Python Socket Scripting. What am i doing wrong? - python

My socket program hangs at clientsocket, address) = serversocket.accept() and doesn't spit our an error or anything.
I followed directions on https://docs.python.org/3/howto/sockets.html
I've been trying to figure it out for an hour now, but to no avail. I'm using python3 btw. What am i doing wrong? EDIT: My intedentation is all screwed up because I pasted it wrong, but other than that my code is as I have it in my file.
#import socket module
import socket
#creates an inet streaming socket.
serversocket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
print('socket created')
#binds socket to a public host, and a well known port
serversocket.bind(('127.0.0.1', 1024))
#print(socket.gethostname())# on desktop prints 'myname-PC')
#become a server socket
serversocket.listen(5) # listens for up to 5 requests
while True:
#accept connections from outside
#print('In while true loop') This works, but we never get to the next print statement. Why the hell is it catching at line 20?
(clientsocket, address) = serversocket.accept()
#clientsocket = serversocket.accept()
print('Ready to serve')
#now we do something with client socket...
try:
message = clientsocket.recv(1024)
filename = message.split()[1]
f = open(filename[1:])
outputdata = f.read()
#send an http header line
clientsocket.send('HTTP/1.1 200 OK\nContent-Type: text/html\n\n')
for i in range(0, len(outputdata)):
clientsocket.send(outputdata[i])
clientsocket.close()
except IOERROR:
clientsocket.send('HTTP/1.1 404 File not found!')
clientsocket.close()

If you haven't written a client script / program to connect to the socket and send it data, it's also going to hang on serversocket.accept() due to there being nothing to accept. But assuming you have...
while True:
#accept connections from outside
#print('In while true loop') This works, but we never get to the next print statement. Why the hell is it catching at line 20?
(clientsocket, address) = serversocket.accept()
#clientsocket = serversocket.accept()
It hangs because the loop never exits due to True always being True. In the example provided, once a connection is accepted they pretend that the server is threaded and the idea is to create a separate thread to begin reading and processing data received allowing the socket to continue to listen for more connections.
while True:
# accept connections from outside
(clientsocket, address) = serversocket.accept()
# now do something with the clientsocket
# in this case, we'll pretend this is a threaded server
ct = client_thread(clientsocket)
ct.run()

Related

I'm encountering a Python error when I mix threading, input, and TCP sockets

I'm creating a program that uses threads to handle sockets and input at the same time. I've narrowed down the errors I'm getting to be replicable in these couple dozen lines of code. What happens to anyone else who runs the code below? I encounter a hang-up in waiting for the recv in the client. If I further try to send() more data in the server, I get a Broken Pipe error. And, even more weirdly, if I comment out the line that calls input(), the sockets work just fine.
What kind of weird interaction is going on between input(), sockets, and threading? And does anyone have a solution to this? Here's some code that generates the error.
Server:
import socket
import threading
def handle_connection(conn, addr):
data = conn.recv(1024)
message = data.decode('ascii').split()
s = "TEST"
conn.send(bytes(s, 'ascii')) #
conn.close()
def handle_input():
while True:
s = input()
print(s)
HOST = "127.0.0.1" # The server's hostname or IP address
PORT = 2000 # The port used by the server
with socket.socket(socket.AF_INET, socket.SOCK_STREAM) as s:
s.bind((HOST, PORT)); #Empty first string = INADDR_ANY
s.listen();
w = threading.Thread(target=handle_input)
w.start()
while True:
conn, addr = s.accept()
x = threading.Thread(target=handle_connection, args=(conn, addr))
x.start()
s.close()
Client:
import socket
HOST = "127.0.0.1" # The server's hostname or IP address
PORT = 2000 # The port used by the server
with socket.socket(socket.AF_INET, socket.SOCK_STREAM) as s:
message = "find_successor a"
s.connect((HOST, PORT))
s.sendall(bytes(message, 'ascii'))
data = s.recv(1024)
print(f"Received {data!r}")
I appreciate any help or insight!

