from a CSV file):
itteration = 2
labels = {}
nameTitle = Label(main, text="Title").grid(row=1, column=1, padx=5)
stockTitle = Label(main, text="Stock").grid(row=1, column=2, padx=5)
buyTitle = Label(main, text="Amount to Buy").grid(row=1, column=3, padx=5)
sellTitle = Label(main, text="Amount to Sell").grid(row=1, column=4, padx=5)
for item in comic_books:
name = item.replace(" ", "")
nameStock = "{}Stock".format(item).replace(" ", "")
nameBuy = "{}Buy".format(item).replace(" ", "")
nameSell = "{}Sell".format(item).replace(" ", "")
labels[name] = Label(main, text=item+":")
labels[name].grid(column=1, row=itteration, padx=5)
labels[nameStock] = Label(main, text=comic_books.get(item))
labels[nameStock].grid(column=2, row=itteration, padx=5)
labels[nameBuy] = Entry(main)
labels[nameBuy].grid(column=3, row=itteration, padx=20)
labels[nameSell] = Scale(main, from_=0, to=comic_books.get(item), orient=HORIZONTAL)
labels[nameSell].grid(column=4, row=itteration, padx=5)
itteration += 1
However, I am not a fan of how the the scales appear to be centering themselves in the row based on both the center of the slider, and the number on top. This makes the slider appear lower than the entry widget next to it.
https://i.imgur.com/9CQTvWS.png
My question is: how would I go about potentially offsetting the position of the scale widgets upwards by a given amount (maybe 5-10px?) from its original position, to push the actual slider in line with the entry widget before it?
Please let me know if you need any extra clarification
Cheers,
-Sean

Using sticky='s' and sticky='n' to stick to bottom (south) and top (north) of cell I got this
I didn't use different values in pady
import tkinter as tk
root = tk.Tk()
l = tk.Label(root, text='Label')
l.grid(column=1, row=0, padx=5, sticky='s', pady=10)
e = tk.Entry(root)
e.grid(column=2, row=0, padx=20, sticky='s', pady=10)
s = tk.Scale(root, from_=0, to=10, orient='horizontal')
s.grid(column=3, row=0, padx=5, sticky='n', pady=10)
root.mainloop()
Using sticky with pady=(0,20) for one widget I got this
import tkinter as tk
root = tk.Tk()
l = tk.Label(root, text='Label')
l.grid(column=1, row=0, padx=5, sticky='s', pady=10)
e = tk.Entry(root)
e.grid(column=2, row=0, padx=20, sticky='s', pady=10)
s = tk.Scale(root, from_=0, to=10, orient='horizontal')
s.grid(column=3, row=0, padx=5, sticky='n', pady=(0,20))
root.mainloop()

Could I have used a for loop somehow?

Just wondering if there is a way to clean this up a little where its a bunch of lines that only changes a little. This is using python 3.4.3, tkinter, and mysql.connector.
Plantname = tk.StringVar()
self.Plantbox = tk.Entry(self, textvariable=Plantname)
self.Plantbox.grid(row=0, column=0)
self.Name = tk.Label(self, text="Name",width=10)
self.Name.grid(row=1, column=0)
self.Amount = tk.Label(self, text="Amount",width=10)
self.Amount.grid(row=1, column=1)
self.Date = tk.Label(self, text="Date",width=10)
self.Date.grid(row=1, column=2)
self.Planting = tk.Label(self, text="Planting #",width=10)
self.Planting.grid(row=1, column=3)
self.batch = tk.Label(self, text="batch #",width=10)
self.batch.grid(row=1, column=4)
self.Name_2 = tk.Label(self, text="0")
self.Name_2.grid(row=2, column=0)
self.Amount_2 = tk.Label(self, text="0")
self.Amount_2.grid(row=2, column=1)
self.Date_2 = tk.Label(self, text="0")
self.Date_2.grid(row=2, column=2)
full code:
https://pastebin.com/JPjrtdEg

Yes, you can use a loop. There's nothing special about tkinter objects that make them any different than any other python object.
for col, heading in enumerate(("Name", "Amount", "Date", "Planting #", "batch #")):
label = tk.Label(self, text=heading, width=10)
label.grid(row=1, column=col)

