Develop Reference

Print Statement using two data types

print("this is your "+t+" warning")
t is supposed to be an integer.
this is probably a silly and stupid question but is it possible to print a variable(in the case t with an int value) and a string("this is your" & "warning") together in one print statement[print()].
If I remember it correctly it's possible in java, not sure though.

You can use string formatting to pass your print statement as one string.
print(f"this is your {t} warning")
In case if you would like to get familiar with string formatting: https://realpython.com/python-f-strings/

yes it is. you can pass multiple values to the print function and each gets printed
print("test", 2, ['something'])

in python, + with string types will work as concatenation. If you use different data types, it will give you TypeError can only concatenate str (not "int") to str.
So you need to use , to concatenate different types:
t= 10
print("this is your",t,"Test")

t = 0
print("this is your", t, "warning")
print(f"this is your {t} warning")
print("this is your " + str(t) + " warning")
print("this is your %d warning" % t)
print("this is your %s warning" % str(t))
# to decide how many numbers after the dot change x in this '%.xf' to the number of numbers after the dot
print("this is your %.3f warning" % float(t))

name="John"
band="Sykler"
print("The band for", name, "is", band, "out of 10")

Python Nested List: How to print specific elements and append to each sublist

quizes = [["Andrew"], ["Amy"], ["Jared"], ["Bob"], ["Sarah"]]
for i in range(len(quizes)):
grade = eval(input("Enter", quizes[i][0],"grade:"))
quizes[i].append(grade)
print(quizes[i])
Hey guys so I been working on this for the past week and can't solve this. I am trying to get my program to ask "Enter [person1] grade: " and so on and append a second element to each sublist which will be their grade and then print the contents of the entire list. Any help is appreciated

The problem is input takes 1 string as a parameter, you are passing 3 instead. So:
quizes = [["Andrew"], ["Amy"], ["Jared"], ["Bob"], ["Sarah"]]
for l in quizes:
grade = eval(input(f"Enter {l[0]} grade:"))
l.append(grade)
print(l)
However, I respectfully don't understand the point of using eval here. Eval turns data into code. Using eval on user input creates a great security hole. In the above code, what if the user input quizes.clear()? The whole array will be emptied. What if he inputs something eviler?
Consider (assumes valid grades only contain numbers):
quizes = [["Andrew"], ["Amy"], ["Jared"], ["Bob"], ["Sarah"]]
for l in quizes:
while True:
try:
grade = float(input(f"Enter {l[0]} grade:"))
except ValueError:
print("Please input a number.")
else:
l.append(grade)
break
print(quizes)

The main problem is that input() accepts only one argument as the input prompt, unlike print which can take any number of arguments - you're giving 3 parameters to the input function - "Enter", quizes[i][0], and "grade:".
You can try concatenating them - like input("Enter "+str(quizes[i][0])+" grade:") (the str() conversion is not needed if you know that all the quizes[i][0] will be strings already),
or even use string formatting - "Enter {} grade".format(quizes[i][0]) or f"Enter {quizes[i][0]} grade:"
This should be enough, but there are 2 more changes you can make to your code if you like -
Iterate over the nested lists directly (for sub_list in quizes:)
Using int() or float() to convert a returned input string containing a number will also work in place of eval
For example
for quiz in quizes:
grade = eval(input("Enter {} grade:".format(quiz[0])))
quiz.append(grade)
print(quiz)
EDIT: Python docs on string formatting The f"..." syntax works only for Python 3.6+

You need to change:
grade = eval(input("Enter", quizes[i][0],"grade:"))
to
grade = eval(input("Enter " + quizes[i][0] + " grade:"))
input does not behave as print does. You can't use commas to join text in any other function (except for a very small number of custom functions and modules), and you should stay away from them at if that's confusing for you to only use them sometimes.
With that change, does your code work now? You didn't tell us why it wasn't working the way you expected.