Getting a ConnectionResetError when client script is stopped on UDP socket

I am making a script that will allow multiple clients to see live camera footage from the server script, this all works fine until one of the client scripts is closed, then a ConnectionResetError is raised, To avoid this I used a try and except block to catch the ConnectionResetError but the same error is raised every time after a connection is lost. Using just socket.recv stops the ConnectionResetError but socket.recv does not return the senders address which is required for the script to send the video stream back to the client.
Server:
host = "0.0.0.0"
port = 5000
buffer_size = 1024
sock = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
sock.bind(("", port))
listeners = list() # the addresses of the clients that want the video stream
def handle_queue(sock):
while True:
try:
message, address = sock.recvfrom(buffer_size) # block the thread until a packet arrives
print(address)
message = str(message, "utf-8") # decode the message
if message == "join":
listeners.append(address) # add the list of listeners
else:
print("unknown queue msg: ", message)
except ConnectionResetError:
print("The connection was forcefully quit")
queue_handler_thread = Thread(target=handle_queue, args=(sock,), daemon=True)
queue_handler_thread.start() # start the queue
the script then uses sock.sendto() for each address in the listeners list
Client:
sock = socket.socket(socket.AF_INET, socket.SOCK_DGRAM)
sock.sendto(bytes("join","utf-8"), (host, port))
while True:
data, address = sock.recvfrom(max_length) # block main thread until a packet is received
I believe what you are looking for is socket.getpeername().
This will return the remote address to which the socket is connected.
Your approach in handling the data in the wire whilst the connection is closed/lost is the right way. Handling via try/catch or using a recv() or recvfrom() method to wait for a response before closing the socket.
Since posting this i have discovered that it is infact TCP and this will not work for the project I am trying to do. Any more guidance and help would be appreciated, I cant seem to find any examples of Multiclient UDP Servers that run through one socket.
I partially resolved my system, after using the Example provided by AztCrw4282.
I was able to find a solution, I instead used the socket.accept() aproach, I am unsure as to whether this is UDP or TCP (I want UDP but with the connect system I think that is the handshake for TCP, but I am not 100% sure), but it works for now.
The client has to connect to the server then the server will accept or deny the connection, upon accepting a thread will be created for that clients connection to be managed. If any errors are thrown when interacting with that client their connection will be closed.
Server
try:
ServerSocket.bind((host, port))
except socket.error as e:
print(str(e))
print('Waiting for a Connection..')
ServerSocket.listen(5)
connections = list()
def threaded_client(connection):
connection.send(str.encode('Welcome to the Server\n'))
while True:
try:
data = str(connection.recv(2048),"utf-8") # this needs to be try catched
print("Packet Recv: ", data)
if data == "join":
print("Client Joined")
if data == "quit":
break
if not data:
break
except ConnectionResetError:
break
print("Closing a connection") # need to handle leaving the stream
connection.close()
def handle_stream():
for connection in connections:
try:
connection.send(bytes(json.dumps(frame_info) ,"utf-8"))
except:
print("Packet send failure, kicking client")
connections.remove(connection)
while True:
Client, address = ServerSocket.accept()
print('Connected to: ' + address[0] + ':' + str(address[1]))
connections.append(Client)
Thread(target=threaded_client, args=(Client, ), daemon=True).start()
ThreadCount += 1
print('Thread Number: ' + str(ThreadCount))
The only part that changes for the client is the part where it connects to the server
try:
ClientSocket.connect((host, port))
except socket.error as e:
print(str(e))

How to send and receive from the same socket in Python?

I'm am trying to write a client program in Python that can send and receive from the same socket, but it is always giving me the same error which address is already in use. Here is the function I'm trying to write.
def Login():
username=raw_input()
password=raw_input()
message=raw_input()
array=[username,password,message]
TCP_IP = '127.0.0.1'
TCP_PORT = 5563
BUFFER_SIZE = 1024 # Normally 1024, but we want fast response
sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
sock.connect((TCP_IP, TCP_PORT))
array_string=pickle.dumps(array)
sock.send(array_string)
sock.close()
sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
sock.bind((TCP_IP, TCP_PORT))
sock.listen(1)
conn, info = sock.accept()
while 1:
data = serverSocket.recv(1024)
if not data:break
conn.send(data)
conn.close()
There is a bunch of truly newbie errors here.
You can't ever connect a TCP socket to itself. There must be two different sockets.
If you really want to get the data you sent earlier at a listening socket, this listening socket must be created, bound and configured to listen before the client side connects (or, at least, in parallel to this connect attempt, in a few seconds, so the connect attempt will try - but this very likely won't work on localhost).
You can't wait on connect and on accept in the same thread if both are blocking. The simplest approach is to separate the client side and the server side to 2 different programs and run them manually in parallel. Then, after successful debugging, you will be able to do this in different threads of the same process, or using an event-driven engine.
While you may not be able to connect a socket to itself to send and receive data, you might be able to learn from the following example inspired by your code that attempts to do something similar.
import _thread
import pickle
import socket
import time
def main():
"""Run a server in a thread and start a client to talk to it."""
_thread.start_new_thread(run_server, ('', 5563))
run_client('localhost', 5563)
def run_server(host, port):
"""Handle all incoming connections by spawning worker threads."""
server = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
server.bind((host, port))
server.listen(5)
while True:
_thread.start_new_thread(handle_connection, server.accept())
def handle_connection(client, address):
"""Answer an incoming question from the connected client."""
print('Incoming connection from', address)
client.settimeout(0.1)
data = recvall(client)
client.shutdown(socket.SHUT_RD)
question = pickle.loads(data)
answer = '''len(username) = {}
len(password) = {}
len(message) = {}'''.format(*map(len, question))
client.sendall(answer.encode())
client.shutdown(socket.SHUT_WR)
client.close()
print('Finished with', address)
def recvall(connection):
"""Receive all data from a socket and return as a bytes object."""
buffer = bytearray()
while True:
try:
data = connection.recv(1 << 12)
except socket.timeout:
pass
else:
if data:
buffer.extend(data)
else:
return bytes(buffer)
def run_client(host, port):
"""Collect information from question and display returned answer."""
client = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
time.sleep(0.1) # wait for server to start listening for clients
client.connect((host, port))
time.sleep(0.1) # wait for handler thread to display connection
username = input('Username: ')
password = input('Password: ')
message = input('Message: ')
question = pickle.dumps((username, password, message))
client.sendall(question)
client.shutdown(socket.SHUT_WR)
answer = recvall(client)
client.shutdown(socket.SHUT_RD)
client.close()
print(answer.decode())
time.sleep(0.1) # wait for handler to cleanly terminate execution
if __name__ == '__main__':
main()

