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Django Include() in urls.py with two apps

I believe this is a simple question but I am having a hard time figuring out why this is not working.
I have a django project and I've added a second app (sales). Prior to the second app, my urls.py simply routed everything to the first app (chart) with the following:
urlpatterns = [
path('admin/', admin.site.urls),
path('', include('chart.urls')),
]
and it worked fine.
I have read the docs over and over a looked at many tutorials, so my impression is that I can simply amend the urls.py to include:
urlpatterns = [
path('admin/', admin.site.urls),
path('sales/', include('sales.urls')),
path('', include('chart.urls')),
]
and it should first look for a url with sales/ and if it finds that then it should route it to sales.urls, and if it doesn't find that then move on and route it to chart.urls. However, when I load this and type in 127.0.0.1:8000/sales, it returns the following error:
Page not found (404)
Request Method: GET
Request URL: http://127.0.0.1:8000/sales/
Raised by: chart.views.index
which tells me that it is not routing my sales/ url to sales.urls but to chart.urls. When I change path('', include('chart.urls')), to path('', include('sales.urls')), it does route it to sales.urls so I know that my sales.urls file is set up correctly.
I know this is probably an easy question but I cannot figure it out with anything I've read. Any help is appreciated.
chart.urls:
from django.urls import path, re_path
from . import views
urlpatterns = [
path('dashboard/', views.chart, name='dashboard'),
path('', views.index, name='index', kwargs={'pagename': ''}),
path('<str:pagename>/', views.index, name='index'),
]
sales.urls:
from django.urls import path
from . import views
urlpatterns = [
path('sales/', views.sales, name='Sales Dashboard'),
]

I think the correct url for the sales page in your case would be http://127.0.0.1:8000/sales/sales/.
This is because sales/ is then looking in the included sales.urls and not finding any urls at the root / (the only url included there is at sales/ (within sales/) so will be sales/sales/
Reply to an OLD question but may be useful for others...

from django.urls import path, include
dont for get to import include

Do this:
urlpatterns = [
url(r'^admin/', include(admin.site.urls)),
url(r'^', include('chart.urls')),
url(r'^sales/', include('sales.urls')),
]
you are not doing it properly since you are not telling your app where go once it is loaded .this r'^' to go directly to chart.url url(r'^', include('chart.urls')),

requested url not found with production setting in django

My website runs with no problem when DEBUG is set to true. but i get requested url not found error when i run the server in production setting. the admin page is fine.
this is my project urls.py:
urlpatterns = patterns('',
url(r'^', include('photography.urls')),
url(r'^admin/', include(admin.site.urls)),
# url(r'^$', 'photography.views.hello_world', name='home'),
)
this is my app urls.py:
urlpatterns = patterns('photography.views',
url(r'^$', views.index, name='index'),
url(r'^albums/(?P<slug>[a-zA-Z0-9-]+)/$', views.photos_by_location, name='photos_by_location'),
)
For testing purpose, i added a hello world view and it gets rendered with commented line in project urls.py. so I guess my way of including app urls is not really good when DEBUG is false . Is there a way to include my app urls that works in production setting?
Any help would be appreciated. thanks.
Update:
tried url(r'^/', include('photography.urls')), with a / after ^. didnt work either.

Django "homepage" app urls.py issue

I am pretty new to Django and when I laid my site out I did it in the following way:
The project is a "portal" of sorts,
App 1 "home" is the app that houses the homepage, login, registration
and other "site-wide" functionality
App 2 "inventory" is a basic asset inventory
App 3 "dashboard" is a set of status dashboards based on assets in the inventory
Right now I am trying to add the login functionality and I have a main project urls.py that looks like this:
File: /portal/urls.py
from django.conf import settings
from django.conf.urls import patterns, include, url
from django.contrib import admin
admin.autodiscover()
urlpatterns = patterns('',
url(r'^$', include('home.urls'), name='home'),
url(r'^admin/', include(admin.site.urls), name='admin'),
url(r'^inventory/', include('inventory.urls'), name='inventory'),
url(r'^dashboard/', include('dashboard.urls'), name='dashboard'),
url(r'^capacity/', include('capacity.urls'), name='capacity'),
)
My plan is to use the inclusion of .../home/urls.py to manage any site-wide functionality such as logging in, registering, etc.
Right now the home index view shows just fine, but anything else in .../home/urls.py gives me a 404
File: /home/urls.py
from django.conf.urls import patterns, url
from home import views
urlpatterns = patterns('',
url(r'^test/$', views.index, name='home_test'),
url(r'^ajax_login/$', views.ajax_login, name='ajax_login'),
url(r'^$', views.index, name='home_index'),
)
At this point I suppose my question is two-fold: Am I approaching this correctly? If so, how can I get the desired functionality? If not, how should I change the way things are set up/laid out to do it the correct "best practices" way?
Thanks in advance!
EDIT
Got it working thanks to dt0xff and holdenweb, accepted holdenweb's answer since it was more accurate including the need to put the home url inclusion below the rest.
Here is my new portal/urls.py file for reference
File: /portal/urls.py
from django.conf import settings
from django.conf.urls import patterns, include, url
from django.contrib import admin
admin.autodiscover()
urlpatterns = patterns('',
url(r'^admin/', include(admin.site.urls), name='admin'),
url(r'^inventory/', include('inventory.urls'), name='inventory'),
url(r'^dashboard/', include('dashboard.urls'), name='dashboard'),
url(r'^capacity/', include('capacity.urls'), name='capacity'),
url(r'^', include('home.urls'), name='home'),
)

