Checking for specific output from Python's DNS Resolver Query - python

I'm trying to write something that will ask users to input a specific domain (say, Google.com), and if _spf.google.com is in the SPF TXT record for Google.com, I want it to say "Yup". If not, I want it to say "Nope." Right now, the code will ask me for the domain, and it'll look up the SPF record, but I can't get it to say "yup." Why not? I've tried turning it into a string, but even that wouldn't get me what I wanted. What am I doing wrong here?
To add to that, what would you guys recommend is a good jumping off point for figuring out what code I'd need to write to figure out how many DNS lookups an SPF record is ultimately using?
import dns.resolver
question= raw_input("What domain do you want? ")
def PrintandGoogle(question):
answer=dns.resolver.query(question,"TXT")
for data in answer:
print data
if "_spf.google.com" in answer:
print "Yup."
else:
print "Nope."
printAndGoogle(question)

If your if is inside your loop:
if "_spf.google.com" in data.to_text():
If your if is outside your loop:
if any("_spf.google.com" in data.to_text() for data in answer):

Related

Find IP address which occurs most frequent and count the number of times that it appears

Hi all First time having to look for assistance but i am sort of at a brick wall for now. i have been learning python since August and i have been giving a challenge to complete for the end of Novemeber and i hope that there could be some help in making my code works. My task requires to find an ip address which occurs most frequent and count the number of times it appears also this information must be displayed to the user i have been giving 4 files .txt that have the ips. I am also required to make use of non trivial data structures and built in python sorting and/or searching functionalities, make use of functions, parameter passing and return values in the program. Below is a sample data structure they have recommended that i use: -
`enter code here`
def analyse_logs(parameter):
# Your Code Hear
return something
def extract_ip(parameter):
# Your Code Hear
return something
def find_most_frequent(parameter):
# Your Code Hear
return something
# Test Program
def main():
# Your Code Hear
# Call Test Program
main()
And below hear is what i have came up with and the code is completley differant from the sample that has been provided but what i have done dosnt give me output straight back instead creats a new text file which has been sorted but now what i am looking for: -
enter code here
def sorting(filename):
infile = open(filename)
ip_addr = []
for line in infile:
temp = line.split()
for i in temp:
ip_addr.append(i)
infile.close()
ip_addr.sort()
outfile = open("result.txt", "w")
for i in ip_addr:
outfile.writelines(i)
outfile.writelines(" ")
outfile.close()
sorting("sample_log_1.txt")e here
The code that i have created has sorted everything thats in the .txt file and outputs the most frequent that has been used all the way to the lest frequent. All i am look for is for an algorithim that can sort through the .txt file, find the IP address thats more frequent then print that ip out and how many times it appears. I hope i have provided everything and i am sure this is probally somthing very basic but i just cant get my head round it.
You should keep the number of times the IP addresses are repeated in a variable. You can use dictionary.
ip_count_dict = {"IP1": repeat_count, "IP2": repeat_count}
When first time you find a IP in your list set repeat_count 1 and after that if you find same ip again just increase counter.
For example,
ip_count_dict = {}
ip_list = ['1.1.1.1','1.1.1.2','1.1.1.3','1.1.1.1']
#Loop and count ips
#Final version of ip_count_dict {'1.1.1.1':2 , '1.1.1.2':1, '1.1.1.3':1}
With this dictionary you can store all ips and sort by their value.
P.S.: Dictionary keeps key,value pairs you can search "sort dictionary by value" after all counting thing done.

Building a ranking list in Python: how to assign scores to contestants?

(I posted this on the wrong section of Stackexchange before, sorry)
I'm working on a assignment which is way above my head. I've tried for days on end figuring out how to do this, but I just can't get it right...
I have to make a ranking list in which I can enter a user, alter the users score, register if he/she payed and display all users in sequence of who has the most score.
The first part I got to work with CSV, I've put only the basic part in here to save space. The menu and import csv have been done: (I had to translate a lot from my native language, sorry if there is a mistake, I know it's a bad habit).
more = True
while more:
print("-" * 40)
firstname = raw_input("What is the first name of the user?: ")
with open("user.txt", "a") as scoreFile:
scoreWrite = csv.writer(scoreFile)
scoreWrite.writerow([firstname, "0", "no"])
scoreFile.close()
mr_dnr = raw_input("Need to enter more people? If so, enter 'yes' \n")
more = mr_dnr in "yes \n"
This way I can enter the name. Now I need a second part (other option in the menu of course) to:
let the user enter the name of the person
after that enter the (new) score of that person.
So it needs to alter the second value in any entry in the csv file ("0") to something the user enters without erasing the name already in the csv file.
Is this even possible? A kind user suggested using SQlite3, but this basic CSV stuff is already stretching it far over my capabilities...
Your friend is right that SQlite3 would be a much better approach to this. If this is stretching your knowledge too far, I suggest having a directory called users and having one file per user. Use JSON (or pickle) to write the user information and overwrite the entire file each time you need to update it.

