Cannot fetch url using neither urllib2 nor requests - python

I'm trying to do this on remote Ubuntu Server:
>>> import urllib2, requests
>>> url = 'http://python.org/'
>>> urllib2.urlopen(url)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/lib/python2.7/urllib2.py", line 126, in urlopen
return _opener.open(url, data, timeout)
File "/usr/lib/python2.7/urllib2.py", line 406, in open
response = meth(req, response)
File "/usr/lib/python2.7/urllib2.py", line 519, in http_response
'http', request, response, code, msg, hdrs)
File "/usr/lib/python2.7/urllib2.py", line 444, in error
return self._call_chain(*args)
File "/usr/lib/python2.7/urllib2.py", line 378, in _call_chain
result = func(*args)
File "/usr/lib/python2.7/urllib2.py", line 527, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
urllib2.HTTPError: HTTP Error 404: Not Found
>>> requests.get(url)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/home/django/zyq2/venv/local/lib/python2.7/site-packages/requests/api.py", line 55, in get
return request('get', url, **kwargs)
File "/home/django/zyq2/venv/local/lib/python2.7/site-packages/requests/api.py", line 44, in request
return session.request(method=method, url=url, **kwargs)
File "/home/django/zyq2/venv/local/lib/python2.7/site-packages/requests/sessions.py", line 382, in request
resp = self.send(prep, **send_kwargs)
File "/home/django/zyq2/venv/local/lib/python2.7/site-packages/requests/sessions.py", line 505, in send
history = [resp for resp in gen] if allow_redirects else []
File "/home/django/zyq2/venv/local/lib/python2.7/site-packages/requests/sessions.py", line 99, in resolve_redir ts
raise TooManyRedirects('Exceeded %s redirects.' % self.max_redirects)
requests.exceptions.TooManyRedirects: Exceeded 30 redirects.
But it works fine on local Windows machine:
>>> urllib2.urlopen(url)
<addinfourl at 57470168 whose fp = <socket._fileobject object at 0x036CB630>>
>>> requests.get(url)
<Response [200]>
I have absolutely no idea about what's going on and would appreciate any suggestion.
Update
I tried S.M. Al Mamun's suggestion and got an exception with long traceback:
>>> req = urllib2.Request(url, headers={ 'User-Agent': 'Mozilla/5.0' })
>>> urllib2.urlopen(req).read()
...
long traceback (more than one page)
...
urllib2.HTTPError: HTTP Error 303: The HTTP server returned a redirect error that would lead to an infinite loop.
The last 30x error message was:
See Other
Infinite loop again (I mean TooManyRedirects exception).

Try using a user-agent:
req = urllib2.Request(url, headers={ 'User-Agent': 'Mozilla/5.0' })
urllib2.urlopen(req).read()
If it doesn't work still, that might be your Ubuntu is offline!

Related

How to use urllib in python?

I was wondering if somebody can help me with getting my code to work.
import urllib.request
import urllib.parse
import re
url = 'https://www.google.com'
values = {'s':'basics',
'submit':'search'}
data = urllib.parse.urlencode(values)
data = data.encode('utf-8')
req = urllib.request.Request(url,data)
resp = urllib.request.urlopen(req)
respData = resp.read()
print(respData)
It is giving me this error message when running the code.
TypeError: POST data should be bytes, an iterable of bytes, or a file object. It cannot be of type str.
I hope someone can help me with my problem. If not thanks anyways.
It is giving me this gigantic error message:
It is giving me this gigantic error
Traceback (most recent call last):
File "C:\Users\user\OneDrive\Desktop\Lotto.py", line 11, in <module>
resp = urllib.request.urlopen(req)
File "C:\Users\user\AppData\Local\Programs\Python\Python37-32\lib\urllib \request.py", line 222, in urlopen
return opener.open(url, data, timeout)
File "C:\Users\user\AppData\Local\Programs\Python\Python37-32\lib\urllib\request.py", line 531, in open
response = meth(req, response)
File "C:\Users\user\AppData\Local\Programs\Python\Python37-32\lib\urllib\request.py", line 641, in http_response
'http', request, response, code, msg, hdrs)
File "C:\Users\user\AppData\Local\Programs\Python\Python37-32\lib\urllib\request.py", line 569, in error
return self._call_chain(*args)
File "C:\Users\user\AppData\Local\Programs\Python\Python37-32\lib\urllib\request.py", line 503, in _call_chain
result = func(*args)
File "C:\Users\user\AppData\Local\Programs\Python\Python37-32\lib\urllib\request.py", line 649, in http_error_default
raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 405: Method Not Allowed
It's not working because you have a TYPO:
data = urllib.parse.urlencode(values)
date = data.encode('utf-8') # YOUR TYPO IS HERE
req = urllib.request.Request(url,data)
You need to change that line to:
data = data.encode('utf-8') # TYPO FIXED!

