Declare variable and if statement in Django template - python

I am developing an application with python Django
what I need to do is to assign a class to a div based on the counter variable value in templates
{% with 1 as counters %}
{% for importance in all_importance %}
{% if counters == 1 %}
<div class="item active" >
{% else %}
<div class="item" >
{% endif %}
{% for image in importance.subtypemodelimage_set.all %}
<img src="{{ image.image.url }}" />
{% endfor %}
</div>
{% counters += 1 %}
{% endfor %}
{% endwith %}
But I face this issue
Invalid block tag: 'counters', expected 'empty' or 'endfor'
where am I making mistake, thanks in advance for your helps

The for loop sets a number of variables available within the loop (full list in django docs here):
...
forloop.first True if this is the first time through the loop
forloop.last True if this is the last time through the loop
...
you can use forloop.first to check for first loop iteration:
{% for importance in all_importance %}
{% if forloop.first %}
<div class="item active" >
{% else %}
<div class="item" >
{% endif %}
{% for image in importance.subtypemodelimage_set.all %}
<img src="{{ image.image.url }}" />
{% endfor %}
</div>
{% endfor %}

Problem is with
{% counters += 1 %}
There is not tag counters. You are interpreting variable as tag.
More over you can't implement that kind of for loop in django template.

Related

Nested Jinja2 for loops

I'm passing 2 variables (3 including a simple one) to some Jinja from a python script.
On certain runs I want to generate a list with links.
<html>
<body>
<h1>{{ title }}</h1>
<table>
{% if packageURLs is defined %}
{% for x in packageURLs: %}
<a href="{{ x }}">
{% endfor %}
{% for i in packagesList: %}
<tr><td>{{ i }}</td></tr>
{% endfor %}
{" else "}
{% for i in packagesList: %}
<tr><td>{{ i }}</td></tr>
{% endfor %}
{% endif %}
</a>
</table>
</body>
for each 'packageURLs' I want to add a tag then some table tags for 'packages' List. What's happening though is its generating HTML but completing each individual for loop first. So I end up with half a page full of links then another with table rows. How can I have it iterate through both initially?
I found a solution:
<html>
<body>
<h1>{{ title }}</h1>
<table>
{% if packageURLs is defined %}
{% for i,x in packagesList %}
<a href="{{ x }}">
<tr><td>{{ i }}</td></tr>
</a>
{% endfor %}
{" else "}
{% for i in packagesList: %}
<tr><td>{{ i }}</td></tr>
{% endfor %}
{% endif %}
</table>
</body>
Which is populated using zip() in the python script:
f = t.render(title=dataType,packagesList=zip(Info,packageURLs),packageURLs=packageURLs)
I kept the last variable out of laziness as a check since I still want to only execute those different chunks sometimes.

Django Template For Loop - reverese last two iterations

I am using Django 1.10 and Python 3.5.
I have been given some code that consists of a for loop that returns 3 iterations of value in alphabetical order.
For example the for loop returns: Chronological, Combination, Functional.
However I need the for loop to return: Chronological, Functional, Combination (the last two iterations/values are reversed). I am forced to keep the for loop.
Is this at all possible with a for loop?
I have tried combining {% if forloop.last %} with {% if forloop.first%} and also setting the value with {% if forloop.counter == 2 %}...set value to Functional...{% endif %} and {% if forloop.counter == 3 %}...set value to Combination...{% endif %} but I cannot get this to achieve what I want.
Here is my code:
{% for resume_format_image in resume_format_images %}
<div class="col-md-4">
{% with "resumes/resume_format_description_"|add:resume_format_image.style.lower|add:".html" as template_name %}
{% include template_name %}
{% endwith %}
</div>
{% endfor %}
I just figured this out:
{% for resume_format_image in resume_format_images %}
<div class="col-md-4">
{% if forloop.first%}
{% include "resumes/resume_format_description_chronological.html" %}
{% elif forloop.last%}
{% include "resumes/resume_format_description_combination.html" %}
{% else %}
{% include "resumes/resume_format_description_functional.html" %}
{% endif %}
</div>
{% endfor %}
I hope this helps someone.

Variable inside a forloop in Python Django

am new to Python and Django.
I have a problem. i want to increment the value of current inside the for loop and check if the value is equal to 1 and if not i want to display some HTML tags.
here is my code.
{% with current=1 %}
{% for howitwork in howitworks%}
{% if current != 1 %}
<div class=item>
<div class=container-fluid>
<div class=row>
<div class="col-md-5 rex-block">
<img src="media/{{ howitwork.image }}" alt>
</div>
<div class="col-md-7 rx-services-box">
<div class=rx-conta-title>
<h3>{{ howitwork.subtitle }}</h3>
</div>
<p>{{ howitwork.description|linebreaks }}</p>
</div>
</div>
</div>
</div>
{% endif %}
{% endfor %}
{% endwith %}
I don't see any errors but its not working.
If you need to skip the logic on first loop iteration just use forloop.first field. It is accessible inside forloop block.
{% for howitwork in howitworks %}
{% if not forloop.first %}
<!-- do stuff -->
{% endfor %}
Use forloop.counter (forloop.counter0 for 0-indexed) instead of current variable.
Here is the possible solution for your snippet:
{% for howitwork in howitworks%}
{{forloop.counter}}
{% if forloop.counter != 1 %}
<div class=item>
<div class=container-fluid>
<div class=row>
<div class="col-md-5 rex-block">
<img src="media/{{ howitwork.image }}" alt>
</div>
<div class="col-md-7 rx-services-box">
<div class=rx-conta-title>
<h3>{{ howitwork.subtitle }}</h3>
</div>
<p>{{ howitwork.description|linebreaks }}</p>
</div>
</div>
</div>
</div>
{% endif %}
{% endfor %}
To check the current iteration count, you can use {{forloop.counter}}
So your condition could be like this
{% if forloop.counter == 1 %}
<!-- Do things -->
{% else %}
<!-- Do some other things -->
{% endif %}

Django {% blocktrans %}: How to handle pluralization inside a for loop?

