Can you name a Django app: urls - python

I'm trying to use this line in urls.py:
from mysite.urls.views import Index
However, Django is saying
ImportError at /
No module named views
I think that is because it's going into /mysite/mysite/urls.py and not /mysite/urls/views.py
The structure is like this (omitted the uninvolved files):
mysite/
templates/
mysite/
settings.py
urls.py
urls/
views.py
manage.py

I found out that was my problem. I followed How to change the name of a Django app? and my problems went away. Long story short, don't name your app: urls.

Add an empty __init__.py inside your urls folder. Why that should work? Take a look here and here

Absolute imports may be what you need:
from __future__ import absolute_import
Credits to this answer: https://stackoverflow.com/a/4931577/1028012

Related

Flask raises TemplateNotFound error even though files in right place [duplicate]

I am trying to render the file home.html. The file exists in my project, but I keep getting jinja2.exceptions.TemplateNotFound: home.html when I try to render it. Why can't Flask find my template?
from flask import Flask, render_template
app = Flask(__name__)
#app.route('/')
def home():
return render_template('home.html')
/myproject
app.py
home.html
You must create your template files in the correct location; in the templates subdirectory next to the python module (== the module where you create your Flask app).
The error indicates that there is no home.html file in the templates/ directory. Make sure you created that directory in the same directory as your python module, and that you did in fact put a home.html file in that subdirectory. If your app is a package, the templates folder should be created inside the package.
myproject/
app.py
templates/
home.html
myproject/
mypackage/
__init__.py
templates/
home.html
Alternatively, if you named your templates folder something other than templates and don't want to rename it to the default, you can tell Flask to use that other directory.
app = Flask(__name__, template_folder='template') # still relative to module
You can ask Flask to explain how it tried to find a given template, by setting the EXPLAIN_TEMPLATE_LOADING option to True. For every template loaded, you'll get a report logged to the Flask app.logger, at level INFO.
This is what it looks like when a search is successful; in this example the foo/bar.html template extends the base.html template, so there are two searches:
[2019-06-15 16:03:39,197] INFO in debughelpers: Locating template "foo/bar.html":
1: trying loader of application "flaskpackagename"
class: jinja2.loaders.FileSystemLoader
encoding: 'utf-8'
followlinks: False
searchpath:
- /.../project/flaskpackagename/templates
-> found ('/.../project/flaskpackagename/templates/foo/bar.html')
[2019-06-15 16:03:39,203] INFO in debughelpers: Locating template "base.html":
1: trying loader of application "flaskpackagename"
class: jinja2.loaders.FileSystemLoader
encoding: 'utf-8'
followlinks: False
searchpath:
- /.../project/flaskpackagename/templates
-> found ('/.../project/flaskpackagename/templates/base.html')
Blueprints can register their own template directories too, but this is not a requirement if you are using blueprints to make it easier to split a larger project across logical units. The main Flask app template directory is always searched first even when using additional paths per blueprint.
I think Flask uses the directory template by default. So your code should be like this
suppose this is your hello.py
from flask import Flask,render_template
app=Flask(__name__,template_folder='template')
#app.route("/")
def home():
return render_template('home.html')
#app.route("/about/")
def about():
return render_template('about.html')
if __name__=="__main__":
app.run(debug=True)
And you work space structure like
project/
hello.py
template/
home.html
about.html
static/
js/
main.js
css/
main.css
also you have create two html files with name of home.html and about.html and put those files in templates folder.
If you must use a customized project directory structure (other than the accepted answer project structure),
we have the option to tell flask to look in the appropriate level of the directory hierarchy.
for example..
app = Flask(__name__, template_folder='../templates')
app = Flask(__name__, template_folder='../templates', static_folder='../static')
Starting with ../ moves one directory backwards and starts there.
Starting with ../../ moves two directories backwards and starts there (and so on...).
Within a sub-directory...
template_folder='templates/some_template'
I don't know why, but I had to use the following folder structure instead. I put "templates" one level up.
project/
app/
hello.py
static/
main.css
templates/
home.html
venv/
This probably indicates a misconfiguration elsewhere, but I couldn't figure out what that was and this worked.
If you run your code from an installed package, make sure template files are present in directory <python root>/lib/site-packages/your-package/templates.
Some details:
In my case I was trying to run examples of project flask_simple_ui and jinja would always say
jinja2.exceptions.TemplateNotFound: form.html
The trick was that sample program would import installed package flask_simple_ui. And ninja being used from inside that package is using as root directory for lookup the package path, in my case ...python/lib/site-packages/flask_simple_ui, instead of os.getcwd() as one would expect.
To my bad luck, setup.py has a bug and doesn't copy any html files, including the missing form.html. Once I fixed setup.py, the problem with TemplateNotFound vanished.
I hope it helps someone.
Check that:
the template file has the right name
the template file is in a subdirectory called templates
the name you pass to render_template is relative to the template directory (index.html would be directly in the templates directory, auth/login.html would be under the auth directory in the templates directory.)
you either do not have a subdirectory with the same name as your app, or the templates directory is inside that subdir.
If that doesn't work, turn on debugging (app.debug = True) which might help figure out what's wrong.
I had the same error turns out the only thing i did wrong was to name my 'templates' folder,'template' without 's'.
After changing that it worked fine,dont know why its a thing but it is.
You need to put all you .html files in the template folder next to your python module. And if there are any images that you are using in your html files then you need put all your files in the folder named static
In the following Structure
project/
hello.py
static/
image.jpg
style.css
templates/
homepage.html
virtual/
filename.json
When render_template() function is used it tries to search for template in the folder called templates and it throws error jinja2.exceptions.TemplateNotFound when :
the file does not exist or
the templates folder does not exist
Create a folder with name templates in the same directory where the python file is located and place the html file created in the templates folder.
Another alternative is to set the root_path which fixes the problem both for templates and static folders.
root_path = Path(sys.executable).parent if getattr(sys, 'frozen', False) else Path(__file__).parent
app = Flask(__name__.split('.')[0], root_path=root_path)
If you render templates directly via Jinja2, then you write:
ENV = jinja2.Environment(loader=jinja2.FileSystemLoader(str(root_path / 'templates')))
template = ENV.get_template(your_template_name)
After lots of work around, I got solution from this post only,
Link to the solution post
Add full path to template_folder parameter
app = Flask(__name__,
template_folder='/home/project/templates/'
)
My problem was that the file I was referencing from inside my home.html was a .j2 instead of a .html, and when I changed it back jinja could read it.
Stupid error but it might help someone.
Another explanation I've figured out for myself
When you create the Flask application, the folder where templates is looked for is the folder of the application according to name you've provided to Flask constructor:
app = Flask(__name__)
The __name__ here is the name of the module where application is running. So the appropriate folder will become the root one for folders search.
projects/
yourproject/
app/
templates/
So if you provide instead some random name the root folder for the search will be current folder.