HTTP ERROR in Python

I seem to be getting this error with urllib.request and it gives me this url error that i cant seem to fix.
raceback (most recent call last):
File "C:\Users\Jarvis\Documents\Python Scripts\MultiCheck by Koala.py", line 133, in <module>
Migration()
File "C:\Users\Jarvis\Documents\Python Scripts\MultiCheck by Koala.py", line 116, in Migration
rawdata_uuid = urllib.request.urlopen(url)
File "C:\Python34\lib\urllib\request.py", line 161, in urlopen
return opener.open(url, data, timeout)
File "C:\Python34\lib\urllib\request.py", line 469, in open
response = meth(req, response)
File "C:\Python34\lib\urllib\request.py", line 579, in http_response
'http', request, response, code, msg, hdrs)
File "C:\Python34\lib\urllib\request.py", line 507, in error
return self._call_chain(*args)
File "C:\Python34\lib\urllib\request.py", line 441, in _call_chain
result = func(*args)
File "C:\Python34\lib\urllib\request.py", line 587, in http_error_default
raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 429: 42
The code im using is here is for a migration checker for a game:
def Migration():
url = "https://api.mojang.com/users/profiles/minecraft/" + einfos
rawdata = urllib.request.urlopen(url)
newrawdata = rawdata.read()
jsondata = json.loads(newrawdata.decode('utf-8'))
results = jsondata['id']
url = "https://sessionserver.mojang.com/session/minecraft/profile/" + results
rawdata_uuid = urllib.request.urlopen(url)
newrawdata_uuid = rawdata_uuid.read()
jsondata_uuid = json.loads(newrawdata_uuid.decode('utf-8'))
try:
results = jsondata_uuid['legacy']
print ("Unmigrated")
except:
print("Migrated")
Error 429 means: Too many requests. You seem to have hit a rate limit. The additional number gives are the seconds you have to wait for the limitation to be dropped. So, try again in 42s, or later.

Python crawl web HttpEror 500 using urlib2

I use url lib, urllib2, cookie lib to scrape a web:get the login page and post the data.
def getpage():
codeurl=r"http://www.xxx/sign_in"
request=urllib2.Request(codeurl)
response=urllib2.urlopen(request)
return response
def parsecode(response):
"""
parse the login page to get the changed code
"""
pattern=re.compile(r"""<meta.*?csrf-token.*?content=(.*?)\s/>""")
code=re.findall(pattern,response.read())[0]
return code
def Hand():
"""
deal with cookie and header
"""
headers={
"Referer":"xxx",
"User-Agent":"xxx"
}
ck=cookielib.MozillaCookieJar()
handle=urllib2.HTTPCookieProcessor(ck)
openner=urllib2.build_opener(handle)
head=[]
for key,value in headers.items():
tup=(key,value)
head.append(tup)
openner.addheaders = head
return openner
def postdata(code,openner):
"""
post the data xxx.com needed
"""
logurl=r"http://www.jianshu.com/sessions"
sign_in={"name":"xxx","password":"xxx","authenticity_token":code}
data=urllib.urlencode(sign_in).encode("utf-8")
x=openner.open(logurl,data)
for item in ck:
print item
However,I met this bug:
Traceback (most recent call last):
File "jianshu.py", line 80, in
postdata(code,op)
File "jianshu.py", line 43, in postdata
x=openner.open(logurl,data)
File "/usr/lib64/python2.7/urllib2.py", line 437, in open
response = meth(req, response)
File "/usr/lib64/python2.7/urllib2.py", line 550, in http_response
'http', request, response, code, msg, hdrs)
File "/usr/lib64/python2.7/urllib2.py", line 475, in error
return self._call_chain(*args)
File "/usr/lib64/python2.7/urllib2.py", line 409, in _call_chain
result = func(*args)
File "/usr/lib64/python2.7/urllib2.py", line 558, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
urllib2.HTTPError: HTTP Error 500: Internal Server Error
Are you possibly missing a ' in between the 'r' and 'http://...' this line:
codeurl=r"http://www.xxx/sign_in"