Now that I'm looking at it, what did yours do wrong?
quizes = [["Andrew"], ["Amy"], ["Jared"], ["Bob"], ["Sarah"]]
for quiz in quizes:
grade = eval(input("Enter " + quiz[0] + " grade:"))
quiz.append(grade)
print(quiz)
print(quizes)

using loops for input list by user

I want to make this code much more elegant, using loop for getting user input into a list and also making the list as a list of floats withot having to define each argument on the list as a float by itself when coming to use them or print them...
I am very new to python 3.x or python in general, this is the first code i have ever written so far so 'mercy me pardon!'
Name = "john"
Place = "Colorado"
print (("Hello %s What's up? \nare you coming to the party tonight in %s\n
if not at least try to make simple calculator:") % (Name, Place))
print ("you will input 2 numbers now and i will devide them for you:")
calc =list(range(2))
calc[0] = (input("number 1:"))
calc[1] = (input("number 2:"))
print (float(calc[0])/float(calc[1]))

Since you are saying you are new to Python, I'm going to suggest you experiment with a few methods yourself. This will be a nice learning experience. I'm not going to give you answers directly here, since that would defeat the purpose. I'm instead going to offer suggestions on where to get started.
Side note: it's great that you are using Python3. Python3.6 supports f-strings. This means you can replace the line with your print function as follows.
print(f"Hello {Name} What's up? "
"\nare you coming to the party tonight in {Place}"
"\n if not at least try to make simple calculator:")
Okay, you should look into the following in order:
for loops
List comprehension
Named Tuples
functions
ZeroDivisionError

Are you looking for something like this :
values=[float(i) for i in input().split()]
print(float(values[0])/float(values[1]))
output:
1 2
0.5

By using a function that does the input for you inside a list comprehension that constructs your 2 numbers:
def inputFloat(text):
inp = input(text) # input as text
try: # exception hadling for convert text to float
f = float(inp) # if someone inputs "Hallo" instead of a number float("Hallo") will
# throw an exception - this try: ... except: handles the exception
# by wrinting a message and calling inputFloat(text) again until a
# valid input was inputted which is then returned to the list comp
return f # we got a float, return it
except:
print("not a number!") # doofus maximus user ;) let him try again
return inputFloat(text) # recurse to get it again
The rest is from your code, changed is the list comp to handle the message and input-creation:
Name = "john"
Place = "Colorado"
print (("Hello %s What's up? \nare you coming to the party tonight in %s\n"+
" if not at least try to make simple calculator:") % (Name, Place))
print ("you will input 2 numbers now and i will devide them for you:")
# this list comprehension constructs a float list with a single message for ech input
calc = [inputFloat("number " + str(x+1)+":") for x in range(2)]
if (calc[1]): # 0 and empty list/sets/dicts/etc are considered False by default
print (float(calc[0])/float(calc[1]))
else:
print ("Unable to divide through 0")
Output:
"
Hello john What's up?
are you coming to the party tonight in Colorado
if not at least try to make simple calculator:
you will input 2 numbers now and i will devide them for you:
number 1:23456dsfg
not a number!
number 1:hrfgb
not a number!
number 1:3245
number 2:sfdhgsrth
not a number!
number 2:dfg
not a number!
number 2:5
649.0
"
Links:
try: ... except:
Lists & comprehensions

How to remove parentheses and comma from printed output

Edit: Apparently I was using python 2. Switching to 3 fixed the issue and now I am getting the proper results without the parentheses/commas. Thanks for the replies - problem solved :D
Beginner at Python and coding in general. Struggling with my first project assignment, but I've gotten so close on my own.
My assignment is to create a code in python that counts the number of coins from a given value i.e. quarters, nickels, dimes, pennies.
My initial code looks like this:
coins=input('Enter amount of change: ')
print("Quarters", coins//25)
coins = coins%25
print("Dimes", coins//10)
coins = coins%10
print("Nickles", coins//5)
coins = coins%5
print('Pennies', coins//1)
Which prompts something like, "Enter amount of change: 86"
('Quarters', 3)
('Dimes', 1)
('Nickles', 0)
('Pennies', 1)
These are the correct values, but my instructor wants it to look like this:
Enter amount of change: 86
Quarters: 3
Dimes: 1
Nickles" 0
Pennies: 1
I can get the colon in there, but how can I remove the parentheses and commas? Thanks