django/python 3.5 imports/separating views.py into separate files

I've looked at just about everything I can here. I'm using python 3.5 and i've seen stuff about how they've changed the way imports work. My django project structure is like this:
project
--app
--views/
--__init__.py
--myFile.py
--__init__.py
--models.py
--admin.py
--urls.py
--etc....
My urls.py is such:
from django.contrib import admin
from django.urls import path
from django.conf.urls import url, include
from . import views
urlpatterns = [
url(r'^api$', views.function_from_myFile_that_is_not_being_found),
otherurls()...
]
The error I'm getting is AttributeError: module 'app.views' has no attribute 'function_from_myFile_that_is_not_being_found'
I'm really lost as to why this is happening. I've tried putting imports in my __init__.py files and that hasn't worked either. Not sure what else I'm missing.
Thanks in advance.
In your project views is a package, not a single module. So you should do
from .views import myFile as views

RedirectView.as_view not working at the root

In a django 1.8 project, I am attempting to redirect http://myProject/ads.txt to an external url http://a.location.that.has.the.ads.txt.file and thus serve the ads.txt file without using ftp to simply place the ads.txt in the root.
Given this minimal directory structure:
django projects
myProject
myapp
urls.py
views.py
someotherapp
yetanotherapp
myProject
settings.py
urls.py (this is the top urls.py)
views.py
in myProject/myProject/urls.py, (the “top” urls.py) I have as the first entry in the urlpatterns list, the lines:
urlpatterns = patterns('',
(r'^ads\.txt', RedirectView.as_view(url='http://a.location.that.has.the.ads.txt.file', permanent=False)),
followed by many more pattern matching regex’s. This does not work and fails with a 404. What does work is
urlpatterns = patterns('',
(r'^foo/ads\.txt', RedirectView.as_view(url='http://a.location.that.has.the.ads.txt.file', permanent=False)),
and then calling http://myProject/foo/ads.txt
Unfortunately, ads.txt files must be placed at the site root. I have tried many different regex’s that test fine in a regex validator, but just don’t work (returns 404). How do I do this without the extra dir “foo”? Any thoughts appreciated. Thank you.
Turns out you cannot redirect with the top level urls.py "routing table" to above the Django project root. A nginx server level redirect did the trick.

how to solve ViewDoesNotExist

I'm new to Django 1.4 and try my first project. It's OK to create the app:
./manage.py startapp APP_NAME
and recognized by Django in urls.py as following:
(r'^home/$', 'APP_NAME.views.home'),
but when I only create a APP_NAME.py files in root directory of projects,and change the urls.py file as following:
(r'^home/$', 'APP_NAME.home'),
the debug page tell me ViewDoesNotExist. Even if I change the urls.py file to (with from...import and without single quotes):
from APP_NAME import home
(r'^home/$', home),
It also doesn't work.
How to solve it? It intricate to create APP for every view file.
Have you actually implemented your home function in 'APP_NAME.__init__.py'; if not, your code will not work, because there is nothing that can be called
python manage.py startapp news
In your created news directory there is a views.py. Now lets add something:
from django.http import HttpResponse
def index(request):
return HttpResponse("Hello")
now in your urls.py you add this:
(r'^news/$', 'news.index'),
Just start the devserver python manage.py runserver and point your browser to http://localhost:8000/news/
You should see "Hello".
Now you could add in your news/views.py some more stuff - like details, archive and so on.
Also be sure to have an empty __init__.py file in every directory you'd like to import.
from app.views import something will not work if there's no init-file within the app-directory.

No Module named Contact Error-Chapter 7 Exercise in Django Book

I've received the following error when trying to set up a contact subdirectory inside the mysite directory.
Here is how I structured the urls.py script:
from mysite.contact import views as contact_views
(r'^contact/$', contact_views.contact),
Do I need to change anything in the settings.py TEMPLATE_DIRS, so, I can call the contact_form.html template correctly?
Yes, template_dirs needs to contain the path to the templates folder.

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