Managing column width tkinter

I have reviewed the documentation on rowconfugre and columnconfigure, and I just do not quite understand how to get it working properly. With the following code, how can I get the 'src_entry' Entry box directly against the 'src' Checkbutton, regardless of what other widget is in column 1? Essentially, I need the size of the column to form to the width of whatever widget is in that space on the grid.
Thanks,
from tkinter import *
class Example(Frame):
def __init__(self, parent):
Frame.__init__(self, parent, background="white")
self.parent = parent
self.parent.title("TCPDUMP Creator")
self.centerWindow()
self.pack(fill=BOTH, expand=1)
menubar = Menu(self.parent)
self.parent.config(menu=menubar)
fileMenu = Menu(menubar)
fileMenu.add_command(label="Exit", command=self.quit)
menubar.add_cascade(label="File", menu=fileMenu)
self.columnconfigure(2, weight=5)
int_lbl = Label(self, text="Interface")
int_lbl.grid(row=1, column=0, sticky=W+E)
self.int_entry = Entry(self, width=15)
self.int_entry.grid(row=1, column=1)
self.anyInt = BooleanVar()
Checkbutton(self, text="Any", variable = self.anyInt).grid(row=1, column=2)
int_lbl = Label(self, text="")
int_lbl.grid(row=2, column=0, columnspan=99, sticky=W+E)
self.notSrc = BooleanVar()
Checkbutton(self, text = "Not--", variable = self.notSrc).grid(row=3, column=0, sticky=W+E)
self.srcIP = BooleanVar()
Checkbutton(self, text="Src", variable = self.srcIP).grid(row=3, column=1)
src_entry = Entry(self, width=15)
src_entry.grid(row=3, column=2)
self.AndOr = StringVar()
self.AndOr.set(None)
Radiobutton(self, text = "And", variable = self.AndOr, value = "And").grid(row=3, column=3, pady=5, padx=2, sticky=E)
Radiobutton(self, text = "Or", variable = self.AndOr, value = "Or").grid(row=3, column=4, pady=5, padx=10, sticky=W)
self.notDst = BooleanVar()
Checkbutton(self, text = "Not--", variable = self.notDst).grid(row=3, column=5, sticky=W+E)
self.dstIP = BooleanVar()
Checkbutton(self, text="Dst", variable = self.dstIP).grid(row=3,column=6, sticky=E, padx=0)
dst_entry = Entry(self, width=15)
dst_entry.grid(row=3, column=7)
int_lbl = Label(self, text="")
int_lbl.grid(row=4, column=0, columnspan=99, sticky=W+E)
self.srcordst = StringVar()
self.srcordst.set(None)
Radiobutton(self, text = "And", variable = self.srcordst, value = "And").grid(row=4, column=1, pady=5, padx=2, sticky=E)
Radiobutton(self, text = "Or", variable = self.srcordst, value = "Or").grid(row=4, column=2, pady=5, padx=10, sticky=W)
def centerWindow(self):
w = 600
h = 300
sw = self.parent.winfo_screenwidth()
sh = self.parent.winfo_screenheight()
x = (sw - w)/2
y = (sh - h)/2.7
self.parent.geometry("%dx%d+%d+%d" % (w, h, x, y))
def main():
root = Tk()
app = Example(root)
root.mainloop()
if __name__ == '__main__':
main()

The best way to do layouts is to break your UI into sections, and then layout each section independently.The reason you're having difficulty is that you're trying to force everything into a single grid, but you don't have items that naturally fit into a grid. You can make it work by using lots of invisible columns and clever use of columnspan, but there are easier ways.
In this specific case, pack and a few intermediate frames is a better solution in my opinion.
From what I see, your UI is made up of four areas:
A row that has an entry for int_entry and a checkbutton
A row that has several checkboxes and radiobuttons, along with an entry
A row with an 'And' and 'Or' radiobutton
A big blank area
The way I would do it is create four frames, one for each area:
frame1 = Frame(self, ...)
frame2 = Frame(self, ...)
frame3 = Frame(self, ...)
frame4 = Frame(self, ...)
You can then use pack to stack those frames horizontally. All of them fill their area in the horizontal direction, and the last frame takes up all of the rest of the data.
frame1.pack(side="top", fill="x")
frame2.pack(side="top", fill="x")
frame3.pack(side="top", fill="x")
frame4.pack(side="top", fill="both", expand=True)
Now, you can add widgets to each frame with little concern for how they affect the rest of the display.
For example, the "Interface" label, the entry and the "Any" checkbutton can go in frame1. pack makes for a sensible choice since you want these aligned to the left of the area (I assume...).
int_lbl = Label(frame1, text="Interface")
self.int_entry = Entry(frame1, width=15)
any_cb = Checkbutton(frame1, text="Any", ...)
int_lbl.pack(side="left")
self.int_entry.pack(side="left")
any_cb.pack(side="left")
Do the same for the other frames. Within each frame you can choose to use pack or grid, as long as you consistently use pack or grid for every widget within the frame. pack is a very natural choice when you want all of your widgets aligned in one direction in the parent widget.