You can use str.format() to produce the required output. For example for quarters:
print('Quarters: {}'.format(coins//25))
This will work in both versions of Python.

The simplest solution I've always used to print values in Python 2, which is the Python version you appear to be using, is the following:
coins=int(input('Enter amount of change: '))
print "Quarters: %i" % (coins//25)
coins = coins%25
print "Dimes: %i" % (coins//10)
coins = coins%10
print "Nickles: %i" % (coins//5)
coins = coins%5
print 'Pennies: %i' % (coins//1)
The % symbol, when used with strings, allows whatever value you want to be printed to be substituted in the string. To substitute multiple values, you separate them with commas. For example:
someInt = 1
someStr = 'print me!'
print "The values are %i and %s" % (someInt, someStr)
This code will substitute in someInt and someStr for %i (used for integers) and %s (used for strings), respectively.
However, the % symbol also functions as the modulus operator, so it does 2 different things when it is being used with strings and when it is being used among two numbers.

Please check :
coins=input('Enter amount of change: ')
print "Quarters:",coins//25
coins = coins%25
print "Dimes:",coins//10
coins = coins%10
print "Nickles:",coins//5
coins = coins%5
print "Pennies:",coins//1

To use the print() syntax on python2 add this to the top of your program:
from __future__ import print_function
otherwise python will interpret the argument to print as a tuple and you'll see ().

I am using Python 3 and the following lines exactly give what your instructor wants:
coins=float(input("Enter amount of change: "))
print("Quarters:", round(coins//25))
coins = coins%25
print("Dimes:", round(coins//10))
coins = coins%10
print("Nickels:", round(coins//5))
coins = coins%5
print("Pennies: %.0f" % coins)

It seems like you are using Python 2. I think you intended to use Python 3 given your use of input() and print() methods, but the code will work in Python 2 by changing print() methods to print keywords. Your code would look like the following in "proper"* Python 2:
coins = input('Enter amount of change: ')
print 'Quarters: ' + str(coins // 25)
coins = coins % 25
print 'Dimes: ' + str(coins // 10)
coins = coins % 10
print 'Nickles: ' + str(coins // 5)
coins = coins % 5
print 'Pennies: ' + str(coins)
Hope this helped!
Footnote: Using % is preferred over using string concatenation, but I still believe that it is easier to read for beginners this way.

Python 3, Variables in loops

I'm new to python, and just playing around, getting to learn different features with this code.(Please read note)
less = ["science", "maths"]
for i in range(0,len(less)):
a = ("You have got; " + (less[i]))
b = (a)
#By putting in print here I figured out that it added science first then maths overrides it.
print(b)
print (b)
At the moment when you print the string at the moment it says:
"You have got; maths"
But i was trying to get it to say:
"You have got; science maths"
Basically, i'm trying to find a way to just add to the variable and not one override the other so when i print it at the end it will have both science and maths.
I am going to expand upon it which is why i need to have the length of the list is the loop and etc.

You can iterate simply over objects in the list and make print statement not terminate the line.
less = ["science", "maths"]
print ("You have got; ", end="")
for i in less:
print (i, end=" ")

less = ["science", "maths"]
print ('You have got; {}'.format(' '.join(less)))

To achieve this, use join:
>>> less = ["science", "maths"]
>>> print("You have got; %s" % ' '.join(less))
You have got; science maths
Explanation: join joins the elements in the list as a single string which you may add at the end of your required string