Is it possible to disable the perspective when plotting in mplot3d, i.e. to use the orthogonal projection?
This is now official included since matplot version 2.2.2 Whats new | github
So for plotting a perspective orthogonal plot you have to add proj_type = 'ortho' then you should have something like that:
fig.add_subplot(121, projection='3d', proj_type = 'ortho')
Example Picture
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Example is taken from the official example script and edited
'''
======================
3D surface (color map)
======================
Demonstrates plotting a 3D surface colored with the coolwarm color map.
The surface is made opaque by using antialiased=False.
Also demonstrates using the LinearLocator and custom formatting for the
z axis tick labels.
'''
from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt
from matplotlib import cm
from matplotlib.ticker import LinearLocator, FormatStrFormatter
import numpy as np
# Make data.
X = np.arange(-5, 5, 0.25)
Y = np.arange(-5, 5, 0.25)
X, Y = np.meshgrid(X, Y)
R = np.sqrt(X**2 + Y**2)
Z = np.sin(R)
# Plot the surface.
fig = plt.figure(figsize=(16,4))
ax.view_init(40, 60)
ax = fig.add_subplot(121, projection='3d')
surf = ax.plot_surface(X, Y, Z, cmap=cm.coolwarm,
linewidth=0, antialiased=False)
ax.set_zlim(-1.01, 1.01)
ax.zaxis.set_major_locator(LinearLocator(10))
ax.zaxis.set_major_formatter(FormatStrFormatter('%.02f'))
ax = fig.add_subplot(122, projection='3d', proj_type = 'ortho')
# Plot the surface.
surf = ax.plot_surface(X, Y, Z, cmap=cm.viridis, linewidth=0, antialiased=False)
ax.set_zlim(-1.01, 1.01)
ax.zaxis.set_major_locator(LinearLocator(10))
ax.zaxis.set_major_formatter(FormatStrFormatter('%.02f'))
plt.show()
NOTE: This has been updated see this answer instead.
Sort of, you can run this snippet of code before you plot:
import numpy
from mpl_toolkits.mplot3d import proj3d
def orthogonal_proj(zfront, zback):
a = (zfront+zback)/(zfront-zback)
b = -2*(zfront*zback)/(zfront-zback)
return numpy.array([[1,0,0,0],
[0,1,0,0],
[0,0,a,b],
[0,0,0,zback]])
proj3d.persp_transformation = orthogonal_proj
It is currently an open issue found here.
Related
I have an issue with smoothing out the mesh representation of my 3D surface with matplotlib. Below, please see my example. I am having a hard time figuring out how to make the plot look nicer/smoother if possible. Thank you for your time in advance!
from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt
from matplotlib import cm
from matplotlib.colors import LightSource
import numpy as np
X = [1,1,1,1,1,1,50,50,50,50,50,50]
Y = [3,5,7,8,9,10,3,5,7,8,9,10]
Z = [5.23,3.11,17.54,0.93,40.11,10.15,1.47,14.32,5.46,55.93,40.8,10.2]
x = np.reshape(X, (2, 6))
y = np.reshape(Y, (2, 6))
z = np.reshape(Z, (2, 6))
X, Y = np.meshgrid(x, y)
fig = plt.figure()
ax = fig.add_subplot(111, projection='3d')
ax.plot_surface(x, y, z)
ax.set_xlabel('Persistence Length')
ax.set_ylabel('Complexity')
ax.set_zlabel('Relative number of configurational states')
surf = ax.plot_surface(x, y, z, cmap=cm.coolwarm,
linewidth=0, antialiased=False)
fig.colorbar(surf, shrink=0.5, aspect=5)
plt.show()
To obtain smooth line/surface you can set antialiased=True on the surface plot. Note that you were plotting two identical surface: in the following example I have eliminated the first.