How to create an ldif from a python dict

i want to write a lot of data to an LDAP-Server (preferably using an ldif), but i also want that every insert/modify/delete in the ldif will be rolled back if there is an error. So basically, i need a function, that creates an ldif from a dict and then get the following behaviour.
Lets assume i have an ldif like this:
dn: uid=user,cn=testing,dc=foobar #Existing and valid entry so it should work
changeType: modify
replace: sn
sn: Alfred
dn: uid=user2,cn=testing,dc=foobar #Non-existent entry so it should fail
changeType: modify #Now because this fails, the first change
replace: sn #should be rolled back...
sn: Carl
So if the second ldif entry fails, i want to rollback the changes that were made previously to only create entries, if the whole ldif is correct.
There seems to be no kind of transactions for ldap which would be exactly what i am looking for. Till now i only found the deprecated ldif parser for python...but since its deprecated i do not want to use it anymore. So if any of you know an alternative please tell me.
Any help would be greatly appreciated
The LDAP client should consider using LDAP transactions as specified in RFC5805.

dictionary key-call

im building a test program. its essentially a database of bugs and bug fixes. it may end up being an entire database for all my time working in python.
i want to create an effect of layers by using a dictionary.
here is the code as of april 29 2011:
modules=['pass']
syntax={'PRINT':''' in eclipse anthing which
you "PRINT" needs to be within a set of paranthesis''','StrRet':'anytime you need to use the return action in a string, you must use the triple quotes.'}
findinp= input('''where would you like to go?
Dir:''')
if findinp=='syntax':
print(syntax)
dir2= input('choose a listing')
if dir2=='print'or'PRINT'or'Print':
print('PRINT' in syntax)
now when i use this i get the ENTIRE dictionary, not just the first layer. how would i do something like this? do i need to just list links in the console? or is there a better way to do so?
thanks,
Pre.Shu.
I'm not quite sure what you want, but to print the content of a single key of dictionary you index it:
syntax['PRINT']
Maybe this help a bit:
modules=['pass']
syntax={
'PRINT':''' in eclipse anthing which
you "PRINT" needs to be within a set of paranthesis''',
'STRRET':'anytime you need to use the return action in a string, you must use the triple quotes.'}
choice = input('''where would you like to go?
Dir:''').upper()
if choice in syntax:
print syntax[choice]
else:
print "no data ..."

Python: Matching & Stripping port number from socket data

I have data coming in to a python server via a socket. Within this data is the string '<port>80</port>' or which ever port is being used.
I wish to extract the port number into a variable. The data coming in is not XML, I just used the tag approach to identifying data for future XML use if needed. I do not wish to use an XML python library, but simply use something like regexp and strings.
What would you recommend is the best way to match and strip this data?
I am currently using this code with no luck:
p = re.compile('<port>\w</port>')
m = p.search(data)
print m
Thank you :)
Regex can't parse XML and shouldn't be used to parse fake XML. You should do one of
Use a serialization method that is nicer to work with to start with, such as JSON or an ini file with the ConfigParser module.
Really use XML and not something that just sort of looks like XML and really parse it with something like lxml.etree.
Just store the number in a file if this is the entirety of your configuration. This solution isn't really easier than just using JSON or something, but it's better than the current one.
Implementing a bad solution now for future needs that you have no way of defining or accurately predicting is always a bad approach. You will be kept busy enough trying to write and maintain software now that there is no good reason to try to satisfy unknown future needs. I have never seen a case where "I'll put this in for later" has led to less headache later on, especially when I put it in by doing something completely wrong. YAGNI!
As to what's wrong with your snippet other than using an entirely wrong approach, angled brackets have a meaning in regex.
Though Mike Graham is correct, using regex for xml is not 'recommended', the following will work:
(I have defined searchType as 'd' for numerals)
searchStr = 'port'
if searchType == 'd':
retPattern = '(<%s>)(\d+)(</%s>)'
else:
retPattern = '(<%s>)(.+?)(</%s>)'
searchPattern = re.compile(retPattern % (searchStr, searchStr))
found = searchPattern.search(searchStr)
retVal = found.group(2)
(note the complete lack of error checking, that is left as an exercise for the user)

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