Develop Reference

Python TkInter create a button to open a specific directory

I want to create a button that opens the special directory like "C:\Users\", But as I searched, I did not find any code except the following code:
from tkinter import *
from tkinter import ttk
from tkinter import filedialog
gui = Tk()
gui.geometry("100x100")
def getFolderPath():
filedialog.askdirectory()
btnFind = ttk.Button(gui, text="Open Folder",command=getFolderPath)
btnFind.grid(row=0,column=2)
gui.mainloop()
What is the correct way to solve this problem?

Use os.startfile("C:\\Users") to use the system file explorer to open the directory.

tkinter askdirectory doesn't work from imported module

I have been using tkinter to supply a file dialog (in python 3.6) which allows users to select a directory. It works fine when it is a sub-function within the same module, but if I move that subfunction into a separate module and then try to import it from that module, it no longer works. Instead the code just hangs when the file dialog should pop up but it never appears.
working code:
This works if I run the main function
from tkinter import Tk
from tkinter.filedialog import askdirectory
def SelectDirectory():
# start up the tk stuff to have a file directory popup
print('start')
root = Tk()
print('postroot')
root.withdraw()
print('postwithdraw')
# let the user pick a folder
basepath = askdirectory(title='Please select a folder')
print('postselection')
root.destroy()
print('postdestroy')
return basepath
def main():
ans = SelectDirectory()
print(ans)
If I instead put this in another module and import it from that module, then it will print until 'postwithdraw' and then just hang.
submod.py:
from tkinter import Tk
from tkinter.filedialog import askdirectory
def SelectDirectory():
# start up the tk stuff to have a file directory popup
print('start')
root = Tk()
print('postroot')
root.withdraw()
print('postwithdraw')
# let the user pick a folder
basepath = askdirectory(title='Please select a folder')
print('postselection')
root.destroy()
print('postdestroy')
return basepath
and then run this:
from submod import SelectDirectory
def main():
ans = SelectDirectory()
print(ans)
It never gets past 'postwithdraw' and the file dialog never pops up.
Does anyone know what I am doing wrong here? I would think it has something to do with the tkinter window not appearing since its not the main module but is there some way to get past that?

Your both versions don't work. Both give 'module' object is not callable.
You have to use
root = Tk.Tk()
instead of
root = Tk()
and then both versions works.
Maybe two Tk in Tk.Tk() seems weird but usually we use lowercase tk instead of Tk in
import tkinter as tk
and then you have
root = tk.Tk()

Python - How to read a file that was selected from Tkinter?

This is for my assignment.
I was given a template like this... def_choosefile() :
import tkinter
from tkinter import filedialog
root_window = tkinter.Tk()
root_window.withdraw()
return filedialog.askopenfilename()
So if i get this correct, it'll prompt a dialog window, asking to select a file. And when a file is selected, the program is supposed to tell what files did it pick. Using these:
selected_file = choose_file()
print ("Selected file: {}".format (selected_file))
after that, how do i make the program read the files normally? Normally i would use:
infile = open('text')
infile.readline()

import tkinter
from tkinter import filedialog
root_window = tkinter.Tk()
root_window.withdraw()
def choose_file():
return filedialog.askopenfilename()
selected_file = choose_file()
with open (selected_file,'r') as readfile:
lines = readfile.read().splitlines()
for line in lines[0:2]:
print (line)

How do I create an Import File Button with Tkinter?

So you know how when you use Notepad (on Windows), for example, and you want to open an old file? You click file, then open, then a file dialog opens ups and you can select the file you want, and the program will display its contents.
Basically, I want to make a button in Python that can do that exact thing.
Here's my function for the button-
def UploadAction():
#What to do when the Upload button is pressed
from tkinter import filedialog
When I click on the button assigned to this action, nothing happens, no errors, no crash, just nothing.

import tkinter as tk
from tkinter import filedialog
def UploadAction(event=None):
filename = filedialog.askopenfilename()
print('Selected:', filename)
root = tk.Tk()
button = tk.Button(root, text='Open', command=UploadAction)
button.pack()
root.mainloop()

Browse files to open and run using GUI python

Hi i have some python scripts. I need to create a GUI with few buttons, to open those files by browsing. I have to run those scripts just by clicking the GUI button, and should write the output into a n excel sheet. I tried with the below code, but with that i can just read the file! please help?
Thank you
from Tkinter import *
from tkFileDialog
import askopenfilename
def callback():
r = open(askopenfilename(),'r')
a = Button(text='click me', command=callback)
a.pack()
mainloop()

inside the callback() instead of opening the file, execute the file using execfile("abc.py")
def callback():
abc = askopenfilename()
execfile("abc.py")

This code below is a simple example that reads each line from the selected input file and then writes it to a new excel file called output.xls. It use the excellent xlwt library for creating the excel file. You could also chose to create a csv file using the csv module that is part of the python standard library which is also readable by excel. The advantages of using xlwt is that you can apply formating, merge cells, formulas, and so many other features that are part of the xls file format.
import xlwt
from Tkinter import *
from tkFileDialog import askopenfilename
def callback():
filename = askopenfilename()
wb = xlwt.Workbook()
ws0 = wb.add_sheet('Sheet1')
with open(filename, 'r') as f:
for i, line in enumerate(f):
ws0.write(i, 0, line.strip())
wb.save('output.xls')
errmsg = 'Error!'
a = Button(text='click me', command=callback)
a.pack()
mainloop()

import Tkinter, tkFileDialog
root = Tkinter.Tk()
root.withdraw()
dirname=tkFileDialog.askdirectory(parent=root,initialdir="/",title='Please select a directory')
do something with dirname
print dirname
#This code for file selection:
from Tkinter import Tk
from tkFileDialog import askopenfilename
Tk().withdraw() # we don't want a full GUI, so keep the root window from appearing
filename = askopenfilename() # show an "Open" dialog box and return the path to the selected file
print(filename)