To obtain a smoother mesh, you probably want to interpolate between your data points. One way to do that is to use griddata from the scipy.interpolate module.
from mpl_toolkits.mplot3d import Axes3D
import matplotlib.pyplot as plt
from matplotlib import cm
import numpy as np
from scipy.interpolate import griddata
X = [1,1,1,1,1,1,50,50,50,50,50,50]
Y = [3,5,7,8,9,10,3,5,7,8,9,10]
Z = [5.23,3.11,17.54,0.93,40.11,10.15,1.47,14.32,5.46,55.93,40.8,10.2]
points = np.array([X, Y]).T
# create a grid of coordinates between the minimum and
# maximum of your X and Y. 50j indicates 50 discretization
# points between the minimum and maximum.
X_grid, Y_grid = np.mgrid[1:50:50j, 3:10:50j]
# interpolate your values on the grid defined above
Z_grid = griddata(points, Z, (X_grid, Y_grid), method='cubic')
fig = plt.figure(constrained_layout=True)
ax = fig.add_subplot(111, projection='3d')
ax.set_xlabel('Persistence Length')
ax.set_ylabel('Complexity')
ax.set_zlabel('Relative number of configurational states')
surf = ax.plot_surface(X_grid, Y_grid, Z_grid, cmap=cm.coolwarm,
linewidth=0, antialiased=True)
fig.colorbar(surf, shrink=0.5, aspect=5)
plt.show()
Here is an example of antialiased=False on the left, vs antialiased=True on the right:
I would like to create a smooth plot in Python. Generally, you can make a plot that looks like the one below:
Source
While this is a nice image, it looks as though it's made out of a mesh of polygons, making it look "coarse." In my own plots I have tried increasing the resolution of my function to no avail. I am trying to achieve the following "smooth" look:
Source
How do I achieve this?
Maybe you were missing rcount and ccount?
# This import registers the 3D projection, but is otherwise unused.
from mpl_toolkits.mplot3d import Axes3D # noqa: F401 unused import
import matplotlib.pyplot as plt
from matplotlib import cm
from matplotlib.ticker import LinearLocator, FormatStrFormatter
import numpy as np
fig = plt.figure()
ax = fig.gca(projection='3d')
# Make data.
X = np.arange(-5, 5, 0.05)
Y = np.arange(-5, 5, 0.05)
X, Y = np.meshgrid(X, Y)
R = np.sqrt(X**2 + Y**2)
Z = np.sin(R)
# Plot the surface.
surf = ax.plot_surface(X, Y, Z, cmap=cm.coolwarm,
linewidth=0, antialiased=False, rcount=200, ccount=200)
# Customize the z axis.
ax.set_zlim(-1.01, 1.01)
ax.zaxis.set_major_locator(LinearLocator(10))
ax.zaxis.set_major_formatter(FormatStrFormatter('%.02f'))
# Add a color bar which maps values to colors.
fig.colorbar(surf, shrink=0.5, aspect=5)
plt.show()
Is it possible to put the color diagram (which is now on the right side of the original figure) on the top of the figure?
My code:
import matplotlib.pyplot as plt
from mpl_toolkits.mplot3d.axes3d import Axes3D, get_test_data
from matplotlib import cm
import numpy as np
# set up a figure twice as wide as it is tall
fig = plt.figure(figsize=plt.figaspect(0.5))
#===============
# First subplot
#===============
# set up the axes for the first plot
ax = fig.add_subplot(1, 2, 1, projection='3d')
# plot a 3D surface like in the example mplot3d/surface3d_demo
X = np.arange(-5, 5, 0.25)
Y = np.arange(-5, 5, 0.25)
X, Y = np.meshgrid(X, Y)
R = np.sqrt(X**2 + Y**2)
Z = np.sin(R)
surf = ax.plot_surface(X, Y, Z, rstride=1, cstride=1, cmap=cm.coolwarm,
linewidth=0, antialiased=False)
ax.set_zlim(-1.01, 1.01)
fig.colorbar(surf, shrink=0.5, aspect=10)
fig.savefig('64bit.png')
You have to add additional axes (add_axes) to put your colorbar at the desired position:
import matplotlib.pyplot as plt
from mpl_toolkits.mplot3d.axes3d import Axes3D, get_test_data
from matplotlib import cm
from mpl_toolkits.axes_grid1 import make_axes_locatable
