Saving Django Formsets - python

The following code successfully adds a new ToolCalibration to my database, however it does not save the SerialFormset or PartFormset. I've been staring at this code trying to figure it out for quite some time now, so any and all help would be greatly appreciated. Thanks!
Forms.py
from django.forms import ModelForm
from django.forms.models import inlineformset_factory
from tool_cal.models import ToolCalibration, SerialNumber, PartNumber
class ToolForm(ModelForm):
class Meta:
model = ToolCalibration
SerialFormSet = inlineformset_factory(ToolCalibration, SerialNumber, can_delete=True)
PartFormSet = inlineformset_factory(ToolCalibration, PartNumber, can_delete=True)
Views.py
class ToolCreate(CreateView):
model = ToolCalibration
template_name = "create.html"
form_class = ToolForm
success_url = '/toolcal/success'
def get(self, request, *args, **kwargs):
"""
Handles GET requests and instantiates blank versions of the form
and its inline formsets.
"""
self.object = None
form_class = self.get_form_class()
form = self.get_form(form_class)
serial_form = SerialFormSet(prefix='serial')
part_form = PartFormSet(prefix='part')
return self.render_to_response(
self.get_context_data(form=form,
serial_form=serial_form,
part_form=part_form))
def post(self, request, *args, **kwargs):
"""
Handles POST requests, instantiating a form instance and its inline
formsets with the passed POST variables and then checking them for
validity.
"""
self.object = None
form_class = self.get_form_class()
form = self.get_form(form_class)
serial_form = SerialFormSet(self.request.POST, prefix='serial')
part_form = PartFormSet(self.request.POST, prefix='part')
if (form.is_valid() and serial_form.is_valid() and
part_form.is_valid()):
return self.form_valid(form, serial_form, part_form)
else:
return self.form_invalid(form, serial_form, part_form)
def form_valid(self, form, serial_form, part_form):
"""
Called if all forms are valid. Creates a ToolCalibration instance along with
associated Serial and Parts and then redirects to a
success page.
"""
self.object = form.save()
serial_form.instance = self.object
serial_form.save()
part_form.instance = self.object
part_form.save()
return HttpResponseRedirect(self.get_success_url())
def form_invalid(self, form, serial_form, part_form):
"""
Called if a form is invalid. Re-renders the context data with the
data-filled forms and errors.
"""
return self.render_to_response(
self.get_context_data(form=form,
serial_form=serial_form,
part_form=part_form))

Have you considered using django-extra-views? It contains a quick and easy CBV for dealing with InlineFormSets.
In addition to an InlineFormSetView and GenericInlineFormSetView, they've also got a CreateWithInlinesView that seems to be just what you want. Relevant docs here.
Example:
from extra_views import InlineFormSet, CreateWithInlinesView, UpdateWithInlinesView,
from extra_views.generic import GenericInlineFormSet
from tool_cal.models import ToolCalibration, SerialNumber, PartNumber
class SerialNumberInline(InlineFormSet):
model = SerialNumber
class PartNumberInline(GenericInlineFormSet):
model = PartNumber
class ToolCreateView(CreateWithInlinesView):
model = ToolCalibration
inlines = [SerialNumberInline, PartNumberInline]
def get_success_url(self):
return self.object.get_absolute_url()
Even if you don't want to use them, you could dig through the code and see how they handle it.

Related

How to I fill an object instance into an UpdateView form in Django?