Tkinter Label Overwrite

I'm using Tkinter to do a small project. Long story short, I want a label to generate some stuff on creation.
Later on, I want to print a label in the same spot but with different text.
I cannot for the life of me figure out how to remove the previous text.
What I wind up with in this example is the text "Does this even work" printed on top of "ALL I WANT IS A VERY LONG AND ANNOYING SENTENCE FOR TESTING"
Thanks!
from Tkinter import *
import pygal
class Application(Frame) :
def __init__(self, root) :
Frame.__init__(self, root)
self.root = root
self.grid()
self.create_widgets()
def create_widgets(self) :
queryLabel = Label(self, text = "Enter your query :")
queryLabel.grid(row=0, column=0, sticky=W)
self.userQuery = StringVar()
qEntry = Entry(self, textvariable=self.userQuery)
qEntry.grid(row=0, column=1, sticky=W)
queryTypeLabel = Label(self,text="Selecting query type: ")
queryTypeLabel.grid(row=2, column=0, sticky=W)
self.searchType = StringVar()
authorButton = Radiobutton( self, text="Author", variable=self.searchType, value="author")
authorButton.grid(row=3,column=0,sticky=W)
memberButton = Radiobutton( self, text="PC Member", variable=self.searchType, value="pcmember")
memberButton.grid(row=3,column=1,sticky=W)
affilButton = Radiobutton( self, text="Affiliation", variable=self.searchType, value="affiliation")
affilButton.grid(row=3,column=2,sticky=W)
self.conference = BooleanVar()
confCheck = Checkbutton(self, text="Select Conference?", variable = self.conference)
confCheck.grid(row=4,column=0,sticky=W)
self.conferenceName = StringVar()
self.conferenceName.set('No Preference')
confDropDown = OptionMenu(self, self.conferenceName, *conferenceOptions)
confDropDown.grid(row=4,column=1,sticky=W)
submit_button = Button( self, text="Submit", command = self.reveal)
submit_button.grid(row=5, column = 0, sticky = W)
#self.graphics_button = Button( self, text="I want Statistics!", command=self.graphics)
#self.graphics_button.grid(row=5, column = 1, sticky= W)
label1 = Label(root, text="ALL I WANT IS A VERY LONG AND ANNOYING SENTENCE FOR TESTING")
label1.grid(row=6, column=0, columnspan=5, sticky=W)
def reveal(self) :
#root.submit_button.grid_destroy()
self.label1 = Label(root, text="Does this even work?")
self.label1.grid(row=6, column=0, columnspan=5, sticky=W)
Bunch of MySQL stuff deleted
### Launch the UI
root = Tk()
root.geometry("800x800+300+300")
app = Application(root)

In reveal, you're creating a new Label which you grid in the same place as the previous label. What you want to do is use this:
# Make label1 an attribute of self to be able to reference it in reveal
self.label1 = Label(root, text="ALL I WANT IS A VERY LONG AND ANNOYING SENTENCE FOR TESTING")
self.label1.grid(row=6, column=0, columnspan=5, sticky=W)
def reveal(self) :
#root.submit_button.grid_destroy()
# Do not create a new Label, but change the existing one
self.label1.config(text="Does this even work?")

I had the exact same issue, and it was incredibly annoying--trying both grid_destroy() and grid_forget(). Neither worked. What worked for me was to call the label 2 times, the first time with many spaces, and the second with what I actually wanted to show. This way, the label content is overwriting spaces, not old content. I know this is not the best way to do this, but it gets me the result I want without a headache:
NumAssetsLabel = tk.Label(self, text="Num of Assets: ", font=('Helvetica', 10))
NumAssetsLabel.grid(row=9, column=3, pady=20, padx=10, sticky="w", columnspan=2)
NumAssetsLabel = tk.Label(self, text="Num of Assets: %s"%runCheck, font=('Helvetica', 10))
NumAssetsLabel.grid(row=9, column=3, pady=20, padx=10, sticky="w", columnspan=2)
Note that I have columnspan=2, to make sure that the number of spaces does not impact the grid.