import numpy as np
# set up a figure twice as wide as it is tall
fig = plt.figure(figsize=plt.figaspect(0.5))
#===============
# First subplot
#===============
# set up the axes for the first plot
ax = fig.add_subplot(1, 2, 1, projection='3d')
# plot a 3D surface like in the example mplot3d/surface3d_demo
X = np.arange(-5, 5, 0.25)
Y = np.arange(-5, 5, 0.25)
X, Y = np.meshgrid(X, Y)
R = np.sqrt(X**2 + Y**2)
Z = np.sin(R)
surf = ax.plot_surface(X, Y, Z, rstride=1, cstride=1, cmap=cm.coolwarm,
linewidth=0, antialiased=False)
ax.set_zlim(-1.01, 1.01)
# position of colorbar
# where arg is [left, bottom, width, height]
cax = fig.add_axes([0.15, .87, 0.35, 0.03])
fig.colorbar(surf, orientation='horizontal', cax=cax)
plt.show()
Yes it is, there are multiple answers here in the site showing you how to move the colorbar around like this one: positioning the colorbar
In your case, you want to combine that with the orientation argument. As far as I know, there is no easy way of just placing the colorbar to the top of your figure automatically, you will have to place it manually. Here is my code that replaces your fig.colorbar(surf, shrink=0.5, aspect=10):
cbax = fig.add_axes([0.1, 0.89, 0.5, 0.05])
fig.colorbar(surf, orientation="horizontal", cax=cbax)
The numbers in the list describe some characteristics of the colorbar which are [left, bottom, width, height] as mentioned in the other answer that I have attached.
These numbers came out nicely for your plot, feel free to change them to your liking.
In order to get the colorbar on top of the plot you need to create some axes, designated to host the colorbar.
This can either be done manually by placing a new axes at some given position in figure coordinates,
cax = fig.add_axes([0.2,0.8,0.3,.05])
fig.colorbar(surf, cax=cax, orientation="horizontal")
or, by using a subplot grid (gridspec), which is shown in the following:
import matplotlib.pyplot as plt
from mpl_toolkits.mplot3d.axes3d import Axes3D
import matplotlib.gridspec as gridspec
import numpy as np
x = np.arange(-5, 5, 0.25)
X, Y = np.meshgrid(x,x)
Z = np.sin(np.sqrt(X**2 + Y**2))
gs = gridspec.GridSpec(2, 2, height_ratios=[0.05,1])
fig = plt.figure()
ax = fig.add_subplot(gs[1,0], projection='3d')
cax = fig.add_subplot(gs[0,0])
surf = ax.plot_surface(X, Y, Z, rstride=1, cstride=1, cmap="coolwarm",
linewidth=0, antialiased=False, vmin=-1, vmax=1)
fig.colorbar(surf, cax=cax, orientation="horizontal", ticks=[-1,0,1])
plt.show()
For a method which avoids having to manually create new axes and instead allows us to keep the colorbar linked to an existing plot axis, we can use the location keyword (method adapted initially from here).
The location argument is meant to be used on colorbars which reference multiple axes in a list (and will throw an error if colorbar is given only one axis), but if you simply put your one axis in a list, it will allow you to use the argument. You can use the following code as an example:
import matplotlib.pyplot as plt
import numpy as np
fig = plt.figure()
ax = fig.add_subplot(111)
axp = ax.imshow(np.random.randint(0, 100, (100, 100)))
cb = plt.colorbar(axp,ax=[ax],location='top')
plt.show()
which yields this plot. From here, you can edit the colorbar using the typical methods (pad, shrink, etc.) to further tune the appearance of your plot.
Fair warning, I haven't seen this method used many other places and it could be less robust than going through the extra steps of creating a new axis for your colorbar.
I have this following code which attempts to plot a function +/- f which defines the graphene dispersion in the momentum space.