urllib HTTP Error: 400 Bad Request

I looked at this answer: Again urllib.error.HTTPError: HTTP Error 400: Bad Request because it was very similar to my question, but that solution did not work. I'm using Python 3.3.2. The lines that are like ..something.. are just values I replaced to protect my privacy. They should be strings
I'm getting an Error 400: Bad request from this code:
import urllib.parse
import urllib.request
url = '..url..'
user_agent = 'Mozilla/4.0 (compatible; MSIE 5.5; Windows NT)'
values = {'email':'..my email address..',
'github':'..my github account..'}
headers = {'User-Agent':user_agent}
data = urllib.parse.urlencode(values)
data = data.encode('utf-8')
req = urllib.request.Request(url, data, headers)
response = urllib.request.urlopen(req) #this line causes the errors
page = response.read()
This is the particular error message:
Traceback (most recent call last):
File "/Users/.../Documents/Code 2040/File.py", line 23, in <module>
response = urllib.request.urlopen(req)
File "/Library/Frameworks/Python.framework/Versions/3.3/lib/python3.3/urllib/request.py", line 156, in urlopen
return opener.open(url, data, timeout)
File "/Library/Frameworks/Python.framework/Versions/3.3/lib/python3.3/urllib/request.py", line 475, in open
response = meth(req, response)
File "/Library/Frameworks/Python.framework/Versions/3.3/lib/python3.3/urllib/request.py", line 587, in http_response
'http', request, response, code, msg, hdrs)
File "/Library/Frameworks/Python.framework/Versions/3.3/lib/python3.3/urllib/request.py", line 513, in error
return self._call_chain(*args)
File "/Library/Frameworks/Python.framework/Versions/3.3/lib/python3.3/urllib/request.py", line 447, in _call_chain
result = func(*args)
File "/Library/Frameworks/Python.framework/Versions/3.3/lib/python3.3/urllib/request.py", line 595, in http_error_default
raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 400: Bad Request

url is not accessible through wget e or script

Hello Guys! I want to access some web page through python script. The url is: http://www.idealo.de/preisvergleich/Shop/27039.html
When I access it through web browser it is OK. But when I want to access it with urllib2:
a = urllib2.urlopen("http://www.idealo.de/preisvergleich/Shop/27039.html")
It gives me the following error:
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/lib/python2.7/urllib2.py", line 126, in urlopen
return _opener.open(url, data, timeout)
File "/usr/lib/python2.7/urllib2.py", line 406, in open
response = meth(req, response)
File "/usr/lib/python2.7/urllib2.py", line 519, in http_response
'http', request, response, code, msg, hdrs)
File "/usr/lib/python2.7/urllib2.py", line 444, in error
return self._call_chain(*args)
File "/usr/lib/python2.7/urllib2.py", line 378, in _call_chain
result = func(*args)
File "/usr/lib/python2.7/urllib2.py", line 527, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
urllib2.HTTPError: HTTP Error 403: Forbidden
Also I tried to access it with wget:
wget http://www.idealo.de/preisvergleich/Shop/27039.html
The error is:
--2012-04-23 12:42:03-- http://www.idealo.de/preisvergleich/Shop/27039.html
Resolving www.idealo.de (www.idealo.de)... 62.146.49.133
Connecting to www.idealo.de (www.idealo.de)|62.146.49.133|:80... connected.
HTTP request sent, awaiting response... 403 Forbidden
2012-04-23 12:42:03 ERROR 403: Forbidden.
Can anyone explain why it is so? And how can I access it using python?
They're blocking some user agents. If you try with the following:
wget -U "Mozilla/5.0" http://www.idealo.de/preisvergleich/Shop/27039.html
it works. So you have to find the way to fake the user agent in your python code to make it work.
Try this:
import urllib2
opener = urllib2.build_opener()
opener.addheaders = [('User-agent', 'Mozilla/5.0')]
a = opener.open("http://www.idealo.de/preisvergleich/Shop/27039.html")

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