I have the following loop in my Django template:
{% for item in state.list %}
<div> HTML (CUSTOMERS BY STATE) </div>
<!-- print sum of customers at bottom of list -->
{% if forloop.last %}
<h4>{{ forloop.counter }} Valued Customers</h4>
{% endif %}
{% endfor %}
Obviously, if I end up with only one customer, I'd like to print singular "Valued Customer"
According to Django's docs, one should use blocktrans. Tried the following, a few flavors of nesting:
{% blocktrans count %}
{% if forloop.last %}
<h4>
{{ forloop.counter }}
Valued Customer
{% plural %}
Valued Customers
</h4>
{% endif %}
{% endblocktrans %}
Keep getting TemplateSyntaxError: Invalid block tag: 'blocktrans', expected 'empty' or 'endfor'
Is there no way to combine with another loop? Any ideas how to solve? Thanks!
Here is the working code, thanks to alko:
{% load i18n %}
<!-- ... -->
{% if forloop.last %}
<h4>
{{ forloop.counter }}
{% blocktrans count count=forloop.counter %}
Valued Customer
{% plural %}
Valued Customers
{% endblocktrans %}
</h4>
{% endif %}
Probably, you forgot to load translation tags. Add following line at the top of your template:
{% load i18n %}
After you fix that, note that for a blocktrans tag after count a variable, whose value will serve for plural detection, should be specified, so you probably need something like
{% blocktrans count count=forloop.counter %}
To pluralize use this:
Customer{{ forloop.counter|pluralize }}

Django-cms show menu: How to show menu under current page?

I'm totally confused by django-cms's show_menu tag. There are four parameters but no full document on these parameters could be found. There are only several exmaples however I cannot find how to show menu under current page only.
Pages are arranged like this:
--Projects
----proj1
----proj2
--Gallery
----gal1
----gal2
In Projects template, how do I set the parameters for show_menu to show only the menu under current page?
Update
#Brandon
I tried exactly this:
{% show_sub_menu 1 "menu/cust_menu.html" %}
As exactly what the document says. However it ends up in this error:
u'menu/cust_menu.html' could not be converted to Integer
You need to use:
{% show_sub_menu 1 %}
http://django-cms.readthedocs.org/en/2.1.3/advanced/templatetags.html#show-sub-menu
There is actually an error in documentation and it seems to be also a little bug introduced in one of the last versions of django cms (planned to be solved in django-cms 3.0 version!).
https://github.com/divio/django-cms/issues/1913
I solved using this:
{% show_menu_below_id "topics_page" 0 4 100 100 "./_menus/menu_topics.html" %}
where "topics_page" is the reverse id (you configure it in advanced section in cms admin).
For recursive rendering of menu, just configure the custom id of subpages for which you want display the next menu level;
in your custom menu template, you can play with child properties and the for loop counter. Below, check a nasty example but still useful if you want to customize your menu template:
{% load menu_tags %}
{% load template_extras %}
{% for child in children %}
{# sub voices topics #}
{% if child.level == 1 %}
{% if not forloop.counter|divisibleby:2 %}
<div class="row-fluid">
{% endif %}
<div class="span6">
<div class="sub1">
<a href="{{ child.attr.redirect_url|default:child.get_absolute_url }}"><span
class="icon-play"></span>{{ child.get_menu_title|capfirst }}</a>
</div>
{% if child.children %}
{% show_menu_below_id child.attr.reverse_id 0 4 100 100 template %}
{% endif %}
</div>
{% if forloop.counter|divisibleby:2 %}
</div> <!-- end row fluid -->
{% endif %}
{% elif child.level == 2 %}
{# 2 - {{ child.attr.reverse_id}} - {{ child.get_menu_title }}#}
<div class="row-fluid">
<div class="span11 offset1">
<div class="sub2">
<a href="{{ child.attr.redirect_url|default:child.get_absolute_url }}">{{ child.get_menu_title|capfirst }}
</a></div>
</div>
</div>
{% if child.children %}
{% show_menu_below_id child.attr.reverse_id 0 4 100 100 template %}
{% endif %}
{% elif child.level == 3 %}
{# leaf node topics #}
{# 3 - {{ child.attr.reverse_id}} - {{ child.get_menu_title }}#}
<div class="row-fluid">
<div class="span10 offset2">
<div class="sub3"><a href="{{ child.attr.redirect_url|default:child.get_absolute_url }}">
<i class="icon-list-alt"></i> {{ child.get_menu_title|capfirst }}</a></div>
</div>
</div>
{% endif %}
{% endfor %}

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