The issue is with your first pattern, which will only match the empty URL. So any empty URL will cause the home/urls.py URLs to be analyzed, but only the empty one will match even in that.
Unfortunately if there is no common prefix then that pattern "^" will match every URL (since they all start at the beginning ...).
So you should either use a common prefix for all the pages, or put the home URL specification at the end to give the other URLs a chance to match before it is tested.

Django looks in urls like this:
Get list of root urls - portal/urls
Find first, which matches to current url
If it is include, go to included urls, cutting off matched part
Your problem is here
url(r'^$', include('home.urls'), name='home'),
I mean, here
'^$'
You want url to match "start and then end of url". It works good with root(dunno.com/), but not with others, because url will contain something more...
So, just remove $ and you are fine
url(r'^', include('home.urls'), name='home'),

you never need to add regex($) at project/urls.py

The included urlconf doesn't have any patterns in it + django

I have been trying out the django tutorial and stuck with this error. I am in the 3rd page of the tutorial and everything was going good until i encountered this error Django Tutorial. I was following the exact steps in the tutorial. This is the error i got
ImproperlyConfigured at /polls
The included urlconf <module 'polls.urls' from 'C:\\Python34\\mysite\\polls\\urls.py'> doesn't have any patterns in it
I am pasting my code here.
ROOT_URLCONF = 'mysite.urls'` in settings.py,
from django.conf.urls import patterns, url
from polls import views
urlpattern = patterns('',
url(r'^$',views.index,name='index')
)`
inside MYSITE/POLLS/URLS.PY
from django.conf.urls import patterns, include, url
from django.contrib import admin
admin.autodiscover()
urlpatterns = patterns('',
# Examples:
# url(r'^$', 'mysite.views.home', name='home'),
# url(r'^blog/', include('blog.urls')),
url(r'^polls/', include('polls.urls')),
url(r'^admin/', include(admin.site.urls)),
)
INSIDE MYSITE.URLS.PY
Sorry if i missed out anything that i had to mention to get a clear picture. Any help would be appreciated.

The first file has urlpattern instead of urlpatterns.

how to set the index page in django like http://127.0.0.1:8000/

I have created a small project like this structure..
|-mysite
|-polls
|---static
|-----polls
|-------css
|---------images
|-------images
|-------js
|---templates
|-----polls
|-templates
|---admin
Here In polls is the app and now i am getting output with this url http://127.0.0.1:8000/polls/
In main folder i.e mysite folder in urls.py i have code like this..
urlpatterns = patterns('',
url(r'^polls/',include('polls.urls',namespace="polls")),
url(r'^admin/', include(admin.site.urls)),
Now in polls folder in urls.py code is..
urlpatterns = patterns('',
url(r'^$',views.index, name = 'index'),
}
Now i want to get the page like main website address like.. http://127.0.0.1:8000/
How to get?
Thanks.

Can you change what you have here
url(r'^polls/',include('polls.urls',namespace="polls")),
to
url(r'^', include('polls.urls', namespace="polls")),
Now the reason is this:
Django urls uses regex. In your example, you're telling django to catch your polls app, beginning from the url as localhost:8000/polls/
Learn more: https://docs.djangoproject.com/en/dev/topics/http/urls/
Even in your root project urls.py, you've got this:
# Examples:
# url(r'^$', 'Toolkit.views.home', name='home'), #this will match url of the type localhost:8000
# url(r'^blog/', include('blog.urls')), # this will match url of the type localhost:8000/blog/
Just look sharp!