Python Server send data not working

I am currently working on a server in Python, the problem I am facing is the client could not retrieve the sent data from server.
The code of the server is:
import sys
import socket
from threading import Thread
allClients=[]
class Client(Thread):
def __init__(self,clientSocket):
Thread.__init__(self)
self.sockfd = clientSocket #socket client
self.name = ""
self.nickName = ""
def newClientConnect(self):
allClients.append(self.sockfd)
while True:
while True:
try:
rm= self.sockfd.recv(1024)
print rm
try:
self.sockfd.sendall("\n Test text to check send.")
print "Data send successfull"
break
except socket.error, e:
print "Could not send data"
break
except ValueError:
self.sockfd.send("\n Could not connect properly")
def run(self):
self.newClientConnect()
self.sockfd.close()
while True:
buff = self.sockfd.recv(1024)
if buff.strip() == 'quit':
self.sockfd.close()
break # Exit when break
else:
self.sendAll(buff)
#Main
if __name__ == "__main__":
#Server Connection to socket:
IP = '127.0.0.1'
PORT = 80
serversocket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
serversocket.setsockopt( socket.SOL_SOCKET, socket.SO_REUSEADDR,1)
print ("Server Started")
try:
serversocket.bind(('',5000))
except ValueError,e:
print e
serversocket.listen(5)
while True:
(clientSocket, address) = serversocket.accept()
print 'New connection from ', address
ct = Client(clientSocket)
ct.start()
__all__ = ['allClients','Client']
#--
And the client connecting is:
import socket
HOST = '192.168.1.4' # The remote host
PORT = 5000 # The same port as used by the server
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((HOST, PORT))
data = s.recv(1024)
s.close()
print 'Received', data#repr(data)
In need of a quick solution....
Thanks,
I tested out your code, and when I commented out
rm= self.sockfd.recv(1024)
print rm
it worked fine. Basically the server stopped there to wait for a message that never came. If it still does not work for you, there might be two problems. Either you have a firewall that blocks the connection somehow, or you have old servers running in the background from previous tries that actually wasn't killed. Check your processes if pythonw.exe or equivalent is running when it shouldn't be, and kill it.
To wait for response:
with s.makefile('rb') as f:
data = f.read() # block until the whole response is read
s.close()
There are multiple issues in your code:
nested while True without break
finally: ..close() is executed before except ValueError: ..send
multiple self.sockfd.close()
etc
Also you should probably use .sendall() instead of .send().
your server code is excepting client send something first,
rm= self.sockfd.recv(1024)
but I don't see any in your code
please try send something in your client code
s.connect((HOST, PORT))
s.send("hello")
Short solution
Add a short sleep after connect.
import time
time.sleep(3)

socket.send working only once in python code for an echo client

I have the following code for an echo client that sends data to an echo server using socket connection:
echo_client.py
import socket
host = '192.168.2.2'
port = 50000
size = 1024
def get_command():
#..Code for this here
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.connect((host,port))
while 1:
msg = get_command()
if msg == 'turn on':
s.send('Y')
elif msg == 'turn off':
s.send('N')
elif msg == 'bye bye':
break
else:
s.send('X')
data = s.recv(size)
print 'Received: ',data
s.close()
echo_server.py
import socket
host = ''
port = 50000
backlog = 5
size = 1024
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind((host,port))
s.listen(backlog)
while 1:
client, address = s.accept()
data = client.recv(size)
if data:
client.send(data)
client.close()
The problem im facing is that in the client s.send works only the first time even though its in an infinite loop. The client crashes with connection timed out, some time after the first send/receive has completed.
Why is s.send working only once ?. How can i fix this in my code ?
Please Help
Thank You
Your server code only calls recv once. You should call accept once if you only want to receive one connection, but then you need to loop calling recv and send.
Your problem is that you are blocking on the accept inside the server's loop.
This is expecting the server to accept connections from more than one client. If you want that, and for each client to send multiple commands, you would need to spawn a new thread (or process) after the accept, with a new while loop (for client communication) in that thread/process.
To fix your example to work with just one client, you need to move the accept outside the loop, like so:
client, address = s.accept()
while 1:
data = client.recv(size)
if data:
client.send(data)

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