I have a CreateView and UpdateView, and upon success in the CreateView I'm trying to return the UpdateView with the object instance already filled in the form. The code below successfully creates the object instance (and redirects to the url with the uuid pattern in it as per the code), but the UpdateView form is empty. Why? How do I fix this?
views.py
class ProductCreate(CreateView):
"""Simple CreateView to create a Product."""
model = Product
form_class = ProductCreateForm
template_name = 'productcreate.html'
def get_success_url(self):
kwargs = {'uuid': self.object.uuid}
return reverse_lazy('productupdate', kwargs=kwargs)
def form_valid(self, form):
#some fields depend on request.user, so we can't set them in the Form.save() method
product = form.save()
product.fk_user = self.request.user
product.save()
return super(ProductCreate, self).form_valid(form)
class ProductUpdate(UpdateView):
"""Simple UpdateView to update a Product"""
model = Product
form_class = ProductCreateForm #same form
template_name = 'productcreate.html' #same template
def get_object(self, **kwargs):
#get the uuid out of the url group and find the Product
return Product.objects.filter(uuid=kwargs.get('uuid')).first()
def get_success_url(self):
kwargs = {'uuid': self.object.uuid}
return reverse_lazy('productupdate', kwargs=kwargs)
urls.py
url(r'^create-product/$', ProductCreate.as_view(), name="productcreate"),
url(r'^update-product/(?P<uuid>#giant_uuid_regex#)/$', ProductUpdate.as_view(), name="productupdate"),
productcreate.html extract:
{{ form.as_p }}
forms.py (I've left out the field cleaning code and a couple of additional fields not in the model):
class ProductCreateForm(forms.ModelForm):
"""Form to support adding a new Product"""
class Meta:
model = Product
fields = (
'field1',
'etc...',
)

Django update field value after submit

I am new here and in Django. But I need your help :)
I have created a search page using ListView,FormMixin class and a simple FormView :
class Search(ListView,FormMixin):
template_name = "users/search.html"
form_class = SearchForm
def get_context_data(self,**kwargs):
"""To get results"""
def post(self, request, *args, **kwargs):
return SearchFormView.as_view()(request)
And
class SearchFormView(FormView):
template_name = 'users/search.html'
form_class = SearchForm
def get_success_url(self):
return reverse_lazy('users:search')
def get_initial(self):
if 'keySearch' in self.request.session:
for k in self.request.session.pop('keySearch'):
initial[k] = self.request.session.pop(k)
return initial
def form_valid(self, form):
print "Form valid"
request = form.cleaned_data
print "Search field {}".format(request)
for k,v in request.iteritems():
self.request.session[k]=v
self.request.session['keySearch']=request.keys()
return super(SearchFormView,self).form_valid(form)
But everytime, I submit the form, the "search" field is blanked. My aim is to keep in the field, the user input and display the keyword and the results of the search in the same time. I guess I am not using the get_initial method in a good way.
Moreover, I am sorry for this dirty code. I hope you have the solution and any comments would be great :)
Best regards
You need to assign the form values and send them again when you render the template, could try it like this if it's useful :
class SearchFormView(View):
template_name='users/search.html'
def get(self, request, *args, **kwargs):
valid_form = yourForm()
return render(request, self.template_name,{
"valid_form" : valid_form,
})

How To Exclude A Value In A ModelMultipleChoiceField?

I do not want the logged in user to show up on this ModelMultipleChoiceField in order to restrict themselves from creating a following relationship with themselves? So how do I exclude the logged in user from the queryset, probably an easy fix but I'm new to Django and it has eluded me for a few hours now.
forms.py
class Add_Profile(forms.ModelForm):
def __init__(self,*args, **kwargs): # initializing your form in other words loading it
super(Add_Profile, self).__init__(*args, **kwargs)
user_id = kwargs.pop('user_id') # taking user_id out of the querylist
self.fields['follows'] = forms.ModelMultipleChoiceField(widget=forms.CheckboxSelectMultiple(), queryset=UserProfile.objects.filter(~Q(id=user_id)))
class Meta:
model = UserProfile
fields = (
'bio',
'follows',
'theme',
'profile_picture',
)
Views.py
#login_required
def edit_profile(request, user_id):
userprofile = UserProfile.objects.get(pk=user_id)
if request.method == 'POST':
edit_profile = Add_Profile(request.POST, request.FILES, instance=userprofile, user_id=request.user.id)
if edit_profile.is_valid():
edit_profile.save()
return redirect('/home/user/{0}/'.format(request.user.username))
else:
print edit_profile.errors
else:
edit_profile = Add_Profile(instance=userprofile, user_id=request.user.id)
return render (request, 'edit.html', {'form': edit_profile,})
Error: init() got an unexpected keyword argument 'user_id'
You can definitely do it using forms.Form instead of forms.ModelForm with something along the lines of this example in the docs:
from django import forms
from django.contrib.auth import get_user_model
class Add_Profile(forms.Form):
follows = forms.ModelMultipleChoiceField(queryset=None)
def __init__(self, user=None, *args, **kwargs):
super(Add_Profile, self).__init__(*args, **kwargs)
if user is not None:
self.fields['follows'].queryset = get_user_model().objects.exclude(pk=user.pk)
else:
self.fields['follows'].queryset = get_user_model.objects.all()
Just pass in the user you wish to exclude when you instantiate the form:
form = Add_Profile() # all users will be present in the dropdown
some_guy = User.objects.get(pk=4)
form = Add_Profile(user=some_guy) # all users except some_guy will be present
Define an __init__ method for the form class. Pass the logged in userid to the form while initializing it, this will work with a model form.
def __init__(self, *args, **kwargs):
user_id = kwargs.pop('user_id')
super(Add_Profile, self).__init__(*args, **kwargs)
self.fields['follows'] = forms.ModelMultipleChoiceField(queryset=UserProfile.objects.filter(~Q(user_id=user_id)))
While initializing your form, you can pass user_id
address_form = Add_Profile(request.POST, user_id=request.user.id)

