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I'm getting crazy syntax errors in my terminal. For example:
end_result = ASCII_to_alpha_list(coded_list)
return ''.join(end_result)
Returns
End_result = ASCII_to_alpha_list(coded_list)
^
SyntaxError: invalid syntax
>>>
What's weirding me out especially is that it doesn't matter what I put down - it returns the same error.
print 'Hi'
returns
print "Hi"
^
SyntaxError: invalid syntax
>>>
Beginner coder here. Thanks for any help!
You almost certainly have an error on the line before, probably a missing close parenthesis.
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I tried running this basic python script to print something, and it doesn't seem to be executing properly.
name = "Tyler";
print{name};
I am getting this error:
File "C:\Users\tyler\main.py", line 2
print{name};
^^^^^^^^^^^
SyntaxError: Missing parentheses in call to 'print'. Did you mean print(...)?
I tried changing line 2 to:
print(...)
but it prints out
Ellipsis, not my name.
You don't need semicolons in Python
The issue was the use of curly braces. Call your variable name with print() like this:
name = "Tyler"
print(name)
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def amp1(array):
for i in range (0,len(array),400)
amp1 [array]= abs(max(array[i:i+400]))
return amp1
print(amp1(node1[3]))
I get this response:
File "<ipython-input-53-972793b81fd0>", line 7
for i in range (0,len(array),400)
^
SyntaxError: invalid syntax
You are missing a ":" at the end of line 7.
Let try like:
def amp1(array):
for i in range (0,len(array),400):
amp1 [array]= abs(max(array[i:i+400]))
return amp1
print(amp1(node1[3]))
You missed a : at the for loop, for i in range (0,len(array),400):
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I know this question has been asked many many times on here, but I seem to not have the same issues as others. I continually get "syntax error invalid syntax else", but do not know why this is. I seem to have everything properly indented and colons after the else statement. Any help would be much appreciated. Thanks
def normalization (fname, attr, normType):
result = {}
df = pd.read_csv(fname)
targ = list(df[df.columns[attr]])
scaler = MinMaxScaler()
df["minmax"] = scaler.fit.transform(df[[df.columns[attr]]])
df["zscore"] = ((df[[df.columns[attr]]]) - (df[[df.columns[attr.mean()]]]))/(df[[df.columns[attr.std(ddof=1)]]])
if normType == "min_max":
result = dict(zip(targ, df.minmax.values.tolist())
else:
result = dict(zip(targ, df.zscore.values.tolist())
return result
result = dict(zip(targ, df.minmax.values.tolist()))
The conversion to dictionary line in the if condition is missing one bracket.
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I am currently trying to create team selection code for my python video game.
Unfortunately, it keeps highliting the ":" of my if statement and saying that it is invalid syntax, even if i change the if statement for another. I tried everything, but after all, it IS an if statement, and i can't do much.
Heres my minimal recreation of the problem. The structure is important as there is netwroking code there;
team1=[]
team2=[]
if (len(team1)+len(team2)):
if team1==team2:
rand = (random.choice([team1, team2])
if rand == "team1":
team1.append(username)
else:
team2.append(username)
else:
if team1>=team2:
team1.append(username)
else:
team2.append(username)
else:
team1.append(username)
The problem is the stray '(' you have before random.choice([team1, team2]). Delete it so it becomes:
rand = random.choice([team1, team2])
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I am new to this and am receiving an error that says print (line 5) is an invalid syntax
from random import randint
r=randint
while True:
s=int(input('How many sides would you like on your die')
print (r(1,s))
The problem is not actually on line 5, but on line 4. You have two ( brackets but only one ). In search of the final ) the Python interpreter checks the following line, and only at that point does it raise the error.
s=int(input('How many sides would you like on your die')
^
There is a closing parenthesis missing.