# 3D Plot of graphene dispersion
from matplotlib import pyplot as plt
from mpl_toolkits.mplot3d import Axes3D
from matplotlib import cm
from matplotlib.ticker import LinearLocator, FormatStrFormatter
import numpy as np
def sqrt(x):
return np.sqrt(x)
def cos(x):
return np.cos(x)
# Constants
a = 1.0
d = a*np.sqrt(3)
t = 2.7
t2 = 0.5
print "The display is not up to the mark! Modification needed.\n"
fig = plt.figure()
ax = fig.gca(projection='3d')
x = np.arange(-2.0*np.pi, 2.0*np.pi, 0.1)
y = np.arange(-2.0*np.pi, 2.0*np.pi, 0.1)
x, y = np.meshgrid(x, y)
f=t*sqrt(3.0+2.0*cos(a*x)+4.0*cos(a/2.0*x)*cos(d/2.0*y))
surf = ax.plot_surface(x, y, f, rstride=1, cstride=1, cmap=cm.jet, linewidth=0, antialiased=False)
f=-f
surf = ax.plot_surface(x, y, f, rstride=1, cstride=1, cmap=cm.jet, linewidth=0, antialiased=False)
ax.set_zlim3d(-3.0, 3.0)
fig.colorbar(surf, shrink=1.0, aspect=5)
plt.show()
which gives me a plot that overflows the z-axis boundary :
However, keeping the same function definition and using gnuplot or Mathematica I was able to produce this
and this
Can any of the last two be reproduced by using python with matplotlib?
I'm not quite sure what you want, since you explicitly set the z-limits inside the range of the data (ax.set_zlim3d(-3.0, 3.0)), but I get a similar plot simply by commenting out this line (and picking a nicer colormap):
# 3D Plot of graphene dispersion
from matplotlib import pyplot as plt
from mpl_toolkits.mplot3d import Axes3D
from matplotlib import cm
from matplotlib.ticker import LinearLocator, FormatStrFormatter
import numpy as np
sqrt = np.sqrt
cos = np.cos
# Constants
a = 1.0
d = a*np.sqrt(3)
t = 2.7
t2 = 0.5
fig = plt.figure()
ax = fig.gca(projection='3d')
x = np.arange(-2.0*np.pi, 2.0*np.pi, 0.1)
y = np.arange(-2.0*np.pi, 2.0*np.pi, 0.1)
x, y = np.meshgrid(x, y)
f=t*sqrt(3.0+2.0*cos(a*x)+4.0*cos(a/2.0*x)*cos(d/2.0*y))
surf = ax.plot_surface(x, y, f, rstride=1, cstride=1, cmap=plt.get_cmap('PuOr'),
linewidth=0, antialiased=False)
f=-f
surf = ax.plot_surface(x, y, f, rstride=1, cstride=1, cmap=plt.get_cmap('PuOr'),
linewidth=0, antialiased=False)
#ax.set_zlim3d(-3.0, 3.0)
fig.colorbar(surf, shrink=1.0, aspect=5)
plt.show()
(Note also that you don't need to define a wrapper function to create an alias to np.sqrt, etc. Functions are first class objects in Python and you can simply assign a name: sqrt = np.sqrt.)
I'm new to python and after installing it I've accomplished to plot my 3d data using matplotlib. Sadly the only thing I don't know how to get done is the color part. My image just shows the surface but doesn't use the color bar at all. Here is my code.
from mpl_toolkits.mplot3d import Axes3D
from matplotlib import cm
from matplotlib.ticker import LinearLocator, FormatStrFormatter
import matplotlib.pyplot as plt
from matplotlib.mlab import griddata
import numpy as np
fig = plt.figure()
ax = fig.gca(projection='3d')
data = np.genfromtxt('Uizq.txt')
x = data[:,0]
y = data[:,1]
z = data[:,2]
xi = np.linspace(min(x), max(x))
yi = np.linspace(min(y), max(y))
ax.set_xlabel('X')
ax.set_ylabel('Y')
ax.set_zlabel('U')
X, Y = np.meshgrid(xi, yi)
Z = griddata(x, y, z, xi, yi)
ax.set_zlim3d(np.min(Z), np.max(Z))
surf = ax.plot_surface(X, Y, Z, rstride=2, cstride=2, cmap=cm.jet,
linewidth=0.5, antialiased=False)
fig.colorbar(surf, shrink=0.5, aspect=5)
plt.show()
you can obviously see that it is all blue, and I want to relate the color with "U" using the full cm.jet spectrum. This might be a very noob question, so sorry if you rolled your eyes.
Add the line
surf.set_clim([np.min(Z),np.max(Z)])
before you add the color bar.
It seems that the 3D plotting does not take into account the masking, so you are including NaN in the data, which confuses the automatic color limits.