django update view and passing context

I have a update view:
class GeneralUserUpdateView(UpdateView):
model = GeneralUser
form_class = GeneralUserChangeForm
template_name = "general_user_change.html"
def dispatch(self, *args, **kwargs):
return super(GeneralUserUpdateView, self).dispatch(*args, **kwargs)
def post(self, request, pk, username):
self.pk = pk
self.username = username
self.gnu = GeneralUser.objects.get(pk=self.pk)
#form = self.form_class(request.POST, request.FILES)
return super(GeneralUserUpdateView, self).post(request, pk)
def form_valid(self, form, *args, **kwargs):
self.gnu.username = form.cleaned_data['username']
self.gnu.email = form.cleaned_data['email']
self.gnu.first_name = form.cleaned_data['first_name']
self.gnu.last_name = form.cleaned_data['last_name']
self.gnu.address = form.cleaned_data['address']
self.gnu.save()
return redirect("user_profile", self.pk, self.username)
Here in this view I want to pass a context like:
context['picture'] = GeneralUser.objects.get(pk=self.pk)
I did trying get_context_data but I cant access pk in there..
Am I doing the update right?? How can I pass that context in there??
You shouldn't be overriding post at all. All of that logic should happen in get_context_data.
In fact, none of your overrides are needed. Everything that you do in form_valid will be done already by the standard form save. And overriding dispatch just to call the superclass is pointless.
Your view should look like this only, with no overridden methods at all:
class GeneralUserUpdateView(UpdateView):
model = GeneralUser
form_class = GeneralUserChangeForm
template_name = "general_user_change.html"
context_object_name = 'picture'
(although it seems a little odd that you want to refer to an instance of GeneralUser as "picture").
Edit to redirect to a specific URL, you can define get_success_url:
def get_success_url(self):
return reverse("user_profile", self.kwargs['pk'], self.kwargs['username'])

Django function based view to class based view

I have this url is http://127.0.0.1:8000/upload/picturelist/1, which makes user_id = 1,
In my urls.py
url(r'^picturelist/(?P<user_id>\d+)$', views.pictureList),
In my view.py
def pictureList(request, user_id):
if int(user_id) != request.user.id:
raise PermissionDenied
How can I make this function based view to use createview?
class pictureList(CreateView):
You could do something like this:
In urls.py: url(r'^picturelist/(?P<user_id>\d+)$', views.MakeItView.as_view()),
In views.py:
class MakeItView(CreateView):
model = myModel
template_name = 'whatever.html'
def get_context_data(self, **kwargs):
context = super(MakeItView, self).get_context_data(**kwargs)
if int(self.kwargs['user_id']) != self.request.user.id:
raise PermissionDenied
return context
I've never used CreateView, but here's what I gather from reading the docs:
You could do it by defining form_valid:
view:
class pictureList(CreateView):
model = YourModelHere
fields = ['whatever','fields','you','want','edited']
def form_valid(self, form):
record = form.save(commit = False)
# assuming the user id is associated
# to the model with fieldname user_id
if (self.request.user == record.user_id):
record.save()
return HttpResponseRedirect(self.get_success_url())
# not sure if this works:
return self.form_invalid()
Then the template would be at 'yourappname/yourmodelhere_form.html'.
See CreateView for an example.

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